Skip to chapter text
ChemistryCh 3 Classification of Elements and Periodicity in Properties

Classification of Elements and Periodicity in Properties: Class 11 Chemistry · Chapter 3

Chemistry Part 1 · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 95 min
  • 46 practice questions
  • 30 MCQs

What you will learn in Classification of Elements and Periodicity in Properties

  • Trace how classification grew from Döbereiner's triads and Newlands' octaves to Mendeleev's periodic law, and explain why Mendeleev's table convinced chemists
  • State the modern periodic law and explain why atomic number, not atomic mass, is the basis of the periodic table
  • Write the IUPAC systematic name and symbol of an element from its atomic number above 100
  • Connect the length of each period and the period, group and block of an element to its electronic configuration
  • Describe the main features of s-, p-, d- and f-block elements and of metals, non-metals and metalloids
  • Explain how electronegativity, ionization enthalpy, electron gain enthalpy and the sizes of atoms and ions change across periods and down groups, including the exceptions
  • Use periodic trends to predict valence, formulas of compounds, the nature of oxides and chemical reactivity
  • Explain the unusual behaviour of the second-period elements and the diagonal relationship

Original companion text aligned to NCERT Chemistry Class 11, Chapter 3, pp. 74–99. Not affiliated with or endorsed by NCERT.

Walk into a busy medical store and ask for a cough syrup. The pharmacist does not search every shelf: syrups sit together, tablets of one kind sit together, and a new brand goes straight into its place. The periodic table does the same job for chemistry. It is a single chart that tells you where each element belongs, which elements behave alike, and roughly how an element you have never handled will behave.

This chapter follows the table from its first rough drafts to the long form printed in your book, and shows why its shape follows from electronic configuration. It then uses the table to explain how size, ionization enthalpy, electron gain enthalpy, electronegativity, valence and reactivity change from element to element. Almost every later chapter of chemistry leans on these trends.

3.1 Why do we need to classify elements?

Around the year 1800 chemists knew roughly thirty elements. By the 1860s the count had passed sixty, and today 118 elements are confirmed, the heaviest of them made in accelerators a few atoms at a time. Each element forms many compounds. Learning all of them one by one would be hopeless.

A good classification fixes this in two ways. It organises what is already known: once you know that sodium and potassium are alike, a fact about one tells you a lot about the other. It also predicts what is not yet known: an empty place in a pattern points to an element waiting to be found, and even hints at its properties. Both payoffs drove the search for a natural arrangement of the elements in the nineteenth century.

3.2 Genesis of Periodic Classification

No single person invented the periodic table. Several chemists, each working with the atomic weights (relative atomic masses) of their time, noticed pieces of the pattern. Follow their attempts in Fig. 3.1 and in the timeline below.

Triads (Döbereiner, 1829). The German chemist Johann Döbereiner found sets of three similar elements in which the middle member had an atomic weight close to the average of the other two, and properties between theirs. Sulphur, selenium and tellurium form such a triad. The idea worked for only a handful of sets, so most chemists treated it as a coincidence.

A spiral on a cylinder (de Chancourtois, 1862). The French geologist A. E. B. de Chancourtois wrote the elements in order of atomic weight along a spiral line wound round a cylinder. Similar elements then fell one above another. His paper reached few chemists and the idea was overlooked.

Octaves (Newlands, 1865). The English chemist John Newlands listed the elements by atomic weight and saw that each element resembled the one seven places after it, the eighth in the count. He compared this with music: after Sa Re Ga Ma Pa Dha Ni comes the upper Sa, which sounds like the first. The rule held only as far as calcium; beyond it, metals such as iron landed among non-metals. Fellow chemists mocked the idea, yet the Royal Society awarded Newlands its Davy Medal in 1887.

2/3Listed by atomic weight, every eighth element resembles the first.

Fig. 3.1Two early patterns: a triad and Newlands' octaves, which break down after calcium.NCERT Tables 3.1–3.2 · p. 75

Step one shows sulphur (32.1), selenium (79.0) and tellurium (127.6) on a number line; a dashed line marks the mean of the two ends, 79.9, almost exactly at selenium. Step two replaces this with two rows of keys labelled Sa to Ni: lithium to fluorine on the first row and sodium to chlorine on the second, so each element sits under its look-alike, as the eighth note repeats the first. Step three adds a third row, potassium, calcium, chromium, titanium, manganese, iron, and cobalt with nickel; the last two keys are crossed out because iron does not resemble oxygen and sulphur, and cobalt and nickel are not halogens.

Curves and tables (Lothar Meyer and Mendeleev, 1868–1870). In Germany, Lothar Meyer took a graphical route. He drew a curve of atomic volume, the volume occupied by a mole of atoms, against atomic weight. It climbs to a sharp peak at each alkali metal and dips in between, like a row of waves, and the waves get wider for heavier elements, something Newlands' fixed octaves could not capture. Meyer's own table dates from 1868, but the Russian chemist Dmitri Mendeleev (1834–1907) got his into print first, in 1869, so Mendeleev usually receives the credit for the periodic law.

LawMendeleev's periodic law

When elements are arranged in order of increasing atomic weight, their physical and chemical properties recur at regular intervals.

Mendeleev is said to have written each element, its atomic weight and its properties on a card, then rearranged the cards until families lined up. His table ran by atomic weight along the rows, with chemically similar elements stacked in columns, or groups. What made it stronger than Meyer's was the evidence behind it: not one physical property but many chemical ones, above all the formulas of each element's oxide and hydride. Two bold decisions made it stand out (Fig. 3.2).

  1. Properties over weights. Tellurium (127.6) is heavier than iodine (126.9), so strict weight order would put iodine with oxygen and sulphur and tellurium with the halogens. Mendeleev swapped them, trusting chemistry over the numbers, and suspected the weights were wrong.
  2. Gaps for the unknown. Where no known element fitted a column, he left a blank and described the missing element. He called the one below aluminium eka-aluminium and the one below silicon eka-silicon (eka is Sanskrit for 'one'). Gallium (1875) and germanium (1886) were later found with properties very close to his forecasts.

4/4Gallium and germanium fill the blanks years later.

Fig. 3.2Mendeleev put chemical likeness ahead of atomic weight and left room for elements not yet discovered.NCERT Fig. 3.1 · p. 77

A grid of groups III to VII with four rows: B to F, Al to Cl, a row with two empty dashed cells followed by As, Se and Br, and In, Sn, Sb, I, Te. In step one iodine and tellurium are outlined as misfits, because by weight iodine would sit under selenium and tellurium under bromine. In step two the two cells slide past each other so tellurium sits under selenium and iodine under bromine. In step three the caption points to the two empty cells kept for unknown elements. In step four the empty cells fill with gallium (69.7) and germanium (72.6), with their discovery years 1875 and 1886.

Timeline

From triads to the modern table

  1. 1829

    Döbereiner's triads

    Groups of three similar elements.

  2. 1862

    de Chancourtois' cylinder

    Elements on a spiral; look-alikes line up.

  3. 1865

    Newlands' octaves

    Every eighth element alike, up to calcium.

  4. 1869

    Mendeleev's periodic table

    Mass order bent for chemistry; gaps left. Lothar Meyer's table follows in print.

  5. 1875–1886

    Predictions confirmed

    Gallium, scandium and germanium are discovered.

  6. 1913

    Moseley's X-ray study

    Atomic number becomes the basis of order.

  7. 1944–45

    Seaborg's actinoid row

    Thorium onwards placed in a second f row.

  8. 2016

    Period 7 completed

    Names announced for elements 113, 115, 117 and 118.

Quick check
1 of 3
Phosphorus (31.0), arsenic and antimony (121.8) behave alike. If they obeyed Döbereiner's rule, what would arsenic's atomic weight be?
Show answer

Answer (D) About 76

(31.0+121.8)/2≈76.4, close to arsenic's real 74.9. Adding instead of averaging gives about 153; the other values do not follow from the rule.

3.3 Modern Periodic Law and the Present Form of the Periodic Table

Mendeleev worked without knowing what an atom contains. Electrons were discovered only in 1897 and the nucleus in 1911, so he could not explain why his law worked, nor why a few pairs such as tellurium and iodine refused to obey weight order. The answer came from X-rays.

In 1913 the English physicist Henry Moseley fired fast electrons at targets made of different elements. Each element gave off X-rays of its own characteristic frequencies ν. When he plotted ν for the strongest line against the element's position in the table, the points fell on a straight line; against atomic mass they did not (Fig. 3.3). The quantity that rose by exactly one from each element to the next was the atomic number Z. It is the charge on the nucleus, equal to the number of protons and to the number of electrons in the neutral atom.

Moseley's relation
ν=a (Z−b)
where
ν
frequency of a characteristic X-ray line
a,b
constants for a given line (b ≈ 1 for the strongest line)

2/2Ordered by atomic number, the points lie on one line.

Fig. 3.3Moseley's plot: atomic number, not atomic mass, gives the smooth order.

Points for titanium, vanadium, chromium, manganese, iron, cobalt, nickel, copper and zinc. In step one the horizontal axis is atomic mass from 48 to 64: the points join in a zig-zag, and nickel, which is lighter than cobalt, sits above it, out of order. In step two the axis changes to atomic number 22 to 30; each point slides sideways and all nine fall on one straight line, with cobalt (27) before nickel (28).

LawModern periodic law

When the elements are arranged in order of increasing atomic number, their physical and chemical properties repeat periodically.

With atomic number as the order, the old misfits behave. Argon (Z=18) comes before potassium (Z=19) though it is heavier; cobalt (27) comes before nickel (28); tellurium (52) before iodine (53). Mendeleev's chemical instinct had been right, and the weights were never wrong: they simply were not the right thing to sort by.

Example

Identifying an element from its X-rays

The strongest X-ray line of iron (Z=26) has frequency 1.55×1018 Hz. A metal sample gives the same kind of line at 2.24×1018 Hz. Taking b=1 in Moseley's relation, find the atomic number of the metal.

Try it yourself first. Then reveal the solution one step at a time.

Ninety-four elements are found in nature, if we count the traces of neptunium and plutonium that form in uranium ores; every heavier element has been made artificially, in reactors or accelerators. Today we see the periodic law as a consequence of something deeper: electronic configurations repeat as shells fill, and configuration fixes chemistry. Section 3.5 makes this connection precise.

The table in your book is the long form, the most widely used of the many layouts chemists have tried, from spirals to pyramids. Read across it and you move along a period (आवर्त); read down and you stay within a group (वर्ग), a family of elements whose outer electronic configurations match. Groups are numbered 1 to 18 from left to right, as IUPAC recommends; older books use labels such as IA, IIB, VIII and 0, so expect to meet both.

  • There are seven periods. The period number is the principal quantum number n of the outermost shell.
  • The periods hold 2, 8, 8, 18, 18, 32 and 32 elements. Period 7 has been complete since elements 113 to 118 were confirmed.
  • Fourteen elements of period 6 (the lanthanoids) and fourteen of period 7 (the actinoids) are printed as two separate rows at the foot of the table, so the main table is not too wide.
Quick check
1 of 3
Argon (39.9) is heavier than potassium (39.1), yet argon comes first in the modern table. Why?
Show answer

Answer (D) Argon has the smaller atomic number

The modern table is ordered by atomic number: argon has Z=18 and potassium Z=19. The masses are correct; they are just not the basis of the order.

3.4 Nomenclature of Elements with Atomic Numbers > 100

Who gets to name a new element? Traditionally its discoverers, with IUPAC's approval. That works until two teams claim the same discovery. From the late 1960s, laboratories at Berkeley in the USA and at Dubna in the Soviet Union both reported element 105. Berkeley called it hahnium, Dubna nielsbohrium, and the argument dragged on until IUPAC settled on dubnium in 1997. Disputes like this arise easily, because superheavy elements are made only a few atoms at a time, in a handful of laboratories with very costly equipment, and many of the atoms decay within seconds.

IUPAC's fix is a temporary name that nobody can argue about, because it is simply the atomic number spelt out. Write each digit of Z as its root from Table 3.2 (the roots come from Latin and Greek numbers), run the roots together and finish with -ium. The first letters of the roots make a three-letter symbol.

Table 3.2IUPAC roots for the digits
DigitRootLetterDigitRootLetter
0niln5pentp
1unu6hexh
2bib7septs
3trit8octo
4quadq9enne
  • Two spelling rules: when enn comes before nil, one n is dropped (ennil); when the name would end in bi-ium or tri-ium, the i is dropped (bium, trium).
  • Element 116, for example, was ununhexium (Uuh) until it was named livermorium (Lv).

3/4Join the roots, add -ium, and take the first letters: ununoctium, Uuo.

Fig. 3.4A systematic name is the digit roots in order plus -ium; the symbol is their first letters.NCERT Tables 3.4–3.5 · p. 80

Step one shows the atomic number 118 as three digit boxes: 1, 1 and 8. Step two adds the root under each digit: un, un and oct, with the first letter of each root highlighted. Step three adds a chip reading plus ium and shows the joined name ununoctium with the symbol Uuo, made from the highlighted letters. Step four adds a band with the permanent name approved in 2016: oganesson, symbol Og.

The temporary name lasts only until a joint IUPAC–IUPAP panel has checked the discovery claim. The discoverers then propose a permanent name with a one- or two-letter symbol, often honouring a place, a laboratory or a scientist, and IUPAC approves it after a period of public comment. Every element up to 118 has now been through this process; the last four names were confirmed in 2016 (Table 3.3).

Table 3.3The newest names in period 7
ZTemporary nameOfficial nameNamed after
113ununtriumnihonium (Nh)Nihon, Japanese for Japan
114ununquadiumflerovium (Fl)Flerov Laboratory, Dubna
115ununpentiummoscovium (Mc)Moscow region
116ununhexiumlivermorium (Lv)Lawrence Livermore Laboratory
117ununseptiumtennessine (Ts)US state of Tennessee
118ununoctiumoganesson (Og)physicist Yuri Oganessian
Example 3.1NCERT Problem 3.1 · p. 81

Systematic names

Write the IUPAC systematic name and symbol for the elements with atomic numbers (a) 119, (b) 190 and (c) 123.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 2
The systematic name of element 104 was , symbol .
Show answer

Answer (1) unnilquadium, (2) Unq

un + nil + quad + ium = unnilquadium, Unq. Its official name is rutherfordium (Rf).

3.5 Electronic Configurations of Elements and the Periodic Table

Here is the payoff of the previous chapter. Take the aufbau order, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, and give each new element one more electron than the last. Start a new row every time a new shell is opened, and line up each element under the one whose outer subshells match. The long form of the table appears without any further rules.

(a) Electronic configurations in periods

A new period begins every time electrons start a new shell, so the period number equals n of the valence shell. The length of a period equals the number of electrons that can go into the subshells filled during it, that is, twice the number of orbitals being filled. Build the table row by row in Fig. 3.5.

  • Period 1 (n=1): only the 1s orbital, so two elements, hydrogen (1s1) and helium (1s2).
  • Periods 2 and 3: one ns and three np orbitals, so eight elements each, lithium to neon and sodium to argon. The 3d orbitals lie above 4s in energy, so they are not used in period 3.
  • Period 4: potassium and calcium fill 4s; then the ten elements from scandium (Z=21, 3d14s2) to zinc (Z=30, 3d104s2) fill 3d, the first transition series; gallium to krypton fill 4p. Nine orbitals, eighteen elements.
  • Period 5: rubidium to xenon in the same pattern, with the 4d series starting at yttrium (Z=39). Again eighteen.
  • Period 6: 6s, 4f, 5d and 6p, sixteen orbitals, 32 elements. The 4f subshell fills from cerium (Z=58) to lutetium (Z=71): the lanthanoids.
  • Period 7: 7s, 5f, 6d and 7p, again 32 elements, ending with oganesson (Z=118) in group 18. The 5f subshell fills after actinium (Z=89) from thorium to lawrencium: the actinoids, most of them made artificially.

4/4(n−2)f joins in: sixteen orbitals, thirty-two elements.

Fig. 3.5Period lengths follow the number of orbitals filled: 2, 8, 18 and 32 elements.NCERT Fig. 3.2 · p. 79

A grid of 18 columns and 7 rows with a total count at the right of each row. Step one shows only period 1: two cells, at the far left and far right, and the caption n = 1, one orbital, two elements. Step two adds periods 2 and 3 with two s cells and six p cells each and the count 8; labels name the s-block and p-block. Step three adds periods 4 and 5 with ten d cells in the middle, count 18, caption nine orbitals. Step four adds periods 6 and 7, count 32, and two separate rows of fourteen f-block cells below, linked by stars to the place in group 3 where they belong.

Why print the lanthanoids and actinoids separately? Squeezing 28 more elements into periods 6 and 7 would make the table very wide. More importantly, the fourteen members of each series are so alike that they would all deserve the single column of group 3. Printing them as two rows keeps every column a family of similar elements.

Example 3.2NCERT Problem 3.2 · p. 82

Why period 4 has eighteen elements

Use quantum numbers and the aufbau order to show that the fourth period must contain 18 elements.

Try it yourself first. Then reveal the solution one step at a time.

(b) Groupwise electronic configurations

Read down a column instead of along a row and the outer configuration stays the same while n grows. Elements of one group therefore have the same number of valence electrons arranged the same way, and that is why they behave alike. The alkaline earth metals of group 2 all end in ns2 (Table 3.4).

Table 3.4Group 2: one outer pattern, six shells
ElementZConfiguration
Beryllium (Be)4[He]2s2
Magnesium (Mg)12[Ne]3s2
Calcium (Ca)20[Ar]4s2
Strontium (Sr)38[Kr]5s2
Barium (Ba)56[Xe]6s2
Radium (Ra)88[Rn]7s2

Notice that the atomic numbers down a group do not rise by a fixed amount: they jump by 8, 8, 18, 18 and 32, the lengths of the periods in between. Configuration, and so chemistry, depends on atomic number, which is why the modern law uses it and not atomic mass.

Quick check
1 of 3
An element has the configuration [Ne]3s23p3. Where is it?
Show answer

Answer (A) Period 3, group 15

The outer shell is n=3, so period 3. It has 2 + 3 = 5 outer electrons in the p-block, so group 10 + 5 = 15 (this is phosphorus). 'Group 5' would be a d-block column.

3.6 Electronic Configurations and Types of Elements: s-, p-, d-, f-Blocks

Because the subshell that receives the last electron decides an element's column, the table splits naturally into four blocks, named after that subshell. Their shapes match the subshell capacities: two columns for s, six for p, ten for d and fourteen for f.

Compare

The four blocks at a glance

s-block

  • Groups 1 and 2
  • Outer: ns1 or ns2
  • Soft, reactive metals

p-block

  • Groups 13 to 18
  • Outer: ns2np1 to ns2np6
  • Metals, metalloids, non-metals

d-block

  • Groups 3 to 12
  • Outer: (n−1)d1−10ns0−2
  • Transition metals

f-block

  • Two rows below
  • Outer: (n−2)f1−14(n−1)d0−1ns2
  • Lanthanoids, actinoids

Two elements break the simple rule. Helium is 1s2, so strictly it is an s-block element, but its shell is full and it is as unreactive as the other noble gases, so it stands at the top of group 18. Hydrogen has a single 1s electron. Like the group 1 metals it can lose it to form HX+; like the halogens it can gain one to reach the helium configuration, forming HX−. Because it fits neither family neatly, many tables place it on its own at the top.

3.6.1 The s-Block Elements

The s-block is just two columns wide: group 1, the alkali metals (ns1), and group 2, the alkaline earth metals (ns2). Sodium has to be kept under kerosene, and none of these metals is found uncombined in rocks or seawater. Their ionization enthalpies are low, so they give up their one or two outer electrons readily and become MX+ or MX2+ ions. Down either column the atoms get bigger, the outer electrons go even more easily and the metals grow more reactive; lithium fizzes gently in water, caesium explodes. Most s-block compounds, common salt among them, are ionic. Lithium and beryllium, the tiny first members, are the exceptions: their compounds are noticeably covalent.

3.6.2 The p-Block Elements

Six columns, groups 13 to 18, form the p-block, where the outer configuration runs from ns2np1 to ns2np6. Read it from the right. Group 18 holds the noble gases: every valence orbital is full, so they neither give up nor accept electrons easily and hardly react at all. Their neighbours are the opposite. The chalcogens of group 16 and the halogens of group 17 sit just short of a full shell, by two electrons and by one. Their electron gain enthalpies are strongly negative, so they grab electrons readily; they are some of the most important non-metals. Moving left within the block, or down any of its columns, metallic character increases. The s- and p-blocks together make up the main group, and their members are known as representative elements.

3.6.3 The d-Block Elements (Transition Elements)

Iron, copper, silver, gold and platinum all come from the ten-column d-block in the middle of the table, groups 3 to 12. The old name transition elements (संक्रमण तत्व) comes from their position, between the very reactive s-block metals on the left and the less active metals of groups 13 and 14 on the right. What sets them apart electronically is where the last electron goes: not into the outermost shell but into the (n−1)d subshell beneath it, giving the pattern (n−1)d1−10ns0−2. Palladium, 4d105s0, has no outer s electron at all. Every d-block element is a metal. Many show several oxidation states, give coloured ions (think of blue copper sulphate solution), are paramagnetic and work as catalysts. Zinc, cadmium and mercury, whose (n−1)d10ns2 arrangement is complete, show few of these features. Class 12 chemistry gives the d-block a chapter of its own.

3.6.4 The f-Block Elements (Inner-Transition Elements)

The two rows printed at the foot of the table make up the f-block. Here the incoming electron goes two shells in from the outside, into 4f or 5f, so the outer pattern is (n−2)f1−14(n−1)d0−1ns2 and the elements are called inner-transition elements. The first row, cerium (Z=58) to lutetium (Z=71), is the lanthanoids; the second, thorium (Z=90) to lawrencium (Z=103), is the actinoids. Because the electrons being added are buried so deep, neighbours within each series are remarkably alike, and all of them are metals. Every actinoid is radioactive. The early actinoids show many oxidation states, which makes their chemistry richer than that of the lanthanoids. Many later ones have been made only in nanogram amounts or less, so little of their chemistry is known. Elements beyond uranium (Z=92) are called transuranium elements.

Example 3.3NCERT Problem 3.3 · p. 84

Placing an element from its atomic number

Without looking at a periodic table, find the period, group and block of the elements with Z=115 and Z=119, and write their outer electronic configurations.

Try it yourself first. Then reveal the solution one step at a time.

InteractiveElement locator

A number box with plus and minus buttons and a slider for the atomic number. A skeleton periodic table of 18 columns, 7 rows and two f-block rows marks the chosen element's cell in black with an orange ring; for 119 and 120 a short eighth row appears. Below it a panel lists the electronic configuration (with the observed one where real atoms differ from the aufbau order), the period, the block, the group and its family name, the number of valence electrons for s- and p-block elements, and whether the element is a metal, metalloid or non-metal. For atomic numbers above 100 it adds the IUPAC systematic name and symbol, and notes explain special cases such as hydrogen, helium, group 12 and radioactive elements.

Fig. 3.6Type any atomic number to see its configuration, period, group and block; above 100 you also get the systematic name.
Quick check
1 of 3
Match each outer configuration with its block.

Tap an item on the left, then its match on the right.

Show answer
Answer
  • 5s2 : s-block
  • 4s24p4 : p-block
  • 4d55s1 : d-block
  • 4f76s2 : f-block
The block is the subshell that receives the last electron: s, p, d or f. Note that 4d55s1 (molybdenum) is d-block even though it has an s electron outside.

3.6.5 Metals, Non-metals and Metalloids

Long before electrons were known, chemists sorted elements into metals and non-metals, and the division still matters. More than three quarters of all elements are metals, filling the left side and the centre of the table; the non-metals are crowded into its upper right corner.

You can tell the two kinds apart by handling them. A metal is lustrous, conducts heat and electricity well, and can be beaten into sheets (malleable, like the silver varq on sweets) or drawn into wire (ductile, like copper). Nearly all metals are solids with high melting points; mercury is a liquid, and gallium (about 30 °C) and caesium (about 28 °C) melt on a hot day. Non-metals are solids or gases at room temperature, bromine being the one liquid. They usually melt and boil at low temperatures, conduct poorly, and break rather than bend when solid; boron and carbon, with extremely high melting points, are the exceptions.

The change from one kind to the other is gradual. Across a period, metallic character fades and non-metallic character grows; down a group, elements become more metallic. Along a stepped diagonal line through the p-block lie elements with a mixture of properties: boron, silicon, germanium, arsenic, antimony and tellurium (Fig. 3.7). They are called metalloids (उपधातु) or semi-metals. Silicon, for instance, looks shiny like a metal but is brittle and conducts electricity only modestly, which is exactly what makes it useful in computer chips and solar cells.

4/4Six metalloids lie along the staircase between them.

Fig. 3.7Metalloids lie along a diagonal staircase between the metals and the non-metals.NCERT Fig. 3.3 · p. 83

A grid of the p-block from boron to xenon, with a note that groups 1 to 12 are all metals. Step one shows the bare grid. Step two shades the metals aluminium, gallium, indium and tin in blue. Step three shades the non-metals, carbon, nitrogen, oxygen, fluorine, neon, phosphorus, sulphur, chlorine, argon, selenium, bromine, krypton, iodine and xenon, in green. Step four hatches the metalloids boron, silicon, germanium, arsenic, antimony and tellurium in yellow and draws two thick stepped lines that enclose them along a diagonal, with a legend.

Compare

Metals and non-metals

Metals

  • Lustrous solids (Hg liquid)
  • High melting points, mostly
  • Good conductors
  • Malleable and ductile
  • Lose electrons: form cations

Non-metals

  • Solids or gases (Br₂ liquid)
  • Low melting points, mostly
  • Poor conductors (graphite excepted)
  • Brittle when solid
  • Gain or share electrons
Example 3.4NCERT Problem 3.4 · p. 85

Ordering metallic character

Arrange S, Mg, Ca, Al and K in increasing order of metallic character.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 2
Which of these are metalloids?
Select all that apply
Show answer
Answer
  • (A) Germanium
  • (B) Arsenic
  • (E) Boron
Boron, germanium and arsenic lie on the staircase. Tin, just below germanium, is a metal; sulphur is a non-metal.

3.7 Periodic Trends in Properties of Elements

Look along period 3 and reactivity follows a U-shape: sodium reacts furiously, silicon hardly at all, chlorine furiously again. Look down a group and the direction depends on the family: the alkali metals grow more reactive from lithium to caesium, the halogens less reactive from fluorine to iodine. Patterns like these call for an explanation in terms of the electrons and energy levels of the atoms. This section builds it, starting with five measurable or estimated properties of isolated atoms and then turning to chemical behaviour.

3.7.1 Trends in Physical Properties

Plot almost any physical property against atomic number, whether the temperature at which an element melts or the energy needed to boil or atomise it, and a repeating pattern appears. Five atomic properties explain most of the chemistry, so we study those. They are the sizes of atoms and of ions, the energy needed to remove an electron, the energy change when one is added, and the pull an atom exerts on shared electrons.

(a) Atomic radius

Where does an atom end? Its electron cloud has no surface: the chance of finding an electron simply fades with distance from the nucleus (first step of Fig. 3.8). Atoms are also about 10−10 m across, far too small to hold against any scale. So chemists never measure a lone atom. They measure something that is sharp, the distance between two nuclei held together in a molecule or a crystal, which X-ray diffraction and spectroscopy give very precisely, and take half of it as the radius.

  • Covalent radius, for non-metals: half the length of a single bond between two identical atoms. The I–I bond in iodine is 267 pm long, so the covalent radius of iodine is about 133 pm.
  • Metallic radius, for metals: half the distance between neighbouring nuclei in the metal crystal. In aluminium the neighbours are 286 pm apart, giving 143 pm.
  • van der Waals radius: half the distance between atoms that touch without bonding, as in solid argon. It is much larger, so noble gas radii must not be compared with covalent radii.

2/4Half the I–I bond length.

Fig. 3.8Atomic radius is defined as half of an internuclear distance.

Step one shows a single atom as shaded rings fading outward from a nucleus, with a dashed circle and the questions edge here or here, because the cloud has no boundary. Step two shows two overlapping iodine atoms with the bond length of 267 pm between the nuclei and half of it, 133 pm, marked as the covalent radius. Step three shows a row of four touching aluminium atoms; neighbouring nuclei are 286 pm apart and half of that, 143 pm, is the metallic radius. Step four shows two argon atoms that only touch, 376 pm apart, giving a van der Waals radius of 188 pm.

Definition
Atomic radius

Half the distance between the nuclei of two identical atoms bonded together: the covalent radius for a non-metal, the metallic radius for a metal.

ExampleIodine: I–I bond 267 pm, so atomic radius about 133 pm.

The numbers show a clear pattern. Across a period the radius shrinks: from roughly 190 pm for sodium to roughly 100 pm for chlorine. Down a group it grows: an alkali metal atom goes from about 150 pm for lithium to about 265 pm for caesium. To see why, we need the idea of effective nuclear charge (प्रभावी नाभिकीय आवेश).

An outer electron is attracted by the nucleus but repelled by every other electron. Inner electrons sit between it and the nucleus and shield (or screen) part of the nuclear charge, so the outer electron feels a net charge Zeff smaller than Z. Electrons in the same shell shield one another only weakly. Across period 2, from lithium to fluorine, Z rises by one at each step but the core stays the same two 1s electrons, so the outer electrons feel an ever stronger pull and are drawn closer. Going from lithium to sodium, by contrast, a whole new shell is added and ten core electrons now shield the nucleus. The outer electron feels about the same net charge but sits in n=3, much farther out (Fig. 3.9).

3/3A new shell: similar net pull, but the electron is much farther out.

Fig. 3.9Counting only inner-shell electrons as shields gives a simple 'core charge'. Same-shell electrons shield a little too, so the real effective charge is somewhat smaller, but the trend is the same.

Step one shows a lithium atom: a +3 nucleus, a shaded core of two electrons and one outer electron on a large dashed shell, with a thin arrow labelled core charge +1. Step two adds fluorine: a +9 nucleus with the same two-electron core and seven outer electrons on a much smaller shell, with a thick arrow labelled core charge +7. Step three adds sodium: a +11 nucleus, a core of ten electrons in two shaded shells, and one outer electron on the largest shell, labelled core charge +1 but n = 3.

(b) Ionic radius

Turn a potassium atom (227 pm) into KX+ and its radius drops to 138 pm; turn a chlorine atom (99 pm) into ClX− and it grows to 181 pm (Fig. 3.10). The two changes mirror each other. The cation has lost an electron but kept all its protons, and here that one 4s electron was the entire outer shell, so what remains is a smaller, tightly held core. The anion has gained an electron but no protons, so repulsion among the electrons grows, each feels a little less of the nucleus, and the cloud swells. Ionic radii themselves come from the spacing of cations and anions in ionic crystals, and they follow the usual period and group trends.

Atoms and ions with the same number of electrons are called isoelectronic species (समइलेक्ट्रॉनी). SX2−, ClX−, KX+ and CaX2+ all have 18 electrons, like argon. With the electron count fixed, size depends on nuclear charge alone: the more protons, the tighter the cloud. So the size order is SX2−>ClX−>KX+>CaX2+: the anion with the larger negative charge is the largest, the cation with the larger positive charge the smallest.

Definition
Isoelectronic species

Atoms or ions that contain the same number of electrons. (For molecules the word is also used for species with the same number of atoms and valence electrons, such as NX2 and CO.)

ExampleBrX−, Kr, RbX+ and SrX2+ all have 36 electrons.

3/3Eighteen electrons each: size falls as nuclear charge rises.

Fig. 3.10Losing electrons shrinks an atom; gaining them swells it. In an isoelectronic series, more protons means a smaller ion.

Step one: a potassium atom of radius 227 pm loses one electron and becomes a much smaller cation of 138 pm; a dashed outline shows the atom's old size, because the whole 4s shell is gone. Step two: a chlorine atom of 99 pm gains one electron and becomes an anion of 181 pm, drawn with a dashed edge, larger than the dashed outline of the atom. Step three: four circles for sulphide (184 pm, Z = 16), chloride (181 pm, Z = 17), potassium ion (138 pm, Z = 19) and calcium ion (100 pm, Z = 20), all with 18 electrons, shrinking as an arrow labelled more protons points to the right.

Example 3.5NCERT Problem 3.5 · p. 87

Largest and smallest

Which of S, SX2−, Cl and ClX− is the largest and which is the smallest?

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
Which change makes the outer electrons of an atom feel a larger effective nuclear charge?
Show answer

Answer (D) Going across a period from left to right

Across a period Z rises by one at each step while the core stays the same, so Zeff rises and atoms shrink. Down a group, new shells add shielding and distance.

(c) Ionization enthalpy

How tightly does an atom hold its electrons? The measure is the ionization enthalpy (आयनन एन्थैल्पी), ΔiH. It is the energy needed to remove the most loosely bound electron from an isolated gaseous atom in its ground state. 'Isolated' and 'gaseous' mean no neighbours pull on the atom; 'ground state' means every atom starts from the same lowest-energy arrangement. Only then can values for different elements be compared fairly. The first ionization enthalpy is the enthalpy change of

X(g)→XX+(g)+eX−
(3.1)

and it is quoted in kJ mol−1. Removing a second electron, from the ion, gives the second ionization enthalpy:

XX+(g)→XX2+(g)+eX−
(3.2)

Pulling a negative electron away from a positive nucleus always costs energy, so every ionization enthalpy is positive. Each successive one is bigger than the last: the second electron has to escape from an ion that already carries a +1 charge, the third from a +2 ion, and so on. The rise is gradual while valence electrons are removed and then jumps enormously when the next electron has to come out of the noble-gas core (Fig. 3.11). When chemists say 'ionization enthalpy' without a qualifier, they mean the first.

2/2The fourth must come from the core: about four times more energy.

Fig. 3.11Successive ionization enthalpies of aluminium: the big jump marks the end of the valence electrons.

Bars for the first three ionization enthalpies of aluminium: 578 from 3p, 1817 from 3s and 2745 kJ per mole from 3s, grouped by a brace labelled 3 valence electrons. In the second step a fourth bar grows to 11 577 kJ per mole, labelled 2p core and about four times bigger, because that electron must come from the neon-like core.

Because a smaller atom holds its electrons closer, ionization enthalpy tracks atomic radius in reverse, and the same two trends appear (Fig. 3.12).

  • Across a period, ΔiH generally increases. New electrons enter the same shell, shield one another poorly, and feel a rising Zeff, so they are held more tightly.
  • Down a group, ΔiH decreases. The outer electron sits in a higher shell, farther out, behind more inner electrons, and together these effects beat the growing nuclear charge.

Over a longer stretch of the table the result is a saw-tooth. The noble gases, with their closed shells, sit at the peaks; the alkali metals, each with a single ns electron outside a noble-gas core, sit in the troughs, which is why they are so reactive. You can draw this pattern yourself in the activity below.

1/3From sodium to argon the value roughly triples.

Fig. 3.12Across period 3 the ionization enthalpy rises, with dips where a 3p electron or a paired electron is removed.NCERT Fig. 3.6 · p. 88

A line plot of first ionization enthalpy for sodium 496, magnesium 738, aluminium 578, silicon 787, phosphorus 1012, sulphur 1000, chlorine 1251 and argon 1521 kJ per mole. Step one shows the overall rise with two small dips. Step two circles magnesium and aluminium and shows orbital boxes: magnesium has a filled 3s pair, aluminium has the same pair plus one electron alone in 3p. Step three circles phosphorus and sulphur: phosphorus has three unpaired 3p electrons, one per box, while sulphur has a pair in one 3p box.

The dips are worth understanding. Magnesium to aluminium: within one shell, an s electron penetrates closer to the nucleus than a p electron, so a 3p electron is shielded more by the inner electrons. Aluminium's 3p electron is therefore easier to remove than magnesium's 3s electron, even though aluminium has one more proton. Phosphorus to sulphur: phosphorus has three 3p electrons in three separate orbitals (Hund's rule), while in sulphur one 3p orbital holds a pair. The repulsion within that pair makes one of them easier to remove. The same two dips appear in period 2, between beryllium and boron and between nitrogen and oxygen.

Example 3.6NCERT Problem 3.6 · p. 89

Estimating an ionization enthalpy

The first ionization enthalpies of nitrogen and fluorine are 1402 and 1681 kJ mol⁻¹. Will oxygen's value be closer to 1310 or to 1540 kJ mol⁻¹? Give a reason.

Try it yourself first. Then reveal the solution one step at a time.

Example

From kJ per mole to a single atom

The first ionization enthalpy of potassium is 419 kJ mol⁻¹. Find the energy needed to ionise one gaseous potassium atom, and the longest wavelength of light that could do it.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
The successive ionization enthalpies of an element are 590, 1145, 4912 and 6491 kJ mol⁻¹. Which group is it most likely in?
Show answer

Answer (D) Group 2

The large jump comes between the second (1145) and third (4912) values, so the atom has two valence electrons: group 2 (this is calcium).

(d) Electron gain enthalpy

Ionization enthalpy measures how hard it is to take an electron away. The opposite question, how readily an atom accepts one, is answered by the electron gain enthalpy (इलेक्ट्रॉन लब्धि एन्थैल्पी), ΔegH, the enthalpy change when an isolated gaseous atom gains an electron to become an anion:

X(g)+eX−→XX−(g)
(3.3)

Think of it as the welcome an atom gives an extra electron. A halogen atom, one electron short of a noble-gas shell, welcomes it warmly: a lot of energy is released and ΔegH is large and negative. A noble gas atom has no room left in its valence shell, so the newcomer would have to sit alone in the next shell, far out and weakly held; energy has to be put in and ΔegH is positive. Most elements fall in between, with modest negative values. Adding a second electron to an ion that is already negative always needs energy, because of the repulsion.

Size and effective nuclear charge set the broad pattern, although it is bumpier than for ionization enthalpy. Small atoms with a high Zeff, towards the right of a period, hold an added electron tightly; larger atoms lower down a group hold it less tightly. So the most negative values sit in the top right corner, in groups 16 and 17.

Yet the very top of those groups breaks the rule. Chlorine's value (−349 kJ mol⁻¹) is more negative than fluorine's (−328 kJ mol⁻¹), and sulphur's (−200 kJ mol⁻¹) more negative than oxygen's (−141 kJ mol⁻¹). Fluorine and oxygen are so small that their n=2 shell is already crowded, and an extra electron there is strongly repelled by the others. Chlorine and sulphur add the electron to the larger n=3 shell, where it has more room (Fig. 3.13).

3/3No gap: the electron would start a new shell, so energy is needed.

Fig. 3.13Room in the shell matters: chlorine releases more energy than fluorine; neon would need energy.

Step one shows a chlorine atom with seven electrons on a roomy third shell and an incoming electron filling the gap; its electron gain enthalpy, −349 kJ per mole, is labelled the most released. Step two adds fluorine, whose seven outer electrons crowd a small second shell; the incoming electron is repelled more, so less energy is released, −328 kJ per mole. Step three adds neon, whose second shell is full, so the incoming electron would have to start a new dashed outer shell; the value is positive and energy is needed.

Example 3.7NCERT Problem 3.7 · p. 90

Ranking electron gain enthalpies

Of O, S, Se and Br, which has the most negative and which the least negative electron gain enthalpy? Explain.

Try it yourself first. Then reveal the solution one step at a time.

(e) Electronegativity

In a hydrogen chloride molecule the bonding pair spends more of its time near chlorine than near hydrogen. The tendency of an atom in a molecule to draw a shared pair towards itself is its electronegativity (विद्युत्-ऋणात्मकता). Because it describes a bonded atom rather than an isolated one, no single experiment measures it; it is expressed on constructed scales instead. Linus Pauling built the first and most popular in 1932 from bond energies, placing fluorine, the strongest electron-puller, near 4 (3.98 on today's revised scale). The Mulliken–Jaffé and Allred–Rochow scales use other data but give similar orderings.

Definition
Electronegativity

How strongly an atom bonded in a molecule pulls a shared electron pair towards itself, expressed on a relative scale.

ExampleIn HCl chlorine (3.16) pulls the bonding pair away from hydrogen (2.20).

Electronegativity increases across a period (lithium 0.98, fluorine 3.98) and decreases down a group (fluorine 3.98, iodine 2.66), following ionization enthalpy, because a small atom with a high Zeff holds bonding electrons close. Treat the numbers as guides rather than constants: an element's electronegativity shifts somewhat with its oxidation state and its bonding partners. Even so, the difference in electronegativity between two atoms is a good predictor of the kind of bond they form, as the next chapter shows.

High electronegativity is the mark of a non-metal, which gains electrons readily; low electronegativity is the mark of a metal, which loses them. So a map of electronegativity doubles as a map of character: as electronegativity climbs across a period, metallic character falls, and as it drops down a group, metallic character rises. Explore all three atomic properties together in Fig. 3.14, then use Table 3.6 as a one-glance summary.

InteractiveTrend map

A grid of 32 main-group elements: groups 1, 2 and 13 to 18 across, periods 2 to 5 down. Three buttons choose the property shown: first ionization enthalpy, Pauling electronegativity or electron gain enthalpy. Each cell shows the element symbol and its value, and is shaded more darkly the more strongly the element holds or attracts electrons; cells without a meaningful value are grey. Tapping a cell shows its group, period, value and, for elements that break the trend, a short reason, such as the half-filled 2p set of nitrogen, the crowded small shell of fluorine or the poor shielding by 3d electrons in gallium. A line under the grid says what pattern to look for.

Fig. 3.14Choose a property and read the colours: darker cells hold electrons more strongly. Tap a cell for its value and the reason behind any oddity.
Table 3.6Summary of periodic trends in main-group elements
PropertyAcross a period (left → right)Down a group
Atomic and ionic radiusdecreasesincreases
Ionization enthalpyincreases (dips at groups 13 and 16)decreases
Electron gain enthalpybecomes more negativebecomes less negative (period 2 is an exception)
Electronegativityincreasesdecreases
Metallic characterdecreasesincreases
Non-metallic characterincreasesdecreases
Quick check
1 of 3
Which element has the most negative electron gain enthalpy?
Show answer

Answer (A) Chlorine

Chlorine releases the most energy. Fluorine is close but its small shell repels the new electron; neon's value is positive.

3.7.2 Periodic Trends in Chemical Properties

Some chemical trends, such as the inert pair effect and the lanthanoid contraction, make most sense group by group and come in later chapters. Two follow so directly from configuration that we take them now: how valence repeats along the periods, and why the second-period elements are the odd ones out.

(a) Periodicity of valence or oxidation states

Count an element's outer electrons and you can usually predict how many bonds it forms. For a representative element the valence is normally either that count or eight minus it. Sodium, with one outer electron, has valence 1; chlorine, with seven, shows valence 1 (eight minus seven) towards hydrogen and up to 7 towards oxygen. Across period 3 the valence towards hydrogen rises from 1 to 4 and falls back to 1, while the highest valence towards oxygen climbs all the way to 7 (Table 3.7).

Table 3.7Valence across period 3, seen in hydrides and highest oxides
Group121314151617
Valence electrons1234567
HydrideNaHMgHX2AlHX3SiHX4PHX3HX2SHCl
Valence in hydride1234321
Highest oxideNaX2OMgOAlX2OX3SiOX2PX4OX10SOX3ClX2OX7
Valence in oxide1234567

Today chemists usually speak of oxidation state (ऑक्सीकरण अवस्था) rather than valence. To find it, give each shared pair to the more electronegative atom and count the charge left on each atom. In HCl chlorine is more electronegative than hydrogen, so chlorine is −1 and hydrogen +1. In ClX2O oxygen is more electronegative than chlorine, so oxygen is −2 and each chlorine is +1. The same element can therefore show different oxidation states, depending on its partner.

Example 3.8NCERT Problem 3.8 · p. 92

Predicting formulas

Predict the formulas of the compounds formed by (a) germanium and chlorine, (b) calcium and nitrogen.

Try it yourself first. Then reveal the solution one step at a time.

Valence is not always a single number. Phosphorus forms both PClX3 and PClX5, and among the transition metals and actinoids several oxidation states for one element are the rule rather than the exception.

(b) Anomalous properties of second period elements

Lithium is an alkali metal, yet in several ways it behaves more like magnesium than like sodium; beryllium, likewise, resembles aluminium more than magnesium. Both form compounds with marked covalent character, whereas the heavier members of groups 1 and 2 form mostly ionic ones. In the same way, each second-period element from lithium to fluorine stands apart from the rest of its group. The resemblance of an element to its lower-right neighbour is called the diagonal relationship (विकर्ण संबंध); see Fig. 3.15.

2/3Li–Mg, Be–Al and B–Si behave alike.

Fig. 3.15Moving one step right and one step down roughly cancels out, so diagonal neighbours have similar size and charge density.NCERT p. 93

Two rows of four cells: Li, Be, B, C on top (shaded as period 2) and Na, Mg, Al, Si below. Step one shows two trend arrows: down a group atoms get larger, across a period they get smaller and more electronegative. Step two draws three diagonal arrows from Li to Mg, Be to Al and B to Si. Step three replaces the across arrow with two circles for the lithium ion (76 pm) and the magnesium ion (72 pm), almost the same size, explaining why diagonal neighbours behave alike.

Why are the second-period elements so different? Their atoms are unusually small, so their ions carry a lot of charge for their size and they attract electrons strongly. On top of this, a second-period atom has only four valence orbitals, 2s and three 2p, so it cannot form more than four covalent bonds. From period 3 onward the valence shell also offers d orbitals (3s, 3p and 3d make nine), so the heavier members can take on more than four electron pairs. Nitrogen stops at NClX3 while phosphorus goes on to PClX5, and oxygen stops at OFX2 while sulphur forms SFX6.

Small second-period atoms can also come close enough for their p orbitals to overlap sideways, forming strong pπ–pπ multiple bonds. Nitrogen is the triple-bonded NX2 and oxygen the double-bonded OX2, while phosphorus prefers PX4 molecules and sulphur SX8 rings, both held together by single bonds. Carbon dioxide is a small molecule with two C=O double bonds; silicon dioxide is a giant network of Si–O single bonds.

Example 3.9NCERT Problem 3.9 · p. 94

Oxidation state versus covalency

In the ion [SiFX6]X2−, are the oxidation state and the covalency of silicon the same?

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
What is the formula of the compound formed by aluminium and oxygen?
Show answer

Answer (C) AlX2OX3

Aluminium (group 13) has valence 3 and oxygen valence 2; the lowest common multiple 6 gives AlX2OX3. AlX3OX2 swaps the subscripts the wrong way.

3.7.3 Periodic Trends and Chemical Reactivity

Put the trends together and reactivity follows. Going left to right along a period, atoms shrink, ionization enthalpy climbs and electron gain enthalpy grows more negative. The far-left element therefore parts with an electron more easily than any other, and the far-right element (leaving out the noble gas) takes one on most eagerly. Both ends are highly reactive, in opposite ways: one forms cations and behaves as a metal (and, as later chapters show, as a reducing agent); the other forms anions and behaves as a non-metal (an oxidising agent). In the middle of the period neither process is easy, so reactivity is lowest there.

Oxides make this visible. Sodium's oxide, NaX2O, dissolves in water to give a strong alkali, so it is basic; the highest oxide of chlorine, ClX2OX7, gives a strong acid, so it is acidic. Between them the character shifts step by step (Fig. 3.16). Aluminium oxide is amphoteric (उभयधर्मी), dissolving in acids and in alkalis alike, and a few oxides of non-metals, such as carbon monoxide and dinitrogen oxide, are neutral and react with neither.

4/4Aluminium oxide reacts with acids and with bases.

Fig. 3.16Across period 3 the highest oxides change from basic through amphoteric to acidic.

Seven boxes in a row hold the highest oxides of period 3: sodium oxide, magnesium oxide, aluminium oxide, silicon dioxide, tetraphosphorus decoxide, sulphur trioxide and dichlorine heptoxide. Step one asks whether each is an acid or a base. Step two shades the first two boxes and brackets them as basic oxides that neutralise acids. Step three shades the last four with a dashed outline and brackets them as acidic oxides that neutralise bases. Step four hatches aluminium oxide in the middle and labels it amphoteric, reacting with both.

Example 3.10NCERT Problem 3.10 · p. 94

Basic, acidic and amphoteric oxides

Use equations to show that magnesium oxide is basic, sulphur trioxide is acidic and aluminium oxide is amphoteric.

Try it yourself first. Then reveal the solution one step at a time.

Transition metals change more gently. Their added electrons go into an inner d subshell, so atomic radii shrink only slightly across the 3d series, and across the 4f series the change is smaller still. Their ionization enthalpies lie above those of the s-block metals and below those of most p-block elements, so they are less electropositive than the metals of groups 1 and 2. Iron rusts slowly, while a freshly cut piece of sodium tarnishes within seconds.

Down a main group, bigger atoms lose electrons more readily and attract extra ones less strongly (apart from the period-2 exceptions in part (d)). Metallic character therefore grows down a group, which makes caesium the most reactive alkali metal, while non-metallic character fades, which makes fluorine the most reactive halogen. Transition metals buck this trend: gold is far less reactive than copper two places above it. Its atoms are only a little larger than copper's (144 against 128 pm) while its nuclear charge is far higher (+79 against +29). So gold holds its electrons more tightly: its first ionization enthalpy is 890 kJ mol⁻¹ against copper's 745 kJ mol⁻¹. Reactivity also decides how elements occur in nature. Sodium, potassium and fluorine are always found combined in compounds, while unreactive gold and platinum can be dug up as the free metals.

Quick check
1 of 2
An oxide dissolves in both dilute hydrochloric acid and sodium hydroxide solution. It is most likely
Show answer

Answer (B) AlX2OX3

Reacting with both an acid and a base is the mark of an amphoteric oxide such as AlX2OX3. CO is neutral and reacts with neither.
Recap

Classification of Elements and Periodicity in Properties: key points and summary

  1. Classification organises known facts and predicts new ones; it grew from Döbereiner's triads, de Chancourtois' spiral and Newlands' octaves to Mendeleev's periodic law of 1869 (Section 3.2).
  2. Mendeleev ordered elements by atomic weight but let chemical likeness override it, and left gaps whose elements (gallium, germanium) were later found as predicted (Section 3.2).
  3. Moseley's X-ray work showed that atomic number is the true basis of order: properties are periodic functions of atomic number (Section 3.3).
  4. The long form has 7 periods of 2, 8, 8, 18, 18, 32 and 32 elements and 18 groups; lanthanoids and actinoids are printed below (Section 3.3).
  5. Elements above Z = 100 get temporary systematic names from digit roots plus -ium, with three-letter symbols, until IUPAC approves a permanent name (Section 3.4).
  6. The period number is the valence shell's n; a period's length is twice the number of orbitals filled in it; a group shares one outer configuration (Section 3.5).
  7. The last subshell filled sets the block: s (groups 1–2), p (13–18), d (3–12) and f (two rows); helium and hydrogen are special cases (Section 3.6).
  8. Metals (over three quarters of the elements) lie to the left, non-metals to the upper right, and metalloids along the diagonal between them (Section 3.6.5).
  9. Atomic radius falls across a period and rises down a group; cations are smaller and anions larger than their atoms; in an isoelectronic series more protons means a smaller species ((a) Atomic radius, (b) Ionic radius).
  10. Ionization enthalpy rises across a period and falls down a group, controlled by effective nuclear charge, shielding and distance, with dips after groups 2 and 15 ((c) Ionization enthalpy).
  11. Electron gain enthalpy is more negative towards the right of a period and less negative lower in a group, but Cl and S beat F and O; noble gases have positive values ((d) Electron gain enthalpy).
  12. Electronegativity is a relative scale for bonded atoms (fluorine highest); it rises with non-metallic character ((e) Electronegativity).
  13. Valence is the outer electron count or eight minus it; oxidation state depends on electronegativity; second-period elements are anomalous and show diagonal relationships (Section 3.7.2).
  14. Reactivity is highest at the ends of a period; oxides change from basic through amphoteric to acidic across a period (Section 3.7.3).
Practice · 46 questions

Practice questions with answers (NCERT “Exercises”)

One question for each NCERT exercise, practising the same skill with new elements and numbers, followed by extra objective questions in board and entrance-exam style.

  1. Short answerEasyNCERT Exercises 3.1

    A classmate says the periodic table is 'just the elements listed by atomic number'. What else does its layout organise, and why does that make it useful?

    Show solution

    It combines two ideas. Along each row the elements follow increasing atomic number. At the same time, elements with the same outer electronic configuration are stacked in the same column, so each group is a family with similar properties. Because of this, an element's position tells you its likely valence, its reactivity and the formulas of its compounds, and the steady trends along rows and down columns let you compare elements you have never studied.

  2. Short answerEasyNCERT Exercises 3.2

    Which property did Mendeleev use to order the elements, and did he always follow it? Describe two ways in which he departed from it.

    Show solution

    He ordered elements by increasing atomic weight, but treated chemical similarity (especially the formulas of oxides and hydrides) as more important. (1) He reversed weight order where properties demanded it, putting tellurium (127.6) before iodine (126.9) so that iodine joined the halogens. (2) He left gaps for undiscovered elements rather than force a known element into the wrong column, and predicted the properties of eka-aluminium and eka-silicon (gallium and germanium).

  3. Short answerMediumNCERT Exercises 3.3

    State the periodic law as Mendeleev gave it and in its modern form. Cobalt (58.93) is heavier than nickel (58.69). Which law places them correctly, and why?

    Show solution

    Mendeleev: properties of elements are periodic functions of their atomic weights. Modern: properties are periodic functions of their atomic numbers. By weight, nickel would come before cobalt, which puts each in the wrong family. By atomic number cobalt (Z=27) comes before nickel (Z=28), the order their chemistry requires. The modern law places them correctly because atomic number fixes the number of electrons, and so the configuration that decides chemistry.

  4. Short answerMediumNCERT Exercises 3.4

    Use quantum numbers and orbital energies to answer:

    1. Show that period 7 can hold at most 32 elements.

      Show solution

      Period 7 fills 7s, 5f, 6d and 7p in turn. These contain 1+7+5+3=16 orbitals, which hold 16×2=32 electrons. Each element adds one electron, so the period has 32 elements (francium, Z=87, to oganesson, Z=118).

    2. The n=3 shell has nine orbitals, yet period 3 has only eight elements. Explain.

      Show solution

      The 3d orbitals are higher in energy than 4s, so they are filled only after 4s, in period 4. Period 3 uses only 3s and 3p, four orbitals, which hold 8 electrons.

  5. Quick answerMediumNCERT Exercises 3.5

    Where would you place the element with Z=116?

    Show answer

    Answer (A) Period 7, group 16, p-block

    116 is two places before oganesson (118, group 18), so it is in group 16 of period 7, with configuration [Rn]5f146d107s27p4. It is livermorium.
  6. Quick answerEasyNCERT Exercises 3.6

    What is the atomic number of the element in period 4, group 15?

    Show answer

    Answer 33

    Group 15 is the fifteenth element of period 4: 19+14=33. This is arsenic, [Ar]3d104s24p3.
  7. Quick answerEasyNCERT Exercises 3.7

    Match each person or place with the symbol of the element named after it.

    Tap an item on the left, then its match on the right.

    Show answer
    Answer
    • Dubna, a Russian research town : Db
    • Japan : Nh
    • Yuri Oganessian : Og
    • Glenn Seaborg : Sg
    Dubnium (105), nihonium (113), oganesson (118) and seaborgium (106).
  8. Short answerEasyNCERT Exercises 3.8

    Lithium, sodium and potassium all react with water to give hydrogen and a hydroxide of formula MOH. Explain this family likeness using electronic configurations.

    Show solution

    Their configurations are [He]2s1, [Ne]3s1 and [Ar]4s1: each has one electron outside a noble-gas core. Chemistry is decided mainly by the outer electrons, so all three lose that single electron easily to form MX+ ions, show valence 1 and react in the same way. Elements of one group share the same outer configuration, so they share their chemistry.

  9. Short answerMediumNCERT Exercises 3.9

    What do the terms atomic radius and ionic radius actually measure? Why can neither be found from one isolated atom?

    Show solution

    Both are half-distances between nuclei of particles that are in contact. Atomic radius is half the internuclear distance between two identical bonded atoms: the covalent radius in a molecule, or the metallic radius in a metal crystal. Ionic radius is the share of the cation–anion distance in an ionic crystal assigned to one ion. A single atom has an electron cloud that fades out with no sharp edge, so it has no definite boundary to measure; only distances between nuclei can be measured precisely.

  10. Short answerMediumNCERT Exercises 3.10

    Predict, with reasons, the larger atom in each pair.

    1. Magnesium or sulphur

      Show solution

      Magnesium. Both are in period 3, so their outer electrons are in the same shell, but sulphur has four more protons with little extra shielding. Its higher effective nuclear charge pulls the electron cloud in, so radius decreases across a period.

    2. Sodium or rubidium

      Show solution

      Rubidium. Both are in group 1, but rubidium's outer electron is in n=5 instead of n=3, with two more filled shells shielding it. Radius increases down a group because each step adds a shell.

  11. Short answerEasyNCERT Exercises 3.11

    Isoelectronic species have the same number of electrons. Name one species isoelectronic with each of the following.

    1. NaX+

      Show solution

      10 electrons: Ne, FX−, OX2−, MgX2+ or AlX3+.

    2. Kr

      Show solution

      36 electrons: BrX−, SeX2−, RbX+ or SrX2+.

    3. SX2−

      Show solution

      18 electrons: Ar, ClX−, KX+ or CaX2+.

    4. IX−

      Show solution

      54 electrons: Xe, TeX2−, CsX+ or BaX2+.

  12. Short answerMediumNCERT Exercises 3.12

    Consider the species PX3−, SX2−, ClX−, KX+, CaX2+ and ScX3+.

    1. What do they have in common?

      Show solution

      Each has 18 electrons, the configuration of argon, 1s22s22p63s23p6: they are isoelectronic.

    2. Arrange them in order of increasing ionic radius.

      1. CaX2+
      2. KX+
      3. PX3−
      4. ScX3+
      5. SX2−
      6. ClX−
      Show answer
      Answer
      1. ScX3+
      2. CaX2+
      3. KX+
      4. ClX−
      5. SX2−
      6. PX3−
      With 18 electrons each, the radius depends on nuclear charge: Sc (21 protons) pulls hardest and is smallest; P (15 protons) is largest.
  13. Short answerMediumNCERT Exercises 3.13

    A magnesium atom (radius about 160 pm) shrinks to less than half that size as MgX2+, while an oxygen atom roughly doubles in size as OX2−. Explain both changes.

    Show solution

    Magnesium loses both 3s electrons, so the whole third shell disappears and the remaining ten electrons, in n=2, are pulled in by twelve protons: the ion is far smaller. Oxygen gains two electrons into its outer shell; the nuclear charge is still +8, but there are now ten electrons repelling one another, so each feels a smaller effective nuclear charge and the cloud expands.

  14. Short answerMediumNCERT Exercises 3.14

    Ionization enthalpy and electron gain enthalpy are defined for an isolated gaseous atom in its ground state. What does each condition achieve?

    Show solution

    'Isolated' and 'gaseous' mean the atom is free of neighbours: in a solid or liquid, bonds and attractions to other atoms would change the energy needed, and by different amounts for different substances. 'Ground state' means every atom starts from its lowest-energy configuration; an excited atom would lose an electron more easily. Together the conditions make the value a property of the atom alone, so values for different elements can be compared fairly.

  15. NumericalMediumNCERT Exercises 3.15

    In a hydrogen atom whose electron is in the n=2 level, the electron's energy is −5.45×10−19 J. How much energy, in kJ mol−1, is needed to ionise one mole of such atoms?

    kJ mol⁻¹
    Show solution
    Eatom=0−(−5.45×10−19)=5.45×10−19 J
    E=5.45×10−19×6.022×1023 J mol−1
    E=3.28×105 J mol−1=328 kJ mol−1

    This is a quarter of hydrogen's ground-state value, because the energy of level n varies as 1/n2.

  16. Short answerMediumNCERT Exercises 3.16

    For the s- and p-block elements of period 4, the first ionization enthalpies increase in the order K < Ga < Ca < Ge < Se < As < Br < Kr. Explain:

    1. why Ga has a lower value than Ca;

      Show solution

      Calcium loses a 4s electron; gallium loses a 4p electron. Within a shell a p electron penetrates less towards the nucleus and is more shielded than an s electron, so it is easier to remove despite gallium's larger nuclear charge.

    2. why Se has a lower value than As.

      Show solution

      Arsenic (4p3) has one electron in each 4p orbital. In selenium (4p4) one orbital holds a pair, and the repulsion between the paired electrons makes one of them easier to remove.

  17. Short answerMediumNCERT Exercises 3.17

    The first ionization enthalpy of potassium (419 kJ mol⁻¹) is lower than that of calcium (590 kJ mol⁻¹), but its second (3052 kJ mol⁻¹) is far higher than calcium's (1145 kJ mol⁻¹). Explain.

    Show solution

    First ionization: both lose a 4s electron, but calcium has one more proton in the same shell, so it holds its 4s electron more tightly. Second ionization: KX+ is [Ar], so its next electron must come from the compact 3p core, close to the nucleus and poorly shielded, which costs a great deal. CaX+ is [Ar]4s1 and still has an outer 4s electron to lose, so its second value is much lower.

  18. Quick answerMediumNCERT Exercises 3.18

    Which factors make the ionization enthalpy of main group elements decrease down a group? Select all that apply.

    Select all that apply
    Show answer
    Answer
    • (A) The outer electron is in a shell with a higher n, farther from the nucleus
    • (B) More inner electrons shield the outer electron
    Distance and shielding both grow and outweigh the rising nuclear charge. The nuclear charge actually increases, and neutrons carry no charge.
  19. Long answerHardNCERT Exercises 3.19

    The first ionization enthalpies (kJ mol⁻¹) of group 14 are C 1086, Si 787, Ge 762, Sn 709 and Pb 716. Explain why germanium is only a little below silicon, and why lead is above tin.

    Show solution

    The large drop from carbon to silicon is the normal effect of a new shell. Between silicon and germanium, however, the ten 3d electrons are added. d electrons shield the nucleus poorly, so germanium's outer electrons feel a larger effective nuclear charge than expected and its value falls only slightly. Between tin and lead both the fourteen 4f electrons and the ten 5d electrons are added, and f electrons shield even more poorly. The effective nuclear charge on lead's 6p electrons rises enough that lead's value ends up slightly higher than tin's.

  20. Short answerEasyNCERT Exercises 3.20

    In each pair, which element has the more negative electron gain enthalpy?

    1. S or Cl

      Show answer

      Answer (B) Cl

      Across period 3 the value becomes more negative; one electron completes chlorine's octet.
    2. O or S

      Show answer

      Answer (B) S

      Oxygen's small, crowded 2p shell repels the added electron, so sulphur's value is more negative.
    3. Br or I

      Show answer

      Answer (A) Br

      Below period 3 the normal trend holds: the larger iodine atom holds the added electron less strongly.
  21. Quick answerMediumNCERT Exercises 3.21

    The first electron gain enthalpy of sulphur is −200 kJ mol−1. What do you expect for its second electron gain enthalpy, SX−(g)+eX−→SX2−(g)?

    Show answer

    Answer (C) Positive

    The incoming electron is repelled by the negative charge of SX−, so energy must be supplied: the second electron gain enthalpy is positive. SX2− exists in solids such as NaX2S only because the strong attraction of the crystal lattice pays this cost.
  22. Short answerMediumNCERT Exercises 3.22

    Fluorine is the most electronegative element, yet chlorine has the more negative electron gain enthalpy. State the basic difference between the two quantities and explain why there is no contradiction.

    Show solution

    Electron gain enthalpy is a measured energy change for a free gaseous atom accepting a whole extra electron. Electronegativity is a relative, unmeasured number describing how strongly an atom in a molecule pulls a shared pair. In free fluorine the added electron must crowd into the small 2p shell, so the energy released is a little less than for chlorine. In a bond, fluorine's small size lets it get very close to the shared pair, so its pull on that pair is the strongest of all. The two quantities describe different situations, so they need not rank the elements the same way.

  23. Short answerMediumNCERT Exercises 3.23

    A student writes: 'The electronegativity of sulphur is 2.58 in every sulphur compound.' How would you respond?

    Show solution

    The statement is not right. Electronegativity is not a measured constant of a free atom; it describes an atom in a particular bonding situation, and it changes with the atom's oxidation state and its partners. Sulphur at −2 in HX2S and sulphur at +6 in SFX6 do not attract electrons equally: the more positive the oxidation state, the stronger the pull. 2.58 is a typical Pauling value, useful for comparisons, not an exact value for every compound.

  24. Short answerMediumNCERT Exercises 3.24

    Describe and explain how the radius changes in each series.

    1. Fe→FeX2+→FeX3+

      Show solution

      The radius decreases at each step: Fe > FeX2+ > FeX3+. The nuclear charge stays +26 while electrons are removed, so the remaining electrons repel each other less and each feels a larger effective nuclear charge; removing the two 4s electrons also empties the outermost shell.

    2. O→OX−→OX2−

      Show solution

      The radius increases at each step: O < OX− < OX2−. The nuclear charge stays +8 while electrons are added, so electron–electron repulsion grows, the effective nuclear charge per electron falls and the cloud spreads out.

  25. Short answerMediumNCERT Exercises 3.25

    Would ordinary hydrogen (1H) and deuterium (2H) have the same first ionization enthalpy? Justify.

    Show solution

    Practically yes. Ionization enthalpy depends on the nuclear charge and the electronic configuration, and isotopes have the same number of protons and electrons, 1s1 in both cases. The extra neutron adds mass but no charge. (Very precise measurements show a difference of only a few hundredths of a per cent, caused by the different nuclear mass; it is negligible in chemistry.)

  26. Short answerEasyNCERT Exercises 3.26

    Give four major differences between metals and non-metals, with one exception to each general rule.

    Show solution
    1. State: metals are mostly solids; non-metals are solids or gases. Exceptions: mercury is a liquid metal, bromine a liquid non-metal.
    2. Conduction: metals conduct heat and electricity well; non-metals poorly. Exception: graphite, a form of carbon, conducts.
    3. Mechanical: metals are malleable and ductile; solid non-metals are brittle. Exception: bismuth is a brittle metal.
    4. Chemistry: metals lose electrons to form cations and basic oxides; non-metals gain or share electrons and form acidic oxides. Exception: aluminium's oxide is amphoteric.
  27. Short answerEasyNCERT Exercises 3.27

    Use the periodic table to identify:

    1. an element with three electrons in its outermost p subshell;

      Show solution

      Any group 15 element (ns2np3), such as nitrogen, phosphorus or arsenic.

    2. an element that would tend to lose one electron;

      Show solution

      An alkali metal (ns1), such as sodium or potassium: losing one electron gives a noble-gas core.

    3. an element that would tend to gain one electron;

      Show solution

      A halogen (ns2np5), such as chlorine or bromine: one more electron completes the octet.

    4. a group that contains a non-metal, a metalloid and a metal.

      Show solution

      Group 14 (carbon non-metal; silicon and germanium metalloids; tin and lead metals) or group 15 (nitrogen and phosphorus; arsenic and antimony; bismuth).

  28. Short answerMediumNCERT Exercises 3.28

    Reactivity increases down group 2 (Be < Mg < Ca < Sr < Ba) but decreases down group 16 (O > S > Se). Explain the opposite directions.

    Show solution

    Group 2 metals react by losing their two s electrons. Down the group atoms get larger and ionization enthalpies fall, so the electrons are lost more easily and reactivity rises. Group 16 non-metals react by gaining or attracting electrons. Down the group atoms get larger, electronegativity falls and an incoming electron is held less strongly, so reactivity falls. (Oxygen's electron gain enthalpy is less negative than sulphur's, but its much higher electronegativity and its strong bonds make it the most reactive member.)

  29. Short answerEasyNCERT Exercises 3.29

    Name the block that has each general outer electronic configuration.

    1. ns2np1−6

      Show answer

      Answer (B) p-block

      The last electron enters an np subshell: groups 13 to 18.
    2. (n−2)f1−14(n−1)d0−1ns2

      Show answer

      Answer (D) f-block

      The last electron enters a subshell two shells in, (n−2)f: the lanthanoids and actinoids.
    3. ns1−2

      Show answer

      Answer (A) s-block

      Only the outer s subshell is filling: groups 1 and 2 (helium, 1s2, is placed in group 18).
    4. (n−1)d1−10ns0−2

      Show answer

      Answer (C) d-block

      The last electron enters the inner (n−1)d subshell: groups 3 to 12.
  30. Short answerMediumNCERT Exercises 3.30

    Give the period, group (where one applies) and block of the element with each outer configuration.

    1. ns2np2 with n=4

      Show solution

      4s24p2: period 4, p-block, group 10+4=14 (germanium).

    2. (n−1)d5ns2 with n=4

      Show solution

      3d54s2: period 4, d-block, group 5+2=7 (manganese).

    3. (n−2)f3(n−1)d0ns2 with n=6

      Show solution

      4f36s2: period 6, f-block, the third lanthanoid, Z=54+2+3=59 (praseodymium). Lanthanoids are printed in the separate row and are not given their own group number.

  31. Short answerHardNCERT Exercises 3.31

    The table gives the first and second ionization enthalpies and the electron gain enthalpy (all in kJ mol⁻¹) of six elements, labelled A to F. Which element is likely to be:

    Table 3.8Data for elements A to F
    ElementFirst ΔiHSecond ΔiHΔegH
    A12512298−349
    B5901145−2
    C15212666positive
    D3762234−46
    E10002252−200
    F4964562−53
    1. the least reactive element?

      Show answer

      Answer (C) C

      C has a very high first ionization enthalpy and a positive electron gain enthalpy: it neither loses nor gains electrons readily, like a noble gas (argon).
    2. the most reactive metal?

      Show answer

      Answer (D) D

      D has the lowest first ionization enthalpy (376), so it loses its outer electron most easily (caesium).
    3. the most reactive non-metal?

      Show answer

      Answer (A) A

      A has a high ionization enthalpy and the most negative electron gain enthalpy (−349), so it gains an electron most readily (chlorine).
    4. the metal that forms a stable binary halide MXX2?

      Show answer

      Answer (B) B

      B has a low first and a moderate second ionization enthalpy, so losing two electrons is easy: it forms MX2+ (calcium). F also has a low first value, but its huge second value (4562) means it forms only MX+.
  32. Short answerEasyNCERT Exercises 3.32

    Write the formula of the stable compound formed between each pair of elements:

    1. sodium and sulphur

      Show solution

      Na has valence 1, S valence 2: NaX2S.

    2. calcium and phosphorus

      Show solution

      Ca has valence 2, P valence 3: CaX3PX2.

    3. boron and fluorine

      Show solution

      B has valence 3, F valence 1: BFX3.

    4. the element with Z=31 and oxygen

      Show solution

      Z=31 is gallium, [Ar]3d104s24p1, group 13, valence 3; oxygen has valence 2: GaX2OX3.

  33. Quick answerEasyNCERT Exercises 3.33

    In the long form of the periodic table, the number of elements in a period equals

    Show answer

    Answer (C) twice the number of orbitals filled during that period

    Period 4 fills 9 orbitals (4s, 3d, 4p) and has 18 elements. 2n2 would give 32 for period 4, which is wrong.
  34. Quick answerMediumNCERT Exercises 3.34

    Which statement about the blocks of the periodic table is incorrect?

    Show answer

    Answer (C) The p-block has eight columns because a p subshell holds eight electrons.

    A p subshell has three orbitals and holds six electrons, so the p-block is six columns wide (groups 13 to 18). The other statements are correct.
  35. Quick answerMediumNCERT Exercises 3.35

    Which of these does not affect how strongly an atom holds its valence electrons?

    Show answer

    Answer (C) The number of neutrons in the nucleus

    Neutrons add mass but no charge, so they leave the valence electrons essentially unchanged. Distance (n), nuclear charge and shielding by core electrons all matter.
  36. Quick answerMediumNCERT Exercises 3.36

    The ions SX2−, ClX−, KX+ and CaX2+ have different sizes mainly because of differences in their

    Show answer

    Answer (A) nuclear charge

    All four have 18 electrons in the same shells (n=3 outermost); only the number of protons differs, from 16 to 20, so the cloud is pulled in more as Z rises.
  37. Quick answerMediumNCERT Exercises 3.37

    The successive ionization enthalpies of an element X are 786, 1577, 3232, 4356 and 16 091 kJ mol⁻¹. In which group is X?

    Show answer

    Answer (C) Group 14

    The values rise steadily for four electrons and then jump almost fourfold, so the fifth electron comes from the core. X has four valence electrons: group 14 (it is silicon).
  38. Quick answerEasyNCERT Exercises 3.38

    For the elements Ge, Ga, Ca and K, the correct order of metallic character is

    Show answer

    Answer (C) K > Ca > Ga > Ge

    Across period 4 metallic character falls from left to right: K (group 1) > Ca (2) > Ga (13) > Ge (14).
  39. Quick answerMediumNCERT Exercises 3.39

    For the elements Si, P, Cl, F and Al, the correct order of non-metallic character is

    Show answer

    Answer (B) F > Cl > P > Si > Al

    Non-metallic character rises across period 3 (Al < Si < P < Cl) and is greater at the top of a group, so F > Cl.
  40. Quick answerMediumNCERT Exercises 3.40

    For F, Cl, Br and S, the correct order of oxidising power is

    Show answer

    Answer (D) F > Cl > Br > S

    Oxidising power falls down group 17 (F > Cl > Br), and sulphur, to the left in period 3, attracts electrons less strongly than any of the halogens here.
  41. Quick answerMedium

    The first ionization enthalpy of sodium is 496 kJ mol⁻¹. What is the longest wavelength of light, in nanometres, that can ionise a gaseous sodium atom? (Use h=6.626×10−34 J s, c=3.00×108 m s−1, NA=6.022×1023 mol−1.)

    nm
    Show answer

    Answer 241 nm

    E=4.96×105/6.022×1023=8.24×10−19 J; λ=hc/E=2.41×10−7 m=241 nm.
  42. Quick answerMedium

    Assertion (A): The first ionization enthalpy of nitrogen is higher than that of oxygen. Reason (R): Nitrogen's three 2p electrons occupy separate orbitals, while in oxygen two 2p electrons share one orbital and repel each other.

    Show answer

    Answer (A) Both A and R are true, and R is the correct explanation of A

    Nitrogen (1402) is above oxygen (1314), and the paired-electron repulsion in oxygen is exactly why.
  43. Quick answerMedium

    Assertion (A): Fluorine has a less negative electron gain enthalpy than chlorine. Reason (R): Fluorine is less electronegative than chlorine.

    Show answer

    Answer (C) A is true but R is false

    A is true (−328 against −349 kJ mol⁻¹), because of repulsion in fluorine's small 2p shell. R is false: fluorine is the most electronegative element.
  44. Quick answerMedium

    Assertion (A): Atomic radius decreases from sodium to chlorine. Reason (R): Chlorine is a non-metal.

    Show answer

    Answer (B) Both A and R are true, but R is not the correct explanation of A

    Both statements are true, but the radius falls because the effective nuclear charge rises across the period, not because chlorine is a non-metal.
  45. Quick answerEasy

    The IUPAC systematic name of element 142 would be .

    Show answer

    Answer unquadbium

    un + quad + bi + ium, with the i of bi dropped before -ium: unquadbium, symbol Uqb.
  46. Quick answerEasy

    Which of these are isoelectronic with neon? Select all that apply.

    Select all that apply
    Show answer
    Answer
    • (A) NaX+
    • (C) MgX2+
    • (E) OX2−
    NaX+ (11 − 1), MgX2+ (12 − 2) and OX2− (8 + 2) have 10 electrons. ClX− and KX+ have 18, like argon.

Find your NCERT exercise question

Our practice questions are written for ncert.ai and follow the NCERT exercises. Find the one that matches the question in your textbook; its answer is with it.

In your NCERT textbookPractice question here
NCERT Exercises 3.1Practice Q1
NCERT Exercises 3.2Practice Q2
NCERT Exercises 3.3Practice Q3
NCERT Exercises 3.4Practice Q4
NCERT Exercises 3.5Practice Q5
NCERT Exercises 3.6Practice Q6
NCERT Exercises 3.7Practice Q7
NCERT Exercises 3.8Practice Q8
NCERT Exercises 3.9Practice Q9
NCERT Exercises 3.10Practice Q10
NCERT Exercises 3.11Practice Q11
NCERT Exercises 3.12Practice Q12
NCERT Exercises 3.13Practice Q13
NCERT Exercises 3.14Practice Q14
NCERT Exercises 3.15Practice Q15
NCERT Exercises 3.16Practice Q16
NCERT Exercises 3.17Practice Q17
NCERT Exercises 3.18Practice Q18
NCERT Exercises 3.19Practice Q19
NCERT Exercises 3.20Practice Q20
NCERT Exercises 3.21Practice Q21
NCERT Exercises 3.22Practice Q22
NCERT Exercises 3.23Practice Q23
NCERT Exercises 3.24Practice Q24
NCERT Exercises 3.25Practice Q25
NCERT Exercises 3.26Practice Q26
NCERT Exercises 3.27Practice Q27
NCERT Exercises 3.28Practice Q28
NCERT Exercises 3.29Practice Q29
NCERT Exercises 3.30Practice Q30
NCERT Exercises 3.31Practice Q31
NCERT Exercises 3.32Practice Q32
NCERT Exercises 3.33Practice Q33
NCERT Exercises 3.34Practice Q34
NCERT Exercises 3.35Practice Q35
NCERT Exercises 3.36Practice Q36
NCERT Exercises 3.37Practice Q37
NCERT Exercises 3.38Practice Q38
NCERT Exercises 3.39Practice Q39
NCERT Exercises 3.40Practice Q40

Quick check: MCQs on Classification of Elements and Periodicity in Properties

  1. 3.2 Genesis of Periodic Classification3 questions
  2. 3.3 Modern Periodic Law and the Present Form of the Periodic Table3 questions
  3. 3.4 Nomenclature of Elements with Atomic Numbers > 1002 questions
  4. (b) Groupwise electronic configurations3 questions
  5. 3.6.4 The f-Block Elements (Inner-Transition Elements)3 questions
  6. 3.6.5 Metals, Non-metals and Metalloids2 questions
  7. (b) Ionic radius3 questions
  8. (c) Ionization enthalpy3 questions
  9. (e) Electronegativity3 questions
  10. (b) Anomalous properties of second period elements3 questions
  11. 3.7.3 Periodic Trends and Chemical Reactivity2 questions
Glossary · 15

Key terms (English–Hindi)

amphoteric oxideउभयधर्मी ऑक्साइडubhaydharmi oxide
An oxide that reacts with both acids and bases, such as AlX2OX3.First seen in the chapter →
atomic radiusपरमाणु त्रिज्याparamanu trijya
Half the distance between the nuclei of two bonded identical atoms: the covalent radius for non-metals, the metallic radius for metals.
diagonal relationshipविकर्ण संबंधvikarn sambandh
The resemblance between a second-period element and the element one place down and to the right, such as Li and Mg.First seen in the chapter →
effective nuclear chargeप्रभावी नाभिकीय आवेशprabhavi nabhikiya aavesh
The net positive charge an outer electron feels after inner electrons screen part of the nuclear charge.First seen in the chapter →
electron gain enthalpyइलेक्ट्रॉन लब्धि एन्थैल्पीelectron labdhi enthalpy
The enthalpy change when an isolated gaseous atom gains an electron; negative when energy is released.First seen in the chapter →
electronegativityविद्युत्-ऋणात्मकताvidyut-rinatmakta
The relative ability of an atom in a molecule to pull a shared electron pair towards itself.First seen in the chapter →
groupवर्गvarg
A vertical column (1 to 18) of elements with similar outer electronic configurations and similar chemistry.First seen in the chapter →
ionization enthalpyआयनन एन्थैल्पीaayanan enthalpy
The energy needed to remove the most loosely held electron from an isolated gaseous atom (or ion) in its ground state, in kJ mol−1.First seen in the chapter →
isoelectronic speciesसमइलेक्ट्रॉनी स्पीशीज़sam-electroni species
Atoms or ions that have the same number of electrons, such as ClX−, Ar and KX+.First seen in the chapter →
metalloidउपधातुupdhatu
An element with properties between those of metals and non-metals, such as silicon and arsenic.First seen in the chapter →
oxidation stateऑक्सीकरण अवस्थाoxikaran avastha
The charge an atom would carry if every shared pair were given to the more electronegative partner.First seen in the chapter →
periodआवर्तaavart
A horizontal row of the periodic table; its number is the principal quantum number of the valence shell.First seen in the chapter →
periodic lawआवर्त नियमaavart niyam
The properties of elements repeat at regular intervals when the elements are arranged by atomic number (Mendeleev used atomic mass).
representative elementप्रतिनिधि तत्वpratinidhi tatva
An s- or p-block element (groups 1, 2 and 13 to 18), also called a main group element.First seen in the chapter →
transition elementसंक्रमण तत्वsankraman tatva
A d-block element (groups 3 to 12) in which electrons enter the inner (n − 1)d subshell.First seen in the chapter →