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ChemistryCh 10 Biomolecules

Biomolecules: Class 12 Chemistry · Chapter 10

Chemistry Part 2 · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 95 min
  • 1 simulation
  • 38 practice questions
  • 35 MCQs

What you will learn in Biomolecules

  • Define carbohydrates by their functional groups and classify them as monosaccharides, oligosaccharides or polysaccharides, and as reducing or non-reducing sugars
  • Deduce the open-chain structure of glucose from its reactions, assign D and L configurations, and explain the cyclic pyranose and furanose forms and anomers
  • Describe the glycosidic linkages in sucrose, maltose, lactose, starch, cellulose and glycogen, and relate them to reducing behaviour, inversion and function
  • Classify amino acids, explain zwitterions and amphoteric behaviour, and describe peptide bonds and the four levels of protein structure
  • Explain denaturation and how enzymes catalyse reactions with high specificity by lowering activation energy
  • Classify vitamins by solubility and link important vitamins to their sources and deficiency diseases
  • Describe the composition and structure of DNA and RNA, base pairing, and the functions of nucleic acids
  • Group hormones by chemical type and describe the roles of insulin, glucagon, thyroxine, epinephrine and the steroid hormones

Original companion text aligned to NCERT Chemistry Class 12, Chapter 10, pp. 281–302. Not affiliated with or endorsed by NCERT.

Picture a plate of dal, rice and curd. The rice is mostly starch, the dal is rich in protein, and the curd brings milk sugar, fat and a crowd of helpful bacteria. Within hours your body has taken these large molecules apart and started to rebuild the pieces as its own: muscle, blood cells, and a fresh copy of your DNA each time a cell divides.

The molecules that living things build and use are called biomolecules (जैव-अणु). The big families are carbohydrates, proteins, nucleic acids and lipids, and smaller helpers such as vitamins, hormones and mineral ions keep the chemistry on track. No single one of these molecules is alive. Life is what thousands of their reactions add up to when they run together in water, at body temperature, each at the right moment, and the study of that chemistry is biochemistry.

This unit takes the families one at a time: what each is made of, how its units are joined, and how its structure explains its job. You will reuse ideas from earlier units along the way: aldehydes, ketones, amines and acids; optical activity and stereocentres (Unit 6); and activation energy from chemical kinetics.

10.1 Carbohydrates

The sugar in your tea, the starch in a chapati and the cellulose in a cotton shirt are all carbohydrates. Green plants make them from carbon dioxide and water using the energy of sunlight, and nearly every other organism, including you, lives on that supply. The small, sweet, water-soluble members of the family are called sugars, and the whole family is also known as the saccharides, from the Greek word for sugar.

The name carbohydrate is a leftover from early chemistry. Many of these compounds have formulas that fit CXx(HX2O)Xy: table sugar, CX12HX22OX11, can be written CX12(HX2O)X11, as if it were carbon plus water. As a test, though, the formula fails in both directions, as the next example shows.

Example

Does the formula decide?

Which of these compounds fit the formula CXx(HX2O)Xy, and which are carbohydrates? (a) Methanal, HCHO. (b) Lactic acid, CHX3CH(OH)COOH (the acid of sour milk). (c) 2-Deoxyribose, CX5HX10OX4, the sugar of DNA, which has an aldehyde group and three –OH groups.

Try it yourself first. Then reveal the solution one step at a time.

What carbohydrates really share is a set of functional groups. Chemically, a carbohydrate is a polyhydroxy aldehyde or a polyhydroxy ketone (optically active), or a larger molecule that breaks down into such units on hydrolysis; polyhydroxy just means carrying several –OH groups.

Definition
Carbohydrate

A polyhydroxy aldehyde or ketone (optically active), or a compound that yields such units on hydrolysis.

Exampleglucose, sucrose, starch, cellulose

10.1.1 Classification of Carbohydrates

The most useful way to sort carbohydrates is to ask what hydrolysis does to them (Fig. 10.1). Boiled with a dilute acid, or treated with the right enzyme, a carbohydrate takes up water at the links between its sugar units, and the links break.

  • Monosaccharides are the simplest sugars, the units from which everything else is built; hydrolysis cannot break them into anything smaller of the same kind. Glucose, galactose and the pentose ribose are examples, and only around twenty occur in nature.
  • Oligosaccharides (Greek oligos, few) break into a small number of units, from two to ten. A disaccharide gives two, a trisaccharide three, and so on. The two-unit kind is by far the one you meet most, whether its halves match, as in trehalose (glucose + glucose, the sugar of insect blood), or differ, as in lactose (galactose + glucose).
  • Polysaccharides are giant chains of hundreds or thousands of units. Because they are tasteless, they are sometimes called non-sugars; the starch in a potato, the cellulose of cotton and the gum that oozes from some trees are all polysaccharides.

2/4Water, with acid or an enzyme, breaks some links. Pairs of units are disaccharides, the commonest oligosaccharides (2–10 units).

Fig. 10.1Hydrolysis breaks the links between sugar units; a monosaccharide is what is left when nothing more can be split.

A row of eight green hexagons, each standing for one sugar unit, joined by short links marked with a dot for the bridging oxygen atom. Step 1: all eight are joined in one chain, labelled polysaccharide. Step 2: with water and an acid or enzyme, every second link has gone, leaving four pairs, labelled disaccharides. Step 3: the remaining links have gone and the eight hexagons stand apart, labelled monosaccharides. Step 4: one hexagon is ringed and the others are faded; the label says that one unit cannot be split into a simpler sugar.

Definition
Monosaccharide

The simplest kind of carbohydrate: a single polyhydroxy aldehyde or ketone unit that hydrolysis cannot split further.

Exampleglucose, fructose, ribose

A second, chemical test sorts carbohydrates by whether they act as reducing agents. Warm the sugar with Tollens' reagent, and a silver mirror forms; warm it with Fehling's solution, and a brick-red precipitate of copper(I) oxide appears. Sugars that give these results are reducing sugars (अपचायी शर्करा). Every monosaccharide passes, ketoses as well as aldoses.Fructose has no –CHO group, yet it reduces both reagents: in their alkaline solution it rearranges, through an enediol, into aldoses. For bigger sugars the answer depends on how the units are joined (Section 10.1.3).

Definition
Reducing sugar

A sugar that reduces Tollens' reagent and Fehling's solution, because it has (or can open up to give) a free aldehyde or keto group.

Exampleglucose, fructose, maltose, lactose

Quick check
1 of 3
Complete hydrolysis of a carbohydrate gives exactly three monosaccharide units. It is
Show answer

Answer (C) an oligosaccharide (a trisaccharide)

Two to ten units on hydrolysis makes an oligosaccharide, and three units make it a trisaccharide. Three is far too few for a polysaccharide, and it is clearly not a monosaccharide, which cannot be hydrolysed at all.

10.1.2 Monosaccharides

A monosaccharide is named by two features: its carbonyl group and its number of carbon atoms. An aldose carries an aldehyde group, −CHO, at one end of the chain; a ketose carries a keto group, >C=O, usually on carbon 2. The carbon count gives triose (3 C), tetrose (4), pentose (5), hexose (6) and heptose (7), and the two ideas combine into one word: glucose is an aldohexose and fructose a ketohexose (Table 10.1).

Table 10.1Monosaccharides named by carbonyl group (aldose –CHO, ketose C=O) and carbon count
CarbonsAldoseKetose
3, trioseglyceraldehydedihydroxyacetone
4, tetroseerythroseerythrulose
5, pentoseriboseribulose
6, hexoseglucose, galactosefructose
7, heptosefew in naturesedoheptulose

10.1.2.1 Glucose

Glucose is the sugar your blood carries to every cell and the unit from which starch, glycogen and cellulose are built; counting the glucose locked up in those polymers, no organic building block is more plentiful on Earth. Ripe fruit and honey contain it free. Two of its old names recall its history: grape sugar, after its best-known source, and dextrose, because its solution turns plane-polarised light to the right.

Preparation. Both routes to glucose are hydrolyses. In the laboratory the starting material is cane sugar: warming its alcoholic solution with a little dilute mineral acid cleaves each sucrose molecule into one glucose and one fructose.

sucrose → glucose + fructose
CX12HX22OX11+HX2O→HX+CX6HX12OX6+CX6HX12OX6

On a large scale the raw material is cheap starch from maize or cassava. It used to be cooked with dilute sulfuric acid in pressure vessels at about 393 K; most factories now let the enzymes amylase and glucoamylase do the cutting at lower temperatures.

starch → glucose
(CX6HX10OX5)n+n HX2O→HX+,heatn CX6HX12OX6

Working out the structure. Before X-ray methods, chemists had to deduce structures from reactions, one question at a time (Fig. 10.2):

  1. How many atoms of each kind? Combustion analysis and a molar-mass measurement settle it: CX6HX12OX6.
  2. Is the carbon skeleton branched? Hydrogen iodide, given long enough, strips away every oxygen and leaves n-hexane, the unbranched alkane.
  3. Is there a carbonyl group? Yes: towards hydroxylamine (forming an oxime) and hydrogen cyanide (adding to give a cyanohydrin) glucose behaves like an aldehyde or a ketone.
  4. Aldehyde or ketone? Bromine water, too gentle to break C–C bonds, converts glucose into gluconic acid without losing a carbon. Only a –CHO group at the end of the chain can be oxidised like that.
  5. How many –OH groups, and where? Acetic anhydride acetylates five of them, giving a pentaacetate. A carbon carrying two –OH groups would lose water, and the pentaacetate is stable, so each –OH has a carbon of its own.
  6. What is at the far end? Nitric acid oxidises both glucose and gluconic acid to saccharic acid, which has a –COOH group at each end. The second one can only come from a primary alcohol group, −CHX2OH, on C6.

4/6Oxidation to a six-carbon acid: the carbonyl group is an aldehyde at C1.

Fig. 10.2Each reaction answers one question; together the answers give OHC−(CHOH)X4−CHX2OH as the open-chain formula.NCERT Structure of glucose · p. 283

On the left, glucose is drawn as a column of six boxes for carbons 1 to 6: CHO at the top, four CHOH boxes, and CH2OH at the bottom. On the right, each step shows one reagent and what it proves. Step 1: the formula C6H12O6. Step 2: hydrogen iodide gives n-hexane and a bracket runs alongside all six boxes, showing an unbranched chain. Step 3: hydroxylamine and hydrogen cyanide react, and the top box is outlined, showing a carbonyl group. Step 4: bromine water turns the top box into COOH, gluconic acid, so the carbonyl is an aldehyde. Step 5: acetic anhydride gives a pentaacetate and boxes 2 to 6 are outlined, showing five OH groups on five carbons. Step 6: nitric acid turns both end boxes into COOH, saccharic acid, so carbon 6 was a primary alcohol.

Together the clues give the open-chain formula OHC−(CHOH)X4−CHX2OH for an aldohexose. Yet that formula leaves something out. Carbons 2, 3, 4 and 5 are all stereocentres, so 24=16 stereoisomers share it. Emil Fischer spent years working out which one is glucose (he received the 1902 Nobel Prize in Chemistry), and he drew the answer in a style still named after him, the Fischer projection: the chain runs straight down with C1 at the top, and at each stereocentre the H and the OH point left or right.

D and L. In the Fischer projection of natural glucose, the –OH on C5, the stereocentre farthest from the aldehyde group, points to the right (Fig. 10.3). The letter D records exactly this. The reference compound is glyceraldehyde, the simplest aldose, which has just one stereocentre. The enantiomer with its –OH on the right is D-glyceraldehyde and its mirror image is L-glyceraldehyde. A sugar, drawn with its most oxidised carbon at the top, is D if the –OH on its lowest stereocentre points the same way as in D-glyceraldehyde and L if it points the other way; the other stereocentres play no part in the label.

Fig. 10.3Compare the lowest stereocentre with glyceraldehyde: OH on the right means D.NCERT D/L configuration · p. 285

Three Fischer projections. On the left, D-glyceraldehyde has CHO at the top, CH2OH at the bottom, and at the single crossing H on the left and OH on the right. Next to it, L-glyceraldehyde has the OH on the left and H on the right; the crossing row of each is boxed. On the right, D-glucose has CHO at the top, CH2OH at the bottom and four crossings for carbons 2 to 5, with OH on the right, left, right and right. The row for carbon 5, the lowest stereocentre, is boxed: its OH is on the right, as in D-glyceraldehyde.

D and L describe configuration, the arrangement of groups in space. They say nothing about which way the compound turns plane-polarised light; that has to be measured and is shown separately as (+), dextrorotatory, or (−), laevorotatory. Natural glucose is D-(+)-glucose. D-glyceraldehyde happens to be (+) as well, but many D sugars are (−), fructose among them. Don't mix up capital D and L with the old lower-case d and l, which were just other symbols for (+) and (−).

Where the open chain fails. The open-chain formula explained most reactions, but a few facts would not fit it:

  • Two standard aldehyde tests fail: Schiff's reagent stays colourless, and sodium hydrogensulfite, NaHSOX3, forms no addition compound.
  • Acetylate glucose and the product ignores hydroxylamine, so whatever happened to the aldehyde group, the pentaacetate has none left.
  • Glucose crystallises in two distinct forms, named α and β. They melt at different temperatures (about 146 °C and 150 °C) and turn polarised light by different amounts: their specific rotations are about +112° and +19°. One open-chain structure cannot explain two isomers.

The ring. The way out is a reaction from aldehyde chemistry: an alcohol adds to a C=O group to give a hemiacetal. In glucose the alcohol and the aldehyde belong to the same molecule. The chain curls round until the –OH on C5 reaches C1; its oxygen bonds to C1, and the carbonyl oxygen becomes a new –OH (Fig. 10.4). The result is a six-membered ring of five carbons and one oxygen.

4/4β-D-glucopyranose: the –OH on C1 is up, on the same side as CHX2OH.

Fig. 10.4C5–OH adds to the aldehyde group; the new –OH on C1 can point down (α) or up (β).NCERT Haworth structures · p. 286

A ring outline is drawn in perspective, with the nearer edge thick. Step 1: the chain is curled so that the OH on carbon 5, at the back of the ring, sits next to carbon 1, which is still an aldehyde with an H and a double-bonded O. Step 2: a dashed curved arrow shows the oxygen of carbon 5 attacking carbon 1. Step 3: the ring is closed by the C1 to O bond, and carbon 1, ringed, now carries H up and OH down: the alpha form. Step 4: the same ring with OH up on carbon 1, on the same side as the CH2OH group on carbon 5: the beta form. The other ring carbons keep OH down on carbon 2, OH up on carbon 3 and OH down on carbon 4 in every step.

Ring closure makes C1 a new stereocentre, so it can happen in two ways. In the α form the new –OH on C1 points to the opposite side of the ring from the CHX2OH group on C5 (down, as usually drawn); in the β form it points to the same side (up). The two forms differ only at C1, now called the anomeric carbon, and a pair of isomers like this are anomers (ऐनोमर). In water, α, β and a trace of the open chain keep converting into one another until they reach equilibrium, at roughly 36 % α and 64 % β, with far less than 1 % open chain.

Definition
Anomers

Two cyclic forms of a sugar that differ only in the configuration at the anomeric carbon (C1 in glucose, C2 in fructose).

Exampleα-D-glucopyranose and β-D-glucopyranose

This explains all three puzzles. With so little open chain present at any moment, slow aldehyde tests such as Schiff's reagent hardly respond. The pentaacetate is locked as a ring, with an acetyl group on C1, so it cannot reopen into an aldehyde. And α and β are the two crystalline forms. Reactions that use up the open chain, such as oxidation by Tollens' reagent, still go to completion, because the equilibrium keeps making more of it.

Dissolve either pure crystal form in water and the rotation slowly drifts to the same final value, +52.7°, as the equilibrium mixture forms; this drift is called mutarotation. Try it in the Fig. 10.5 lab.

InteractiveMutarotation lab

Two buttons choose which crystals to dissolve: pure α-D-glucose or pure β-D-glucose. A Play button starts the clock, with Pause and Reset buttons beside it. A polarimeter dial and a number show the specific rotation, starting at +112.2 degrees for alpha or +18.7 degrees for beta. Three bars show the percentages of the alpha ring, the open chain and the beta ring; the open chain stays below 0.01 per cent and is labelled as too small to draw. A graph plots rotation against time in minutes; both starting points approach the same final value of about +52.7 degrees, with 36 per cent alpha and 64 per cent beta. A status line describes what is happening in words.

Fig. 10.5Dissolve α or β crystals, press Play, and watch the anomers interconvert while the polarimeter reading drifts to the equilibrium value.

Drawn as a flat hexagon seen almost edge-on, with the ring oxygen at the back right and C1 on the right, the ring is a Haworth projection. A group on the right of the Fischer projection points down in the Haworth projection. Because the six-membered ring resembles the heterocycle pyran, CX5HX6O, these ring forms are called pyranoses: α-D-glucopyranose and β-D-glucopyranose.

10.1.2.2 Fructose

Fructose, CX6HX12OX6, is an isomer of glucose with the same unbranched six-carbon chain. The difference is the carbonyl group: instead of an aldehyde at C1, fructose has a ketone at C2, flanked by a CHX2OH group (C1) and the rest of the chain, which makes it the most important ketohexose. Its configuration at C3, C4 and C5 matches glucose, so it is a D sugar, yet it is strongly laevorotatory: D-(−)-fructose.

Honey and many fruits contain free fructose, and every sucrose molecule contains one fructose unit. Weight for weight it tastes sweeter than table sugar, which is why food makers like it.

Ring closure works as for glucose, except that the C5 oxygen now attacks the keto carbon, C2 (the product is strictly a hemiketal). Counting from C2 round to C5 and back through the oxygen gives a five-membered ring of four carbons and one oxygen, the same ring as in the heterocycle furan, CX4HX4O, hence the name furanose (Fig. 10.6). The anomeric carbon is C2, and again there are α and β anomers. Fructose can also form six-membered rings in water, but in sucrose it is always the furanose.

Fig. 10.6The –OH on C5 closes a five-membered ring onto the C2 keto group.NCERT Structure of fructose · p. 286

On the left is a Fischer projection of D-fructose: CH2OH at the top as carbon 1, C=O at carbon 2 (boxed), then crossings for carbon 3 with OH on the left, and carbons 4 and 5 with OH on the right; the carbon 5 row is boxed. CH2OH is at the bottom as carbon 6. An arrow points to the right-hand drawing, a Haworth projection of beta-D-fructofuranose: a five-membered ring of four carbons and an oxygen at the back, with the nearer edge thick. The ringed anomeric carbon 2 carries OH up and CH2OH (carbon 1) down to the right; carbon 3 has OH up, carbon 4 has OH down, and carbon 5 carries CH2OH (carbon 6) up.

Quick check
1 of 4
Glucose reacts with bromine water to give gluconic acid, which still has six carbons. What does this show?
Show answer

Answer (C) The carbonyl group is an aldehyde at the chain end

A mild oxidant turns an aldehyde, –CHO, into –COOH without breaking the chain; a ketone would not react this way. The straight chain comes from the HI result, the five –OH groups from acetylation, and the primary alcohol from nitric acid.

10.1.3 Disaccharides

Two monosaccharides can join when an –OH group on one reacts with an –OH group on the other and a molecule of water is lost. The two units end up bridged by an oxygen atom, C–O–C. This bridge is a glycosidic linkage (ग्लाइकोसाइडी बंध), and at least one of the carbons it joins is an anomeric carbon. Hydrolysis, by dilute acid or by an enzyme, adds the water back and frees the two monosaccharides.

Definition
Glycosidic linkage

The C–O–C bridge that joins two monosaccharide units, formed with the loss of a water molecule and involving at least one anomeric carbon.

Examplethe α(1→4) link in maltose

Whether a disaccharide is a reducing sugar depends on its anomeric carbons. If one unit still has its anomeric carbon free, carrying an –OH, that ring can open to an aldehyde, so the sugar reduces Tollens' and Fehling's reagents. If both anomeric carbons are tied up in the linkage, neither ring can open and the sugar is non-reducing. Fig. 10.7 compares the three common disaccharides.

3/3C1 of α-glucose joined to C2 of β-fructose: both anomeric carbons are used, so sucrose is non-reducing.

Fig. 10.7A free anomeric carbon makes a reducing sugar; sucrose has none.

Each step shows two sugar rings joined through an oxygen bridge. Step 1, maltose: two green glucose hexagons; the bridge runs from carbon 1 of the left ring, dipping below the line (alpha), to carbon 4 of the right ring, whose carbon 1 is ringed and carries a free OH. Step 2, lactose: an orange galactose hexagon on the left joined from its carbon 1 by a bridge rising above the line (beta) to carbon 4 of a glucose hexagon; carbon 1 of the glucose is again free. Step 3, sucrose: a glucose hexagon joined from carbon 1 to carbon 2 of a purple five-membered fructose ring; both linked carbons are circled with dashes and the label says no anomeric carbon is free, so sucrose is non-reducing.

Sucrose, cane or beet sugar, is the sugar in your kitchen. Its glycosidic linkage joins C1 of an α-D-glucose unit to C2 of a β-D-fructose unit. These are the anomeric carbons of both units, so sucrose is a non-reducing sugar. Hydrolysis gives equal amounts of glucose and fructose (the equation in 10.1.2.1).

Sucrose turns plane-polarised light to the right (specific rotation +66.5°). Glucose is dextrorotatory too (+52.7°), but fructose is strongly laevorotatory (−92.4°). So as sucrose is hydrolysed, the rotation falls, passes through zero and ends up negative. Because the sign of rotation is inverted, the equimolar mixture of glucose and fructose is called invert sugar (अपवृत्त शर्करा). Honey is mostly invert sugar, made when bees add the enzyme invertase to nectar.

Definition
Invert sugar

The equimolar mixture of glucose and fructose formed by hydrolysing sucrose; it is laevorotatory, whereas sucrose is dextrorotatory.

Examplehoney, mostly

Example

Watching the rotation invert

A solution of 10.0 g of sucrose in 100 mL of water is placed in a polarimeter tube 1.00 dm long. Observed rotation = specific rotation × length (dm) × concentration (g/mL). Specific rotations: sucrose +66.5°, glucose +52.7°, fructose −92.4°. Find (a) the starting reading, (b) the reading after complete hydrolysis, and (c) the fraction of sucrose hydrolysed when the reading is zero.

Try it yourself first. Then reveal the solution one step at a time.

Maltose, malt sugar, is what amylase leaves behind when it chops up starch, in your mouth or in sprouting grain. Both of its units are α-D-glucose, linked α(1→4): the bridge runs from the anomeric C1 of one unit to C4 of the other. That leaves the second unit's C1 unattached, its ring free to open into an aldehyde, so maltose reduces Tollens' and Fehling's reagents.

Lactose is found only in milk. Its galactose unit, in the β form, uses its anomeric C1 to bond to C4 of a glucose unit (a β(1→4) link), and once again the glucose end is left with a free anomeric carbon: lactose is a reducing sugar too. Many adults make little lactase, the enzyme that splits lactose, so milk upsets their stomachs while curd does not: in curd, bacteria have already used up much of the lactose.

Compare

Three common disaccharides

Sucrose

  • α-D-glucose + β-D-fructose
  • C1 of glucose to C2 of fructose
  • non-reducing
  • hydrolysis gives invert sugar

Maltose

  • two α-D-glucose units
  • α(1→4)
  • reducing
  • from starch, by amylase

Lactose

  • β-D-galactose + D-glucose
  • β(1→4)
  • reducing
  • in milk; split by lactase
Quick check
1 of 3
Why is sucrose a non-reducing sugar?
Show answer

Answer (D) Both anomeric carbons are used in its glycosidic linkage

The C1–C2 link ties up the anomeric carbons of glucose and fructose, so neither ring can open into a free carbonyl group. Maltose and lactose are disaccharides that do reduce, so it is not true of all disaccharides; and fructose by itself is a reducing sugar.

10.1.4 Polysaccharides

Nearly all the carbohydrate in the living world is polysaccharide. Organisms use these giant molecules for two purposes, as a compact store of fuel or as tough building material. Three of them are made of glucose alone, and they show how a small change in the linkage produces very different materials (Fig. 10.8).

3/4Glycogen: built like amylopectin but branched every 8–12 units.

Fig. 10.8Same glucose units, different links and branching: coil, tree, bush or fibre.

Each blue bead is one glucose unit. Step 1, amylose: a single long chain of beads looping up and down like a coil, with no branches, joined alpha 1 to 4. Step 2, amylopectin: a long horizontal chain with three side chains slanting up from it; each branch point is an orange bead, marking an alpha 1 to 6 link. Step 3, glycogen: the same kind of chain with six branches close together, several of which branch again, so the molecule is much bushier. Step 4, cellulose: four straight horizontal chains lie side by side, with short dashed lines between neighbouring chains for hydrogen bonds.

Rice, wheat, bajra, potatoes and tapioca owe their food value mainly to starch, the fuel store of plants and the biggest source of carbohydrate in the human diet. It is a mixture of two polymers of α-D-glucose. Amylose, the smaller part (typically 15–25 %), is an unbranched chain of hundreds to thousands of units joined by α(1→4) linkages; it coils into a helix and dissolves in hot water. Amylopectin, the larger part, does not dissolve in water. Its chains use the same α(1→4) links but sprout a branch through an α(1→6) linkage every 20–30 units or so.

Cotton is almost pure cellulose, and wood is roughly half cellulose: it is the material of plant cell walls, and no organic compound is more plentiful among plants. Its chains are unbranched and built from β-D-glucose units joined by β(1→4) linkages. The β links keep each chain straight and flat, so neighbouring chains lie side by side and hydrogen-bond into strong, insoluble fibres.

Animals, yeasts and fungi store glucose as glycogen. Built like amylopectin but branched far more often, about every 8–12 units, it earns the nickname animal starch. Your liver and muscles hold most of it, and the brain a little. The branching is the point: every branch ends in a chain end, and when blood glucose drops, enzymes release glucose from hundreds of ends at the same time.

Compare

Starch, glycogen and cellulose

Starch

  • plant fuel store
  • α-glucose; α(1→4), branches α(1→6)
  • amylose + amylopectin
  • digested by amylase

Glycogen

  • animal fuel store (liver, muscle)
  • α-glucose; like amylopectin
  • more highly branched
  • broken down fast when needed

Cellulose

  • plant cell walls
  • β-glucose; β(1→4)
  • straight, unbranched chains
  • not digested by humans
Quick check
1 of 3
Which difference best explains why humans digest starch but not cellulose?
Show answer

Answer (B) Starch has α-glycosidic links, cellulose has β-glycosidic links

Both are polymers of glucose. Our digestive enzymes cut α(1→4) and α(1→6) links but not β(1→4) links. Cellulose is unbranched, and its molecules are large.

10.1.5 Importance of Carbohydrates

Carbohydrates are the main fuel in most diets. Digestion turns starch and sugars into glucose, and cells oxidise glucose to carbon dioxide and water, capturing the energy released. Plants put spare glucose away as starch and animals as glycogen, to be drawn on later.

As materials, carbohydrates are everywhere in daily life: the wood of a door, the cotton and rayon of your clothes, the paper of a notebook, the starch that stiffens a starched kurta, and the sugars that yeast ferments when bread rises. They also turn up as parts of bigger molecules. Ribose and deoxyribose form part of the backbones of RNA and DNA (Section 10.5), and short sugar chains attached to proteins and lipids at cell surfaces act as identity tags; your ABO blood group, for example, is set by a few sugar units on your red blood cells.

Practice · 3 questions

Practice: carbohydrates: questions with answers

  1. Short answerEasyNCERT Intext Question 10.1

    Sucrose dissolves readily in water, but naphthalene and hexane hardly dissolve at all. Explain the difference in terms of their molecules.

    Show solution

    AnswerSucrose's many –OH groups hydrogen-bond with water.

    A sucrose molecule carries eight –OH groups, each of which can form hydrogen bonds with water molecules; these attractions make up for breaking the hydrogen bonds between water molecules, so sucrose dissolves. Naphthalene and hexane are hydrocarbons with no polar groups. They cannot hydrogen-bond with water, so water molecules stay bonded to each other and the hydrocarbon stays out.

  2. Short answerEasyNCERT Intext Question 10.2

    Maltose is warmed with dilute acid until hydrolysis is complete. Name the product or products and give the mole ratio. How would the answer differ for lactose?

    Show solution

    AnswerMaltose: glucose only (2 mol per mol). Lactose: galactose + glucose, 1 : 1.

    Maltose is two α-D-glucose units joined α(1→4), so one mole gives two moles of D-glucose. Lactose is β-D-galactose joined β(1→4) to D-glucose, so one mole gives one mole of D-galactose and one mole of D-glucose.

  3. Short answerMediumNCERT Intext Question 10.3

    Glucose forms an oxime with hydroxylamine, but glucose pentaacetate does not. Explain.

    Show solution

    AnswerThe pentaacetate is a locked ring with no free –CHO.

    In solution, cyclic glucose is in equilibrium with a little open-chain aldehyde, which hydroxylamine traps as the oxime; the equilibrium then supplies more. In the pentaacetate, the –OH on C1 has been acetylated along with the other four. Without a free hemiacetal –OH, the ring cannot reopen, so no aldehyde group is ever present for hydroxylamine to attack.

10.2 Proteins

In 1838 the Swedish chemist Jöns Berzelius suggested the name protein, from the Greek proteios, of first importance, and the name has stood up well. Muscle, skin, hair and nails are largely protein; so are the enzymes that digest your food, the haemoglobin that carries oxygen, the antibodies that fight infection and hormones such as insulin. No other class of biomolecule is as abundant in a cell or does as many different jobs. You need a steady supply to grow and to repair tissue, and dal, soya, paneer, eggs, nuts, fish and chicken are all good sources.

Every protein is a long chain built from α-amino acids (ऐमीनो अम्ल), so we begin with them.

10.2.1 Amino Acids

Boil any protein with acid for long enough and it falls apart into α-amino acids, compounds of general formula HX2N−CH(R)−COOH in which the amino group and the carboxyl group sit on the same carbon, the α-carbon. (Move the amino group one carbon further from the carboxyl group and you have a β-amino acid, then γ, δ and so on, but these are not the building units of proteins.) The group R, the side chain, is what makes one amino acid different from another; some side chains carry a further functional group, such as –OH, –SH, a second –COOH or a second −NHX2.

Definition
α-Amino acid

A compound with an amino group and a carboxyl group on the same carbon atom, general formula HX2N−CH(R)−COOH where R is the side chain. Proteins are built from twenty of them.

Examplealanine, R = CHX3

Nobody in a biochemistry lab calls alanine 2-aminopropanoic acid: amino acids keep the names given when they were discovered, which often recall a source or a property. Asparagine was first isolated from asparagus juice; cysteine takes its name from cystine, which was discovered in bladder stones (Greek kystis, bladder). To write long chains compactly, each one also has a three-letter symbol (Ala, Gly…) and a one-letter code (A, G…). Table 10.3 lists the twenty amino acids of proteins, grouped by the kind of side chain.

Table 10.3The twenty amino acids of proteins by side chain: name, three-letter symbol, one-letter code (* = essential in the diet)NCERT Table 10.2 · p. 290
Side chainAmino acids
Non-polarglycine Gly G; alanine Ala A; valine* Val V; leucine* Leu L; isoleucine* Ile I; methionine* Met M; phenylalanine* Phe F; tryptophan* Trp W; proline Pro P
Polar, unchargedserine Ser S; threonine* Thr T; cysteine Cys C; tyrosine Tyr Y; asparagine Asn N; glutamine Gln Q
Acidic (extra –COOH)aspartic acid Asp D; glutamic acid Glu E
Basic (extra N base)lysine* Lys K; arginine* Arg R; histidine* His H

10.2.2 Classification of Amino Acids

Amino acids are sorted in two ways. The first counts acidic and basic groups. One amino group and one carboxyl group, as in alanine or serine, make an amino acid neutral. A side chain with an extra carboxyl group makes it acidic (aspartic acid and glutamic acid), and a side chain with an extra basic nitrogen group makes it basic (lysine, arginine and histidine).

The second sorting is about diet. Your body can make about half of the twenty from other compounds; these are non-essential amino acids, for example glycine, alanine and glutamic acid. The others cannot be made at all, or not fast enough, and must come from food. These are the essential amino acids (आवश्यक ऐमीनो अम्ल), such as valine, lysine and tryptophan. Ten are usually listed for growing children; adults make enough arginine, so for them the list is nine. Cereals are short of lysine and pulses are short of methionine, which is why dal eaten with rice provides better protein than either alone.

Definition
Essential amino acid

An amino acid that the body cannot make in sufficient amounts, so it must be supplied by the diet.

Examplelysine, tryptophan, valine

Properties. Put some crystals of glycine on a spatula and they behave nothing like an amine or a carboxylic acid. They are colourless, dissolve readily in water and only melt, with decomposition, at high temperatures, often above 200 °C: the behaviour of a salt. The reason is an acid–base reaction inside the molecule (Fig. 10.9). The carboxyl group passes a proton to the amino group of the same molecule, giving the ion HX3NX+−CH(R)−COOX− with one positive and one negative charge. Such a dipolar ion is a zwitterion (ज़्विटर आयन), from the German Zwitter, hybrid. It is neutral overall, but its charged ends attract neighbouring molecules strongly, as the ions in a salt crystal do.

2/4The –COOH passes a proton to the –NH₂: a dipolar ion with no net charge.

Fig. 10.9One molecule, two charged ends: acid protonates the –COO⁻ end, base deprotonates the –NH₃⁺ end.NCERT Zwitter ion · p. 292

An alpha-amino acid is drawn as an amino group on the left, the alpha carbon CH with its side chain R below, and a carboxyl group on the right. Step 1: the uncharged form, H2N and COOH, with a note that this is not how it exists in water. Step 2: a curved arrow shows a proton moving from COOH to the amino group, giving H3N plus on the left and COO minus on the right, net charge zero: the zwitterion. Step 3: an H plus ion arrives from an added acid and joins the COO minus end, giving H3N plus and COOH, net charge plus one. Step 4: an OH minus ion from an added base removes a proton from the H3N plus end, giving H2N and COO minus, net charge minus one.

Definition
Zwitterion

A dipolar ion that carries a positive and a negative charge on different atoms but is neutral overall; amino acids exist mainly in this form.

Exampleglycine as HX3NX+−CHX2−COOX−

A zwitterion is amphoteric: it reacts with acids and with bases. Add acid and the −COO− end picks up a proton, leaving a cation; add base and the −NHX3X+ end loses one, leaving an anion. This is one reason proteins help to hold the pH of blood and cells steady. The Fig. 10.10 simulation treats the two charged ends as point charges, so you can see which end an approaching ion is drawn to.

SimulationA zwitterion as a +/− pair

Two fixed point charges sit side by side in the middle of the stage: a positive one on the left for the protonated amino group and a negative one on the right for the carboxylate group. Field lines run from the positive charge to the negative one. A small positive test charge, standing for an H+ ion from an acid, can be dragged anywhere, and an arrow and a readout show the size and direction of the force on it. A button flips the test charge to negative, standing for an OH- ion from a base.

Fig. 10.10The + charge stands for the –NH₃⁺ end and the − charge for the –COO⁻ end. The small test charge plays an ion that approaches the molecule.
Try this
  • Drag the positive test charge (an H⁺ ion) around the molecule. Which end pulls it hardest? That is the group an acid protonates.
  • Press Make it −q to turn the test charge into an OH⁻ ion. Which end does it head for now?
  • Move the test charge far from the pair. Why is the force so much weaker, even though the molecule has two charges?

Optical activity. In every α-amino acid except glycine, where R is just H, the α-carbon carries four different groups. It is therefore a stereocentre, and the amino acid is chiral and optically active. Each exists in D and L forms, assigned by comparison with glyceraldehyde as for sugars. Proteins are built almost entirely from the L forms: in a Fischer projection with –COOH at the top, the −NHX2 of an L-amino acid points to the left.

Quick check
1 of 4
Which amino acid is not optically active?
Show answer

Answer (D) glycine

In glycine R = H, so the α-carbon carries two hydrogens and is not a stereocentre. Alanine, serine and lysine each have four different groups on the α-carbon.

10.2.3 Structure of Proteins

The peptide bond. Amino acids join by condensation. The carboxyl group of one reacts with the amino group of the next, a molecule of water is lost, and an amide link, −CO−NHX−, forms (Fig. 10.11). In protein chemistry this amide link is called the peptide bond or peptide linkage (पेप्टाइड आबंध).

Definition
Peptide bond

The amide link, –CO–NH–, formed when the carboxyl group of one amino acid condenses with the amino group of another, with loss of water.

Examplethe –CO–NH– in alanylglycine

2/3Water is lost and a C–N bond forms: alanylglycine, Ala-Gly.

Fig. 10.11Each peptide bond forms with the loss of one water molecule.NCERT Peptide bond · p. 292

Structures are drawn as zigzag chains. Step 1: alanine on the left and glycine on the right; the OH of alanine's carboxyl group and one H of glycine's amino group are boxed. Step 2: the boxed OH and H leave as a water molecule, shown above, and a new carbon to nitrogen bond, highlighted, joins the carbonyl carbon of alanine to the nitrogen of glycine: the dipeptide alanylglycine. Step 3: serine has been added at the right in the same way, so the chain has two highlighted peptide bonds; the free amino group at the left end is labelled N-terminus and the free carboxyl group at the right end is labelled C-terminus.

Two amino acids joined this way form a dipeptide, and the order matters. When alanine supplies the carboxyl group and glycine the amino group, the product, HX2N−CH(CHX3)−CO–NH−CHX2−COOH or Ala-Gly, is alanylglycine, a different compound from glycylalanine (Gly-Ala). By convention a peptide is written from the end with the free amino group (the N-terminus) to the end with the free carboxyl group (the C-terminus). Names follow the count of residues: tripeptide (two peptide bonds), tetrapeptide, pentapeptide, hexapeptide and so on.

Beyond about ten residues we simply say polypeptide. Chemists usually keep the word protein for chains of a hundred or more residues (molar mass above roughly 10 000 g/mol), but the cut-off is loose: insulin has just 51 residues, split between two chains, and still counts as a protein because it folds into a definite working shape. Build some peptides of your own in the Fig. 10.12 builder.

InteractivePeptide builder

Ten buttons add amino acids to the right-hand end of a chain: glycine, alanine, valine, leucine, serine, cysteine, phenylalanine, lysine, aspartic acid and glutamic acid, up to six residues. The chain is drawn as labelled beads from the free amino end on the left, marked H2N, to the free carboxyl end on the right, marked COOH, with each peptide bond highlighted. Readouts give the peptide's full name, its three-letter and one-letter sequences, the number of peptide bonds and of water molecules released, the molar mass, the count of acidic and basic side chains, and how many different chains of this length could be made from the twenty amino acids. Undo, Clear and Reverse buttons change the chain; Reverse shows that the reversed sequence is a different peptide.

Fig. 10.12Tap amino acids to add them to the chain, then compare names, peptide bonds, water lost and molar mass.
Example

Counting and weighing peptides

Molar masses: glycine 75.07, alanine 89.09, serine 105.09 and water 18.02 g/mol. (a) How many different dipeptides can be made from glycine and alanine, if each may be used more than once? (b) How many different tripeptides contain one glycine, one alanine and one serine? (c) Find the molar mass of Ala-Gly-Ser.

Try it yourself first. Then reveal the solution one step at a time.

Fibrous and globular proteins. Compare a strand of your hair with the white of an egg. Hair is made of a fibrous protein, keratin. Many long chains lie parallel, cross-linked by hydrogen bonds and by disulfide (S–S) bridges, so the material is tough and water cannot pull it apart. Egg white is mostly albumin, a globular protein. Each chain folds back on itself into a compact ball with water-attracting groups on the outside, so it dissolves.

Compare

Fibrous and globular proteins

Fibrous

  • long chains lying side by side
  • insoluble in water
  • structural jobs: strength, support
  • keratin (hair, nails, wool), collagen (tendons), myosin (muscle), fibroin (silk)

Globular

  • chains folded into compact balls
  • usually soluble in water
  • working jobs: catalysis, transport, signals
  • enzymes, haemoglobin, albumins, insulin

Four levels of structure. A protein is described at four levels, each built on the one before (Fig. 10.13).

3/5The whole chain folded in three dimensions, here into a globule.

Fig. 10.13Sequence, local shape, whole fold, then several chains together; denaturation undoes all but the first.NCERT Fig. 10.3 · p. 294

Step 1, primary: a row of twelve beads, each with a one-letter amino acid code, from H2N on the left to COOH on the right. Step 2, secondary: on the left the chain coiled into a helix, on the right three straight strands lying side by side with dashed hydrogen bonds between them. Step 3, tertiary: one chain, including a coil and two strands, folded into a compact globule, with a disulfide bridge marked S–S. Step 4, quaternary: four such globules packed together, two labelled alpha and two labelled beta, as in haemoglobin. Step 5, denatured: the same twelve lettered beads, still in the same order, hang in a loose, irregular zigzag with no regular shape, and a note says the sequence is unchanged but the activity is lost.

The primary structure is the sequence of amino acids in each polypeptide chain, read from the N-terminus. It is set by the gene for that protein, and it decides everything else. Change a single amino acid and you have a different protein. In sickle-cell anaemia, one glutamic acid in each β-chain of haemoglobin is replaced by valine, and red blood cells stiffen into sickle shapes.

The secondary structure is the regular local shape of the chain's backbone, held by hydrogen bonds between the C=O of one peptide group and the N–H of another (Fig. 10.14). Two shapes are common. In the α-helix the chain twists into a right-handed coil; the C=O of each residue is hydrogen-bonded to the N–H four residues further along, so these bonds run up the helix almost parallel to its axis and every backbone C=O and N–H is used. In a β-pleated sheet, stretches of chain lie next to one another as almost fully extended zigzags. Each strand hydrogen-bonds sideways to its neighbours, and the zigzags line up into regular folds, like a paper fan.

1/2Each C=O bonds to the N–H four residues along: the hydrogen bonds run parallel to the axis.

Fig. 10.14In a helix the hydrogen bonds link turns of one chain; in a sheet they link neighbouring strands.NCERT Figs 10.1 and 10.2 · p. 293

Step 1, alpha-helix: a chain of residue dots winds up a vertical coil, about three and a half residues per turn, with the nearer half of each turn drawn darker. Dashed lines on the near face join residues to the one four places further along, so the hydrogen bonds run steeply up the helix, nearly parallel to its axis. Step 2, beta-pleated sheet: three zigzag strands lie side by side, with arrowheads showing that neighbouring strands run in opposite directions. Short dashed lines cross between neighbouring strands: the hydrogen bonds hold separate strands together.

The tertiary structure is the overall three-dimensional folding of a whole chain: its helices, sheets and loops packed together into a fibre or a globule. It is held by hydrogen bonds, disulfide bridges between cysteine side chains, attractions between oppositely charged side chains (salt bridges), and van der Waals forces between the many non-polar side chains, which cluster in the core, away from the water.

Many proteins are teams of several folded chains. Each chain is a subunit, and the way the subunits fit together is the quaternary structure; a protein with only one chain has none. Haemoglobin is the classic example: two α-chains and two β-chains, each folded around an iron-containing haem group, pack together into one oxygen-carrying unit.

Quick check
1 of 3
Put the levels of protein structure in order, simplest first.
  1. amino acid sequence
  2. subunits packed
  3. fold of one chain
  4. helix or sheet
Show answer
Answer
  1. amino acid sequence
  2. helix or sheet
  3. fold of one chain
  4. subunits packed
Primary (sequence), secondary (local helix or sheet), tertiary (overall fold of a chain), quaternary (arrangement of several chains).

10.2.4 Denaturation of Proteins

Crack an egg into a hot pan and the clear, runny white turns opaque and firm within seconds: its main protein, albumin, has been denatured. In a living cell each protein has one particular folded shape, its native state, held mostly by weak forces. Heat shakes the hydrogen bonds apart; a change of pH alters the charges on side chains and breaks salt bridges; alcohol, heavy-metal ions and concentrated salt solutions interfere too. The chain unravels, tangles with its neighbours and stops working. Only the covalent backbone survives: the peptide bonds, and so the primary structure, are untouched, while the secondary, tertiary and any quaternary structure are lost. This is denaturation (विकृतीकरण).

Definition
Denaturation

Loss of a protein's secondary, tertiary and quaternary structure, and of its biological activity, caused by heat, a change of pH or chemicals; the primary structure stays intact.

Exampleegg white setting when cooked

Kitchens are full of other examples. Squeeze lemon juice into hot milk and the acid makes the milk protein casein coagulate into paneer; when curd sets, bacteria do the same job slowly by turning lactose into lactic acid. A hair straightener works on the same principle, breaking hydrogen bonds in keratin so the hair can be reshaped. Most denaturation, like cooking an egg, cannot be undone.

Quick check
1 of 2
When an egg is boiled, which level of structure of its proteins is not destroyed?
Show answer

Answer (B) primary

Heat breaks the weak forces behind the secondary, tertiary and quaternary structure, but not the covalent peptide bonds, so the sequence survives.
Practice · 2 questions

Practice: proteins: questions with answers

  1. Short answerMediumNCERT Intext Question 10.4

    Glycine melts, with decomposition, at about 233 °C, while chloroacetic acid, a molecule of similar size with a –COOH group, melts at about 63 °C. Explain the difference, and predict which of the two dissolves better in benzene.

    Show solution

    AnswerGlycine is an ionic zwitterion; chloroacetic acid is molecular. Chloroacetic acid dissolves better in benzene.

    Solid glycine consists of HX3NX+CHX2COOX− zwitterions packed like the ions of a salt, so a lot of energy is needed to separate them; it decomposes before it melts cleanly. Chloroacetic acid has no basic group, so it cannot form a zwitterion; its molecules are held only by hydrogen bonds and dipole attractions, which give way at a far lower temperature. Benzene is non-polar and cannot surround charged ions, so the ionic glycine is practically insoluble in it, while molecular chloroacetic acid dissolves much better.

  2. Short answerEasyNCERT Intext Question 10.5

    A boiled egg weighs almost the same as the raw egg, yet its white is now solid and no liquid seems to be left. Where has the water gone?

    Show solution

    AnswerIt is trapped in the network of denatured protein.

    Heat denatures the albumin: the globules unfold and the chains bond to one another into a three-dimensional network. The water has not left. It is held inside this network, hydrogen-bonded to the protein chains, much as water is held in a set jelly, so the white looks and feels solid.

10.3 Enzymes

Chew a piece of plain bread for a minute and it starts to taste sweet: amylase in your saliva is already splitting its starch into maltose. In a flask the same breakdown needs boiling acid, yet your body runs thousands of such reactions at about 37 °C, close to pH 7 and in water. The difference is made by enzymes (एंज़ाइम): biological catalysts that speed up reactions enormously and are not used up, so a small amount does a great deal of work. Nearly all enzymes are globular proteins (a few are RNA molecules).

Definition
Enzyme

A biological catalyst, almost always a globular protein, that speeds up a specific reaction of a specific substrate.

Examplemaltase, which hydrolyses maltose

Enzymes are highly specific. Each one usually acts on one compound, its substrate, or on a small family of similar compounds, and it catalyses one kind of reaction. Most are named by adding -ase to the name of the substrate or of the reaction. Maltase hydrolyses maltose; sucrase, also called invertase, hydrolyses sucrose; lactase acts on lactose and urease on urea. Enzymes that catalyse redox reactions, oxidising one substrate while reducing another, are called oxidoreductases.

maltose → two glucose
CX12HX22OX11+HX2O→maltase2 CX6HX12OX6

10.3.1 Mechanism of Enzyme Action

Like any catalyst, an enzyme changes neither the overall energy change of a reaction nor its equilibrium position. It offers a different route with a lower activation energy (Fig. 10.15). First the substrate binds in a small pocket on the enzyme's surface, the active site, to form an enzyme–substrate complex. There, side chains hold the substrate in exactly the right orientation, strain the bonds that must break and pass protons on or take them away. Then the products leave and the enzyme is free for the next substrate molecule.

enzyme catalysis
E+S⇌ES→E+P
where
E
enzyme
S
substrate
ES
enzyme–substrate complex
P
products

2/4The substrate binds in the active site: the enzyme–substrate complex, a dip on the energy curve.

Fig. 10.15The enzyme gives a lower-energy route through the enzyme–substrate complex and comes out unchanged.NCERT 10.3.1 · p. 295

The top half is an energy graph. A dashed curve rises to a tall peak, labelled without enzyme; a solid curve has a small first hump, a shallow dip for the enzyme–substrate complex and a small second hump, labelled with enzyme. Both end at the same, lower product level. A dot moves along the solid curve. The bottom half shows a large blob, the enzyme, with a notch in its top: the active site. Step 1: a substrate made of two linked hexagons, like maltose, floats above the notch; the dot is at the start. Step 2: the substrate sits in the notch, forming the complex; the dot is in the dip. Step 3: the link between the hexagons has broken and the two product hexagons move away, leaving the enzyme unchanged; the dot is at the end. Step 4: two vertical arrows compare the heights of the two barriers: the barrier with the enzyme is much lower.

In 1894 Emil Fischer pictured the active site as a lock into which only the right key, the substrate, fits, which accounts for specificity. We now know that the fit is often induced: the enzyme changes shape a little as the substrate binds, closing around it like a hand around a ball. Because the active site depends on the folded shape of the protein, anything that denatures the enzyme, such as high temperature or the wrong pH, destroys its activity. Most human enzymes work best near 37 °C, but pepsin, which digests protein in the acidic stomach, works best near pH 2.

Example

How much faster?

At body temperature, 310 K, an enzyme lowers the activation energy of a reaction from 86 kJ/mol to 50 kJ/mol. Use R=8.314 J K−1 mol−1 and assume that the Arrhenius factor A is unchanged. By what factor does the rate constant increase?

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
An enzyme speeds up a reaction mainly by
Show answer

Answer (A) lowering the activation energy

A catalyst provides a route with a lower barrier. It changes neither the equilibrium position nor the overall energy change, and enzymes work at body temperature.

10.4 Vitamins

Sailors on long voyages once lost teeth and bled from the gums until it was noticed that lemons and limes prevented it. People who lived on polished rice developed weak, swollen legs and heart failure. Neither disease is caused by a germ. Each comes from the lack of a particular compound that the body needs in tiny amounts, a vitamin (विटामिन).

Vitamins are a chemically mixed bag (alcohols, amines, acids and ring compounds), so they are defined by their role rather than their structure: organic compounds that the body needs in tiny amounts but cannot make in sufficient quantity, and so must get from food. Each does a particular job, and a shortage shows up as a particular deficiency disease. Our own cells make a little vitamin D in skin exposed to sunlight, and gut bacteria supply some B vitamins and vitamin K; plants, by contrast, make nearly all of them, which is one reason fresh vegetables and fruit matter so much. Letters label them, A, B, C, D, E and K, and the B group divides further into B1, B2, B6, B12 and others.

Definition
Vitamin

An organic compound needed in small amounts, usually from the diet, for a specific function in the body; its lack causes a deficiency disease.

Examplevitamin C (ascorbic acid)

Too much can harm, too. Fat-soluble vitamins build up in the body, and large doses of vitamins A and D are poisonous, so supplements are for a doctor to prescribe, not for guesswork; a varied diet supplies what most people need.

10.4.1 Classification of Vitamins

Vitamins are grouped by whether they dissolve in fat or in water, and the grouping predicts how the body handles them (Fig. 10.16).

  • Fat-soluble: A, D, E and K. Insoluble in water, they travel with dietary fat into the body and are kept in reserve in the liver and in body fat, so a store can last for months, and so can an overdose.
  • Water-soluble: the B group and C. These dissolve in blood plasma, and whatever is surplus is filtered out by the kidneys into the urine. Vitamin B12 is the exception, stockpiled in the liver for years; the rest have to be eaten regularly.

3/4A, D, E and K go into the liver and fat tissue; spare B and C leave through the kidneys.

Fig. 10.16Fat-soluble vitamins are stored; water-soluble ones are washed out in urine, except B₁₂.

A flow diagram: food on the left, the bloodstream in the middle, a store labelled liver and fat tissue at the top right, and kidneys to urine at the bottom right. Fat-soluble vitamins A, D, E and K are orange circles inside an oil drop; water-soluble vitamins B and C are blue circles in water. Step 1: all six sit in the food. Step 2: all of them move into the blood. Step 3: A, D, E and K move up into the store, while the B and C circles flow down to the kidneys and out in urine. Step 4: a B12 circle moves into the liver store, labelled as the exception among water-soluble vitamins.

Table 10.5Some important vitamins, good food sources and deficiency diseasesNCERT Table 10.3 · p. 296
VitaminSourcesLack causes
A (retinol)carrots, ripe mango and papaya, spinach, milk, fish-liver oilnight blindness; xerophthalmia (dry eyes, damaged cornea)
B₁ (thiamine)whole grains, hand-pounded rice, pulses, groundnuts, yeastberiberi (nerve and heart damage, swelling of the legs)
B₂ (riboflavin)milk, curd, eggs, green leafy vegetablescheilosis (cracked lips and mouth corners), inflamed tongue
B₆ (pyridoxine)whole cereals, pulses, bananas, meatconvulsions (fits), especially in infants
B₁₂ (cobalamin)milk, curd, eggs, fish, meat (animal foods only)pernicious anaemia (large, immature red cells; tiredness)
C (ascorbic acid)amla, guava, citrus fruits, tomatoes, green chilliesscurvy (bleeding gums, slow wound healing)
D (calciferol)sunlight on the skin; egg yolk, oily fishrickets (soft, bowed legs) in children; osteomalacia (weak, painful bones) in adults
E (tocopherol)vegetable oils such as sunflower and wheat-germ oil, nuts, seedsred blood cells that burst easily; muscle weakness
K (phylloquinone)green leafy vegetables; also made by gut bacteriaslow blood clotting, easy bleeding
Flash cards · 9

Which vitamin is missing?

1 / 9
Quick check
1 of 3
Match each vitamin with the disease its lack causes.

Tap an item on the left, then its match on the right.

Show answer
Answer
  • B₁ : beriberi
  • C : scurvy
  • D : rickets
  • K : slow blood clotting
Thiamine (B₁) prevents beriberi, ascorbic acid (C) scurvy, vitamin D rickets, and vitamin K is needed to make clotting proteins.

10.5 Nucleic Acids

In 1869 Friedrich Miescher, working in Tübingen, washed white blood cells off used surgical bandages and extracted from their nuclei a new substance, rich in phosphorus and acidic. We now call it a nucleic acid. There are two kinds, deoxyribonucleic acid (DNA) and ribonucleic acid (RNA), and both are long chains of units called nucleotides, so they are also called polynucleotides.

Their most famous job is heredity, the passing of characteristics from one generation to the next. DNA, wound around proteins, makes up the chromosomes in the nucleus of every cell, and its sequence carries the instructions that make a child resemble its parents. How DNA is copied, read and controlled is the subject of Class 12 Biology, Chapter 5 (Molecular Basis of Inheritance). Here we look at the chemistry: what nucleic acids are made of and how the pieces are joined.

10.5.1 Chemical Composition of Nucleic Acids

Break a nucleic acid down completely with acid and you are left with just three kinds of molecule. One is phosphoric acid, HX3POX4. One is a five-carbon sugar: β-D-ribose if you started with RNA, β-D-2-deoxyribose if you started with DNA (deoxy because the –OH on C2 of ribose is replaced by H). The rest are flat, ring-shaped organic molecules rich in nitrogen, called bases.

Five bases occur in all. Adenine (A) and guanine (G) are purines, with two fused rings; cytosine (C), thymine (T) and uracil (U) are pyrimidines, with a single ring. Thymine turns up only in DNA and uracil only in RNA, while the other three are common to both (Table 10.6). A single methyl group is all that distinguishes thymine from uracil.

Table 10.6The bases of nucleic acids
Base (symbol)FamilyFound in
adenine (A)purine (two rings)DNA and RNA
guanine (G)purineDNA and RNA
cytosine (C)pyrimidine (one ring)DNA and RNA
thymine (T)pyrimidineDNA only
uracil (U)pyrimidineRNA only

10.5.2 Structure of Nucleic Acids

Think of the repeating unit as built in two moves (Fig. 10.17). First a base bonds to the sugar at C1′; to keep the sugar's atoms apart from the base's own numbering, the sugar carbons get a prime (1′ to 5′). Base plus sugar is a nucleoside. Second, phosphoric acid forms an ester with the –OH on C5′, and the nucleoside becomes a nucleotide (न्यूक्लियोटाइड).

Definition
Nucleotide

A base, a pentose sugar and a phosphate group joined together, with the base on C1′ and the phosphate on C5′ of the sugar; nucleic acids are chains of nucleotides.

Exampleadenosine monophosphate (AMP)

4/4The next nucleotide's phosphate bonds to the C3′ oxygen: a 3′–5′ phosphodiester link.

Fig. 10.17Base + sugar = nucleoside; + phosphate on C5′ = nucleotide; nucleotides join 3′ to 5′.NCERT Figs 10.5 and 10.6 · p. 298

A five-membered sugar ring is drawn with its ring oxygen at the top and its carbons numbered 1 prime on the right, 2 prime and 3 prime along the front, 4 prime on the left and 5 prime above 4 prime. Step 1: the sugar, a phosphate circle marked P and a box marked base are drawn apart; carbon 2 prime carries the label OH / H, for OH in RNA and H in DNA. Step 2: the base joins carbon 1 prime: a nucleoside. Step 3: the phosphate joins through an oxygen to carbon 5 prime: a nucleotide. Step 4: a second nucleotide appears below; its phosphate is bonded to the 3 prime oxygen of the upper sugar, forming a phosphodiester link. The top of the chain is labelled 5 prime end and the bottom 3 prime end.

Nucleotides link into a chain through their phosphate groups. The phosphate on C5′ of one nucleotide forms a second ester bond with the –OH on C3′ of the nucleotide before it, so each phosphate bridges two sugars in a phosphodiester linkage. The result is a repeating backbone, sugar–phosphate–sugar–phosphate, with a base hanging from every sugar. The two ends differ: one has a free phosphate on C5′ (the 5′ end) and the other a free –OH on C3′ (the 3′ end). A sequence is therefore read in a direction, usually 5′ → 3′, and the order of bases along the chain is the primary structure of the nucleic acid.

Watson and Crick's 1953 model gave DNA its famous secondary structure: two strands, running in opposite directions, twisted round a shared axis into a double helix, with the backbones outside and the bases stacked inside (Fig. 10.18). Only certain pairs of bases fit between the backbones, and they are held by hydrogen bonds: adenine with thymine (two bonds) and guanine with cytosine (three). Each pair joins a two-ring purine to a one-ring pyrimidine, so every rung of the ladder has the same width. The two strands are therefore not identical but complementary: the sequence of one fixes the sequence of the other.

2/4A pairs with T by two hydrogen bonds; G pairs with C by three.

Fig. 10.18A purine always pairs with a pyrimidine: A with T (two hydrogen bonds), G with C (three).NCERT Fig. 10.7 · p. 299

Step 1: base shapes. Purines adenine and guanine are drawn as a hexagon fused to a pentagon; pyrimidines cytosine, thymine and uracil as single hexagons. Step 2: pairs. Adenine faces thymine with two dashed hydrogen bonds, and guanine faces cytosine with three; both pairs are the same total width. Step 3: a straight ladder with two backbones, the left running 5 prime to 3 prime downwards and the right 3 prime to 5 prime, and five base-pair rungs. Step 4: the same two strands twisted into a double helix, the backbones crossing over each other with the rungs between them.

Example

Using base pairing

(a) In a sample of double-stranded DNA from a bacterium, 18 % of the bases are adenine. What percentages are thymine, guanine and cytosine? (b) One strand has the sequence 5′-AGCTTAGC-3′. Write the complementary strand, also from 5′ to 3′.

Try it yourself first. Then reveal the solution one step at a time.

RNA is usually a single strand. Parts of it fold back on themselves wherever short stretches of bases can pair, forming hairpins and loops; in RNA, uracil pairs with adenine. Because the strand has no partner strand, RNA shows no fixed ratio between its bases. Cells make three main kinds of RNA:

  • messenger RNA (mRNA) carries a copy of a gene's instructions from the DNA to the ribosomes;
  • ribosomal RNA (rRNA) makes up most of the ribosome, the machine that joins amino acids into proteins;
  • transfer RNA (tRNA) brings each amino acid to the ribosome and matches it to the instructions on the mRNA.

10.5.3 Biological Functions of Nucleic Acids

Every cell in your body carries the same DNA, a copy of a copy made at each of trillions of cell divisions. That faithful copying is what heredity rests on. Before a cell divides, the two strands of each DNA molecule part, every exposed base picks up its partner, and two identical double helices result, one for each daughter cell. Over many generations the same mechanism keeps a species recognisably itself.

Most of DNA's instructions are instructions for proteins, yet DNA never makes a protein itself. A gene's sequence is first copied into mRNA; at the ribosome, whose core is rRNA, tRNA molecules read the mRNA three bases at a time and deliver the matching amino acids, which are joined by peptide bonds. The details belong to biology, but the chemistry you have just met, base pairing and the peptide bond, is what makes them possible.

Quick check
1 of 4
A nucleoside differs from a nucleotide in that the nucleoside
Show answer

Answer (C) has no phosphate group

Nucleoside = base + sugar; nucleotide = base + sugar + phosphate. Both can contain ribose or deoxyribose.

10.6 Hormones

Get a sudden fright and within seconds your heart races and your muscles receive extra fuel. Part of that response is carried not by nerves but by a chemical released into the blood. Such messengers are hormones (हॉर्मोन): molecules secreted by the endocrine glands (the pancreas, thyroid, adrenal glands and others) straight into the bloodstream, which delivers them all over the body; only target cells with the matching receptor respond. Tiny amounts are enough.

Definition
Hormone

A messenger molecule made by an endocrine gland and carried in the blood to target cells, where it controls a particular process.

Exampleinsulin, thyroxine, testosterone

Chemically, hormones belong to three families:

Compare

Three chemical families of hormones

Steroids

  • four fused carbon rings, made from cholesterol
  • estrogens (estradiol), androgens (testosterone), progesterone, cortisol

Peptides and proteins

  • chains of amino acids
  • insulin, glucagon, endorphins, growth hormone

Amino acid derivatives

  • small molecules made from one amino acid
  • epinephrine (adrenaline), norepinephrine, thyroxine

A central job of hormones is to keep conditions in the body steady, and blood glucose is a good example (Fig. 10.19). After a meal, glucose floods into the blood and the pancreas releases insulin. Insulin lets muscle and fat cells take glucose in and makes the liver store it as glycogen, so the level falls back. Between meals, when the level drops, the pancreas releases glucagon, which makes the liver break down glycogen and release glucose. Pulling in opposite directions, the two hormones keep blood glucose within narrow limits; in diabetes this control fails.

2/4Glucose rises; insulin makes cells take it up and the liver store it as glycogen.

Fig. 10.19Insulin lowers blood glucose and glucagon raises it; together they hold it steady.

A vertical gauge on the left shows the blood glucose level, with a shaded band for the normal range. In the middle is the pancreas, and on the right the liver and body cells. Step 1: the level sits inside the band. Step 2: after a meal the level is above the band; an arrow labelled insulin runs from the pancreas to the liver and cells, and glucose dots move into the liver to be stored as glycogen. Step 3: between meals the level is below the band; an arrow labelled glucagon runs from the pancreas to the liver, and glucose dots move out of the liver into the blood. Step 4, diabetes: the level is far above the band and the insulin arrow is crossed out, so glucose is not taken up.

Other hormones prepare the body for action or steer its development. Epinephrine and norepinephrine (adrenaline and noradrenaline) from the adrenal glands produce the fight-or-flight response to a sudden stimulus: a faster heartbeat and more glucose in the blood. Growth hormone and the sex hormones control growth and development.

Thyroxine, from the thyroid gland in the neck, is a derivative of the amino acid tyrosine that carries four iodine atoms; it sets the pace of the body's metabolism. Too little causes hypothyroidism, with tiredness, sluggishness and weight gain, and too much causes hyperthyroidism. A diet short of iodine starves the thyroid of raw material, so it becomes underactive and swells into a goitre.

Steroid hormones come from the adrenal glands and the gonads. The outer layer of each adrenal gland, the cortex, makes two kinds. One kind, typified by cortisol, raises blood glucose by making new glucose from other molecules, calms inflammation (which is why cortisone-type creams soothe rashes) and helps you weather physical stress. The other, typified by aldosterone, tells the kidneys how much sodium and water to hold back, and so helps set blood pressure. When the adrenal cortex is destroyed, both are lost and the result is Addison's disease: blood sugar runs low, muscles feel weak, and an illness or injury that others shrug off can become life-threatening. Daily replacement of both kinds of hormone keeps patients well.

At puberty the gonads (testes or ovaries) step up production of their own steroids. Testosterone drives the male changes, such as a deeper voice and facial hair. Estradiol drives the female changes and, with progesterone, runs the monthly cycle; progesterone's special task is to ready the lining of the uterus for a fertilised egg.

Quick check
1 of 3
Which pair of hormones acts in opposite directions on blood glucose?
Show answer

Answer (A) insulin and glucagon

Insulin lowers blood glucose and glucagon raises it. Epinephrine and norepinephrine work together in the fight-or-flight response.
Practice · 3 questions

Practice: vitamins, nucleic acids and hormones: questions with answers

  1. Short answerEasyNCERT Intext Question 10.6

    A student swallows one large vitamin C tablet each Sunday instead of eating fruit and vegetables during the week. Why is this a poor plan?

    Show solution

    AnswerVitamin C is water-soluble and not stored; the excess is lost in urine.

    Vitamin C dissolves in water, so whatever the body cannot use soon after the tablet is filtered out by the kidneys and leaves in the urine; it is not stored. By midweek the level will have fallen again. Water-soluble vitamins need a regular daily supply from the diet.

  2. Short answerEasyNCERT Intext Question 10.7

    A DNA nucleotide containing the base cytosine is hydrolysed completely. Name the three products.

    Show solution

    AnswerCytosine, 2-deoxy-D-ribose and phosphoric acid.

    A nucleotide is a base, a sugar and a phosphate. Complete hydrolysis breaks the bond between the base and C1′ and the ester bond at C5′, giving cytosine, the DNA sugar β-D-2-deoxyribose, and phosphoric acid, HX3POX4.

  3. Short answerMediumNCERT Intext Question 10.8

    Analysis of any double-stranded DNA gives equal amounts of A and T, and of G and C. Analysis of a typical RNA gives four amounts with no such relation. What does this suggest about the structure of RNA?

    Show solution

    AnswerRNA is single-stranded.

    In DNA the equalities come from complementary pairing between two strands: every A on one strand faces a T on the other, and every G faces a C. RNA shows no such ratios, so it cannot consist of two fully paired strands; it is a single strand, paired only in short stretches where it folds back on itself.

Recap

Biomolecules: key points and summary

  1. A carbohydrate is a polyhydroxy aldehyde or ketone (optically active) or a compound that hydrolyses into such units; fitting CXx(HX2O)Xy proves nothing (Section 10.1).
  2. By hydrolysis they are monosaccharides, oligosaccharides (2–10 units) or polysaccharides; sugars that reduce Tollens' or Fehling's reagent are reducing sugars (Section 10.1.1).
  3. Monosaccharides are named by carbonyl group and carbon count: glucose is an aldohexose, fructose a ketohexose (Section 10.1.2).
  4. Reactions reveal the open chain of glucose, OHC−(CHOH)X4−CHX2OH in condensed form, and it is D because the –OH on C5 lies on the right, as in D-glyceraldehyde (Section 10.1.2.1).
  5. The C5–OH adds to C1, giving six-membered α and β pyranose rings (anomers) in equilibrium with a trace of open chain; fructose closes C5 to C2 into furanose rings (Section 10.1.2.2).
  6. Glycosidic linkages join sugar units; sucrose (C1–C2) is non-reducing and inverts on hydrolysis, while maltose and lactose keep a free anomeric carbon and are reducing (Section 10.1.3).
  7. Starch (amylose + amylopectin) and glycogen store α-glucose; cellulose, β(1→4)-linked straight chains, builds plant cell walls (Section 10.1.4).
  8. Proteins are polymers of about twenty α-amino acids; amino acids exist as zwitterions, are amphoteric and, except glycine, optically active (mostly L) (Section 10.2.2).
  9. Essential amino acids must come from the diet; non-essential ones are made in the body (Section 10.2.2).
  10. Peptide bonds, –CO–NH–, join amino acids; protein structure is described as primary, secondary (α-helix, β-sheet), tertiary and quaternary (Section 10.2.3).
  11. Denaturation by heat or pH destroys the higher levels of structure and the activity, but not the sequence (Section 10.2.4).
  12. Enzymes are specific protein catalysts that lower activation energy through an enzyme–substrate complex (Section 10.3.1).
  13. Vitamins A, D, E and K are fat-soluble and stored; B and C are water-soluble and must be eaten regularly; each deficiency causes a specific disease (Section 10.4.1).
  14. Nucleic acids are polynucleotides of a base, a pentose and phosphate; DNA (deoxyribose; A, G, C, T) is a double helix with A–T and G–C pairing, RNA (ribose; U for T) is single-stranded; hormones are steroid, peptide or amino-acid messengers (Section 10.5.2, Section 10.6).
Practice · 30 questions

Practice questions with answers (NCERT “Exercises”)

  1. Short answerEasyNCERT Exercises Q10.1

    What makes a carbohydrate a monosaccharide? Name one aldose and one ketose.

    Show solution

    AnswerIt cannot be hydrolysed further. E.g. glucose, fructose.

    A monosaccharide is the simplest carbohydrate: a polyhydroxy aldehyde or ketone that cannot be hydrolysed into anything simpler of the same kind. Glucose (or ribose, galactose) is an aldose; fructose (or ribulose) is a ketose.

  2. Short answerEasyNCERT Exercises Q10.2

    Which of these give a silver mirror with Tollens' reagent: glucose, fructose, sucrose, maltose? What do the ones that do have in common?

    Show solution

    AnswerGlucose, fructose and maltose: all are reducing sugars.

    Glucose, fructose and maltose reduce Tollens' reagent; sucrose does not. All monosaccharides are reducing sugars (fructose too, because it rearranges to aldoses in alkali), and maltose keeps one free anomeric carbon whose ring can open to an aldehyde. In sucrose both anomeric carbons are tied up in the glycosidic link, so no ring can open. Sugars that reduce these reagents are called reducing sugars.

  3. Short answerEasyNCERT Exercises Q10.3

    A tree uses carbohydrates in two very different ways. Name the main carbohydrate for each use and say why its structure suits the job.

    Show solution

    AnswerStarch for storage; cellulose for structure.

    Storage: starch, a compact, branched, insoluble polymer of α-glucose, packs a lot of glucose into a small space, and enzymes can quickly release it again.

    Structure: cellulose, unbranched β(1→4) chains that lie straight and hydrogen-bond into strong, insoluble fibres, forms the cell walls that support the plant.

  4. Quick answerEasyNCERT Exercises Q10.4

    Which of these are disaccharides?

    Select all that apply
    Show answer
    Answer
    • (A) sucrose
    • (D) lactose
    • (F) maltose
    Sucrose, lactose and maltose each hydrolyse to two monosaccharide units. Glucose, 2-deoxyribose and galactose are monosaccharides.
  5. Short answerEasyNCERT Exercises Q10.5

    What is a glycosidic linkage? In maltose, which carbons does it join?

    Show solution

    AnswerA C–O–C link between sugar units; C1 and C4 in maltose.

    A glycosidic linkage is the oxygen bridge, C–O–C, that joins two monosaccharide units; it forms with the loss of a water molecule, and at least one of the joined carbons is an anomeric carbon. In maltose it joins C1 of one α-D-glucose unit to C4 of the other: an α(1→4) linkage.

  6. Short answerMediumNCERT Exercises Q10.6

    A liver cell stores glucose as glycogen, a potato cell as starch. Give two structural differences between these stores and explain why heavy branching suits an animal.

    Show solution

    AnswerGlycogen is one polymer, more branched than amylopectin; many chain ends release glucose fast.

    Starch is a mixture of unbranched amylose and branched amylopectin (a branch every 20–30 units). Glycogen is a single polymer, built like amylopectin but much more highly branched (a branch every 8–12 units). Both use α(1→4) chains with α(1→6) branches.

    An animal often needs glucose quickly, for example in a running muscle. Enzymes remove glucose units from chain ends, and the many branches of glycogen give many ends to work on at once.

  7. Short answerEasyNCERT Exercises Q10.7

    Name the products, with their mole ratio, when (i) cane sugar and (ii) milk sugar are completely hydrolysed. Which of the two product mixtures turns plane-polarised light to the left?

    Show solution

    Answer(i) Glucose + fructose, 1 : 1, laevorotatory. (ii) Galactose + glucose, 1 : 1.

    (i) Sucrose gives D-glucose and D-fructose in a 1 : 1 ratio. Because fructose's laevorotation (−92.4°) outweighs glucose's dextrorotation (+52.7°), this mixture, invert sugar, is laevorotatory.

    (ii) Lactose gives D-galactose and D-glucose in a 1 : 1 ratio.

  8. Short answerMediumNCERT Exercises Q10.8

    Starch and cellulose are both polymers of glucose. What is the key structural difference, and what does it mean for (a) the shape of the chains and (b) digestion by humans?

    Show solution

    Answerα links in starch, β links in cellulose.

    Starch is built from α-D-glucose joined by α(1→4) links (with α(1→6) branches in amylopectin); cellulose is built from β-D-glucose joined by β(1→4) links.

    (a) α links make amylose coil into a helix, while β links keep cellulose chains straight, so they pack side by side into hydrogen-bonded fibres.

    (b) Human digestive enzymes cut α links but not β links, so we digest starch, while cellulose passes through as fibre.

  9. Short answerMediumNCERT Exercises Q10.9

    What is formed when D-glucose reacts with each reagent, and what does each result tell us about its structure?

    1. Bromine water

      Show solution

      AnswerGluconic acid: an aldehyde group.

      Gluconic acid, HOCHX2–(CHOH)X4–COOH. The mild oxidant turns –CHO into –COOH without losing a carbon, so the carbonyl group is an aldehyde.

    2. Hydroxylamine

      Show solution

      AnswerAn oxime: a carbonyl group.

      Glucose oxime. Hydroxylamine reacts with carbonyl groups, so glucose has a C=O group.

    3. Nitric acid

      Show solution

      AnswerSaccharic acid: a primary alcohol at C6.

      Saccharic acid, HOOC–(CHOH)X4–COOH. Both ends become –COOH, so C6 carries a primary alcohol group, –CH₂OH.

    4. HI, on long heating

      Show solution

      Answern-Hexane: an unbranched chain.

      The product, CHX3(CHX2)X4CHX3 or n-hexane, shows that all six carbons form one unbranched chain.

  10. Short answerHardNCERT Exercises Q10.10

    The open-chain formula of glucose fails to account for some of its behaviour. Describe three such observations and show how the ring structure accounts for each.

    Show solution

    AnswerSchiff's/NaHSO₃ tests, pentaacetate vs NH₂OH, α and β forms.

    (1) Glucose gives no Schiff's test and no hydrogensulfite addition product: almost all of it is in the ring form, and these slow tests detect too little open-chain aldehyde.

    (2) Glucose pentaacetate does not react with hydroxylamine: the acetyl group on C1 locks the ring, so no –CHO group can form.

    (3) Glucose exists as two crystalline forms, α and β, with different melting points and rotations: ring closure makes C1 a stereocentre, and the two anomers are these two forms. In water they interconvert through the open chain (mutarotation).

  11. Short answerEasyNCERT Exercises Q10.11

    Distinguish essential from non-essential amino acids and name two of each. Why does dal eaten with rice give better protein than rice alone?

    Show solution

    AnswerEssential: lysine, valine. Non-essential: glycine, alanine.

    Essential amino acids cannot be made by the body (or not fast enough) and must come from the diet, e.g. lysine, valine, leucine, tryptophan. Non-essential amino acids are made in the body, e.g. glycine, alanine, serine, glutamic acid.

    Rice, like other cereals, is short of lysine, while pulses are rich in it (and short of methionine, which rice supplies). Eaten together they provide all the essential amino acids.

  12. Short answerEasyNCERT Exercises Q10.12

    Explain each term with an example.

    1. Peptide bond

      Show solution

      AnswerThe amide link –CO–NH– between residues.

      The amide link, –CO–NH–, formed when the –COOH of one amino acid condenses with the −NHX2 of another, with loss of water. Example: the bond joining alanine to glycine in Ala-Gly.

    2. Primary structure

      Show solution

      AnswerThe sequence of amino acids.

      The order of amino acids in a polypeptide chain, read from the N-terminus. Example: replacing one glutamic acid by valine in haemoglobin's β-chain changes the protein (sickle-cell haemoglobin).

    3. Denaturation

      Show solution

      AnswerLoss of folded shape and activity.

      Loss of a protein's secondary, tertiary and quaternary structure, and of its activity, caused by heat, a pH change or chemicals; the sequence is unchanged. Example: egg white setting when cooked.

  13. Short answerEasyNCERT Exercises Q10.13

    Name and describe the two common kinds of secondary structure in proteins.

    Show solution

    AnswerThe α-helix and the β-pleated sheet.

    α-Helix: the chain twists into a right-handed coil; the C=O of each residue hydrogen-bonds to the N–H four residues further on, so the bonds run along the axis.

    β-Pleated sheet: chains stretched almost straight lie side by side, held by hydrogen bonds between neighbouring strands, and the sheet is pleated.

  14. Quick answerEasyNCERT Exercises Q10.14

    The α-helix of proteins is stabilised mainly by

    Show answer

    Answer (A) hydrogen bonds between backbone C=O and N–H groups

    Each C=O is hydrogen-bonded to the N–H four residues along. Disulfide bridges and ionic attractions mainly hold tertiary structure; peptide bonds join residues along the chain, not across turns.
  15. Short answerEasyNCERT Exercises Q10.15

    Contrast fibrous and globular proteins, giving two examples of each.

    Show solution

    AnswerFibrous: keratin, myosin. Globular: insulin, albumin.

    Fibrous proteins have long chains lying side by side, joined by hydrogen bonds and disulfide bridges; they are insoluble in water and do structural jobs. Examples: keratin, collagen, myosin.

    Globular proteins have chains folded into compact, roughly spherical shapes; they are usually water-soluble and do working jobs such as catalysis and transport. Examples: insulin, albumins, haemoglobin, enzymes.

  16. Short answerHardNCERT Exercises Q10.16

    Show how the zwitterion of alanine reacts with (a) HX+ and (b) OHX−. Why is alanine called amphoteric?

    Show solution

    AnswerIt reacts with both acids and bases.

    The zwitterion is HX3NX+−CH(CHX3)–COOX−.

    (a) With acid, the –COO⁻ end accepts H⁺: the product is the cation HX3NX+−CH(CHX3)–COOH.

    (b) With base, the −NHX3X+ end gives up H⁺ to OH⁻, forming water and the anion HX2N−CH(CHX3)–COOX−.

    Because it reacts with both acids and bases, alanine is amphoteric.

  17. Short answerEasyNCERT Exercises Q10.17

    What are enzymes? Give two ways in which they differ from typical laboratory catalysts.

    Show solution

    AnswerProtein biocatalysts; highly specific, work under mild conditions.

    Enzymes are biological catalysts, nearly always globular proteins, that speed up reactions in living things by lowering the activation energy.

    Unlike most laboratory catalysts they are highly specific (one substrate, one reaction), and they work under mild conditions (about 37 °C, near neutral pH) and are destroyed by heat or extreme pH, because these denature them.

  18. Short answerEasyNCERT Exercises Q10.18

    A protein solution is heated to 90 °C. Which levels of structure are affected, which survive, and why is the protein's activity lost?

    Show solution

    Answer2°, 3° and 4° are lost; 1° survives.

    Heat breaks the hydrogen bonds and other weak forces, so the secondary, tertiary and any quaternary structure are destroyed: helices uncoil and globules unfold. The peptide bonds are covalent and survive, so the primary structure is unchanged. Activity depends on the exact folded shape (for an enzyme, the shape of its active site), so it is lost.

  19. Short answerEasyNCERT Exercises Q10.19

    Vitamins A and C behave very differently in the body.

    1. What property is used to divide vitamins into two groups, and which group does each of A and C belong to?

      Show solution

      AnswerSolubility: A is fat-soluble, C is water-soluble.

      By solubility in fat or water. Vitamin A belongs to the fat-soluble group (A, D, E, K); vitamin C belongs to the water-soluble group (the B vitamins and C).

    2. A patient's blood takes unusually long to clot. Which vitamin might be lacking?

      Show answer

      Answer (C) vitamin K

      Vitamin K is needed to make clotting proteins; without it blood takes longer to clot.
  20. Short answerEasyNCERT Exercises Q10.20

    What goes wrong in the body without vitamin A, and without vitamin C? For each, suggest two foods from an Indian kitchen that would prevent it.

    Show solution

    AnswerA: vision, eyes (carrots, mango). C: gums, healing (amla, guava).

    Vitamin A keeps the eyes healthy; without it we suffer night blindness and xerophthalmia. Sources: carrots, ripe mango or papaya, spinach, milk.

    Vitamin C keeps gums and skin healthy and helps wounds heal; without it we develop scurvy. Sources: amla, guava, oranges and other citrus fruits, tomatoes.

  21. Short answerEasyNCERT Exercises Q10.21

    Describe what a nucleic acid molecule is built from, and name two jobs that nucleic acids do in a cell.

    Show solution

    AnswerPolynucleotides; heredity and protein synthesis.

    Nucleic acids (DNA and RNA) are polymers of nucleotides, each made of a base, a pentose sugar and a phosphate group.

    Functions: DNA stores hereditary information and copies itself so that each daughter cell gets the same instructions; RNA uses the information in DNA to make proteins.

  22. Short answerEasyNCERT Exercises Q10.22

    Distinguish a nucleoside from a nucleotide, with an example of each.

    Show solution

    AnswerNucleoside = base + sugar; nucleotide = + phosphate.

    A nucleoside is a base joined to C1′ of a pentose sugar, e.g. adenosine (adenine + ribose). A nucleotide is a nucleoside with a phosphate group esterified at C5′, e.g. adenosine monophosphate, AMP.

  23. Short answerHardNCERT Exercises Q10.23

    A student says that the two strands of a DNA molecule must be identical copies of each other. Correct the statement, using the strand 5′-GATTC-3′ to show what its partner looks like.

    Show solution

    AnswerPartner: 5′-GAATC-3′.

    Hydrogen bonds form only between A and T and between G and C, so the base on one strand fixes the base opposite it. The strands also run in opposite directions.

    Opposite 5′-GATTC-3′ lies 3′-CTAAG-5′, which read 5′ to 3′ is 5′-GAATC-3′. This is a different sequence from the first strand, yet completely determined by it: the strands are complementary.

  24. Short answerEasyNCERT Exercises Q10.24

    Compare DNA and RNA under four headings: sugar, bases, number of strands and main job.

    Show solution

    AnswerSugar, base (T/U), strands, function.

    Sugar: DNA has 2-deoxyribose; RNA has ribose.

    Bases: both have A, G and C; DNA has thymine, RNA has uracil.

    Strands: DNA is a double helix of two complementary strands; RNA is usually a single strand.

    Function: DNA stores hereditary information and copies itself; RNA (mRNA, tRNA, rRNA) carries out protein synthesis.

  25. Short answerEasyNCERT Exercises Q10.25

    Name the three kinds of RNA in a cell and the job of each.

    Show solution

    AnswermRNA, rRNA, tRNA.

    Messenger RNA (mRNA) carries the instructions for a protein from DNA to the ribosome; ribosomal RNA (rRNA) forms most of the ribosome; transfer RNA (tRNA) brings amino acids to the ribosome and matches them to the mRNA.

  26. Quick answerEasy

    How many peptide bonds are there in a pentapeptide?

    Show answer

    Answer 4

    n residues are joined by n − 1 bonds: 5 − 1 = 4.
  27. Quick answerEasy

    Every sugar of the D series is dextrorotatory.

    Show answer

    Answer False

    False. D refers to configuration; the sign of rotation must be measured. D-fructose, for example, is laevorotatory.
  28. Quick answerMedium

    What is the molar mass of the dipeptide Gly-Gly, in g/mol? (Glycine 75.07, water 18.02 g/mol.)

    g/mol
    Show answer

    Answer 132.12 g/mol

    2(75.07)−18.02=132.12 g/mol.
  29. Quick answerEasy

    Which of these hormones are steroids?

    Select all that apply
    Show answer
    Answer
    • (A) testosterone
    • (C) cortisol
    • (E) estradiol
    Testosterone, cortisol and estradiol are steroids. Insulin is a peptide, and thyroxine is made from the amino acid tyrosine.
  30. Quick answerMedium

    In a double-stranded DNA, 42% of the bases are G + C together. What percentage of the bases is thymine?

    %
    Show answer

    Answer 29 %

    A + T = 100 − 42 = 58%, and A = T, so T = 29%.

Find your NCERT exercise question

Our practice questions are written for ncert.ai and follow the NCERT exercises. Find the one that matches the question in your textbook; its answer is with it.

In your NCERT textbookPractice question here
NCERT Intext Question 10.1Practice: carbohydrates · Q1
NCERT Intext Question 10.2Practice: carbohydrates · Q2
NCERT Intext Question 10.3Practice: carbohydrates · Q3
NCERT Intext Question 10.4Practice: proteins · Q1
NCERT Intext Question 10.5Practice: proteins · Q2
NCERT Intext Question 10.6Practice: vitamins, nucleic acids and hormones · Q1
NCERT Intext Question 10.7Practice: vitamins, nucleic acids and hormones · Q2
NCERT Intext Question 10.8Practice: vitamins, nucleic acids and hormones · Q3
NCERT Exercises Q10.1Exercises · Q1
NCERT Exercises Q10.2Exercises · Q2
NCERT Exercises Q10.3Exercises · Q3
NCERT Exercises Q10.4Exercises · Q4
NCERT Exercises Q10.5Exercises · Q5
NCERT Exercises Q10.6Exercises · Q6
NCERT Exercises Q10.7Exercises · Q7
NCERT Exercises Q10.8Exercises · Q8
NCERT Exercises Q10.9Exercises · Q9
NCERT Exercises Q10.10Exercises · Q10
NCERT Exercises Q10.11Exercises · Q11
NCERT Exercises Q10.12Exercises · Q12
NCERT Exercises Q10.13Exercises · Q13
NCERT Exercises Q10.14Exercises · Q14
NCERT Exercises Q10.15Exercises · Q15
NCERT Exercises Q10.16Exercises · Q16
NCERT Exercises Q10.17Exercises · Q17
NCERT Exercises Q10.18Exercises · Q18
NCERT Exercises Q10.19Exercises · Q19
NCERT Exercises Q10.20Exercises · Q20
NCERT Exercises Q10.21Exercises · Q21
NCERT Exercises Q10.22Exercises · Q22
NCERT Exercises Q10.23Exercises · Q23
NCERT Exercises Q10.24Exercises · Q24
NCERT Exercises Q10.25Exercises · Q25

Quick check: MCQs on Biomolecules

  1. 10.1.1 Classification of Carbohydrates3 questions
  2. 10.1.2.2 Fructose4 questions
  3. 10.1.3 Disaccharides3 questions
  4. 10.1.4 Polysaccharides3 questions
  5. 10.2.2 Classification of Amino Acids4 questions
  6. 10.2.3 Structure of Proteins3 questions
  7. 10.2.4 Denaturation of Proteins2 questions
  8. 10.3.1 Mechanism of Enzyme Action3 questions
  9. 10.4.1 Classification of Vitamins3 questions
  10. 10.5.3 Biological Functions of Nucleic Acids4 questions
  11. 10.6 Hormones3 questions
Glossary · 15

Key terms (English–Hindi)

anomerऐनोमरainomar
One of two cyclic forms of a sugar that differ only in configuration at the anomeric carbon (C1 of glucose).First seen in the chapter →
carbohydrateकार्बोहाइड्रेटkaarbohaaidret
An optically active polyhydroxy aldehyde or ketone, or a compound that hydrolyses to such units.First seen in the chapter →
denaturationविकृतीकरणvikriteekaran
Loss of a protein's folded shape and activity through heat, pH change or chemicals; the sequence stays intact.First seen in the chapter →
enzymeएंज़ाइमenzaaim
A biological catalyst, almost always a globular protein, specific for its substrate and reaction.First seen in the chapter →
essential amino acidआवश्यक ऐमीनो अम्लaavashyak aimeeno amla
An amino acid the body cannot make in enough amount, so it must come from food.First seen in the chapter →
glycosidic linkageग्लाइकोसाइडी बंधglaaikosaaidee bandh
The C–O–C bridge joining two sugar units, formed with loss of water.First seen in the chapter →
hormoneहॉर्मोनhormon
A chemical messenger made by an endocrine gland and carried in the blood to target cells.First seen in the chapter →
invert sugarअपवृत्त शर्कराapavritt sharkara
The laevorotatory equimolar mixture of glucose and fructose obtained by hydrolysing sucrose.First seen in the chapter →
monosaccharideमोनोसैकेराइडmonosaikeraaid
A carbohydrate that cannot be hydrolysed into a simpler sugar, such as glucose or fructose.
nucleotideन्यूक्लियोटाइडnyookliyotaaid
A base, a pentose sugar and a phosphate joined together; the unit of DNA and RNA.First seen in the chapter →
peptide bondपेप्टाइड आबंधpeptaaid aabandh
The amide link –CO–NH– joining two amino acids in a peptide or protein.First seen in the chapter →
reducing sugarअपचायी शर्कराapachaayee sharkara
A sugar that reduces Tollens' reagent and Fehling's solution because it has, or can open to give, a free carbonyl group.First seen in the chapter →
vitaminविटामिनvitaamin
An organic compound needed in small amounts in the diet; its lack causes a deficiency disease.First seen in the chapter →
zwitterionज़्विटर आयनzvitar aayan
A dipolar ion with −NHX3X+ and −COO− groups, neutral overall.First seen in the chapter →
α-amino acidऐमीनो अम्लaimeeno amla
A compound with −NHX2 and −COOH on the same carbon; the building unit of proteins.First seen in the chapter →

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