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MathematicsCh 10 Circles

Circles: Class 10 Maths · Chapter 10

Mathematics · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 50 min
  • 1 simulation
  • 25 practice questions
  • 10 MCQs

What you will learn in Circles

  • Decide whether a line is a non-intersecting line, a secant or a tangent to a circle, by counting common points or by comparing its distance from the centre with the radius.
  • Describe a tangent as the limiting position of a secant, and explain why a circle has exactly one tangent at each point and at most two tangents parallel to a given line.
  • Prove that the radius to the point of contact is perpendicular to the tangent, and use this right angle with Pythagoras theorem to find lengths.
  • State how many tangents pass through a point inside a circle, on it and outside it.
  • Prove that the two tangents from an external point are equal, and that the line from that point to the centre bisects the angle between them.
  • Solve board-style problems on tangent lengths, angles between tangents, concentric circles, and triangles and quadrilaterals drawn around a circle.

Original companion text aligned to NCERT Mathematics Class 10, Chapter 10, pp. 144–153. Not affiliated with or endorsed by NCERT.

10.1 Introduction

Watch a kite flyer on Makar Sankranti letting out string. The thread unwinds from the round firki and leaves it in a straight line that only grazes the rim. Lines like that, which brush a circle at one point, are what this chapter is about.

So here is the first question: how many points can a straight line and a circle have in common? To answer it you need only the Class 9 picture of a circle (वृत्त): each of its points is exactly r from the centre O, where r is the radius. Chords and arcs, which you met there, will turn up again along the way.

Lay a bangle flat on your desk and slide a ruler towards it, keeping the edge straight. Think of the edge as a line and the bangle as a circle (Fig. 10.1). Three things can happen, one after another:

  1. The edge misses the bangle. Line and circle have no point in common. The line is a non-intersecting line for this circle.
  2. The edge just grazes the bangle. They share exactly one point. The line is a tangent (स्पर्श रेखा) to the circle.
  3. The edge cuts across the bangle. They share two points. The line is a secant (छेदक रेखा) of the circle.

2/3When d=r the line meets the circle at one point T: a tangent.

Fig. 10.1As a line moves towards a circle, the number of common points goes 0, 1, 2.NCERT Fig. 10.1 · p. 144

A circle with centre O and a radius r is drawn on the left, and a vertical line stands to its right. In the first step the line is far away: its distance d from O, shown by a dashed segment, is more than r, and the panel reads Misses, d > r, 0 points. In the second step the line has slid closer until d equals r; it touches the circle at one point T, and the panel reads Tangent, d = r, 1 point. In the third step the line has moved further in, d is less than r, it crosses the circle at A and B, and the panel reads Secant, d < r, 2 points.

Could a line meet a circle in three points, or more? No. In Class 9 you saw that three points on one straight line never lie on a circle. So a line and a circle share at most two points, and the three cases above are the only ones possible.

The figure also gives a quick test. Let d be the perpendicular distance from the centre O to the line, and r the radius. If d>r the line misses the circle; if d=r it touches it; if d<r it cuts it twice. You will see the reason in Section 10.2.

Quick check
1 of 3
A circle has radius 5 cm, and a line is 3 cm from its centre. What is the line?
Show answer

Answer (A) a secant

d=3<5=r, so the line cuts the circle twice: a secant. A tangent needs d=r exactly.

10.2 Tangent to a Circle

Definition
Tangent

A tangent to a circle is a straight line that has exactly one point in common with the circle.

ExampleThe kite string at the point where it leaves the firki.

Two questions follow at once. Does every point of a circle have a tangent through it? And could one point have two different tangents? A small experiment answers both.

4/4Q has merged with P: the line meets the circle only at P. It is the tangent at P.

Fig. 10.2As the line turns about P, the second point Q slides into P.NCERT Fig. 10.3 (i) · p. 145

A circle with centre O and a point P at its lowest point. A straight line passes through P. In the first step it rises steeply and cuts the circle again at a point Q far from P; the chord PQ is highlighted and the corner reads 2 points in common. In the second and third steps the line has turned towards the horizontal and Q has slid much closer to P, so the highlighted chord is shorter. In the fourth step the line is horizontal, Q has merged with P, the line is labelled tangent, and the corner reads Only P in common.

A second experiment looks at a whole family of parallel lines instead of lines through one point.

3/3At 5 cm from O, on each side, the chord shrinks to a point: two tangents parallel to the grid lines.

Fig. 10.3On squared paper the chords shrink until two parallel lines just touch the circle.NCERT Fig. 10.3 (ii) · p. 146

Squared paper with 1 cm squares and a circle of radius 5 cm centred at O. In the first step the grid line through O is highlighted as a chord of length 10 cm. In the second step the chords on the grid lines 1, 2, 3 and 4 cm above and below O are highlighted too; labels on the right give 10, 9.8, 9.2, 8 and 6 cm for the upper half, so the chords shrink as the lines move away from O. In the third step the two lines 5 cm above and 5 cm below O are drawn as tangents touching the circle at one point each, with the secants between them.

Why these numbers? From Class 9, the perpendicular from the centre to a chord bisects the chord. So half the chord, the distance d of the line from O and the radius r form a right triangle, and Pythagoras gives the length of the chord:

chord=2r2−d2
(10.1)
where
r
the radius of the circle
d
the distance of the line from the centre

With r=5 and d=3 the chord is 216=8 cm, as in the table. As d grows towards r the chord shrinks, and at d=r it is zero: the line is a tangent. For d>r the number under the root is negative, so there is no chord and the line misses the circle. This is the test from Section 10.1, now with a reason.

Definition
Point of contact

The single point that a tangent shares with the circle. We say the tangent touches the circle at this point.

Now join the centre to the point of contact. The radius you draw and the tangent seem to meet at a right angle. Check it with a protractor before we prove it.

Theorem 10.1Tangent and radius

The radius drawn to the point of contact of a tangent is perpendicular to that tangent.

4/4OP is the shortest distance from O to the tangent, so it meets the tangent at 90∘.

Fig. 10.4Every point of the tangent except P is farther from O than P is.NCERT Fig. 10.5 · p. 147

A circle with centre O and a radius OP of 3 cm; a slanted tangent touches it at P. In the first step only the circle, the tangent and the radius are shown. In the second step a point Q on the tangent 4 cm from P is joined to O by a dashed line, and the label reads OQ = 5 cm, more than 3 cm. In the third step Q is 2.5 cm from P on the other side and OQ is about 3.9 cm, again more than 3 cm. In the fourth step a right-angle mark appears at P with the note that OP is the shortest distance, so there is a right angle at P.

SimulationTangent and radius explorer

The stage shows a circle, its centre O, a point P on the rim and the tangent at P. The radius OP is drawn with a right-angle mark at P. A second point Q sits on the tangent and is joined to O by a dashed line. You can drag P anywhere on the circle, and the tangent turns with it, and drag Q along the tangent. Readouts show OP, OQ, PQ and the angle OPQ, which stays 90 degrees, while OQ is always longer than the radius.

Fig. 10.5Drag P around the circle and Q along the tangent at P.
Try this
  • Drag Q towards P. Can you ever make OQ shorter than OP?
  • Move P to three different places on the circle. Does ∠OPQ ever change?
  • Read off OP, PQ and OQ, and check that OQ2=OP2+PQ2.

Because the angle at the point of contact is a right angle, every radius–tangent pair gives a right triangle, and Pythagoras finds missing lengths.

Example

Length of a tangent by Pythagoras

A circular pond has centre O and radius 7 m. Asha stands at a point Q, 25 m from O. At a point P, a straight path from Q just grazes the pond. How far is it from Q to P?

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
QP touches a circle with centre O at P, and ∠PQO=35∘. What is ∠POQ?
Show answer

Answer (C) 55∘

∠OPQ=90∘ (Theorem 10.1), so ∠POQ=180∘−90∘−35∘=55∘. The answer 145∘ forgets the right angle at P.
Practice · 4 questions

Practice 10.1: questions with answers

  1. Short answerEasyNCERT Exercise 10.1, Q1

    Riya says: “A circle has only two tangents, because I can fit my ruler against it on just two sides.” Is she right? How many tangents does a circle have?

    Show solution

    Riya is wrong. Every point of a circle has exactly one tangent (Two consequences), and a circle has infinitely many points, so it has infinitely many tangents. What Riya noticed is that, for one fixed direction of the ruler, only two tangents are parallel to it (Activity 10.2).

  2. Quick answerEasyNCERT Exercise 10.1, Q2

    Fill in the blanks.

    1. A line that has exactly one point in common with a circle is called a

      Show answer

      Answer tangent

      One common point: a tangent.
    2. A secant and a circle have points in common.

      Show answer

      Answer two

      A secant cuts the circle at two points.
    3. Of all the lines parallel to one given line, at most can be tangents to a circle.

      Show answer

      Answer two

      Only the two lines at distance r from the centre, one on each side, touch the circle.
    4. A tangent touches a circle at P. The point P is called the

      Show answer

      Answer point of contact

      It is the point of contact.
  3. Quick answerMediumNCERT Exercise 10.1, Q3

    O is the centre of a circle of radius 9 cm. A line through a point Q touches the circle at P, and OQ=41 cm. The length QP is

    Show answer

    Answer (B) 40 cm

    ∠OPQ=90∘, so QP=412−92=1600=40 cm. The values 32 and 50 subtract or add the lengths, and 1762 adds the squares.
  4. DiagramMediumNCERT Exercise 10.1, Q4

    Draw a circle of radius 3 cm with centre O, and a line m that is 5 cm from O. Then draw (a) a line parallel to m that is a tangent to the circle, and (b) a line parallel to m that is a secant. How far is each of your lines from O?

    Show solution

    AnswerThe tangent is 3 cm from O (there are two choices); a secant is less than 3 cm from O, for example the line through O.

    1. Draw the circle and the line m. With a set square draw OK⊥m, so OK=5 cm.
    2. OK crosses the circle at a point A, 3 cm from O. Through A draw the line perpendicular to OA; it is parallel to m. It is 3 cm from O, so it touches the circle at A: a tangent.
    3. Through O draw a line parallel to m. It is 0 cm from O, less than the radius, so it cuts the circle twice: a secant (in fact a diameter).
    4. Any parallel line closer than 3 cm to O is a secant. A second tangent lies on the far side, through the other end B of the diameter along OK.

10.3 Number of Tangents from a Point on a Circle

Each point on a circle has exactly one tangent. Now turn the question around. Pick a point P anywhere in the plane, perhaps inside the circle or far outside it. How many tangents to the circle pass through P? The answer depends only on where P is.

3/3From an outside point there are exactly two tangents, touching at A and B.

Fig. 10.6The number of tangents through P depends on where P is.NCERT Fig. 10.6 · p. 148

A circle with centre O and a point P on a horizontal line through O. In the first step P is inside the circle; three lines through P are drawn and each crosses the circle at two points, and the panel reads Inside, 0 tangents. In the second step P has moved onto the circle and a single vertical tangent passes through it; the panel reads On, 1 tangent. In the third step P is outside the circle and two tangents from P touch the circle at A and B; the panel reads Outside, 2 tangents.

  • P inside the circle: no tangent passes through P.
  • P on the circle: exactly one tangent passes through P.
  • P outside the circle: exactly two tangents pass through P.
Definition
Length of a tangent

For a point P outside a circle, the length of the tangent from P is the distance PA from P to the point of contact A.

Look again at the two tangents from P in Fig. 10.6. The segments PA and PB look exactly the same length, and a ruler agrees. A proof shows that this happens for every outside point.

Theorem 10.2Equal tangents

The two tangents drawn to a circle from a point outside it have equal lengths.

4/4By RHS the triangles are congruent, so PA=PB and PO bisects ∠APB.

Fig. 10.8Two right triangles with a common hypotenuse and equal radii are congruent.NCERT Fig. 10.7 · p. 149

A circle with centre O at the upper left and a point P at the lower right. In the first step the two tangents PA and PB are drawn. In the second step the radii OA and OB are added with right-angle marks at A and B, and P is joined to O by a dashed line. In the third step triangle OAP is shaded blue and triangle OBP green. In the fourth step PA and PB carry equal tick marks, the two angles at P between each tangent and PO carry arcs, and the label reads PA = PB.

The Pythagoras form gives a formula for the tangent length from any outside point P:

PA=PB=OP2−r2
(10.2)
where
OP
the distance of the point from the centre
r
the radius
InteractiveTangent lab

A circle of radius 3 cm with centre O and three modes. In Point mode you drag a point P, or set its distance and direction with sliders: inside the circle three sample lines through P all cut the circle twice and the panel says no tangent; on the circle one tangent appears at right angles to OP; outside, the two tangents PA and PB appear with radii and right-angle marks, and a table shows OP, PA and PB (always equal), the value of the square root of OP squared minus r squared, and that angle APB plus angle AOB is 180 degrees. In Turn mode a slider turns a line about a point P of the circle; the chord PQ shrinks and becomes zero when the line is at 90 degrees to OP. In Slide mode a horizontal line moves up and down; its chord is 2 times the square root of 9 minus d squared, and it becomes a tangent at 3 cm from O.

Fig. 10.9Drag P inside, onto and outside the circle, or switch to the Turn and Slide modes.

The three examples below use the two theorems together, the way board questions do.

3/3OA=65 and OP=25, so AP=60 and AB=120 (in cm).

Fig. 10.10The touching point P is the midpoint of the chord AB.NCERT Fig. 10.8 · p. 149

Two circles with the same centre O, with a ring of dots around them like a rangoli. A horizontal chord AB of the larger circle touches the smaller circle at P, directly above O. In the second step the radius OP is drawn with a right-angle mark at P, and AP and PB carry equal tick marks. In the third step OA is drawn dashed and the lengths are labelled: OP 25, OA 65 and AP 60, in centimetres.

Example 10.1NCERT Example 1 · p. 149

A rangoli line

For a rangoli, Meera draws two circles with the same centre O (concentric circles), of radii 65 cm and 25 cm. She lays a straight line of white powder AB, a chord of the bigger circle, which touches the smaller circle at P and nowhere else. (a) Prove that P is the midpoint of AB. (b) Find the length of AB.

Try it yourself first. Then reveal the solution one step at a time.

3/3∠OAP=90∘, so ∠OAB=90∘−65∘=25∘.

Fig. 10.11∠OAB is half of ∠APB.NCERT Fig. 10.9 · p. 150

A circle with centre O near the top and a point P below it; two tangents from P touch the circle at A and B, and the angle at P is marked 50 degrees. In the second step the chord AB is drawn, the tangents carry equal tick marks, and the base angles of triangle PAB are marked 65 degrees each. In the third step the radius OA is drawn with a right-angle mark at A, and the angle between OA and AB is marked 25 degrees.

Example 10.2NCERT Example 2 · p. 150

Angles made by two tangents

Tangents from an outside point P touch a circle (centre O) at A and B, and ∠APB=50∘. (a) Find the angles PAB and OAB in degrees. (b) Prove that ∠OAB=12∠APB for any two tangents from an outside point.

Try it yourself first. Then reveal the solution one step at a time.

3/3∠OAT=90∘, and similar triangles give TA=7.5 m.

Fig. 10.12The fence TA, the radius OA and the line OT form a right triangle.NCERT Fig. 10.10 · p. 150

A green circular garden with centre O. A straight path AB near the top is labelled 12 m, and two fences along the tangents at A and B meet at the gate T above the garden. In the second step T is joined to O by a dashed line crossing AB at M with a right angle; AM is labelled 6, OM 8 and the radius OA 10. In the third step a right-angle mark appears at A between the radius and the fence, and TA is labelled 7.5, all in metres.

Example 10.3NCERT Example 3 · p. 150

Fences along two tangents

A circular garden has centre O and radius 10 m. A straight path AB, 12 m long, joins two points on its edge. Fences are built along the tangents at A and B, and they meet at a gate T. Find the length TA of each fence.

Try it yourself first. Then reveal the solution one step at a time.

3/3Each side is a sum of two letters, and the perimeter is 2(x+y+z).

Fig. 10.13Equal tangents from each corner split every side into two labelled parts.

A triangle ABC whose three sides touch a circle drawn inside it. In the second step the two tangent segments from A are coloured blue and labelled x, the two from B green and labelled y, and the two from C orange and labelled z. In the third step a panel on the right adds them up: AB = x + y, BC = y + z, CA = z + x, so the perimeter is 2x + 2y + 2z.

Quick check
1 of 4
Tangents from P to a circle of radius 5 cm are 12 cm long. How far is P from the centre?
cm
Show answer

Answer 13 cm

OP=52+122=169=13 cm.
Practice · 13 questions

Practice 10.2: questions with answers

  1. Quick answerEasyNCERT Exercise 10.2, Q1

    From a point P, the tangent to a circle is 20 cm long, and P is 29 cm from the centre. The radius of the circle is

    Show answer

    Answer (A) 21 cm

    r=292−202=441=21 cm. The value 9 cm subtracts the lengths, and 1241 adds the squares.
  2. Quick answerMediumNCERT Exercise 10.2, Q2

    The tangents from P touch a circle (centre O) at A and B, and the radii OA and OB make ∠AOB=125∘. Then ∠APB is

    Show answer

    Answer (C) 55∘

    The angles at A and B are 90∘ each, so ∠APB=360∘−180∘−125∘=55∘.
  3. Quick answerMediumNCERT Exercise 10.2, Q3

    Two tangents drawn from P touch a circle (centre O) at A and B, and the angle between them is 64∘. Then ∠AOP is

    Show answer

    Answer (D) 58∘

    OP bisects ∠APB, so ∠APO=32∘, and in right △OAP, ∠AOP=90∘−32∘=58∘. 116∘ is the whole of ∠AOB.
  4. ProofEasyNCERT Exercise 10.2, Q4

    AB is a diameter of a circle. Prove that the tangent at A and the tangent at B never meet.

    Show solution

    By Theorem 10.1 the tangent at A is perpendicular to the radius OA, which lies along AB, so it makes 90∘ with AB. In the same way the tangent at B makes 90∘ with AB.

    The two tangents make co-interior angles of 90∘+90∘=180∘ with the line AB, so they are parallel. Parallel lines never meet.

  5. ProofMediumNCERT Exercise 10.2, Q5

    A carpenter draws the tangent to a round table top at a point P of its edge. Then she draws the line through P at right angles to that tangent.

    1. Prove that this line passes through the centre O of the table top.

      Show solution

      By Theorem 10.1, OP is perpendicular to the tangent at P. Through P only one line can be perpendicular to the tangent, so the carpenter's line is the line OP. It passes through O.

    2. How can she find the centre using two such lines?

      Show solution

      She repeats this at a second point Q of the edge (not at the far end of the diameter through P). Both lines pass through O, so the centre is where they cross.

  6. NumericalEasyNCERT Exercise 10.2, Q6

    A point is 37 cm from the centre of a circle, and the tangent from it is 35 cm long. Find the radius, in cm.

    cm
    Show solution

    r2=372−352=1369−1225=144, so r=12 cm.

  7. NumericalMediumNCERT Exercise 10.2, Q7

    Two concentric circles have radii 17 cm and 8 cm. A chord of the larger circle touches the smaller one. Find the length of the chord, in cm.

    cm
    Show solution

    The radius of the small circle to the point of contact (8 cm) is perpendicular to the chord, so it bisects the chord.

    Half the chord =172−82=225=15 cm, so the chord is 30 cm.

  8. ProofMediumNCERT Exercise 10.2, Q8

    A quadrilateral PQRS circumscribes a circle: each of its sides touches the circle.

    1. Prove that PQ+RS=QR+SP.

      Show solution

      Let the tangent lengths from P, Q, R, S be a, b, c, d; by Theorem 10.2 the two tangents from each corner are equal.

      Then PQ=a+b, QR=b+c, RS=c+d and SP=d+a.

      So PQ+RS=a+b+c+d=QR+SP.

    2. If PQ=9 cm, QR=7 cm and RS=6 cm, find SP in cm.

      cm
      Show solution

      9+6=7+SP, so SP=8 cm.

  9. ProofHardNCERT Exercise 10.2, Q9

    Two parallel lines ℓ and m both touch a circle whose centre is O. A third tangent touches the circle at R and meets ℓ at E and m at F.

    1. Prove that ∠EOF=90∘.

      Show solution

      Let ℓ touch the circle at U and m at V. From E the tangents EU and ER are equal, so OE bisects ∠UEF (remarks after Theorem 10.2). Likewise OF bisects ∠VFE.

      As ℓ∥m, the co-interior angles ∠UEF and ∠VFE add up to 180∘. Their halves add up to 90∘: ∠OEF+∠OFE=90∘.

      So in △EOF, ∠EOF=180∘−90∘=90∘.

    2. If the radius is 6 cm and ER=4 cm, find RF in cm.

      cm
      Show solution

      OR⊥EF (Theorem 10.1). In right △EOF the altitude OR gives △ERO∼△ORF (AA), so EROR=ORRF.

      RF=OR2ER=364=9 cm.

  10. ProofMediumNCERT Exercise 10.2, Q10

    Tangents from an external point P touch a circle with centre O at A and B.

    1. Prove that ∠APB+∠AOB=180∘.

      Show solution

      In quadrilateral OAPB, ∠OAP=∠OBP=90∘ (Theorem 10.1). The four angles add up to 360∘, so ∠APB+∠AOB=360∘−180∘=180∘.

    2. Deduce that O, A, P and B lie on one circle.

      Show solution

      In OAPB the opposite angles at A and B add up to 180∘. From Class 9, a quadrilateral with a pair of opposite angles adding up to 180∘ is cyclic. (This circle is the one on diameter OP in the box on why there are two tangents.)

  11. ProofMediumNCERT Exercise 10.2, Q11

    A parallelogram ABCD circumscribes a circle.

    1. Prove that ABCD is a rhombus.

      Show solution

      By tangent pairs (as in Question 8), AB+CD=BC+DA.

      In a parallelogram AB=CD and BC=DA, so 2AB=2BC, that is, AB=BC.

      A parallelogram with two adjacent sides equal has all four sides equal: it is a rhombus.

    2. Can a rectangle that is not a square circumscribe a circle? Explain.

      Show solution

      No. A rectangle is a parallelogram, so by (a) it would have to be a rhombus, and a rectangle with all sides equal is a square.

  12. NumericalHardNCERT Exercise 10.2, Q12

    △PQR circumscribes a circle of radius 3 cm, which touches QR at S with QS=4 cm and SR=6 cm.

    1. Find PQ in cm.

      cm
      Show solution

      Let the tangent length from P be x. Tangent pairs give PQ=x+4, PR=x+6 and QR=10, so the semi-perimeter is s=x+10.

      Join the centre I to P, Q and R. Triangles IQR, IRP and IPQ all have height 3 cm, so the area is 12×3×2s=3(x+10).

      Heron's formula gives the area as s⋅x⋅4⋅6=24x(x+10).

      So 9(x+10)2=24x(x+10), that is 9(x+10)=24x, which gives x=6. Hence PQ=10 cm.

    2. Find PR in cm.

      cm
      Show solution

      PR=x+6=12 cm. Check: sides 10, 10 and 12 give s=16 and area 16⋅6⋅6⋅4=48=3×16.

  13. ProofHardNCERT Exercise 10.2, Q13

    Quadrilateral ABCD circumscribes a circle with centre O.

    1. Prove that ∠AOB+∠COD=180∘.

      Show solution

      Let the circle touch AB, BC, CD, DA at P, Q, R, S. Join O to all eight points.

      Triangles OAS and OAP are congruent (RHS), so ∠AOS=∠AOP. Likewise ∠BOP=∠BOQ, ∠COQ=∠COR and ∠DOR=∠DOS.

      The eight angles round O add up to 360∘ and form four equal pairs, so ∠AOP+∠BOP+∠COR+∠DOR=180∘.

      Since ∠AOP+∠BOP=∠AOB and ∠COR+∠DOR=∠COD, we get ∠AOB+∠COD=180∘.

    2. If ∠AOB=100∘, find ∠COD in degrees.

      °
      Show solution

      ∠COD=180∘−100∘=80∘.

10.4 Summary

1/4Three facts carry the whole chapter.

Fig. 10.14The three big ideas of the chapter.

Three panels side by side. The first shows a circle with three horizontal lines: a dashed one that misses it, a blue tangent touching it at one point and a purple secant crossing it at two points, captioned 0, 1 or 2 points. The second shows a radius meeting a tangent with a right-angle mark, captioned right angle at contact. The third shows two tangents from an outside point P with equal tick marks, captioned equal tangents. The first step shows all three panels; each later step brightens one panel and dims the other two.

Recap

Circles: key points and summary

  1. A line and a circle share no point (non-intersecting line), one point (tangent) or two points (secant), never three (Section 10.1).
  2. If d is the distance of a line from the centre, the line misses the circle when d>r, touches it when d=r and cuts it when d<r ((10.1)).
  3. A tangent is the limiting position of a secant whose two meeting points come together (Activity 10.1).
  4. At most two tangents are parallel to a given line (Activity 10.2).
  5. The tangent at a point is perpendicular to the radius drawn to the point of contact (Theorem 10.1).
  6. Each point of a circle has exactly one tangent; the line through the centre and the point of contact is the normal (Two consequences).
  7. Through a point inside a circle pass no tangents, through a point on it one, and through a point outside it exactly two (Section 10.3).
  8. The two tangents from an outside point are equal (Theorem 10.2).
  9. The tangent length from P is OP2−r2 ((10.2)).
  10. OP bisects the angle between the tangents and is the perpendicular bisector of the chord AB (More from the same two triangles).
  11. The angle between two tangents and the angle at the centre between the radii to the points of contact add up to 180° (Practice 10.2, Q10).
  12. Around a circle, each corner of a polygon gives a pair of equal tangents (Count the tangent pairs).
Flash cards · 6

Key terms

1 / 6

Board exam practice

Practice · 8 questions

Practice questions with answers (NCERT “Board exam practice”)

  1. Quick answerEasy

    The angle between the two tangents from a point P to a circle of radius 4 cm is 60∘. Then OP equals

    Show answer

    Answer (C) 8 cm

    PO bisects the angle, so in right △OAP, ∠APO=30∘ and sin⁡30∘=4OP. So OP=8 cm. The value 43 cm is the tangent length PA, not OP.
  2. Quick answerMedium

    Assertion (A): From a point 5 cm from the centre of a circle of radius 3 cm, each tangent is 4 cm long. Reason (R): A radius drawn to the point of contact meets the tangent at a right angle.

    Show answer

    Answer (A) Both A and R are true, and R is the correct explanation of A.

    The right angle makes △OAP right-angled, so each tangent is 52−32=4 cm. R is true and is exactly what A needs.
  3. Quick answerEasy

    Assertion (A): A tangent to a circle can be drawn through a point inside the circle. Reason (R): Every line through a point inside a circle cuts the circle at two points.

    Show answer

    Answer (D) A is false but R is true.

    R is true, and it is exactly why A is false: a line through an inside point is always a secant.
  4. ProofMedium

    The tangents at the ends A and B of a chord (not a diameter) meet at T. Prove that ∠TAB=∠TBA.

    Show solution

    TA and TB are the tangents from the external point T, so TA=TB (Theorem 10.2). In △TAB the angles opposite the equal sides are equal, so ∠TBA=∠TAB.

  5. NumericalMedium

    A circle is drawn inside △ABC so that it touches all three sides. The triangle is right-angled at B, with AB=6 cm and BC=8 cm. Find the radius of the circle, in cm.

    cm
    Show solution

    AC=62+82=10 cm. Let the circle (centre O, radius r) touch AB at P, BC at Q and AC at R.

    OPBQ has right angles at P, B and Q, and OP=OQ=r, so it is a square: BP=BQ=r.

    Tangent pairs give AR=AP=6−r and CR=CQ=8−r. So (6−r)+(8−r)=10, which gives r=2 cm.

  6. Long answerHard

    Prove that the radius to the point of contact of a tangent makes a right angle with the tangent. Hence find the length of the tangent from a point 53 cm from the centre of a circle of radius 28 cm.

    1. Prove the theorem.

      Show solution

      Let the tangent ℓ touch the circle (centre O) at P. Any other point Q of ℓ lies outside the circle, or ℓ would meet the circle twice; so OQ>OP.

      Thus OP is the shortest segment from O to ℓ. The shortest segment from a point to a line is the perpendicular, so OP⊥ℓ.

    2. Find the tangent length, in cm.

      cm
      Show solution

      532−282=2809−784=2025=45 cm.

  7. ProofMedium

    A circle touches two lines that cross at V. Prove that the line from V to the centre of the circle cuts the angle between the two lines into two equal parts.

    Show solution

    Let the circle, centre O, touch the lines at A and B. Then VA and VB are the two tangents from the external point V.

    Right triangles OAV and OBV have OA=OB and the common hypotenuse OV, so they are congruent (RHS). Hence ∠AVO=∠BVO: VO bisects the angle between the lines.

  8. Short answerMedium

    Case study: a flour-mill belt. In a chakki, a flat belt runs round two pulleys of radius 15 cm each, with centres X and Y that are 80 cm apart. Each straight part of the belt touches both pulleys, at A on the first and at B on the second.

    1. Why is XA parallel to YB?

      Show solution

      Both radii are perpendicular to the same straight line AB (Theorem 10.1), so they are parallel.

    2. What kind of quadrilateral is XABY?

      Show answer

      Answer (B) a rectangle

      XA and YB are parallel and equal (15 cm), so XABY is a parallelogram, and its angles at A and B are right angles: a rectangle.
    3. How long is each straight part AB, in cm?

      cm
      Show solution

      Opposite sides of a rectangle are equal: AB=XY=80 cm.

    4. The belt goes half-way round each pulley. Find its total length in cm, using π=227.

      cm
      Show solution

      Two straight parts and two half-circles: 2×80+2π×15=160+6607≈254.3 cm.

Find your NCERT exercise question

Our practice questions are written for ncert.ai and follow the NCERT exercises. Find the one that matches the question in your textbook; its answer is with it.

In your NCERT textbookPractice question here
NCERT Exercise 10.1, Q1Practice 10.1 · Q1
NCERT Exercise 10.1, Q2Practice 10.1 · Q2
NCERT Exercise 10.1, Q3Practice 10.1 · Q3
NCERT Exercise 10.1, Q4Practice 10.1 · Q4
NCERT Exercise 10.2, Q1Practice 10.2 · Q1
NCERT Exercise 10.2, Q2Practice 10.2 · Q2
NCERT Exercise 10.2, Q3Practice 10.2 · Q3
NCERT Exercise 10.2, Q4Practice 10.2 · Q4
NCERT Exercise 10.2, Q5Practice 10.2 · Q5
NCERT Exercise 10.2, Q6Practice 10.2 · Q6
NCERT Exercise 10.2, Q7Practice 10.2 · Q7
NCERT Exercise 10.2, Q8Practice 10.2 · Q8
NCERT Exercise 10.2, Q9Practice 10.2 · Q9
NCERT Exercise 10.2, Q10Practice 10.2 · Q10
NCERT Exercise 10.2, Q11Practice 10.2 · Q11
NCERT Exercise 10.2, Q12Practice 10.2 · Q12
NCERT Exercise 10.2, Q13Practice 10.2 · Q13

Quick check: MCQs on Circles

  1. 10.1 Introduction3 questions
  2. 10.2 Tangent to a Circle3 questions
  3. 10.3 Number of Tangents from a Point on a Circle4 questions
Glossary · 9

Key terms (English–Hindi)

circleवृत्तvritt
All the points of a plane that are one fixed distance (the radius) from a fixed point (the centre).First seen in the chapter →
circumscribeपरिगतparigat
A polygon circumscribes a circle when every side of the polygon is a tangent to the circle.First seen in the chapter →
concentric circlesसंकेंद्रीय वृत्तsankendriya vritt
Circles that have the same centre.First seen in the chapter →
length of a tangentस्पर्श रेखा की लंबाईsparsh rekha ki lambai
For a point P outside a circle, the distance from P to the point of contact of a tangent drawn from P.
non-intersecting lineअप्रतिच्छेदी रेखाapratichchhedi rekha
A line that has no point in common with a given circle.First seen in the chapter →
normalअभिलंबabhilamb
The line through the centre of a circle and a point of contact; it is perpendicular to the tangent there.First seen in the chapter →
point of contactस्पर्श बिंदुsparsh bindu
The single point that a tangent shares with a circle.
secantछेदक रेखाchhedak rekha
A line that meets a circle at two points.First seen in the chapter →
tangentस्पर्श रेखाsparsh rekha
A line that meets a circle at exactly one point, its point of contact.First seen in the chapter →