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MathematicsCh 12 Surface Areas and Volumes

Surface Areas and Volumes: Class 10 Maths Chapter 12 Hinglish mein

Kisi object ko basic solids mein todo, phir bahar dikhne wali surfaces aur andar ki jagah ko jodo

Mathematics · Hinglish notes, simulations aur practice · Official NCERT chapter PDF ↗

Published · Updated

  • 45 min
  • 27 practice questions
  • 11 MCQs

Is chapter mein aap kya seekhenge

  • Roz ki kisi cheez ko un basic solids mein todo jinse woh bani hai: cuboid, cube, cylinder, cone, sphere aur hemisphere
  • Tay karo ki kaun se faces bahar rehte hain aur kaun se do solids ke judne ki jagah chhup jaate hain
  • Combined solid ka total surface area nikaalo, us ring ko bhi gin kar jo chhota face bade face par baithne se bach jaati hai
  • Aise solid ka surface area nikaalo jismein se hollow khoda gaya ho, hollow ke andar ki surface ko bhi gin kar
  • Combined solid ka volume uske parts ke volumes jod kar nikaalo, aur hollow ya raised base ko ghatao
  • Capacity, cost, mass aur counting ke sawaal question mein diye gaye π ki value se solve karo

NCERT Mathematics Class 10, Chapter 12, pp. 161–170 par based original companion text. Yeh NCERT se juda nahi hai aur NCERT ne ise endorse nahi kiya hai.

12.1 Introduction

Kisi kitchen, chemist ki dukaan ya chhat par ghoomo aur un cheezon ko gino jo sirf ek cylinder, cone ya sphere hain. Jitna socha tha, usse kam milengi. Dawai ka capsule ek cylinder hai jiske dono ends par ek gol cap hai. Chhat ki water tank ek cylinder hai jiska dhakkan ek cone hai. Ice-cream cone ek cone hai jiske upar ek gol scoop baitha hai.

Inmein se har ek combination of solids (ठोसों का संयोजन) hai: do ya zyada basic solids jo flat faces par jude hain (Fig. 12.1). Class 9 mein tumne har basic solid ka surface area aur volume alag-alag nikaala tha. Ab hum un results ko un cheezon par lagaate hain jo tum sach mein haath mein lete ho.

3/3Har object basic solids ka ek combination hai.

Fig. 12.1Roz ki cheezein aksar do ya teen basic solids ko jod kar bani hoti hain.NCERT Fig. 12.2 · p. 161

Teen roz ki cheezein saath-saath khadi hain, jin par capsule, water tank aur ice-cream cone likha hai. Step 1 mein woh poori dikhti hain. Step 2 har ek ko uske joints se alag karta hai: capsule ke gol ends uske beech wale hisse se door khisak jaate hain, tank ka dhakkan upar uth jaata hai, aur scoop cone se upar uth jaata hai. Jo flat faces andar chhupe the, un par stripes hain. Step 3 har object ke neeche uski recipe likhta hai: cylinder plus 2 hemispheres, cylinder plus cone, aur cone plus hemisphere.

Definition
Combination of solids

Aisa solid jo do ya zyada basic solids (cuboid, cube, cylinder, cone, sphere, hemisphere) ko unke flat faces par jod kar bana ho.

ExampleEk capsule: ek cylinder jiske dono ends par ek-ek hemisphere hai.

Aisi cheez ke liye humein kabhi bilkul naye formula ki zaroorat nahi padti. Hum use un pieces mein todte hain jinhe hum jaante hain, har piece ka hisaab lagaate hain, aur phir answers ko dhyaan se jodte hain. Table mein Class 9 ke woh results hain jo tum use karoge. Curved surface area ke liye hum CSA aur total surface area ke liye TSA likhte hain.

Table 12.1Basic solids ke formulas (Class 9 se)
Curved ya side surfaceTotal surfaceVolume
Cuboid l×b×h2h(l+b)2(lb+bh+hl)lbh
Cube, edge a4a26a2a3
Cylinder2πrh2πr(r+h)πr2h
Coneπrlπr(l+r)13πr2h
Sphere4πr24πr243πr3
Hemisphere2πr23πr223πr3
Definition
Total surface area (TSA)

Kisi solid ke poore bahari hisse ka area: har curved part aur har flat face jise tum chhoo sakte ho.

ExampleEk band tin ka dabba: uski curved side plus upar aur neeche ke circles.

Ek entry mein ek trap chhupa hai. Cone ki curved surface mein uski slant height l, yaani tip se rim tak dhalaan wali side ki lambai, use hoti hai. Yahan vertical height use nahi hoti, yaani h. Radius, height aur slant height milkar ek right triangle banate hain, isliye Pythagoras se slant height mil jaati hai.

Cone ki slant height
l=r2+h2
(12.1)
jahan
l
slant height
r
base ka radius
h
vertical height

Hemisphere (अर्धगोला) aadha sphere hota hai. Uske curved part ka area sphere ka aadha hota hai, 2πr2, aur uska flat face ek circle hai jiska area hai πr2. In do pieces ko dimaag mein alag-alag rakho. Is chapter mein curved part aksar bahar rehta hai, jabki flat face aksar chhup jaata hai.

Zyadatar questions batate hain ki π ki kaun si value leni hai: 227 (kaam ki jab radius 7 ka multiple ho) ya 3.14. Agar kuch na bataya ho, to lo π=227. Aakhri line tak π ko symbol hi rehne do. Tab tum usse sirf ek baar multiply karte ho, aur rounding errors chhote rehte hain.

Warm-up: basic solids
3 mein se 1
Ek gol pencil, jo nukeeli kar di gayi hai aur jismein eraser nahi hai, kin do basic solids se bani hai?
Answer dekho

Answer (B) ek cylinder aur ek cone

Body ek cylinder hai aur nukeela end ek cone hai. Hemisphere se end gol hota, capsule jaisa.

12.2 Solids ke Combination ka Surface Area

Maan lo ek factory capsules par cheeni ki patli layer chadhaati hai. Coating sirf bahar lagti hai, isliye factory ko woh area chahiye jise tum ungli ki tip se chhoo sako. Hum ise kaise nikaalein?

Capsule ko dimaag mein banao (Fig. 12.2). Ek cylinder lo jiska radius r hai aur length h, aur usi radius ke do hemispheres. Har piece ke flat circular faces hain. Pieces ko aapas mein dabao to woh flat faces mil jaate hain. Ab woh capsule ke andar hain, jahan coating nahi pahunch sakti. Bahar teen curved pieces bachte hain: cylinder ki gol deewar aur har hemisphere ka dome.

3/3Bahar sirf teen curved surfaces bachti hain.

Fig. 12.2Capsule ke bahar sirf curved surfaces rehti hain.NCERT Fig. 12.4 · p. 162

Step 1 mein beech mein ek cylinder hai aur dono taraf ek-ek hemisphere, thoda door. Chaaron flat circular faces par stripes hain aur un par flat faces likha hai. Step 2 hemispheres ko andar khiskaata hai jab tak woh cylinder ko chhoo na lein; stripes gayab ho jaati hain aur labels par chhupe likha aata hai, kyunki flat faces ab andar hain. Step 3 bahar ke hisse ko bold colour mein outline karta hai aur teen curved surfaces par 2 pi r squared, 2 pi r h aur 2 pi r squared likhta hai, saath mein length h aur radius r mark hain.

Har hemisphere ke liye 2πr2 aur cylinder ke liye 2πrh jodne par capsule ka total surface area S milta hai.

Capsule ka TSA
S=4πr2+2πrh
(12.2)
jahan
r
cylinder aur har hemisphere ka radius
h
cylindrical part ki length

Yahi soch solids ke kisi bhi pair par kaam karti hai. Cone hemisphere par theek se tabhi baithta hai jab dono ke radii barabar hon: tab dono flat circles ek doosre ko poora dhak lete hain aur joint smooth hota hai. Radii alag hon to bade circle ka ek hissa ring ki tarah khula reh jaata hai, aur woh ring bahar hi rehti hai (Example 12.3).

Chalo is idea ko kuch solids par lagaate hain. Har example mein, kuch bhi calculate karne se pehle object ka sketch banao, uske parts ke naam likho aur bahar dikhne wali surfaces ki list banao.

1/3Kul height 7 cm, chaudaai 6 cm.

Fig. 12.3Ek plumb bob: same radius ke cone par ek hemisphere.NCERT Fig. 12.6 · p. 163

Ek plumb bob dhaage se latka hai. Uska upar wala hissa hemisphere hai aur neeche wala hissa neeche point karta cone. Step 1 kul height 7 cm aur joint par chaudaai 6 cm mark karta hai. Step 2 ek dashed axis banata hai aur hemisphere, radius 3 cm, aur cone par label lagaata hai, jiski height 7 minus 3, yaani 4 cm hai. Step 3 axis, ek radius aur dhalaan wali side se bane right triangle ko shade karta hai aur slant height l = 5 cm likhta hai.

Example 12.1NCERT Example 1 · p. 163

Ek plumb bob

Mistri ka brass plumb bob (साहुल) same radius ke cone ke upar laga ek hemisphere hai (Fig. 12.3). Bob 7 cm uncha hai aur sabse chaudi jagah par 6 cm chauda. Uski poori surface par chrome-plating karni hai. Plate hone wala area nikaalo; lo π=227.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1/37 cm diameter ke dome wala ek cuboid block.

Fig. 12.4Dome chhat ka ek circle chhupata hai par apni curved surface jod deta hai.NCERT Fig. 12.7 · p. 164

Ek cuboid block, 10 cm lamba, 8 cm gehra aur 6 cm uncha, jiske saamne wale face par ek chhota darwaaza bana hai aur chhat ke beech mein 7 cm chauda hemispherical dome hai. Step 1 model ko uske measurements ke saath dikhata hai. Step 2 dome ko upar uthakar halka kar deta hai, aur chhat par ek striped circle dikhta hai jis par dhaka, roof ka part, minus pi r squared likha hai. Step 3 dome ko wapas rakhta hai, uski curved surface bold mein outline hoti hai aur us par dome surface, plus 2 pi r squared likha hai, isliye net badlaav plus pi r squared hai.

Example 12.2NCERT Example 2 · p. 164

Ek model mandir

Mandir ka ek souvenir model lakdi ka cuboid hai, 10 cm lamba, 8 cm chauda aur 6 cm uncha. Uski chhat ke beech mein 7 cm diameter ka hemispherical dome laga hai (Fig. 12.4). Model ka total surface area nikaalo. Lo π=227.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Shortcut par dhyaan do. Flat face par chipka hemisphere hamesha surface area mein bilkul πr2 jodta hai, neeche block chahe jaisa bhi ho.

1/3Cone: radius 4 cm, height 3 cm. Knob: radius 1 cm, height 2.5 cm.

Fig. 12.5Knob cone ke top ka sirf beech wala hissa dhakta hai, isliye ek ring bach jaati hai.NCERT Fig. 12.8 · p. 165

Ek lattu: radius 4 cm aur height 3 cm ka cone neeche point karta hai, aur radius 1 cm aur height 2.5 cm ka cylindrical knob uske flat top ke beech mein khada hai. Cone laal rang ka hai aur knob hara. Step 1 measurements deta hai. Step 2 knob ke chaaron taraf cone ke flat top par stripes lagaata hai aur right mein ek top view jodta hai: radius 4 cm ke circle aur knob ke radius 1 cm ke circle ke beech ek striped ring, jis par pi R squared minus pi r squared likha hai. Step 3 neeche do lines jodta hai: laal mein cone ki curved surface plus ring aati hai, aur hare mein knob ki side aur top.

Example 12.3NCERT Example 3 · p. 165

Do rangon wala toy top

Lakdi ka ek lattu (लट्टू) radius 4 cm aur height 3 cm ka cone hai, jo neeche point karta hai. Radius 1 cm aur height 2.5 cm ka ek cylindrical knob cone ke flat top ke centre par khada hai (Fig. 12.5). Cone wala hissa laal rang se paint hota hai aur knob hare se. Har rang ka area nikaalo. Use karo π=3.14.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1/3Ek pathar ka cylinder jiske top mein hemispherical hollow hai.

Fig. 12.6Bahar ki side, upar ki ring aur hollow ke andar polish karo.NCERT Fig. 12.9 · p. 166

Left mein pathar ka ek solid cylinder hai, 28 cm chauda aur 20 cm uncha, jiske top ke beech mein ek gol hollow hai, jis par hollow radius 7 cm likha hai. Step 1 khal ko uske measurements ke saath dikhata hai. Step 2 right mein beech se kata hua khal jodta hai: ek rectangle jiske top edge ke beech se radius 7 cm ka half-circle hollow khoda gaya hai. Step 3 polish hone wali surfaces ko bold mein outline karta hai, yaani bahar ki side, upar ki flat ring aur hollow ka andar, base ko dashed line se mark karke us par polish nahi likhta hai, aur formula 2 pi R h plus pi times R squared minus r squared plus 2 pi r squared dikhata hai.

Example 12.4NCERT Example 4 · p. 166

Ek pathar ka khal

Masale peesne ka pathar ka khal (खल) radius 14 cm aur height 20 cm ka ek solid cylinder hai. Uske top ke centre se radius 7 cm ka ek hemispherical hollow khoda gaya hai (Fig. 12.6). Base ko chhod kar, jo zameen par tika hai, har surface par polish karni hai. Polish hone wala area nikaalo. Lo π=227.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

InteractiveSolid combiner

Paanch combined solids ki ek interactive drawing: capsule, hemisphere par cone, cylinder par cone, cube par hemisphere aur hemispherical hollow wala cylinder. Sliders radius aur heights badalte hain. Pull apart button parts ko alag karta hai aur un flat faces par stripes lagaata hai jo judne ke baad chhup jaate hain. Ek table har part ka akela total surface area, ghataaya gaya chhupa area aur solid ka total surface area dikhati hai; doosri table har part ka volume aur unka sum ya difference dikhati hai. Do buttons pi = 22/7 aur pi = 3.14 ke beech switch karte hain.

Fig. 12.7Ek solid chuno, uske measurements badlo aur use alag karke dekho ki kaun se faces chhupte hain.
Dikhne wali surfaces
4 mein se 1
Radius 2 cm ka ek hemisphere 6 cm edge wale cube ke top face par chipkaya gaya hai. Akele cube ki tulna mein surface area
Answer dekho

Answer (C) 4π cm2 badhta hai

Yeh chhupata hai πr2=4π aur jodta hai 2πr2=8π, yaani net faayda 4π cm2. 8π chunne ka matlab hai cube ke face ka chhupa circle bhool jaana.
Practice · 10 questions

Practice 12.1: answers ke saath

Jab tak question kuch aur na kahe, lo π=227.

  1. NumericalEasyNCERT Exercise 12.1, Q1

    Cube ke shape ke teen lakdi ke blocks, har ek ka volume 27 cm3, ek line mein chipka kar ek cuboid banaya gaya hai.

    1. Cuboid ka surface area nikaalo.

      cm²
      Solution dikhao

      Har cube ka edge =273=3 cm, isliye cuboid 9 cm x 3 cm x 3 cm ka hai.

      2(27+9+27)=126 cm2.

    2. Yeh teen alag cubes ke total surface area se kitna kam hai?

      cm²
      Solution dikhao

      Teen cubes: 3×6×9=162 cm2.

      162−126=36 cm2: chaar chhupe faces, har ek 9 cm2 ka.

  2. NumericalMediumNCERT Exercise 12.1, Q2

    Ek dairy ke milk vat ka bottom hemispherical hai aur seedhi cylindrical sides same radius ki hain, aur dhakkan nahi hai. Yeh 1.4 m chauda hai aur rim se sabse neeche ke point tak 1.9 m gehra hai. Iske andar tin ki coating karni hai.

    1. Andar ka surface area nikaalo.

      m²
      Solution dikhao

      r=0.7 m; cylinder ki height h=1.9−0.7=1.2 m.

      Andar =2πr2+2πrh=2πr(r+h).

      2×227×0.7×1.9=8.36 m2.

    2. Tinning ka kharcha ₹ 250 per m² hai. Kul kharcha nikaalo.

      ₹
      Solution dikhao

      8.36×250=2090, yaani ₹ 2090.

  3. NumericalMediumNCERT Exercise 12.1, Q3

    Machhli pakadne ka float radius 1.4 cm ka ek cone hai jo same radius ke hemisphere par laga hai. Float ki kul height 6.2 cm hai. Uska total surface area nikaalo.

    cm²
    Solution dikhao

    Cone ki height =6.2−1.4=4.8 cm; l=1.96+23.04=5 cm.

    TSA =2πr2+πrl=πr(2r+l).

    227×1.4×7.8=4.4×7.8=34.32 cm2.

  4. NumericalMediumNCERT Exercise 12.1, Q4

    Chandan ki lakdi ka ek block, 14 cm × 10 cm × 8 cm, apne 14 cm × 10 cm wale face par rakha hai. Uske top face par ek hemisphere lagana hai.

    1. Hemisphere zyada se zyada kitna chauda ho sakta hai?

      cm
      Solution dikhao

      Top face 14 cm x 10 cm ka hai, isliye us par sabse bade circle ka diameter 10 cm hai.

    2. Us hemisphere ke saath solid ka total surface area nikaalo.

      cm²
      Solution dikhao

      Cuboid: 2(140+80+112)=664 cm2.

      Hemisphere jodta hai πr2=227×25≈78.57 cm2.

      Kul ≈742.57 cm2.

  5. Short answerHardNCERT Exercise 12.1, Q5

    Lakdi ki ek sindoor dibbi ek cube hai jiska edge hai a. Uske top face ke centre se radius a4 ka ek hemispherical hollow khoda gaya hai.

    1. Dibbi ka surface area is variable ke terms mein nikaalo: a.

      Solution dikhao

      Answera216(96+π)

      Cube: 6a2. Hollow hataata hai π(a4)2 aur jodta hai 2π(a4)2, yaani net +πa216.

      Surface area =6a2+πa216=a216(96+π).

    2. Iski value nikaalo jab a=8 cm.

      cm²
      Solution dikhao

      6416(96+227)=4×99.14≈396.57 cm2.

  6. NumericalEasyNCERT Exercise 12.1, Q6

    Ghar ka gas cylinder lagbhag ek cylinder hai jiske dono ends par ek-ek hemisphere hai. Yeh kul 70 cm lamba aur 28 cm chauda hai. Valve aur collar ko chhod kar uski bahari surface ka area nikaalo.

    cm²
    Solution dikhao

    r=14 cm; cylindrical part ki length hai 70−28=42 cm.

    Area =2πr(2r+h)=2×227×14×70.

    =88×70=6160 cm2.

  7. NumericalMediumNCERT Exercise 12.1, Q7

    Desert camp ka ek tent 2.5 m uncha aur 7 m chauda cylinder hai, jiske upar slant height 4.5 m ka cone hai. Farsh ke liye canvas use nahi hota.

    1. Kitna canvas chahiye, uska area nikaalo.

      m²
      Solution dikhao

      r=3.5 m. Canvas =2πrh+πrl=πr(2h+l).

      227×3.5×9.5=11×9.5=104.5 m2.

    2. Canvas ₹ 240 per m² ka hai. Kul kharcha nikaalo.

      ₹
      Solution dikhao

      104.5×240=25 080, yaani ₹ 25 080.

  8. NumericalMediumNCERT Exercise 12.1, Q8

    Agarbatti ka stand lakdi ka ek solid cylinder hai, radius 3 cm aur height 10 cm. Uske top mein radius 3 cm aur gehraai 4 cm ka ek conical hollow kaata gaya hai. Stand ka total surface area nikaalo.

    cm²
    Solution dikhao

    Hollow ki slant height: l=9+16=5 cm.

    TSA =2πrh+πr2+πrl=π(60+9+15)=84π.

    84×227=264 cm2.

  9. NumericalHardNCERT Exercise 12.1, Q9

    Ek carpenter lakdi ka ek solid cylinder banata hai, 14 cm chauda aur 20 cm uncha. Har flat end ke centre se woh 7 cm chauda ek hemisphere khod deta hai. Taiyaar cheez ka total surface area kitna hai?

    cm²
    Solution dikhao

    R=7 cm, r=3.5 cm. Side: 2πRh=280π.

    Dono end rings: 2π(R2−r2)=2π(49−12.25)=73.5π.

    Dono hollows: 2×2πr2=49π.

    Kul =402.5π=402.5×227=1265 cm2.

  10. Quick answerEasy

    Radius r ka ek hemisphere ek cube ke ek face par laga hai, aur cube ka edge isse bada hai: 2r. Solid ka TSA hai cube ka TSA

    Answer dekho

    Answer (B) plus πr2

    Yeh face ka πr2 chhupata hai aur jodta hai 2πr2, yaani net +πr2. 3πr2 jodna galti se hemisphere ka poora TSA le leta hai.

12.3 Solids ke Combination ka Volume

Surface area nakhrewala hai: solids judne par faces gayab ho jaate hain. Volume aisa nahi hai. Cylinder ke andar ki har thodi si jagah naye solid ke andar bhi hai, aur hemisphere ke andar ki bhi. Kuch chhupta nahi aur kuch do baar nahi gina jaata. Isliye combined solid ka volume (आयतन) bas uske parts ke volumes ka sum hai (Fig. 12.8).

2/3Jodne par tank mein aata hai V1+V2. Joint par koi jagah nahi jaati.

Fig. 12.8Jodne se volumes judte hain; khodne se ghatte hain.

Step 1 mein left par V1 likha ek cylinder hai aur right par V2 likha ek hemisphere, flat face upar. Step 2 hemisphere ko cylinder ke neeche le jaata hai aur gol bottom wala tank banata hai, jis par jude: jodo, V = V1 + V2 likha hai. Step 3 hemisphere ko cylinder ke top ke andar le jaata hai aur use khaali dashed hollow ki tarah dikhata hai, jis par khoda: ghatao, V = V1 minus V2 likha hai.

Combined solid ka volume
V=V1+V2
(12.3)
jahan
V1,V2
do parts ke volumes (hollow ho to ghatao: V=V1−V2)

Jab solid ek container ho, to uske andar ki jagah ka volume uski capacity (धारिता) hai. Capacities aksar litres mein di jaati hain: 1 L=1000 cm3 aur 1 m3=1000 L. Volume nikaalne ke baad, bilkul aakhir mein convert karo.

1/3Chaudaai 14 m, lambai 20 m, deewar ki height 3 m.

Fig. 12.9Polyhouse ek cuboid hai jiske upar aadha cylinder hai.NCERT Fig. 12.12 · p. 167

Ek lamba greenhouse tircha bana hai. Uski deewarein 14 m chauda, 20 m lamba aur 3 m uncha cuboid banati hain, aur uski curved plastic chhat 14 m diameter ka aadha cylinder hai jo lambai ke saath leta hai. Step 1 measurements deta hai. Step 2 wahan dashed line banata hai jahan deewarein chhat se milti hain aur do parts par cuboid aur half cylinder likhta hai. Step 3 andar do uthi hui plant beds aur ek worker jodta hai, saath mein note: air equals total volume minus beds and tools minus workers.

Example 12.5NCERT Example 5 · p. 167

Polyhouse mein hawa

Ek kisaan ke polyhouse (plastic se dhaka greenhouse) ki seedhi deewarein 20 m lamba, 14 m chauda aur 3 m uncha cuboid banati hain. Uski chhat 14 m diameter ka aadha cylinder hai jo poori lambai tak chalta hai (Fig. 12.9).

(a) Khaali hone par usmein kitni hawa hoti hai? (b) Kaam ke din beds, pots aur tools ki jagah hai 160 m3, aur andar ke 12 log har ek lagbhag 0.07 m3 jagah lete hain. Kitni hawa bachti hai? Lo π=227.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1/3Andar ka diameter 8 cm, andar ki height 6 cm.

Fig. 12.10Raised base ki wajah se tub mein jitna lagta hai usse kam aata hai.NCERT Fig. 12.13 · p. 168

Cylinder ki shape ka ek tub, 8 cm chauda aur 6 cm gehra. Step 1 tub ko bahar se uske measurements ke saath dikhata hai. Step 2 dashed lines mein dikhata hai ki uska base 1.5 cm unche cone ki shape mein upar uthaya gaya hai, jis par raised base likha hai. Step 3 sirf cone ke upar ki jagah bharta hai, jo tub mein sach mein aata hai, aur us par asli capacity likha hai, saath mein formula pi r squared h minus one third pi r squared h1.

Example 12.6NCERT Example 6 · p. 168

Dikhne wali aur asli capacity

Ek mithai ki dukaan rabri ko cylindrical tubs mein pack karti hai, jinka andar ka diameter 8 cm aur andar ki height 6 cm hai. Har tub ka bottom ek cone ki shape mein upar uthaya gaya hai, jiska base wahi 8 cm ka hai aur height 1.5 cm (Fig. 12.10). Tub ki dikhne wali capacity aur asli capacity nikaalo. Use karo π=3.14.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1/3Length 16 mm, diameter 6 mm.

Fig. 12.11Khaali kone hain pocket minus capsule.NCERT Fig. 12.14 · p. 169

Ek capsule side par leta hai: ek cylinder jiske dono ends par ek-ek hemisphere hai, kul 16 mm lamba aur 6 mm chauda, do hisson mein do rang. Step 1 measurements deta hai. Step 2 uske chaaron taraf ek dashed cylinder banata hai, yaani blister pocket, jo capsule jitna hi lamba aur chauda hai. Step 3 capsule ke gol ends aur pocket ke beech ke chaar khaali kono par stripes lagaata hai, jis par gap equals pocket minus capsule likha hai.

Example 12.7NCERT Example 7 · p. 169

Blister mein capsule

Ek capsule ek cylinder hai jiske dono ends par ek-ek hemisphere hai. Yeh kul 16 mm lamba hai aur iska diameter 6 mm hai, aur yeh cylinder ki shape ke blister pocket mein baitha hai jo ise theek se gher leta hai (Fig. 12.11). Nikaalo (a) capsule ka volume aur (b) pocket mein bachi khaali jagah. Use karo π=3.14.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Volumes judte hain
4 mein se 1
Ek cone aur ek hemisphere, har ek ka volume 50 cm3, apne flat faces par jode gaye hain. Naye solid ka volume hai
Answer dekho

Answer (A) bilkul 100 cm3

Volumes bilkul jud jaate hain: joint par koi jagah nahi jaati. Sirf surface area chhupe faces kho deta hai, isiliye 100 se kam chunne ka mann karta hai.
Practice · 9 questions

Practice 12.2: answers ke saath

Jab tak question kuch aur na kahe, lo π=227.

  1. Short answerMediumNCERT Exercise 12.2, Q1

    Lakdi ke ek ghoomne wale toy ka base radius r ka hemisphere hai aur uske flat face par height 2r ka cone laga hai. Lo r=3 cm.

    1. Toy ka volume nikaalo, π ko symbol hi rehne do.

      Solution dikhao

      Answer36π cm3

      23πr3+13πr2(2r)=43πr3.

      Jab r=3: 43π×27=36π cm3.

    2. Dikhao ki yeh us sphere ke volume ke barabar hai jiska radius hai r.

      Solution dikhao

      23πr3+23πr3=43πr3, yaani sphere ka volume. Height 2r wale cone ka volume bilkul gaayab upar wale hemisphere jitna hai.

  2. NumericalMediumNCERT Exercise 12.2, Q2

    Kaagaz ki Diwali lantern (आकाश कंदील) ek cylinder hai jiske dono ends par ek-ek cone hai. Yeh 28 cm chaudi aur kul 60 cm lambi hai, aur har cone 12 cm uncha hai. Iske andar ki hawa ka volume nikaalo.

    cm³
    Solution dikhao

    r=14 cm; cylinder ki length hai 60−24=36 cm.

    Cylinder: πr2×36. Do cones: 2×13πr2×12=πr2×8.

    V=227×196×44=27 104 cm3.

  3. NumericalMediumNCERT Exercise 12.2, Q3

    Patli Diwali candles moulds mein dhaali jaati hain. Har candle 1.4 cm diameter aur 10 cm length ka cylinder hai jiske upar 3 cm height ka cone hai. Girne-bikharne ke liye lagbhag 10% extra wax pighlaya jaata hai. 50 candles ke liye kitna wax pighlana padega?

    cm³
    Solution dikhao

    r=0.7 cm. Ek candle: πr2(10+33)=227×0.49×11=16.94 cm3.

    50 candles: 847 cm3. 10% extra ke saath: 847×1.1=931.7 cm3.

  4. NumericalMediumNCERT Exercise 12.2, Q4

    Tyohaar ke laddoos ke liye lakdi ki ek tray 21 cm × 14 cm × 4 cm ka cuboid hai. Uske top mein chhe hemispherical hollows khode gaye hain, har ek ka radius 2.1 cm. Tray mein kitni lakdi bachi hai?

    cm³
    Solution dikhao

    Cuboid: 21×14×4=1176 cm3.

    Ek hollow: 23×227×2.13=19.404 cm3; chhe: 116.424 cm3.

    Lakdi =1176−116.424≈1059.58 cm3.

  5. NumericalMediumNCERT Exercise 12.2, Q5

    Purani kahaani ke pyaase kauwe ki tarah, Meena radius 1 cm ke spherical kankad radius 4 cm ke cylindrical matke mein daalti hai, jismein thoda paani bhara hai. Saare kankad doob jaate hain. Kitne kankad paani ko 2.5 cm upar uthayenge?

    Solution dikhao

    Upar utha paani =π×42×2.5=40π cm3.

    Ek kankad =43π×13=43π cm3.

    Number =40π÷43π=30.

  6. NumericalMediumNCERT Exercise 12.2, Q6

    Gym ka ek dumbbell solid iron ka hai: radius 6 cm aur motaai 3 cm ki do barabar discs (cylinders), jo radius 1.5 cm aur length 12 cm ke cylindrical handle se judi hain. Iron ki density lagbhag 7.8 g per cm³ hai. Use karo π=3.14.

    1. Iron ka volume nikaalo.

      cm³
      Solution dikhao

      Discs: 2×π×36×3=216π. Handle: π×2.25×12=27π.

      Kul =243π=763.02 cm3.

    2. Uska mass kg mein nikaalo, do decimal places tak.

      kg
      Solution dikhao

      763.02×7.8=5951.556 g≈5.95 kg.

  7. NumericalHardNCERT Exercise 12.2, Q7

    Radius 35 cm aur height 100 cm ka ek cylindrical drum kinaare tak paani se bhara hai. Ek solid, jo same radius ke hemisphere par ek cylinder (radius 21 cm, height 50 cm) se bana hai, gol end neeche rakh kar andar utaara jaata hai jab tak woh bottom ko na chhoo le, aur paani bahar gir jaata hai. Drum mein kitne litres bachte hain?

    L
    Solution dikhao

    Drum: 227×352×100=385 000 cm3.

    Solid: πr2(50+23×21)=227×441×64=88 704 cm3.

    Yeh 71 cm uncha hai, isliye poora paani mein dooba hai.

    Bacha =296 296 cm3≈296.3 L.

  8. NumericalMediumNCERT Exercise 12.2, Q8

    Mitti ki ek surahi ka body sphere ki shape ka hai jiska andar ka diameter 18 cm hai, aur uski cylindrical gardan ka andar ka diameter 4 cm aur length 10 cm hai. Bechne wala kehta hai ki ismein 3.5 litres aata hai. Gardan ko sphere ke upar alag cylinder maan kar iski capacity litres mein, do decimal places tak, nikaalo. Kya bechne wala sahi hai? Use karo π=3.14.

    L
    Solution dikhao

    Body: 43×3.14×93=3052.08 cm3.

    Gardan: 3.14×22×10=125.6 cm3.

    Kul =3177.68 cm3≈3.18 L. 3.5 L ka daawa zyada hai.

  9. Quick answerEasy

    Ek hemispherical hollow, jiska volume 60 cm3 hai, ek solid cylinder mein se khoda gaya hai jiska volume hai 500 cm3. Bache hue solid ka volume hai

    Answer dekho

    Answer (C) 440 cm3

    Hollow ghatata hai: 500−60=440 cm3. (Iske ulat, surface area badh jaata hai.)

12.4 Summary

Recap

Summary aur key points

  1. Combination of solids basic solids ko jod kar banta hai: cuboid, cube, cylinder, cone, sphere aur hemisphere (Section 12.1).
  2. Cone ki curved surface mein slant height use hoti hai, l=r2+h2 ((12.1)).
  3. Combined solid ka TSA sirf un surfaces ko ginta hai jo bahar rehti hain. Chipke flat faces dono parts par chhup jaate hain (Key idea).
  4. Capsule ka TSA hai 4πr2+2πrh ((12.2)).
  5. Flat face par chipka hemisphere chhupata hai πr2 aur jodta hai 2πr2, yaani net faayda πr2 (Example 12.2).
  6. Jab chhota face bade face par baithta hai, to bachi hui ring π(R2−r2) ab bhi dikhti hai (Example 12.3).
  7. Khoda gaya hollow ek flat circle hata deta hai par apna curved andar ka hissa jod deta hai, isliye surface area badhta hai (Key idea).
  8. Combined solid ka volume uske parts ke volumes ka sum hai; hollow ya raised base ko ghataya jaata hai ((12.3)).
  9. Capacity container ke andar ki jagah ka volume hai: 1 L=1000 cm3 aur 1 m3=1000 L (Section 12.3).
  10. Question mein di gayi π ki value use karo, aur aakhri line tak π ko symbol hi rehne do (Section 12.1).

3/3Hollow: uska volume ghatao, par uski andar ki surface jodo.

Fig. 12.12Combined solids ke teen rules.

Teen cards ek-ek karke aate hain. Pehla, Surface, hemisphere se jude cone ko dikhata hai jiska chhupa joint dashed hai, aur kehta hai jo dikhe, jodo, jude face chhodo. Doosra, Volume, hemispherical base par cylinder dikhata hai aur kehta hai parts jodo, kuch nahi khota. Teesra, Hollow, ek cylinder dikhata hai jiske top mein dashed hemispherical hollow hai, aur kehta hai volume: ghatao, area: andar jodo.

Flash cards · 6

Quick recall

1 / 6

Board-exam practice

Yeh questions CBSE board paper ke formats par hain: multiple choice, assertion–reason, short answer, long answer aur ek case study.

Practice · 8 questions

Practice questions answers ke saath (NCERT “Board-exam practice”)

Jab tak question kuch aur na kahe, lo π=227.

  1. Quick answerEasy

    Do cubes, har ek ka edge 4 cm, face se face jode gaye hain. Bane hue cuboid ka total surface area hai

    Answer dekho

    Answer (B) 160 cm2

    Har cube ka hai 96 cm2; jodne se do faces chhup jaate hain: 192−32=160 cm2. 192 chhupe faces ko bhool jaata hai.
  2. Quick answerEasy

    Radius r aur height k ka ek cone same radius ke cylinder par khada hai, jiski height hai h. Solid ka volume hai

    Answer dekho

    Answer (C) πr2(h+k3)

    πr2h+13πr2k=πr2(h+k3).
  3. Quick answerMedium

    Ek solid cylinder ka radius r hai aur height 2r, aur uske dono ends se radius r ka ek-ek hemisphere khoda gaya hai. Bacha hua volume hai

    Answer dekho

    Answer (A) 23πr3

    2πr3−43πr3=23πr3.
  4. Quick answerEasy

    Assertion (A): Ek cone same radius ke hemisphere par laga hai. Solid ka TSA cone ke CSA plus hemisphere ke CSA ke barabar hai. Reason (R): Jo do flat circular faces jude hain, woh solid ke bahar nahi hain.

    Answer dekho

    Answer (A) A aur R dono true hain, aur R, A ka sahi explanation hai.

    Dono true hain, aur chhupe flat faces hi wajah hain ki sirf do curved surfaces gini jaati hain.
  5. Quick answerMedium

    Assertion (A): Jab do solids jode jaate hain, to naye solid ka volume unke volumes ke sum se kam hota hai. Reason (R): Jab do solids jode jaate hain, to unki surfaces ka kuch hissa chhup jaata hai.

    Answer dekho

    Answer (D) A false hai, lekin R true hai.

    Volumes bilkul jud jaate hain, isliye A false hai. R true hai: isi wajah se surface areas seedhe nahi judte.
  6. Short answerMedium

    Ek solid radius 7 cm aur height 10 cm ka cylinder hai jiske upar same radius aur height 24 cm ka cone hai.

    1. Iska total surface area nikaalo.

      cm²
      Solution dikhao

      l=72+242=25 cm.

      TSA =2πrh+πr2+πrl=π(140+49+175)=364π.

      364×227=1144 cm2.

    2. Iska volume nikaalo.

      cm³
      Solution dikhao

      πr2(h+k3)=π×49×18=882π.

      882×227=2772 cm3.

  7. Long answerHard

    Gaon ki ek water tank radius 3 m aur height 7 m ka cylinder hai, jiska bottom same radius ka hemisphere hai aur dhakkan flat hai. Use karo π=3.14.

    1. Iski capacity litres mein nikaalo.

      L
      Solution dikhao

      V=πr2h+23πr3=π(63+18)=81π.

      81×3.14=254.34 m3=254 340 L.

    2. Iski curved surfaces ke bahar ₹ 45 per m² ki dar se paint hota hai. Kharcha nikaalo.

      ₹
      Solution dikhao

      Area =2πrh+2πr2=π(42+18)=60π=188.4 m2.

      188.4×45=8478, yaani ₹ 8478.

    3. Har ghar ek din mein 450 L use karta hai. Ek bhari tank kitne gharon ko ek din ka paani de sakti hai?

      Solution dikhao

      254 340÷450=565.2, yaani 565 ghar.

  8. Long answerMedium

    Case study. Ek mithai ki dukaan do gol gulab jamun andar ke radius 4.2 cm wali hemispherical steel ki katori (कटोरी) mein deti hai aur katori ko kinaare tak chaashni se bhar deti hai. Har gulab jamun radius 1.4 cm ka sphere hai.

    1. Katori ki capacity nikaalo.

      cm³
      Solution dikhao

      23πr3=23×227×4.23=155.232 cm3.

    2. Ek serving mein kitni chaashni hai?

      cm³
      Solution dikhao

      Do gulab jamun: 2×43π(1.4)3≈23.00 cm3.

      Chaashni ≈155.23−23.00=132.23 cm3.

    3. Katori ke bahar nakkashi ki jaati hai. Uska bahar ka radius bhi 4.2 cm maan kar nakkashi wala area nikaalo.

      cm²
      Solution dikhao

      2πr2=2×227×17.64=110.88 cm2.

    4. Chaashni radius 7 cm aur height 20 cm ke cylindrical tin se aati hai. Ek tin se kitni poori servings bhar sakti hain?

      Solution dikhao

      Tin =227×49×20=3080 cm3.

      3080÷132.23≈23.3, yaani 23 poori servings.

Apna NCERT exercise question dhoondo

Hamare practice questions ncert.ai ke liye likhe gaye hain aur NCERT exercises ko follow karte hain. Apni textbook ke question se match karne wala question dhoondo; uska answer uske saath hai.

Tumhari NCERT textbook meinYahan practice question
NCERT Exercise 12.1, Q1Practice 12.1 · Q1
NCERT Exercise 12.1, Q2Practice 12.1 · Q2
NCERT Exercise 12.1, Q3Practice 12.1 · Q3
NCERT Exercise 12.1, Q4Practice 12.1 · Q4
NCERT Exercise 12.1, Q5Practice 12.1 · Q5
NCERT Exercise 12.1, Q6Practice 12.1 · Q6
NCERT Exercise 12.1, Q7Practice 12.1 · Q7
NCERT Exercise 12.1, Q8Practice 12.1 · Q8
NCERT Exercise 12.1, Q9Practice 12.1 · Q9
NCERT Exercise 12.2, Q1Practice 12.2 · Q1
NCERT Exercise 12.2, Q2Practice 12.2 · Q2
NCERT Exercise 12.2, Q3Practice 12.2 · Q3
NCERT Exercise 12.2, Q4Practice 12.2 · Q4
NCERT Exercise 12.2, Q5Practice 12.2 · Q5
NCERT Exercise 12.2, Q6Practice 12.2 · Q6
NCERT Exercise 12.2, Q7Practice 12.2 · Q7
NCERT Exercise 12.2, Q8Practice 12.2 · Q8

Quick check: MCQs

  1. Warm-up: basic solids3 questions
  2. Dikhne wali surfaces4 questions
  3. Volumes judte hain4 questions
Glossary · 8

Key terms (English + Hindi)

capacityधारिताdhaarita
Container ke andar ki jagah ka volume, aksar litres mein diya jaata hai.Chapter mein pehli baar yahan aaya →
combination of solidsठोसों का संयोजनthoson ka sanyojan
Do ya zyada basic solids ko jod kar bana solid, jaise hemisphere par laga cone.Chapter mein pehli baar yahan aaya →
curved surface areaवक्र पृष्ठीय क्षेत्रफलvakra prishthiya kshetraphal
Solid ki surface ke sirf curved hisse ka area, uske flat faces ko chhod kar.Chapter mein pehli baar yahan aaya →
densityघनत्वghanatva
Per unit volume mass. Iron ki density lagbhag 7.8 g per cm³ hai.Chapter mein pehli baar yahan aaya →
hemisphereअर्धगोलाardhgola
Sphere ka aadha hissa, jo uske centre se kaata gaya ho. Iski curved surface 2πr2 hai aur flat face hai πr2.Chapter mein pehli baar yahan aaya →
slant heightतिर्यक ऊँचाईtiryak oonchai
Cone ki dhalaan wali side ke saath tip se base ke rim tak ki lambai: l=r2+h2.Chapter mein pehli baar yahan aaya →
total surface areaकुल पृष्ठीय क्षेत्रफलkul prishthiya kshetraphal
Solid ki poori bahari surface ka area: uske curved parts aur flat faces milakar.Chapter mein pehli baar yahan aaya →
volumeआयतनaayatan
Solid jitni jagah gherta hai, cubic units jaise cm³ mein naapa jaata hai.Chapter mein pehli baar yahan aaya →

Tum chapter ke end tak pahunch gaye