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PhysicsCh 1 Units aur Measurement

Units and Measurement: Class 11 Physics Chapter 1 Hinglish mein

Physics Part 1 · Hinglish notes, simulations aur practice · Official NCERT chapter PDF ↗

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  • 80 min
  • 1 simulation
  • 25 practice questions
  • 25 MCQs

Is chapter mein aap kya seekhenge

  • Samjhana ki unit kya hoti hai, aur base quantities, derived quantities aur systems of units mein fark karna
  • Saat SI base quantities aur unki units ke naam batana, aur plane aur solid angles ko radians aur steradians mein naapna
  • Significant figures ginna, values ko scientific notation mein likhna aur order of magnitude ka estimate lagaana
  • Products, quotients, sums aur differences ke liye significant-figure rules lagaana, aur sahi tarah round off karna
  • Measured values se calculate kiye gaye result ki uncertainty ka estimate lagaana
  • Physical quantities ke dimensional formulae aur dimensional equations likhna
  • Dimensional analysis se equations check karna, units convert karna aur relations nikaalna, aur iski limits batana

NCERT Physics Class 11, Chapter 1, pp. 1–12 par based original companion text. Yeh NCERT se juda nahi hai aur NCERT ne ise endorse nahi kiya hai.

1.1 Introduction

Kolkata ka ek tailor note karta hai ki sleeve 58 cm lambi honi chahiye. Pune ka ek pharmacist kisi powder ka 250 mg taulta hai. Dono ek hi kaam kar rahe hain: ek quantity ko ek agreed standard se compare karna aur ginna ki woh standard usmein kitni baar fit hota hai. Wahi standard unit (मात्रक) hai. Poori physics aise hi comparisons par tiki hai, isliye hum units se shuru karte hain, aur is baat se ki kisi measured number par kitna bharosa kiya ja sakta hai.

Isliye ek measured result ke do parts hote hain: ek pure number, yaani uska numerical measure, aur ek unit. “Corridor 40 hai” se kuch pata nahi chalta; “corridor 40 m hai” ek measurement hai. Agar tum chhoti unit par switch karte ho, to number usi proportion mein badh jaata hai, taaki dono ka product same rahe (Fig. 1.1):

Unit badalna
n1u1=n2u2
(1.1)
jahan
n1,n2
dono numerical measures
u1,u2
dono units

Jaise, 2.5 m hi 250 cm bhi hai: unit 100 guna chhoti hui aur number 100 guna bada.

3/3Unit B aadhi lambi hai aur 6 baar fit hoti hai: 3uA=6uB.

Fig. 1.1Ek hi length do units mein naapi gayi. Unit ko aadha karne se number double ho jaata hai.

Figure ke upar ek plank rakha hai. Pehle step mein woh akela hai, saath mein sawaal hai ki woh kitni units lamba hai. Doosre step mein A likhe teen barabar blocks uske neeche ek ke baad ek rakhe hain aur theek uski length ke barabar hain, isliye n barabar 3. Teesre step mein B likhe chhe chhote blocks, har ek A se aadha lamba, bhi plank ke barabar aate hain, isliye n barabar 6, aur label 3 u A barabar 6 u B dikhata hai ki number guna unit nahi badalta.

Speed distance divided by time hai. Density mass divided by volume hai. Force mass times acceleration hai. Kyunki physical quantities aise judi hoti hain, isliye sabke liye kuch hi independent standards kaafi hain. Hum kuch base quantities chunte hain (inhe fundamental quantities bhi kehte hain), jaise length, mass aur time, aur har ek ke liye ek base unit tay karte hain. Baaki har unit base units ko multiply aur divide karke banti hai; yeh derived units (व्युत्पन्न मात्रक) hain, jaise metre per second. Base units ka ek chuna hua set, unse banne wali saari derived units ke saath, system of units kehlata hai (Fig. 1.2).

4/4Mass × acceleration se force milta hai: 1 kg m s−2 ko newton (N) kehte hain.

Fig. 1.2Derived units base units ko multiply aur divide karke banti hain.

Left mein teen boxes mein base quantities hain: length metres mein, time seconds mein aur mass kilograms mein. Doosre step mein length se ek arrow area ke box tak jaata hai, square metres mein. Teesre step mein length aur time se arrows speed tak jaate hain, metres per second mein, aur divide by time likha ek aur arrow acceleration tak jaata hai, metres per second squared mein. Chauthe step mein mass aur acceleration se arrows force tak jaate hain, kilogram metre per second squared mein, jiska naam newton hai.

Definition
Unit

Kisi physical quantity ki ek fixed amount, jis par poori duniya sehmat hai, aur jo us quantity ka paimaana hai. Measure karne ka matlab hai yeh pata karna ki quantity mein aisi kitni units hain.

Example1.5 kg chawal mein 1.5 numerical measure hai aur kilogram unit hai.

Quick check
3 mein se 1
Ek rod 3.6 m lambi hai. Metre se 4 guna lambi unit mein uska numerical measure kya hai?
Answer dekho

Answer (B) 0.9

Badi unit kam baar fit hoti hai: n2=n1u1/u2=3.6×1/4=0.9. 4 se multiply karna (jisse 14.4 aata hai) nayi unit ko aise treat karta hai jaise woh chhoti ho.

1.2 International system of units

Beesvi sadi ke beech tak alag-alag desh, aur science ki alag-alag branches bhi, alag systems mein naapti thin. Teen systems khaas taur par common the. Unmein length, mass aur time ke liye chuni gayi base units alag thin (Table 1.1).

Table 1.1Chaar systems mein length, mass aur time ki base units. SI MKS ki teen units rakhta hai aur chaar aur base units jodta hai.
SystemLengthMassTime
CGScentimetregramsecond
FPS (British)footpoundsecond
MKSmetrekilogramsecond
SImetrekilogramsecond

Aaj lagbhag poori duniya ek hi system use karti hai, Système International d'Unités (French mein International System of Units), yaani SI. Ise 1960 mein General Conference on Weights and Measures (CGPM) ki ek meeting mein apnaya gaya; CGPM ek intergovernmental body hai jiske saath Paris ke paas BIPM, yaani International Bureau of Weights and Measures, kaam karta hai. SI ko apni maujooda saat base units 1971 mein mili, jab mole joda gaya. November 2018 mein CGPM ne saaton units ko constants of nature ki fixed values ke terms mein dobara define kiya, aur nayi definitions 20 May 2019 se laagu hui. SI multiples powers of ten mein chalte hain, isliye millimetres, metres aur kilometres ke beech convert karne mein sirf decimal point khiskaana padta hai. Ab se is book mein har quantity SI units mein hai, jab tak hum kuch aur na kahein.

Table 1.2Saat SI base quantities aur units. 2019 se har unit kisi constant of nature ki ek exact value declare karke fix ki jaati hai. In values ko yaad karne ki zaroorat nahi hai.
Base quantityUnitSymbolDefine karne wala constant (exact value)
Lengthmetremvacuum mein light ki speed, c=299 792 458 m s−1
MasskilogramkgPlanck constant, h=6.626 070 15×10−34 J s
Timesecondscaesium-133 ki hyperfine frequency, ΔνCs=9 192 631 770 Hz
Electric currentampereAelementary charge, e=1.602 176 634×10−19 C
Thermodynamic temperaturekelvinKBoltzmann constant, k=1.380 649×10−23 J K−1
Amount of substancemolemolAvogadro constant, NA=6.022 140 76×1023 mol−1
Luminous intensitycandelacd540×1012 Hz light ki luminous efficacy, Kcd=683 lm W−1

Ek constant kisi unit ko kaise define kar sakta hai? Metre ko lo. Vacuum mein light hamesha same speed se chalti hai, aur SI bas declare kar deta hai ki woh speed exactly 299 792 458 metres per second hai. Tab ek metre woh distance hai jo light ek second ke 1/299 792 458 hisse mein tay karti hai. Koi bhi achhi equipped laboratory ise bana sakti hai, kisi master rod se milaane ki zaroorat nahi. Baaki units bhi isi tarah fix ki jaati hain: second caesium atom ki ek frequency se, kilogram Planck constant ke through, aur isi tarah aage.

Mole ke baare mein ek savdhaani: hamesha batao ki tum kaun si entities gin rahe ho. Hydrogen atoms ke ek mole aur hydrogen molecules ke ek mole, dono mein lagbhag 6.022×1023 particles hote hain, lekin doosre ka mass pehle ka double hai.

Baaki har unit in saat se derive hoti hai. Kai derived units ke khaas naam hain, jaise newton (force), joule (energy), watt (power), pascal (pressure) aur hertz (frequency). SI ke bahar ki kuch units itni convenient hain ki woh iske saath use hoti rehti hain (Table 1.3): kheti ki zameen hectare mein bikti hai, anaaj ke daam per quintal bataye jaate hain, aur diamonds carats mein taule jaate hain.

Table 1.3SI ke saath use hone wali kuch units.
UnitSymbolSI units mein value
minutemin60 s
hourh3600 s
dayd86 400 s
degree (angle)°(π/180) rad
litreL10−3 m3
tonnet103 kg
quintalq100 kg
hectareha104 m2
carat (gems)ct2×10−4 kg
barbar105 Pa
standard atmosphereatm101 325 Pa
astronomical unitau1.496×1011 m
electronvolteV1.602×10−19 J

Prefixes kisi unit ko powers of ten se scale karte hain (Table 1.4). Symbols kuch fixed rules follow karte hain, jinse likhi hui value duniya mein har jagah bina confusion ke padhi jaati hai:

Table 1.4SI prefixes jo tum sabse zyada use karoge.
PrefixSymbolFactor
teraT1012
gigaG109
megaM106
kilok103
centic10−2
millim10−3
microµ10−6
nanon10−9
picop10−12
femtof10−15
  • Unit symbols seedhe (upright) print hote hain aur unmein kabhi plural s ya full stop nahi lagta: 5 kg, 5 kgs nahi.
  • Number aur symbol ke beech space chhodo, jaise 3 m ya 25 °C mein; sirf angle ke signs exception hain, jaise 30°.
  • Logon ke naam par rakhi gayi units ke symbols capital hote hain (N, Pa, W), lekin naam khud lower case mein likhe jaate hain (newton, pascal, watt).
  • Ek baar mein ek hi prefix use karo: 1 ng likho, 1 mµg nahi; prefix aur uski unit milkar ek hi symbol banate hain, isliye km² ka matlab (km)² hai.

Plane angle aur solid angle

Do aur SI units angles naapti hain. Plane angle do lines ke beech ka khulaav hai jo ek point par milti hain. Us point ke around radius r ka ek circle banao; lines length s ka ek arc kaat deti hain. Angle ko is ratio se define kiya jaata hai

Plane angle
θ=sr
(1.2)
jahan
s
arc ki length
r
circle ka radius

Iski unit radian (rad) hai. Ek radian woh angle hai jiska arc radius ke barabar ho. Poore chakkar ka arc 2πr hota hai, isliye poora chakkar 2π rad hai, aur 1 rad=180∘/π≈57.3∘. Kyunki θ ek ratio hai, isliye isse fark nahi padta ki tum kitna bada circle banate ho (Fig. 1.3).

3/3Jab arc radius ke barabar ho, to angle 1 rad≈57.3∘ hota hai.

Fig. 1.3Angle arc aur radius ka ratio hai, isliye yeh circle ke size par depend nahi karta.NCERT Fig. 1.1 · p. 2

Left mein ek point se do rays angle theta par nikalti hain. Pehle step mein radius r ka ek blue arc mark hai, jiski arc length s hai. Doosre step mein unhi rays ke beech radius 2r ka ek orange arc dikhta hai; uski length 2s hai, isliye arc aur radius ka ratio nahi badalta. Teesre step mein right mein ek alag drawing aisa angle dikhati hai jiski arc length uske radius r ke barabar hai; label kehta hai ki yeh angle 1 radian hai, lagbhag 57.3 degrees.

SimulationArc, radius aur angle

Ek circle jis par do points A aur B hain aur centre O se radii bane hain. Tum B ko circle par ek-ek degree ke steps mein drag kar sakte ho aur radius badalne ke liye ek handle drag kar sakte ho. Readouts angle AOB degrees mein, arc length AB aur chord AB centimetres mein, aur radius r dikhate hain, saath mein arc length ka formula bhi.

Fig. 1.4Angle badalne ke liye point B ko drag karo, aur circle ka size badalne ke liye radius handle ko drag karo. Arc AB ko radius r se compare karo.
Try karo
  • B ko tab tak drag karo jab tak arc AB radius ke barabar na ho jaaye. Angle kya dikhata hai? Ise 180° divided by π se compare karo.
  • Angle ko 90° par set karo, phir radius handle ko drag karo. Har baar arc AB ko r se divide karo: kya ratio badalta hai?
  • AB ko diameter bana do. Arc kitne radii lamba hai, aur angle kitne radians ka hai?

Solid angle iska three-dimensional version hai: ek cone ka khulaav, jaise torch ki beam. Cone ki nok ko radius r ke sphere ke centre par rakho; cone sphere ki surface se area dA ka ek chhota patch kaat deta hai. Solid angle hai

Solid angle
dΩ=dAr2
(1.3)
jahan
dA
sphere par patch ka area
r
sphere ka radius

Iski unit steradian (sr) hai. Double size ke sphere par usi cone mein patch chaar guna bada hota hai, isliye ratio fixed rehta hai (Fig. 1.5). Poore sphere ka area 4πr2 hai, isliye ek point ke around saari directions milkar 4π sr≈12.6 sr banati hain. Radian aur steradian do lengths aur do areas ke ratios hain, isliye dono dimensionless hain: unka naam hai lekin koi dimension nahi.

2/3Radius 2r par patch ka area 4 dA hai, aur (2r)2=4r2: wahi solid angle.

Fig. 1.5Solid angle area divided by radius squared hai, isliye yeh sphere ke size par depend nahi karta.NCERT Fig. 1.1 · p. 2

Ek sphere bana hai jiska centre O hai. Pehle step mein O se do lines ek patla cone banati hain jo radius r ke sphere par area dA ka ek chhota blue patch kaatta hai. Doosre step mein radius 2r ka ek sphere use gher leta hai, aur wahi cone chaar guna area ka ek orange patch kaatta hai, isliye solid angle nahi badalta. Teesre step mein poora chhota sphere shade hai aur label dikhata hai ki poora sphere 4 pi steradians subtend karta hai.

Quick check
4 mein se 1
Inmein se kaun si SI base unit nahi hai?
Answer dekho

Answer (A) newton

Newton ek derived unit hai, 1 N=1 kg m s−2. Candela aur mole anjaan lag sakte hain, lekin dono base units hain.

1.3 Significant figures

Ek hi pencil ko do rulers se naapo to tum alag-alag sankhya mein digits likhoge (Fig. 1.6). Sirf poore centimetres wale scale par pencil ka sira 7 aur 8 ke beech hai, aadhe se thoda pehle, isliye tum 7.4 cm record karte ho: 7 nishan se padha gaya aur 4 aankh se andaaza lagaya gaya. Millimetre marks wale scale par sira 7.4 aur 7.5 cm ke beech hai, aur tum ek aur digit ka andaaza laga sakte ho: 7.46 cm. Har reading mein aakhri digit ko chhod kar har digit seedhe scale se aata hai, aur aakhri ek dhyaan se lagaya gaya guess hai.

Kisi bhi measured value ko likhne ka yahi rule hai: saare digits jin par tumhe pakka bharosa hai, phir ek estimated digit, aur uske baad kuch nahi. Yeh sab milkar measurement ke significant figures (सार्थक अंक) hain. Tum imaandaari se kitne claim kar sakte ho, yeh instrument ke sabse chhote division, yaani uske least count (अल्पतमांक), par depend karta hai. Pencil ke liye 7.4613 cm likhna aisi precision ka claim hoga jo koi bhi ruler nahi de sakta.

3/3Significant figures = saare pakke digits + pehla estimated digit.

Fig. 1.6Scale jitna barik, utne zyada digits tum padh sakte ho. Tum jo aakhri digit likhte ho woh hamesha estimate hota hai.

Upar ek peeli pencil zero se shuru hokar rakhi hai, aur uski nok se ek dashed line neeche jaati hai. Pehle step mein sirf poore centimetres wala ruler nok ko 7 aur 8 ke beech dikhata hai, aur reading 7.4 centimetres dikhti hai jismein 4 estimated digit ke rang mein hai. Doosre step mein neeche millimetre marks wala ruler aata hai; nok 7.4 aur 7.5 ke beech hai, aur reading 7.46 centimetres ho jaati hai, ab 6 estimated digit hai. Teesre step mein 7.4 ke neeche ek bracket par sure likha hai aur 6 ke around ek box par estimated likha hai.

Kyunki yeh ginti measurement se tay hoti hai, isliye yeh us unit par depend nahi kar sakti jo tum likhte ho. Ek sikke ka mass 3.79 g hi 0.00379 kg bhi hai: extra zeros sirf decimal point khiskaate hain, aur dono forms mein teen significant figures hain. Yeh dhyaan mein rakhte hue, likhe hue number mein significant figures ginne ke rules yeh hain:

  1. Har non-zero digit significant hota hai. 3.47 mein teen significant figures hain.
  2. Non-zero digits ke beech ke zeros significant hote hain, decimal point chahe kahin bhi ho. 40.08 aur 4008 dono mein chaar hain.
  3. 1 se chhote number mein, pehle non-zero digit se pehle wale zeros nahi gine jaate, aur na hi woh zero jo aam taur par decimal point se pehle likha jaata hai. Yeh sirf decimal point ki jagah batate hain: 0.0036 mein do significant figures hain.
  4. Bina decimal point wale whole number ke aakhri zeros significant nahi hote. Is convention se 5600 m mein do significant figures hain.
  5. Decimal point ke baad aakhri zeros significant hote hain. 2.50 mein teen significant figures hain aur 0.07100 mein chaar.

4/5Aakhir ka zero, decimal point ke baad, naapa gaya tha: yeh gina jaata hai. Total: 4.

Fig. 1.7Shuru ke zeros kabhi nahi gine jaate. Beech ke zeros hamesha gine jaate hain. Aakhri zeros sirf decimal point ke baad gine jaate hain.

Number 0.005070 bade digits mein likha hai, har box mein ek. Doosre step mein pehle teen zeros fade hokar cross ho jaate hain aur unpar place-holders label hai, kyunki woh sirf decimal point ki jagah batate hain. Teesre step mein 5, 0 aur 7 wale boxes green ho jaate hain aur label kehta hai ki yeh gine jaate hain, kyunki zero non-zero digits ke beech hai. Chauthe step mein aakhri zero bhi green ho jaata hai, kyunki woh decimal point ke baad aata hai, aur total 4 significant figures padhta hai. Paanchve step mein whole number 5070 metres sirf 3 figures ke saath dikhaya gaya hai, bagal mein 5.070 times 10 cubed metres 4 figures ke saath.

Rule 4 asli information chhupa sakta hai. Ek groundsman boundary rope ko tape se 6500 cm naapta hai, nearest centimetre tak sahi, yaani chaaron digits naape gaye the. Phir bhi 6500 cm likhne par value mein sirf do significant figures lagte hain, kyunki uske zeros whole number ke aakhir mein hain. Unit ko metres mein badlo to wahi length 65.00 m padhti hai, jahan rule 5 se chaaron digits gine jaate hain. Zeros par khatam hone wala whole number yeh bata hi nahi sakta ki woh zeros naape gaye the ya nahi.

Scientific notation yeh shaq door karta hai. Value ko a×10b ki tarah likho, jahan 1≤a<10 aur b ek positive ya negative whole number hai. a ka har digit significant hai, aur power of ten sirf scale tay karta hai. Rope 6.500×103 cm hai, ya 6.500×10−2 km: kisi bhi unit mein chaar significant figures. Agar tape sirf nearest metre tak padha gaya hota, to tum 6.5×103 cm likhte. Scientific notation na ho to rules 4 aur 5 par chalo.

Formulas ke kuch numbers measurements hote hi nahi. Sphere ke surface area 4πr2 mein 4, 12mv2 mein 12, aur 1 min=60 s mein 60 exact hain. Aise numbers ko unlimited significant figures wala samjho (4 = 4.000…), isliye yeh kabhi result ki precision ko limit nahi karte. π=3.14159… jaise constants ko utne figures tak le sakte ho jitne data ko chahiye; aam taur par 3.14 ya 3.142 kaafi hai.

Scientific notation se size ka jaldi andaaza bhi milta hai. Agar a≤5 ho to a ko 1 par round karo, aur agar a>5 ho to 10 par. Tab value lagbhag ek single power of ten, 10n, hoti hai, aur hum kehte hain ki woh 10n ke order ki hai; exponent n uska order of magnitude (परिमाण की कोटि) hai.Kuch books 5 ki jagah 10≈3.16 par round karti hain. Hum NCERT ka rule follow karte hain; dono tab tak same answer dete hain jab tak a 3.16 aur 5 ke beech na ho. Mount Everest 8.849×103 m ooncha hai; kyunki 8.849>5, yeh 104 m ke order ka hai. Moon 3.84×108 m door hai, 108 m ke order ka. Isliye lagbhag 108/104=104 Everests, ek ke upar ek rakhe jaayein, to Moon tak pahunch jaayenge. Fig. 1.8 kuch aur lengths ko powers of ten ki isi seedhi par dikhata hai.

3/3Earth (107 m) aur Earth–Sun distance (1011 m): baal se 15 orders of magnitude aage.

Fig. 1.8Kuch lengths ke orders of magnitude. Har tick pichhle wale ka das guna hai.

Metres mein sizes ka ek horizontal axis left mein ten to the minus ten se right mein ten to the eleven tak jaata hai, har power of ten par ek tick. Pehle step mein ek atom, ek virus aur ek insaani baal ten to the minus ten, minus seven aur minus four par mark hain. Doosre step mein ek insaan aur ek cricket pitch ten to the zero aur ten to the one par dikhte hain. Teesre step mein Earth ka diameter aur Earth–Sun distance ten to the seven aur ten to the eleven par dikhte hain, aur baal se Earth–Sun distance tak ek bracket par ten to the fifteen times likha hai.

Quick check
4 mein se 1
0.03060 kg mein kitne significant figures hain?
Answer dekho

Answer (B) 4

Shuru ke zeros (0.0) sirf decimal point ki jagah tay karte hain. 3, beech ka 0, 6 aur decimal point ke baad aakhri 0, sab gine jaate hain: chaar. Har zero ko ginna (6) aam galti hai.

1.3.1 Significant figures ke saath arithmetic operations ke rules

Tum ek toy car ko 1.25 m par time karte ho aur 3.8 s aata hai. Calculator speed 0.328947368 m/s batata hai. Sirf pehle do digits ka koi matlab hai: time do figures tak pata tha, isliye speed 0.33 m/s hai. Calculate kiya gaya result kabhi bhi un measurements se zyada precise nahi ho sakta jinse woh bana. Do rules pakka karte hain ki use isi tarah report kiya jaaye.

PropertyMultiply aur divide karna

Result mein utne significant figures rehte hain jitne sabse kam significant figures wali measured value mein hain.

PropertyAdd aur subtract karna

Result mein utne decimal places rehte hain jitne sabse kam decimal places wali measured value mein hain.

Ek dukaandaar 12.6 kg chawal ki bori, jo 0.1 kg tak padhne wale platform scale par tauli gayi, ek carton mein 0.845 kg daal ke packet ke saath rakhta hai, jo 1 g tak padhne wale kitchen scale par taula gaya. Calculator 13.445 kg deta hai. Lekin bori ka mass kilogram ke hundredths ya thousandths ke baare mein kuch nahi batata, isliye sum ke woh columns bhi unknown hain (Fig. 1.9). Total 13.4 kg hai.

3/3Ek decimal place rakho: 13.4 kg.

Fig. 1.9Sum mein, jis column mein koi unknown digit ho, answer ka wahi column bhi unknown ho jaata hai.

Do masses, 12.6 aur 0.845 kilograms, ek ke neeche ek likhe hain aur unke decimal points ek line mein hain, aur unka sum 13.445 ek line ke neeche likha hai. Doosre step mein 12.6 ki khaali hundredths aur thousandths jagahon mein question marks aa jaate hain, aur un do columns ko shade karke unreliable label diya gaya hai. Teesre step mein sum ke aakhri do digits fade ho jaate hain aur answer 13.4 kilograms dikhta hai.

Yeh rule sach mein decimal places ka hai, significant figures ka nahi. Ek balance par ek bottle 152.37 g ki aati hai aur ek tablet 0.42 g ki. Dono gram ke hundredth tak pata hain, isliye total 152.79 g apne aakhri digit tak reliable hai, bhale hi 0.42 g mein sirf do significant figures hain; sum ko do figures tak round karna teen achhe digits ko phenk dena hoga. Subtraction ulta bhi kar sakta hai. Do clinical thermometers 36.8∘C aur 36.6∘C padhte hain, har ek mein teen significant figures, phir bhi unka difference, 0.2∘C, mein sirf ek hai. Lagbhag barabar do measurements ka chhota difference hamesha, relatively, kisi bhi ek measurement se kahin kam certain hota hai.

1.3.2 Uncertain digits ko round off karna

Calculation aam taur par utne digits se zyada deta hai jitne tum rakh sakte ho, isliye result ko round karna padta hai. Jab chhoda jaane wala hissa aakhri rakhi jagah ki aadhi unit se saaf taur par zyada ya kam ho, to rule wahi jaana-pehchaana hai: teen significant figures tak, 4.837 ban jaata hai 4.84 aur 4.832 ban jaata hai 4.83.

Dilchasp case tab hai jab chhoda jaane wala digit exactly 5 ho, jo theek beech mein hai. Aisi values ko hamesha upar round karne se results average mein upar khisak jaayenge. Convention yeh hai: agar 5 se pehle wala digit even hai, to use waise hi chhod do; agar odd hai, to use ek badha do. Isliye 6.125 round hokar 6.12 banta hai (2 even hai) aur 6.135 round hokar 6.14 (3 odd hai). Bahut saari roundings mein aadhe ties neeche jaate hain aur aadhe upar. Tie rule sirf tab lagta hai jab chhoda gaya hissa exactly 5 ho; 6.1251 aadhe se zyada hai aur upar round hokar 6.13 banta hai (Fig. 1.10).

3/36.125→6.12 (2 even hai) lekin 6.135→6.14 (3 odd hai).

Fig. 1.10Teen significant figures tak rounding. Ties even padosi ki taraf jaate hain.

Ek number line 6.12 se 6.14 tak jaati hai, har thousandth par chhote ticks aur 6.125 aur 6.135 par dashed halfway marks ke saath. Pehle step mein value 6.123 left mein 6.12 par kood jaati hai, kyunki aadhe se kam chhoda gaya. Doosre step mein 6.128 right mein 6.13 par kood jaati hai, kyunki aadhe se zyada chhoda gaya. Teesre step mein do halfway values dikhti hain: 6.125 neeche 6.12 par jaati hai kyunki 2 even hai, aur 6.135 upar 6.14 par jaati hai kyunki 3 odd hai.

Do aadatein picture poori karti hain. Kai steps wali calculation mein intermediate results mein ek extra digit rakho aur sirf final answer ko round karo; Section 1.3.3 dikhata hai ki warna kya galat hota hai. Aur constants ko sensible figures tak use karo: Avogadro constant 6.02214076×1023 mol−1 ko aam taur par 6.02×1023 mol−1 liya jaata hai, aur π ko 3.14 ya 3.142, taaki data ki precision se match kare. Neeche wala inspector tumhari type ki hui kisi bhi value ke significant figures ginta hai aur use round karta hai, theek inhi rules se.

InteractiveSignificant-figure inspector

Measured value ke liye ek text box, 0.005070, 3200 aur 6.125 jaise example buttons ke saath. Har digit apne box mein dikhta hai: gine jaane wale digits ki solid outline hai aur counts likha hai, shuru ke zeros dashed hain aur unpar place label hai, aur shaq wale aakhri zeros dotted hain aur unpar question mark hai. Cards significant figures ki sankhya, scientific notation mein value aur uska order of magnitude dikhate hain, saath mein use kiye gaye rules samjhane wala note. Ek menu value ko kam significant figures tak round karta hai aur rounding samjhata hai, exact 5 ke liye even-digit rule bhi.

Fig. 1.11Ek measured value type karo ya koi example chuno. Inspector gine jaane wale digits ko mark karta hai, value ko scientific notation mein likhta hai, uska order of magnitude nikaalta hai aur use round karta hai.
Example 1.1NCERT Example 1.1 · p. 6

Ball bearing ka surface area aur volume

Ek steel ball bearing ka radius 0.6150 cm hai, jo screw gauge se naapa gaya. Iska surface area aur volume sahi significant figures tak nikaalo.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Example 1.2NCERT Example 1.2 · p. 6

Marathon runner ki average speed

Ek runner marathon, 42.195 km, 2.1 h mein poori karti hai (sirf ghante ke nearest tenth tak time kiya gaya). Uski average speed sahi significant figures ke saath likho.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1.3.3 Arithmetic calculations ke results mein uncertainty nikaalne ke rules

Significant figures precision ka ek rough guide hain. Jab hume har measurement ki uncertainty pata ho, to hum isse behtar kar sakte hain aur calculate kiye gaye result ki uncertainty ka estimate laga sakte hain. Teen observations mein woh sab aa jaata hai jo tumhe chahiye.

(1) Product mein relative errors add hote hain. Mass m=2.50±0.01 kg ki ek trolley v=1.20±0.02 m/s par chalti hai. Har value ka relative error (आपेक्षिक त्रुटि) uski uncertainty divided by value hai: mass ke liye 0.01/2.50=0.4% aur speed ke liye 0.02/1.20=1.7%. Tab momentum p=mv=3.00 kg m/s mein lagbhag 0.4%+1.7%=2.1% ka relative error hota hai, jo 0.06 kg m/s hai. Isliye hum p=3.00±0.06 kg m/s report karte hain. Fig. 1.12 dikhata hai ki yeh rule kahan se aata hai, sabse aasaan product ki picture se, yaani rectangle ka area.

3/3Corner Δl Δb negligible hai, isliye ΔA/A=Δl/l+Δb/b.

Fig. 1.12Extra area lagbhag poora do strips se aata hai; corner do chhoti quantities ka product hai.

Ek green rectangle jiski length l neeche aur breadth b side mein hai, uska area A barabar l b hai. Doosre step mein right side ke saath width delta l ki ek patli strip judti hai, jiska area b delta l hai, aur upar height delta b ki ek patli strip, jiska area l delta b hai. Teesre step mein area delta l times delta b wala chhota corner square negligible ke roop mein highlight hota hai, aur result delta A over A barabar delta l over l plus delta b over b dikhta hai.

DerivationProduct ka relative error

Maan lo asli length aur breadth l±Δl aur b±Δb ke andar hain. Area zyada se zyada itna ho sakta hai

(l+Δl)(b+Δb)=lb+b Δl+l Δb+Δl Δb

Aakhri term do chhoti quantities ka product hai. 0.1 cm ke errors ke liye yeh 0.01 cm2 hai, baaki terms ke saamne negligible. Isliye area mein sabse bada error hai

ΔA=b Δl+l Δb
(1.4)

A=lb se divide karne par rule apne sabse kaam ke form mein milta hai:

Relative errors add hote hain
ΔAA=Δll+Δbb
(1.5)

Yahi result quotient l/b ke liye bhi sahi hai, kyunki worst case mein ek value zyada badi aur doosri zyada chhoti hoti hai. Square ke liye, l2=l×l, isliye relative error double ho jaata hai; cube ke liye teen guna.

(2) Sums aur differences mein absolute errors add hote hain. Length 25.4±0.1 cm ki ek rod se 3.86±0.01 cm kaata jaata hai. Bacha tukda zyada se zyada 25.5−3.85=21.65 cm lamba ho sakta hai ya kam se kam 25.3−3.87=21.43 cm, isliye yeh 21.54±0.11 cm hai: sirf 21.5 cm likhne layak hai. Badi uncertainty haavi rehti hai, isiliye sums aur differences ko sabse kam decimal places tak round kiya jaata hai, aur isiliye difference mein kisi bhi value se kam significant figures ho sakte hain.

(3) Barabar significant figures ka matlab barabar precision nahi hai. Ek stopwatch ek sprint start ke liye 2.05 s aur ek chhoti race ke liye 8.75 s padhti hai, dono ±0.01 s tak aur dono teen significant figures ke saath. Pehle ka relative error 0.01/2.05≈0.5% hai, doosre ka sirf 0.01/8.75≈0.1%. Significant figures ginna ek rough guide hai; relative error precision ka exact measure hai.

Aakhir mein, yeh rahi wajah ki tum intermediate steps mein ek extra digit kyun rakhte ho. Edge 1.27 m wale cube ka volume do steps mein nikaalo. Ek face ka area 1.6129 m2 hai; ise 1.61 m2 par round karo, edge se multiply karo, aur tumhe 2.0447≈2.04 m3 milta hai. Lekin asli volume, 1.273=2.048 m3, round hokar 2.05 m3 banta hai. Beech wale step mein chaar figures rakho, 1.613 m2, aur product 2.0485 sahi tarah 2.05 m3 par round hota hai.

Quick check
4 mein se 1
3.6 cm×1.452 cm ko sahi significant figures tak likho.
Answer dekho

Answer (A) 5.2 cm2

3.6 mein do significant figures hain, sabse kam, isliye product 5.2272 ko 5.2 cm2 report kiya jaata hai. Teen figures (5.23) rakhna kam precise factor ki jagah zyada precise factor ko follow karna hai.

1.4 Physical quantities ke dimensions

Do quantities size aur units mein bahut alag ho sakti hain aur phir bhi ek hi kism ki cheez ho sakti hain. Green light ki wavelength aur Mount Everest ki height, dono lengths hain. Snail ki speed aur light ki speed, dono length divided by time hain. Dimensions ka idea isi kism ko pakadta hai, aur size ko ignore karta hai.

Har physical quantity saat SI base quantities se banai ja sakti hai, isliye hum in saat ko basic dimensions maante hain aur har ek ko square brackets mein likhte hain: mass [M], length [L], time [T], amount of substance [mol], electric current [A], temperature [K] aur luminous intensity [cd]. Kisi quantity ko base quantities ke product ki tarah likho; har ek par jo exponent hai woh us base quantity mein uska dimension (विमा) hai, aur yeh saare exponents milkar quantity ke dimensions hain. Kisi symbol ke around square brackets, jaise [v], ko “v ke dimensions” padha jaata hai.

Mechanics mein inmein se teen kaafi hain: [M], [L] aur [T]. Kisi mechanical quantity ke dimensions nikaalne ke liye uski definition ko peeche mass, length aur time tak le jaao. Momentum mass times velocity hai, aur velocity length per unit time hai, isliye

Momentum ke dimensions
[p]=[M] [L][T]=[MLT−1]

Exponents seedhe brackets se padh lo: momentum mass aur length mein first power ka hai, aur time mein power −1 ka. Force, yaani mass times acceleration, [MLT−2] aata hai. Area, length times length, [L2] hai; yeh zor dene ke liye ki mass aur time ka koi role nahi, hum ise [M0L2T0] likh sakte hain. Do cheezein jaan-boojh kar chhodi gayi hain. Size nahi aata: ek din mein ek metre khisakne wala glacier aur rifle ki goli, dono dimensions [LT−1] ke saath chalte hain. Na hi quantity ka khaas matlab aata hai, jaise tum Section 1.6.2 mein dekhoge. Fig. 1.13 chaar common quantities ke exponents ki picture dikhata hai.

3/4Mass se multiply karo: [MLT−2].

Fig. 1.13Dimensions powers hain. Line ke upar ke bars positive powers hain, neeche ke negative.

M, L aur T label wale teen bars ek zero line par khade hain, plus aur minus one aur two par grid lines ke saath. Pehle step mein, speed ke liye, M 0 hai, L plus 1 aur T minus 1. Doosre step mein, acceleration, T bar neeche minus 2 tak badh jaata hai. Teesre step mein, force, M bar plus 1 tak uthta hai jabki L plus 1 aur T minus 2 rehte hain. Chauthe step mein, pressure, L bar palat kar minus 1 par aa jaata hai, yaani M plus 1, L minus 1 aur T minus 2. Har step mein upar quantity ka naam aur dimensional formula dikhta hai.

Quick check
3 mein se 1
Force dwara kiye gaye work, W=Fd, ke dimensions kya hain?
Answer dekho

Answer (B) [ML2T−2]

[F][d]=[MLT−2][L]=[ML2T−2]. Pehla option khud force hai; teesra power hai, yaani work per unit time.

1.5 Dimensional formulae aur dimensional equations

Har derived quantity ek relation se define hoti hai, aur woh relation uske dimensions tay karta hai. Power ko lo, work karne ki rate: P=W/t, jahan work W force times distance hai. Har symbol ko uske dimensions se replace karo aur har base quantity ke exponents jodo (Fig. 1.14). Result, [ML2T−3], power ka dimensional formula (विमीय सूत्र) hai: shaamil base quantities ki ek chhoti list, har ek apne exponent ke saath. Equation ki tarah likhne par, [P]=[ML2T−3], yeh ek dimensional equation (विमीय समीकरण) ban jaata hai. Teen aur yeh rahe:

Dimensional equations
[a]=[M0LT−2][p]=[MLT−1][ρ]=[ML−3T0]
(1.6)

Table 1.5 un quantities ke dimensional formulae ikattha karta hai jo tum is book mein sabse zyada use karoge. Ise yaad karne ki zaroorat nahi: har row apne defining relation se ek-do line mein nikal aati hai.

3/3M, L aur T ki powers jodo: [P]=[ML2T−3].

Fig. 1.14Dimensional equation likhna: relation, substitute, powers jodo.

Teen boxes ek ke upar ek rakhe hain aur unke beech arrows hain. Pehle step mein upar wala box relation P barabar W over t barabar F d over t dikhata hai. Doosre step mein beech wala box har symbol ko uske dimensions se replace karta hai: M L T to the minus 2 times L, divided by T. Teesre step mein neeche wala box result M L squared T to the minus 3 deta hai, aur ek side panel powers jodta hai: M 1 hai, L 1 plus 1 barabar 2 hai, aur T minus 2 minus 1 barabar minus 3 hai.

Table 1.5Kuch common quantities ke dimensional formulae. Ek jaisi quantities ke ratios dimensionless hote hain.
QuantityDefining relationSI unitDimensional formula
Arealength × breadthm2[L2]
Volumelength × breadth × heightm3[L3]
Densitymass ÷ volumekg m−3[ML−3]
Velocity, speeddisplacement ÷ timem s−1[LT−1]
Accelerationvelocity ÷ timem s−2[LT−2]
Momentum, impulsemass × velocitykg m s−1[MLT−1]
Forcemass × accelerationN[MLT−2]
Work, energy, torqueforce × distanceJ (torque ke liye N m)[ML2T−2]
Powerwork ÷ timeW[ML2T−3]
Pressure, stressforce ÷ areaPa[ML−1T−2]
Frequency1 ÷ periodHz[T−1]
Angle, strain, refractive indexek jaisi quantities ka ratiorad, ya koi nahi[M0L0T0]
Spring constantforce ÷ extensionN m−1[MT−2]
Gravitational constantFr2/(m1m2)N m2 kg−2[M−1L3T−2]
Planck constant, angular momentumenergy ÷ frequencyJ s[ML2T−1]
Electric chargecurrent × timeC[AT]
Example

Defining relation se dimensional formula

Shahad ko hilaana mushkil hai kyunki uski layers ek doosre par slide karne ka virodh karti hain. Zaroori force F=ηA ΔvΔx hai, jahan A ek layer ka area hai, Δv distance Δx door do layers ki speed ka difference hai, aur η liquid ki ek property hai jise viscosity kehte hain. η ka dimensional formula aur SI unit nikaalo.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Quick check
3 mein se 1
Har quantity ko uske dimensional formula se match karo.

Left mein koi item tap karo, phir right mein uska match.

Answer dekho
Answer
  • power : [ML2T−3]
  • pressure : [ML−1T−2]
  • momentum : [MLT−1]
  • frequency : [T−1]
Power energy per time hai, pressure force per area hai, momentum mass × velocity hai aur frequency ek time ka reciprocal hai.

1.6 Dimensional analysis aur uske applications

Dimensions sirf labels nahi hain. Sirf ek hi kism ki quantities ko add, subtract ya compare kiya ja sakta hai, isliye dimensions is par sakht limits lagaate hain ki ek sahi equation kaisi dikh sakti hai. In limits ko use karna dimensional analysis (विमीय विश्लेषण) kehlata hai. Isse hum equations check kar sakte hain, units convert kar sakte hain, aur kabhi-kabhi poori theory hone se pehle hi kisi relation ka form predict kar sakte hain.

Kisi bhi calculation mein units ko numbers ke saath le kar chalo aur unhe symbols ki tarah cancel hone do: numerator ke hours denominator ke hours ko cancel karte hain, isliye (km/h)×h=km. Dimensions bhi aise hi behave karte hain, [MLT−2]/[M]=[LT−2]. Units ko is tarah handle karna unhe convert karne ka sabse safe tareeka bhi hai: har unit ko nayi units mein uski value se replace karo, phir simplify karo.

Example

Pressure ko CGS units mein convert karna

Atmospheric pressure lagbhag 1.0×105 Pa hai. Ise pressure ki CGS unit, dyne per square centimetre, mein likho, jahan 1 dyn=1 g cm s−2.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Yahi idea ek general recipe deta hai. Maan lo kisi quantity ke dimensions [MaLbTc] hain aur ek system mein uska numerical measure n1 hai, jiski mass, length aur time ki units M1, L1 aur T1 hain. Har base unit par n1u1=n2u2 ((1.1)) lagaane par, doosre system mein uska measure hai

Systems ke beech convert karna
n2=n1(M1M2)a×(L1L2)b(T1T2)c
(1.7)

1.6.1 Equations ki dimensional consistency check karna

Paanch kilograms plus teen seconds kisi bhi cheez ke aath nahi hote. Sum, difference ya equality sirf ek hi kism ki quantities ke beech matlab rakhti hai, isliye sahi physical equation ke har term ke dimensions same hone chahiye.

PrinciplePrinciple of homogeneity of dimensions

Physically meaningful equation mein dono sides ke har term ke dimensions same hote hain.

Principle of homogeneity lagaana jaldi ho jaata hai. Constant acceleration a se chal rahi kisi body ke liye ek student ko v2=u2+2as yaad hai. Har term ek squared speed honi chahiye, [L2T−2]. Terms v2 aur u2 saaf taur par hain, aur [as]=[LT−2][L]=[L2T−2], isliye equation pass ho jaati hai. Agar usne v=u+at2 likha hota, to aakhri term ke dimensions [L] hote jabki baakiyon ke [LT−1], aur equation fail ho jaati (Fig. 1.15).

3/3v=u+at2 mein aakhri term [L] hai, [LT−1] nahi: inconsistent, isliye yeh zaroor galat hai.

Fig. 1.15Equation ke har term ke dimensions same hone chahiye.

Equation v squared barabar u squared plus 2 a s likhi hai, har term ek box mein. Doosre step mein teeno terms ke neeche dimensions L squared T to the minus 2 dikhte hain, boxes green ho jaate hain aur label consistent padhta hai. Teesre step mein neeche ek doosri equation, v barabar u plus a t squared, dikhti hai; uske pehle do terms ke dimensions L T to the minus 1 hain lekin aakhri ke dimensions L hain, isliye uska box dashed aur orange hai aur label inconsistent padhta hai.

Dimensions check karna asal mein units check karna hai, lekin aise form mein jo ek saath har system mein kaam karta hai: tum metres mein socho ya feet mein, grams mein ya kilograms mein, length [L] hi hai. Koi conversion factors nahi chahiye, isliye yeh kisi bhi naye result ka sabse jaldi wala pehla test hai.

Kuch quantities ke koi dimensions hote hi nahi. Do ek jaisi quantities ka ratio ek pure number hai: angle (arc ÷ radius), strain (extension ÷ original length), relative density (ek density ÷ doosri). Isi tarah, sin⁡x, log⁡x ya ex jaise function ka argument dimensionless hona chahiye. Aise functions apne argument ki powers ke sums se bante hain, jaise ex=1+x+x2/2+…, aur x, x2 aur x3 ko tabhi add kiya ja sakta hai jab x ek pure number ho. Isliye y=Asin⁡ωt mein ωt ke koi dimensions nahi hain, to [ω]=[T−1].

Is test ki ek kamzori hai: pure-number factors ise dikhte hi nahi. Equations v2=u2+2as, v2=u2+as aur v2=u2+4as teeno pass ho jaati hain, haalaanki sirf pehli sahi hai. Test mein fail hona prove karta hai ki equation galat hai; pass hona sirf yeh dikhata hai ki equation sahi ho sakti hai.

Example 1.3NCERT Example 1.3 · p. 8

Behte liquids ke liye ek relation check karna

Pipe mein smoothly beh rahe liquid ke liye ek book P+12ρv2+ρgh=constant deti hai, jahan P pressure hai, ρ density, v speed, g acceleration due to gravity aur h height. Kya yeh relation dimensionally consistent hai?

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Example 1.4NCERT Example 1.4 · p. 9

Sound ki speed ke formulas ko rule out karna

Sound ek gas mein speed v se chalti hai jo gas ke pressure P aur uski density ρ par depend karti hai. Paanch formulas suggest kiye gaye hain, jahan γ ek pure number hai:

  • (a) v=P/ρ
  • (b) v=ρ/P
  • (c) v=P/ρ
  • (d) v=γP/ρ
  • (e) v=P/ρ+P/ρ

Sirf dimensions se tum kaun se rule out kar sakte ho?

Pehle khud try karo. Phir solution ek-ek step karke kholo.

1.6.2 Physical quantities ke beech relation nikaalna

Dimensions sirf check karne se zyada kar sakte hain. Maan lo hume experiment ya ek achhe physical guess se pata hai ki result kin quantities par depend karta hai. Maan lo result un quantities ki powers ka product hai, ek dimensionless constant se guna, aur maang karo ki dono sides ke dimensions same hon. Mechanics mein isse teen equations milti hain, M, L aur T ke liye ek-ek, isliye yeh method zyada se zyada teen unknown powers tay kar sakta hai.

Example 1.5NCERT Example 1.5 · p. 9

Kheenchi hui string par wave ki speed

Sitar ki string ko chhedo to ek wave uske saath daudti hai. Maan lo wave ki speed v string ke tension F, uske mass per unit length μ, aur uski length l par depend karti hai. Dimensions se relation ka form nikaalo.

Pehle khud try karo. Phir solution ek-ek step karke kholo.

Neeche wala exponent finder tumhe yeh method paanch aur situations par try karne deta hai. Powers ko tab tak badlo jab tak dimensions match na ho jaayein, aur dhyaan do ki kaun si quantities matter hi nahi karti.

InteractiveExponent finder

Ek menu paanch situations deta hai: kheenchi hui string par wave, oonchai se gira patthar, spring par uchhalta mass, gehre paani par lehrein aur tez ball par air drag. Har ek ke liye teen quantities unke dimensions ke saath listed hain, aur buttons har power ko aadhe-aadhe steps mein badhaate ya ghataate hain. Ek table M, L aur T ki chahiye wali powers ko tumhare product ki powers se compare karta hai, current formula dikhta hai, aur ek message batata hai ki ab bhi kya alag hai ya match confirm karta hai aur us quantity ka naam batata hai jo hat jaati hai. Ek button powers ki teen equations dikhata hai.

Fig. 1.16Ek situation chuno, phir har quantity ki power ko tab tak badhao ya ghatao jab tak dono sides ke dimensions same na ho jaayein.

Dimensional analysis powerful hai, lekin iski saaf limits hain:

  • Yeh dimensionless constants nahi nikaal sakta, jaise upar wala k, 12mv2 mein 12 ya kisi period mein 2π.
  • Yeh same dimensions wali quantities mein fark nahi kar sakta, jaise work aur torque, dono [ML2T−2].
  • Yeh sirf product-of-powers forms dhoondhta hai. Yeh s=ut+12at2 jaise terms ke sum ke liye fail ho jaata hai, aur sin⁡, log⁡ ya ex wale relations ke liye bhi.
  • Mechanics mein yeh zyada se zyada teen unknown powers tay kar sakta hai, kyunki compare karne ke liye sirf teen base dimensions hain.
  • Yeh nahi bata sakta ki shuru mein kaun si quantities matter karti hain; uske liye physical samajh ya experiment chahiye.
Quick check
4 mein se 1
Kaun si equation dimensionally galat hai? Yahan s ek distance hai, u aur v speeds hain, a ek acceleration hai aur t ek time.
Answer dekho

Answer (C) v=u+12at2

v=u+12at2 mein aakhri term ke dimensions [LT−2][T2]=[L] hain, ek length, jabki v aur u speeds hain. Baaki teeno mein se har ek consistent hai.
Recap

Summary aur key points

  1. Measurement ek quantity ko ek chune hue standard, uski unit, se compare karta hai; result numerical measure times unit hota hai, aur n1u1=n2u2 (Section 1.1).
  2. Base quantities ki base units hoti hain; baaki saari units unse derive hoti hain, aur sab milkar ek system of units banati hain (Section 1.1).
  3. SI mein saat base units hain (m, kg, s, A, K, mol, cd), jo 2019 se constants of nature ki exact values se define hoti hain; CGS, FPS aur MKS pehle ke systems the (Section 1.2).
  4. Plane angle θ=s/r radians mein naapa jaata hai aur solid angle dΩ=dA/r2 steradians mein; dono dimensionless hain (Plane angle aur solid angle).
  5. Kuch non-SI units, jaise litre, hectare aur electronvolt, abhi bhi use hoti hain; prefixes aur unit symbols fixed rules follow karte hain (Section 1.2).
  6. Significant figures reliable digits plus pehla uncertain digit hain; unki sankhya instrument par depend karti hai, unit par nahi (Section 1.3).
  7. Scientific notation, a×10b, aakhri zeros ka confusion door karta hai; order of magnitude sabse paas wali power of ten ka exponent hai (Section 1.3).
  8. Products aur quotients sabse kam significant figures rakhte hain; sums aur differences sabse kam decimal places rakhte hain (Section 1.3.1).
  9. Aadhe se zyada chhoda gaya hissa aakhri digit ko badha deta hai aur aadhe se kam use waisa hi chhod deta hai; exact 5 sirf odd digit ko badhata hai. Intermediate steps mein ek extra digit rakho (Section 1.3.2).
  10. Product ya quotient mein relative errors add hote hain; subtraction significant figures ki sankhya ko kaafi ghata sakta hai (Section 1.3.3).
  11. Dimensions base quantities ki woh powers hain jinse koi quantity banti hai; force ka dimensional formula [MLT−2] hai (Section 1.4, Section 1.5).
  12. Units aur dimensions ordinary algebra follow karte hain, jisse unit conversion aasaan ho jaata hai (Section 1.6).
  13. Principle of homogeneity se valid equation ke har term ke dimensions same hote hain; dimensionally galat equation galat hai, lekin consistent equation bhi galat ho sakti hai (Section 1.6.1).
  14. Dimensional analysis product-of-powers relations nikaal sakta hai, lekin dimensionless constants, terms ke sums ya same dimensions wali quantities ka fark nahi (Section 1.6.2).
Flash cards · 10

Yaad rakhne wale dimensional formulae

1 / 10
Practice · 25 questions

Practice questions answers ke saath (NCERT “Exercises”)

Numerical answers sahi significant figures tak do. Questions 1–17 wahi skills practise karte hain jo NCERT Exercises 1.1–1.17 karti hain, nayi situations aur numbers ke saath; questions 18–25 board aur entrance jaisi extra practice hain.

  1. NumericalEasyNCERT Exercise 1.1

    Values bharo.

    1. Ek matchbox 5.0 cm×3.5 cm×1.5 cm ka hai. Cubic metres mein uska volume kya hai?

      m³
      Answer dekho

      Answer 0.000026 m³

      V=5.0×3.5×1.5=26.25 cm3, aur 1 cm3=10−6 m3, isliye do significant figures tak V=2.6×10−5 m3.
    2. Ek cubical die ke edges 1.6 cm ke hain. Square millimetres mein uska total surface area kya hai?

      mm²
      Answer dekho

      Answer 1500 mm²

      Millimetres mein edge 16 hai, isliye A=6×162=1536 mm2. Edge mein do significant figures hain, isliye A=1.5×103 mm2.
    3. Ek train 90 km/h par lagaataar chal rahi hai. 10 seconds mein woh kitne metres tay karti hai?

      m
      Answer dekho

      Answer 250 m

      90 km/h=90×1000 m/3600 s=25 m/s, isliye 10 s mein woh 2.5×102 m tay karti hai.
    4. Aluminium paani se 2.70 guna dense hai. Kilograms per cubic metre mein uski density kya hai?

      kg/m³
      Answer dekho

      Answer 2700 kg/m³

      Paani ki density 1.00 g cm−3=1000 kg m−3 hai, isliye aluminium ki 2.70 g cm−3=2.70×103 kg m−3 hai.
  2. NumericalMediumNCERT Exercise 1.2

    Har quantity ko convert karo.

    1. 1 kg m−1 s−2 ko g cm−1 s−2 mein

      g cm⁻¹ s⁻²
      Answer dekho

      Answer 10 g cm⁻¹ s⁻²

      1 kg m−1 s−2=103 g×(102 cm)−1×1 s−2=10 g cm−1 s−2.
    2. ek astronomical unit, 1.496×1011 m, ko light-years mein (1 ly=9.46×1015 m)

      ly
      Answer dekho

      Answer 0.0000158 ly

      1.496×1011/9.46×1015=1.58×10−5 ly.
    3. 1.5 m s−2 ke acceleration ko centimetres per minute squared mein

      cm min⁻²
      Answer dekho

      Answer 540000 cm min⁻²

      1 m=100 cm aur 1 s=(1/60) min, isliye 1.5 m s−2=1.5×100×602=540 000 cm min−2=5.4×105 cm min−2 (do significant figures).
    4. Planck constant, 6.63×10−34 J s, ko erg seconds mein (1 erg=1 g cm2 s−2)

      erg s
      Answer dekho

      Answer 6.63e-27 erg s

      1 J=103 g×(102 cm)2×1 s−2=107 erg, isliye h=6.63×10−27 erg s.
  3. NumericalMediumNCERT Exercise 1.3

    Standard atmospheric pressure lagbhag 1.01×105 Pa hai, jahan 1 Pa=1 kg m−1 s−2. Units ke ek naye system mein mass ki unit α kg hai, length ki unit β m aur time ki unit γ s.

    1. Dikhao ki nayi units mein pressure ki numerical value 1.01×105 α−1βγ2 hai.

      Solution dikhao

      Answer1.01×105 α−1βγ2

      Ek kilogram α−1 nayi mass units hai, ek metre β−1 nayi length units aur ek second γ−1 nayi time units. Pressure ke dimensions [ML−1T−2] hain, isliye

      1 Pa=α−1 (β−1)−1 (γ−1)−2=α−1βγ2

      nayi units. 1.01×105 se multiply karne par result milta hai. Yeh equation (1.7) hai, a=1, b=−1, c=−2 ke saath.

    2. Agar α=2, β=0.5 aur γ=20 ho to numerical value kya hai?

      nayi units
      Answer dekho

      Answer 10100000 nayi units

      1.01×105×12×0.5×202=1.01×105×100=1.01×107.
  4. Short answerEasyNCERT Exercise 1.4

    Kya 1 km ki walk lambi hai? Ek chhote bachche ke liye haan; ek long-distance runner ke liye bilkul nahi. Samjhao ki kisi dimensional quantity ko bada ya chhota kehna comparison ke standard ke bina kyun bematlab hai, aur har statement ko aise dobara likho ki woh ek pakka comparison kare.

    1. Ek din lamba time hai.

      Solution dikhao

      Ek din, 8.64×104 s, ek heartbeat (∼1 s) se lagbhag 105 guna lamba hai, lekin 75 saal ki zindagi (2.4×109 s) ka sirf lagbhag 1/27 000 hai, aur Earth ki umar (∼1.4×1017 s) ka to bahut hi chhota hissa.

    2. Mount Everest bahut ooncha hai.

      Solution dikhao

      8.85 km par Everest Qutub Minar (73 m) se lagbhag 120 guna ooncha hai, phir bhi yeh Earth ke radius (6371 km) ka sirf 0.14% hai: planet par ek chhoti si silvat.

    3. Ek machchhar bahut halka hai.

      Solution dikhao

      Ek machchhar, lagbhag 2.5 mg, ek honeybee (∼0.1 g) se lagbhag 40 guna halka hai, lekin paani ke ek molecule (3.0×10−26 kg) se lagbhag 1020 guna bhaari.

    4. Light bahut hi tez chalti hai.

      Solution dikhao

      Light, 3.0×108 m/s, hawa mein sound (343 m/s) se lagbhag das lakh guna tez hai, aur isse tez kuch nahi chalta; phir bhi Sun se hum tak pahunchne mein ise lagbhag 8 minutes lagte hain.

  5. NumericalEasyNCERT Exercise 1.5

    Length ki ek nayi unit socho, jo aise chuni gayi hai ki vacuum mein light exactly 1 unit per second chale; time ab bhi seconds mein naapa jaata hai. Sabse paas hone par Mars se light ko Earth tak pahunchne mein lagbhag 3.0 minutes lagte hain.

    1. Length ki nayi unit mein Earth–Mars distance kya hai?

      nayi units
      Answer dekho

      Answer 180 nayi units

      3.0 min=180 s; light ki speed 1 nayi unit per second hone se distance 1.8×102 nayi units (light-seconds) hai.
    2. Yeh distance metres mein kitna hai?

      m
      Answer dekho

      Answer 54000000000 m

      180 s×3.0×108 m/s=5.4×1010 m, lagbhag 54 million kilometres.
  6. Short answerMediumNCERT Exercise 1.6

    Inmein se kaun sa instrument length ko sabse precisely naapta hai? (i) ek vernier callipers jiske 10 vernier divisions 9 main-scale millimetres ke barabar hain; (ii) pitch 1.0 mm ka screw gauge jiske circular scale par 200 divisions hain; (iii) ek travelling microscope jo 0.001 cm tak padhta hai.

    Solution dikhao

    Precision least count se tay hoti hai. Ek vernier division 910 mm hai, isliye vernier ka least count 1−0.9=0.1 mm hai. Screw gauge ka pitch ÷ divisions =1.0/200=0.005 mm hai. Microscope 0.01 mm tak padhta hai. Isliye (ii) sabse precise hai, microscope se do guna barik aur vernier se bees guna barik.

  7. NumericalEasyNCERT Exercise 1.7

    400 guna magnify karne wale microscope mein ek pollen grain 12.0 mm chauda dikhta hai (15 readings ka average). Grain ke asli diameter ka estimate lagao.

    mm
    Solution dikhao

    Asli size = dikhne wala size ÷ magnification =12.0 mm/400=0.0300 mm, yaani 3.00×10−5 m ya 30.0 μm, jo pollen grain ka typical size hai.

  8. Short answerMediumNCERT Exercise 1.8

    Neeche diye sawaalon ke answer do.

    1. Sirf millimetres marked 15 cm ke ruler se tum apni notebook ki ek sheet ki thickness kaise nikaal sakte ho?

      Solution dikhao

      200 sheets ko dabaa kar saath rakho (sheets gino, page numbers nahi: har sheet par do pages hote hain) aur stack ki thickness naapo, jaise 9 mm. Tab ek sheet 9/200=0.045 mm hai. Ruler ki lagbhag 1 mm ki uncertainty 200 sheets mein bant jaati hai, isliye har sheet lagbhag 0.005 mm tak pata hoti hai.

    2. Ek student claim karti hai ki woh 0.5 mm-pitch screw ke circular scale par bas 5000 divisions khod kar screw gauge ko 0.0001 mm tak padhne layak bana sakti hai. Kya woh sahi hai?

      Solution dikhao

      Nahi. Zyada divisions least count ko sirf kaagaz par kam karte hain. Itne barik divisions aankh se padhe nahi ja sakte, aur asli limit is baat se tay hoti hai ki screw thread kitna uniform hai, backlash (screw ki direction ulti hone par dheelapan) se, aur object kitni mazbooti se pakda gaya hai.

    3. Tumhe kisi measurement ko kai baar repeat karke mean lene ko kyun kaha jaata hai? Kya 50 repetitions 5 se behtar honge?

      Solution dikhao

      Har reading mein chhote random errors hote hain, kabhi zyada bade aur kabhi zyada chhote. Mean mein yeh errors kuch had tak cancel ho jaate hain, isliye mean ek single reading se zyada asli value ke paas hota hai. Jitni zyada readings, utna achha cancellation, isliye 50 readings 5 se zyada reliable mean deti hain (jab tak error random ho, instrument ka koi fixed error nahi).

  9. NumericalEasyNCERT Exercise 1.9

    Phone screen par ek photograph 2.4 cm2 gherti hai. Deewar par project karne par wahi picture 1.35 m2 gherti hai. Projector ki linear magnification kya hai?

    Solution dikhao

    1.35 m2=13 500 cm2. Area magnification =13 500/2.4=5625. Lengths square root se magnify hoti hain: m=5625=75. (2.4 cm2 se tay do significant figures tak bhi yeh 75 hai.)

  10. Quick answerEasyNCERT Exercise 1.10

    Har value mein significant figures ki sankhya batao.

    1. 0.00450 kg mein significant figures hain.

      Answer dekho

      Answer 3

      4, 5 aur decimal point ke baad aakhri 0; shuru ke zeros nahi gine jaate.
    2. 3.080×105 m mein significant figures hain.

      Answer dekho

      Answer 4

      3.080 ke saare digits gine jaate hain, beech wala aur aakhri zero bhi.
    3. 0.10070 s mein significant figures hain.

      Answer dekho

      Answer 5

      1, 0, 0, 7 aur aakhri 0 gine jaate hain; sirf decimal point se pehle wala zero nahi gina jaata.
    4. 4500 m, aise likha hua, mein significant figures hain.

      Answer dekho

      Answer 2

      Bina decimal point wale whole number ke aakhri zeros nahi gine jaate. Agar woh naape gaye the to 4.500×103 m likho.
  11. NumericalMediumNCERT Exercise 1.11

    Swimming pool ki ek lane 50.00 m lambi aur 2.50 m chaudi hai, aur usmein 1.8 m ki gehraai tak paani bhara hai.

    1. Lane mein paani ki surface ka area sahi significant figures tak nikaalo.

      m²
      Answer dekho

      Answer 125 m²

      50.00×2.50=125.0 m2; width mein teen significant figures hain, isliye area 125 m2 hai.
    2. Lane mein paani ka volume sahi significant figures tak nikaalo.

      m³
      Answer dekho

      Answer 220 m³

      125.0×1.8=225.0 m3. Depth mein do significant figures hain, isliye do rakho: chhoda gaya hissa exactly 5 hai aur usse pehle wala digit, 2, even hai, isliye volume 2.2×102 m3 hai.
  12. NumericalMediumNCERT Exercise 1.12

    Ek carpenter ek plank ko mote taur par 3.2 m lamba naapta hai. Ek barik steel tape se woh do tukde mark karke kaatta hai, 0.875 m aur 0.862 m lambe.

    1. Plank ka kitna hissa bacha hai, sahi precision tak?

      m
      Answer dekho

      Answer 1.5 m

      3.2−0.875−0.862=1.463 m. Plank sirf 0.1 m tak pata hai, isliye bacha tukda 1.5 m hai.
    2. Do kate hue tukdon mein kitna fark hai, sahi precision tak?

      m
      Answer dekho

      Answer 0.013 m

      0.875−0.862=0.013 m, teen decimal places tak (sirf do significant figures bachte hain).
  13. Short answerMediumNCERT Exercise 1.13

    Tezi se chalti rod us observer ko chhoti dikhti hai jiske paas se woh guzarti hai. Ek student ko formula L=L01−v2 yaad hai, jahan L0 rest par rod ki length hai aur v uski speed, lekin woh bhool gayi hai ki light ki speed c kahan aati hai. Dimensions se c ko sahi jagah rakho.

    Solution dikhao

    AnswerL=L01−v2/c2

    L aur L0 dono lengths hain, isliye square root dimensionless hona chahiye. Uske andar 1 ek pure number hai, isliye v2 ko kisi aisi cheez se divide karna hoga jiske dimensions [L2T−2] hon: woh c2 hai. Isliye L=L01−v2/c2, jo physically bhi sahi lagta hai, kyunki v≪c hone par L→L0.

  14. NumericalMediumNCERT Exercise 1.14

    Carbon atom ko 0.70 Å radius ka sphere maano, jahan 1 A˚=10−10 m. Carbon ke ek mole ke atoms ka total volume cubic metres mein kya hai?

    m³
    Solution dikhao

    Ek atom ka volume: 43πr3=43π(7.0×10−11 m)3=1.44×10−30 m3. Ek mole ke liye: 1.44×10−30×6.02×1023=8.7×10−7 m3, ek cubic centimetre se kam (radius se tay do significant figures).

  15. NumericalHardNCERT Exercise 1.15

    STP (0 °C aur 1 atm) par kisi bhi ideal gas ka ek mole 22.4 L gherta hai. Hawa ke ek molecule ko lagbhag 3.0 Å diameter ka sphere maano.

    1. Ek mole mein molecules ke total volume ka estimate cubic metres mein lagao.

      m³
      Answer dekho

      Answer 0.0000085 m³

      r=1.5×10−10 m; 43πr3×NA=1.41×10−29×6.02×1023=8.5×10−6 m3 (lagbhag 8.5 cm3).
    2. Molar volume aur is volume ka ratio nikaalo.

      Answer dekho

      Answer 2600

      22.4×10−3 m3/8.5×10−6 m3≈2.6×103.
    3. Ratio itna bada kyun hai?

      Solution dikhao

      Gas mein molecules apne size ki tulna mein ek doosre se bahut door hote hain. Molecules khud volume ka sirf kuch hazaar mein ek hissa gherte hain; baaki khaali jagah hai jismein woh aazaadi se ghoomte hain. Iske ulat, liquid ya solid mein molecules lagbhag chhoote hue pack hote hain.

  16. Short answerMediumNCERT Exercise 1.16

    Highway par raat ki drive mein sadak ke kinaare ki streetlights tezi se peeche chhoot jaati hain, door ki pahadi par ek gaon ki lights dheere-dheere peeche khisakti hain, aur Moon car ke saath-saath chalta lagta hai. In observations ko samjhao.

    Solution dikhao

    Hamari aankhein motion ko is baat se aankti hain ki kisi object ki taraf line of sight kitni tezi se ghoomti hai. Speed v se chal rahi car ke bagal mein distance d par kisi object ke liye line of sight lagbhag v/d radians per second se ghoomti hai. v=20 m/s par: 10 m door ki streetlight 2 rad/s deti hai, tez sweep; 4 km door ka gaon 0.005 rad/s deta hai, dheema khisakna; Moon, 3.84×108 m door, lagbhag 5×10−8 rad/s deta hai, jo notice karne ke liye bahut hi chhota hai.

    Isliye drive karte waqt Moon usi direction mein rehta hai. Kyunki sadak ke paas ki har cheez peeche khisakti hai jabki Moon window mein apni jagah par tika rehta hai, isliye woh tumhare saath chalta lagta hai.

  17. NumericalMediumNCERT Exercise 1.17

    Jupiter zyaadatar hydrogen aur helium se bana hai, do sabse halke elements, aur iski koi solid surface nahi hai.

    1. Tumhare guess mein iski mean density gas ki density (lagbhag 1 kg/m³) ke zyada paas hogi, ya liquids aur solids ki range (10³ se 10⁴ kg/m³) ke?

      Solution dikhao

      Halki gases se kam density lagti hai, lekin planet ka bahut bada mass gas ko behad dabaata hai, isliye ordinary gases se kahin zyada density ki ummeed karna theek hai. Part (b) guess ko check karta hai.

    2. Apna guess in values se check karo: Jupiter ka mass =1.90×1027 kg, mean radius =6.99×107 m.

      kg/m³
      Answer dekho

      Answer 1330 kg/m³

      V=43π(6.99×107)3=1.43×1024 m3, isliye ρ=1.90×1027/1.43×1024=1.33×103 kg/m3: liquids ki range mein, paani se thoda zyada dense. Andar ka bahut bada pressure hydrogen ko liquid jaisi densities tak dabaa deta hai.
  18. Quick answerEasy

    Force ke torque, 𝐫×𝐅, ka dimensional formula iske jaisa hai

    Answer dekho

    Answer (A) work

    Torque force × distance hai, [ML2T−2], work jaisa hi, haalaanki dono alag quantities hain.
  19. Quick answerMedium

    Assertion (A): Equation v=u+12at dimensionally consistent hai. Reason (R): Har dimensionally consistent equation physically sahi hoti hai.

    Answer dekho

    Answer (C) A true hai, lekin R false hai.

    v=u+12at ka har term [LT−1] hai, isliye A true hai. Lekin sahi relation v=u+at hai: galat factor 12 test paas kar leta hai, isliye R false hai.
  20. Quick answerMedium

    Ek ball ka radius 0.4% ke relative error ke saath naapa gaya hai. Uske calculate kiye gaye volume mein percentage error kitna hai?

    %
    Answer dekho

    Answer 1.2 %

    V∝r3, aur r3=r×r×r, isliye relative errors teen baar add hote hain: 3×0.4%=1.2%.
  21. Quick answerEasy

    Ek newton mein kitne dynes hote hain? (1 dyn=1 g cm s−2)

    dyn
    Answer dekho

    Answer 100000 dyn

    1 N=1 kg m s−2=103 g×102 cm×1 s−2=105 dyn.
  22. Quick answerHard

    Agar light ki speed c, Planck constant h aur gravitational constant G ko base quantities maana jaaye, to kis combination ke dimensions length ke hain?

    Answer dekho

    Answer (A) hG/c3

    [hG]=[ML2T−1][M−1L3T−2]=[L5T−3]. [c3]=[L3T−3] se divide karne par [L2] bachta hai, isliye hG/c3 ek length hai (Planck length).
  23. Quick answerEasy

    In lengths ko magnitude ke badhte order mein lagao.

    1. Earth ka diameter
    2. insaani baal ki thickness
    3. ek insaan ki height
    4. ek atom ka diameter
    5. Earth se Sun tak ka distance
    Answer dekho
    Answer
    1. ek atom ka diameter
    2. insaani baal ki thickness
    3. ek insaan ki height
    4. Earth ka diameter
    5. Earth se Sun tak ka distance
    Lagbhag 10−10, 10−4, 100, 107 aur 1011 m.
  24. Quick answerMedium

    Quantities ke har pair ko us dimensional formula se match karo jo dono ka same hai.

    Left mein koi item tap karo, phir right mein uska match.

    Answer dekho
    Answer
    • work aur torque : [ML2T−2]
    • angular momentum aur Planck constant : [ML2T−1]
    • pressure aur stress : [ML−1T−2]
    • frequency aur angular speed : [T−1]
    Har pair ke dimensions same hain haalaanki quantities alag hain; isi wajah se dimensional analysis inmein fark nahi kar sakta.
  25. Quick answerMedium

    4.52×0.01302.6 ko sahi significant figures tak evaluate karo.

    Answer dekho

    Answer (D) 0.023

    Calculator 0.0226 deta hai. Value 2.6 mein sirf do significant figures hain, isliye answer 0.023 hai. Dhyaan do ki 0.0130 mein teen hain, kyunki uska aakhri zero decimal point ke baad aata hai.

Apna NCERT exercise question dhoondo

Hamare practice questions ncert.ai ke liye likhe gaye hain aur NCERT exercises ko follow karte hain. Apni textbook ke question se match karne wala question dhoondo; uska answer uske saath hai.

Tumhari NCERT textbook meinYahan practice question
NCERT Exercise 1.1Practice Q1
NCERT Exercise 1.2Practice Q2
NCERT Exercise 1.3Practice Q3
NCERT Exercise 1.4Practice Q4
NCERT Exercise 1.5Practice Q5
NCERT Exercise 1.6Practice Q6
NCERT Exercise 1.7Practice Q7
NCERT Exercise 1.8Practice Q8
NCERT Exercise 1.9Practice Q9
NCERT Exercise 1.10Practice Q10
NCERT Exercise 1.11Practice Q11
NCERT Exercise 1.12Practice Q12
NCERT Exercise 1.13Practice Q13
NCERT Exercise 1.14Practice Q14
NCERT Exercise 1.15Practice Q15
NCERT Exercise 1.16Practice Q16
NCERT Exercise 1.17Practice Q17

Quick check: MCQs

  1. 1.1 Introduction3 questions
  2. Plane angle aur solid angle4 questions
  3. 1.3 Significant figures4 questions
  4. 1.3.3 Arithmetic calculations ke results mein uncertainty nikaalne ke rules4 questions
  5. 1.4 Physical quantities ke dimensions3 questions
  6. 1.5 Dimensional formulae aur dimensional equations3 questions
  7. 1.6.2 Physical quantities ke beech relation nikaalna4 questions
Glossary · 15

Key terms (English + Hindi)

base quantityमूल राशिmool raashi
SI mein independent chuni gayi saat quantities mein se ek, jaise length, mass aur time.Chapter mein pehli baar yahan aaya →
derived unitव्युत्पन्न मात्रकvyutpann maatrak
Base units ko multiply aur divide karke bani unit, jaise m s−1 ya newton.Chapter mein pehli baar yahan aaya →
dimensional equationविमीय समीकरणvimiya sameekaran
Aisi equation jo quantity ko uske dimensional formula ke barabar rakhti hai, jaise [F]=[MLT−2].Chapter mein pehli baar yahan aaya →
dimensional formulaविमीय सूत्रvimiya sootra
[MLT−2] jaisa expression jo dikhata hai ki kaun si base quantities, kin powers ke saath, milkar ek quantity banati hain.Chapter mein pehli baar yahan aaya →
dimensionsविमाएँvimaayen
Woh exponents jo har base quantity par hote hain jab physical quantity ko base quantities ke product ki tarah likha jaata hai.Chapter mein pehli baar yahan aaya →
least countअल्पतमांकalpatamaank
Sabse chhoti value jo koi instrument seedhe padh sakta hai, jaise school ruler par 1 mm.Chapter mein pehli baar yahan aaya →
order of magnitudeपरिमाण की कोटिparimaan ki koti
Value ke sabse paas wali power of ten ka exponent: a×10b ka order of magnitude b hai agar a≤5, aur b+1 agar a>5.Chapter mein pehli baar yahan aaya →
principle of homogeneityविमीय समांगता का सिद्धांतvimiya samaangata ka siddhaant
Valid physical equation mein add, subtract ya equate hone wale har term ke dimensions same hote hain.Chapter mein pehli baar yahan aaya →
radianरेडियनradian
Plane angle ki SI unit: circle ke centre par woh angle jiska arc radius ke barabar ho; θ=s/r.Chapter mein pehli baar yahan aaya →
relative errorआपेक्षिक त्रुटिaapekshik truti
Value ki uncertainty divided by value; 100 se multiply karne par yeh percentage error hai.Chapter mein pehli baar yahan aaya →
scientific notationवैज्ञानिक संकेतनvaigyanik sanketan
Number ko a×10b ki tarah likhna, jahan 1≤a<10; a ka har digit significant hai.Chapter mein pehli baar yahan aaya →
significant figuresसार्थक अंकsaarthak ank
Measured value ke woh digits jo reliably pata hain, plus pehla uncertain digit.Chapter mein pehli baar yahan aaya →
steradianस्टेरेडियनsteradian
Solid angle ki SI unit: sphere ke centre se nikla woh cone jo uski surface ka r2 area kaatta hai; Ω=A/r2.Chapter mein pehli baar yahan aaya →
system of unitsमात्रकों की पद्धतिmaatrakon ki paddhati
Base units ka poora set, unse bani derived units ke saath, jaise CGS, FPS, MKS ya SI.Chapter mein pehli baar yahan aaya →
unitमात्रकmaatrak
Kisi quantity ki ek fixed amount, jis par poori duniya sehmat hai, aur jisse usi quantity ki doosri amounts compare ki jaati hain.Chapter mein pehli baar yahan aaya →

Tum chapter ke end tak pahunch gaye