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BiologyCh 11 Photosynthesis in Higher Plants

Photosynthesis in Higher Plants: Class 11 Biology · Chapter 11

Biology · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 80 min
  • 18 practice questions
  • 32 MCQs

What you will learn in Photosynthesis in Higher Plants

  • Explain how the early experiments of Priestley, Ingenhousz, Sachs, Engelmann and van Niel built the modern equation of photosynthesis, and show that the oxygen released comes from water
  • Relate the structure of the chloroplast to the division of work between the light reactions and the carbon (dark) reactions
  • Interpret absorption and action spectra and explain the roles of chlorophyll a and the accessory pigments
  • Trace electrons through the Z scheme, and compare cyclic and non-cyclic photophosphorylation
  • Explain ATP synthesis in the chloroplast by chemiosmosis
  • Describe the three stages of the Calvin cycle and calculate the ATP and NADPH needed for a given amount of sugar
  • Compare C3 and C4 plants in leaf anatomy, biochemistry and photorespiration
  • Apply Blackman’s law of limiting factors to light, carbon dioxide, temperature and water

Original companion text aligned to NCERT Biology Class 11, Chapter 11, pp. 131–152. Not affiliated with or endorsed by NCERT.

Stand at the edge of a wheat field in Punjab and you can study it in two ways. An ecologist counts the crop, the weeds, the aphids and the mynas feeding among them. A biochemist sees something else: countless chloroplasts turning sunlight, air and water into sugar. Both are biology. This unit takes the second view. It explains how a flowering plant makes its food (this chapter), releases energy from it (Chapter 12) and uses that energy to grow and develop (Chapter 13). Each time, we trace a whole-plant event back to cells and molecules, and we note where the surroundings speed it up or hold it back.

Trace the food on a lunch plate backwards and you always reach a green plant: the rice and dal directly, the curd through a cow that ate fodder. Green plants are autotrophs: they build their own organic food from simple inorganic raw materials. Animals, fungi and most bacteria are heterotrophs, which must eat food that an autotroph made first.

Definition
Photosynthesis

The process in which green plants (and algae and some bacteria) use light energy, captured by pigments such as chlorophyll, to build sugars from carbon dioxide and water, usually releasing oxygen.

ExampleA neem leaf in the afternoon sun is fixing COX2 into sugar and giving off OX2 through its stomata.

Photosynthesis matters for two reasons. It is the doorway through which the Sun's energy enters almost every food chain on Earth, and it keeps topping up the oxygen in the air that we and most other organisms need to breathe. In this chapter we open up the machinery: the pigments that catch light, the membranes that turn light into chemical energy, and the enzymes that spend that energy on fixing carbon.

11.1 What Do We Know?

From earlier classes you know three requirements: chlorophyll, light and carbon dioxide. Each was shown with the same trick. Deny one part of a leaf a single requirement, then ask the leaf whether it made starch. Iodine gives the answer, because it stains starch blue-black and leaves the rest of a decolourised leaf a pale brown-yellow.

In Fig. 11.1 a variegated leaf (green with white patches) has a strip of black paper clipped across it. After some hours in sunlight, only the parts that were both green and uncovered stain for starch. A second leaf is pushed halfway into a sealed bottle holding cotton soaked in potassium hydroxide (KOH), which absorbs COX2 from the air inside. Only the half left outside makes starch. Both halves had the same light, chlorophyll and water, so the missing COX2 is the only difference that can explain the result.

3/3Starch-making needs chlorophyll, light and COX2.

Fig. 11.1Iodine shows starch only where chlorophyll, light and COX2 were all present.NCERT 11.1 · p. 133

Left: a leaf with a white patch and a black paper strip clipped across it. Right: a second leaf hangs down with its lower half pushed through a cork into a bottle that has potassium hydroxide cotton at the bottom. Step one shows the set-ups in light. In step two the leaves have been tested with iodine: the green, uncovered parts of the left leaf are blue-black, while the white patch and the strip's shadow stay brown; the half of the right leaf in air is blue-black and the half inside the bottle is brown. Step three adds the conclusions: starch needs chlorophyll and light, and it needs carbon dioxide.

Quick check
1 of 3
In the bottle experiment, why does the half of the leaf inside the bottle make no starch?
Show answer

Answer (D) The KOH removed the COX2 around it

KOH absorbs COX2, so the enclosed half has light, chlorophyll and water but no COX2. The leaf was never cut and the glass lets light through, so those distractors fail.

11.2 Early Experiments

Our picture of photosynthesis was pieced together from a chain of simple experiments. Each one answered a question and raised the next.

Joseph Priestley (1733–1804), an English clergyman with a passion for chemistry, ran a famous series of bell-jar tests in the early 1770s. A sealed jar of air could keep a candle alight, or a mouse alive, for only a short time; after that it would support neither. Yet if a sprig of mint shared the jar for some days, the same air became fit for both again. Priestley's explanation: whatever flames and breathing animals take out of the air, green plants put back. In 1774 he went on to isolate the gas we now call oxygen.

Jan Ingenhousz (1730–1799), a Dutch-born physician working in England, asked a question Priestley had not: does it matter when the plant does this? Repeating the jar test in sunlight and in darkness, he found that the plant restores the air only in light (Fig. 11.2). Water plants made the point visible. In bright sun their green leaves and stems streamed tiny bubbles, in the dark they produced none, and non-green parts never did; the gas proved to be oxygen. So the air-restoring process needs sunlight and happens only in green tissue.

3/4Days later a lens relights the wick and the candle keeps burning.

Fig. 11.2Priestley's mint repaired the air; Ingenhousz showed it does so only in light.NCERT Fig. 11.1 · p. 134

A glass bell jar sits on a base. In step one a lit candle stands inside. In step two the flame has gone out and a wisp of smoke rises. In step three a potted mint plant shares the jar, the sun shines and a lens focuses sunlight onto the wick: days later the candle burns again. In step four the same jar with the mint stands in darkness under a moon, and the candle goes out.

Around the middle of the nineteenth century the German botanist Julius von Sachs tied this gas exchange to food. Testing leaves with iodine, he found starch only in green tissue that had been in light, and he traced chlorophyll to discrete bodies inside the cell, the chloroplasts. The glucose that green tissue makes as a plant grows is mostly stored as that starch.

Which colours of light drive photosynthesis? In 1882 the German physiologist T. W. Engelmann (1843–1909) answered this with an elegant trick (Fig. 11.3). Through a prism he cast a small spectrum along a filament of the green alga Cladophora, in water containing aerobic bacteria. These bacteria swim towards oxygen, so they served as living oxygen detectors. They crowded under the blue and red parts of the spectrum and stayed sparse under green. A plot of photosynthetic output against wavelength is called an action spectrum. Engelmann's was the first ever measured, and you will see in Section 11.4 that its two peaks line up with the colours chlorophylls a and b absorb best.

3/3They crowd under blue and red: the first action spectrum.

Fig. 11.3Bacteria that seek oxygen gathered where the alga photosynthesised fastest: under blue and red light.NCERT p. 135

A prism at the top spreads light into a spectrum, violet on the left to red on the right, laid along a green algal filament on a slide; a scale marks 400 to 700 nanometres. In step one only the spectrum and filament are shown. In step two rod-shaped bacteria are spread evenly along the filament. In step three the bacteria have crowded under the blue and red bands and are sparse under green, and a curve below shows the number of bacteria at each colour, high in blue and red and low in green.

By the second half of the nineteenth century the essentials were agreed: in light, plants make carbohydrate from COX2 and water and give off oxygen. The overall change was written as

COX2+HX2O→light[CHX2O]+OX2
(11.1)
where
[CHX2O]
one carbon’s worth of carbohydrate (six of them make a glucose)

Where does the oxygen come from: the COX2 or the water? The microbiologist Cornelius van Niel (1897–1985) cracked this by studying purple and green sulphur bacteria. They photosynthesise without releasing oxygen, using hydrogen sulphide (HX2S) instead of water and leaving sulphur or sulphate behind. Comparing them with plants, he saw one general pattern: in every case light provides the energy for a hydrogen donor, HX2A, to reduce COX2 to carbohydrate, and the rest of the donor, A, is set free.

COX2+2 HX2A→light[CHX2O]+2 A+HX2O
(11.2)

For a sulphur bacterium the donor is HX2S and the product A is sulphur. For a green plant the donor is water, so A must be oxygen: the OX2 a plant releases comes from water, not from COX2.This was confirmed in 1941 by feeding algae water labelled with 18O. NCERT calls this a radioisotope technique; 18O is in fact a stable heavy isotope, detected by its mass. Balancing the equation for one glucose, with every oxygen molecule coming from water, gives

Overall equation
6 COX2+12 HX2O→lightCX6HX12OX6+6 HX2O+6 OX2
(11.3)

Equation (11.3) sums up the inputs and outputs of dozens of separate steps; it is not one reaction.

Example 11.1

Following heavy oxygen

A suspension of algae is given water in which every oxygen atom is the heavy isotope 18O; the COX2 is ordinary. Using equation (11.3), (a) which product carries the label, and (b) why must the equation show 12 water molecules on the left rather than 6?

Try it yourself first. Then reveal the solution one step at a time.

Timeline

From bell jars to radioactive carbon

  1. early 1770s

    Priestley: plants repair air

    A mint sprig keeps a sealed jar’s air fit for a candle and a mouse.

  2. 1779

    Ingenhousz: light and green parts

    Only in sunlight, and only green parts, release oxygen.

  3. mid-1800s

    Sachs: sugar in chloroplasts

    Green tissue makes glucose, stored as starch; chlorophyll sits in chloroplasts.

  4. 1882

    Engelmann: first action spectrum

    Oxygen-seeking bacteria crowd under blue and red light.

  5. 1930s

    van Niel: oxygen from water

    Sulphur bacteria show hydrogen comes from a donor; for plants the donor is water.

  6. 1941

    Heavy-oxygen tracer

    Labelled water confirms the oxygen comes from water.

  7. 1950s

    Calvin: the carbon pathway

    Radioactive carbon maps the cycle that fixes COX2.

Quick check
1 of 3
Which conclusion did van Niel draw from comparing sulphur bacteria with green plants?
Show answer

Answer (D) The oxygen plants release comes from water

In bacteria the hydrogen donor HX2S leaves sulphur behind; in plants the donor is water, so the released oxygen must come from water. Most learners guess COX2 because it contains oxygen, but its oxygen ends up in sugar and water.

11.3 Where Does Photosynthesis Take Place?

Leaves do most of the work, but they have no monopoly: any green tissue can photosynthesise. Young green stems, the green sepals of a flower bud, unripe fruits such as green chillies and raw mangoes, and the flattened green stems of cacti such as Opuntia all contain chloroplasts and fix carbon.

Within a leaf, most chloroplasts sit in the mesophyll (you met their structure in Chapter 8), lined up against the cell walls rather than floating in the middle of the cell. They can shift their position along the walls as the light changes (Fig. 11.4).

Each chloroplast is wrapped in two membranes, an outer and an inner one. Inside lies a third membrane system: flattened sacs called thylakoids, stacked like coins into grana and joined by unstacked stroma lamellae. Around them is the stroma, a protein-rich fluid that also holds ribosomes, starch grains and lipid droplets.

2/3Grana, stroma lamellae and stroma inside a double membrane.

Fig. 11.4Membranes catch light and make ATP and NADPH; the stroma makes sugar.NCERT Fig. 11.2 · p. 136

Step one shows a mesophyll cell under light from above, with a thick cell wall, a large vacuole and chloroplasts lined up along the walls. Step two zooms into one chloroplast and labels the outer membrane, inner membrane, stacked grana, the stroma lamellae linking them, the stroma, ribosomes, starch grains and lipid droplets. Step three highlights the thylakoid membranes, labelled as making ATP and NADPH, and tints the stroma, labelled as where sugars are made.

A chloroplast works like a factory with two rooms. The thylakoid membranes (grana and stroma lamellae) are the power room: they catch light and turn its energy into two portable forms, ATP and NADPH. The stroma is the assembly room: its enzymes spend ATP and NADPH on building sugar from COX2, and store some of the sugar as starch. The power room runs only while light falls on it, so its steps are called the light reactions, or photochemical reactions.

The assembly room has no light switch of its own; it simply stops when the power room stops sending ATP and NADPH. Out of habit its steps are still called the dark reactions, although carbon reactions is the better name: in a living leaf they run by day, alongside the light reactions, and halt soon after the light goes.

Compare

Two phases of photosynthesis

Light reactions

  • Where: thylakoid membranes (grana, stroma lamellae)
  • Driven directly by light
  • Use water, light, ADP + Pi and NADPX+
  • Make ATP and NADPH, release OX2

Carbon (dark) reactions

  • Where: stroma
  • Not driven by light directly, but need the light reactions’ products
  • Use COX2, ATP and NADPH
  • Make sugars (then sucrose, starch)
Quick check
1 of 3
Which of these take place on the thylakoid membranes?
Select all that apply
Show answer
Answer
  • (A) Absorption of light
  • (B) Splitting of water
  • (D) Making ATP and NADPH
Light capture, water splitting and the making of ATP and NADPH are membrane events. COX2 fixation and starch-making are done by enzymes in the stroma.

11.4 How Many Types of Pigments are Involved in Photosynthesis?

Crush a spinach leaf in a little acetone and you get a green liquid. Is that green one substance or several? Paper chromatography answers the question (Fig. 11.5): a solvent creeping up a strip of paper carries each pigment in the extract a different distance, so a mixture spreads out into separate bands.

A leaf extract separates into four bands. Chlorophyll a is bright or blue-green and chlorophyll b yellow-green; xanthophylls are yellow, and carotenes range from yellow to orange. NCERT calls this last band carotenoids; strictly, xanthophylls and carotenes are both kinds of carotenoid.

3/3Carotenes travel farthest and chlorophyll b least.

Fig. 11.5One green spot separates into four pigments.NCERT p. 137

A tall jar holds a little solvent at the bottom, and a paper strip hangs from the lid with its lower end in the solvent. In step one a dark green spot of leaf extract sits on a pencil start line just above the solvent. In step two the solvent has climbed halfway and the spot has begun to split into overlapping coloured bands. In step three the solvent front is near the top and four bands are separate: carotenes (orange-yellow) highest, then xanthophylls (yellow), chlorophyll a (blue-green) and chlorophyll b (yellow-green) lowest.

Pigments are coloured because they absorb some wavelengths of light and not others. Chlorophylls take in blue and red strongly and let much of the green bounce back, which is why leaves look green to us. No pigment is more plentiful in the plant world than chlorophyll a.

A graph of how strongly a pigment absorbs each wavelength is its absorption spectrum. A graph of how fast photosynthesis runs under each wavelength is the action spectrum. Fig. 11.6 puts them together. The match is striking: the action spectrum peaks in the blue and the red, exactly where chlorophyll a absorbs most strongly (near 430 and 660 nm). That is the evidence for calling chlorophyll a the chief pigment of photosynthesis.

3/3The rate of photosynthesis follows all the pigments together.

Fig. 11.6Photosynthesis peaks where chlorophyll a absorbs, but accessory pigments widen the range.NCERT Fig. 11.3 · p. 137

A graph with wavelength from 400 to 700 nanometres along the bottom, over a strip of spectrum colours, and absorption or rate up the side. Step one shows the absorption of chlorophyll a: a tall peak in the blue near 430 nanometres, almost nothing in the green and a second peak in the red near 660. Step two adds chlorophyll b as a dashed line, with peaks near 455 and 640, and carotenoids as a dotted line absorbing only between about 400 and 520 nanometres. Step three draws the action spectrum as a thick line: high in the blue and red, lower but not zero in the green, and higher than chlorophyll a alone between about 450 and 500 nanometres.

Definition
Action spectrum

A graph of the rate of photosynthesis (for example, oxygen released) under light of each wavelength. Compare it with an absorption spectrum, which shows how much light one pigment absorbs.

ExampleEngelmann's bacteria traced the first action spectrum of a green alga.

The match is not perfect, though. Between about 450 and 500 nm, and in part of the green, photosynthesis runs faster than chlorophyll a's absorption alone would allow. The extra comes from the accessory pigments: chlorophyll b, the xanthophylls and the carotenes, which also sit in the thylakoid membranes. They absorb wavelengths that chlorophyll a uses poorly and hand the energy to chlorophyll a, widening the range of light a leaf can use. They also guard chlorophyll a against photo-oxidation, damage by absorbed light energy that cannot be used safely.

Quick check
1 of 3
Which pigment is the chief pigment of photosynthesis?
Show answer

Answer (A) Chlorophyll a

Chlorophyll a forms the reaction centres, and its absorption peaks match the peaks of the action spectrum. The others are accessory pigments that feed energy to it.

11.5 What is Light Reaction?

The light reactions, also called the photochemical phase, have light and water as inputs and three outputs: oxygen and two energy-rich carriers, ATP and NADPH. In between, the energy of absorbed light is used to split water and to push its electrons on to NADPX+.

The work is done by large protein complexes in the thylakoid membrane. The pigments are organised into two photosystems, known as PS I and PS II, each built around its own light-harvesting complex (LHC). Do not read the numbers as a running order: PS I got its name because it was discovered first, but in the light reactions PS II acts before it.

On its own, a chlorophyll molecule in full sunlight catches only a handful of photons each second, too few to keep the chemistry busy. A photosystem therefore works like a dish aerial (Fig. 11.7). Hundreds of pigment molecules of several kinds, held in place by proteins, form the antenna. Whichever of them absorbs a photon passes the energy on, molecule to molecule, towards the centre of the dish. There sits one special chlorophyll a molecule, the reaction centre, the only molecule in the photosystem that actually gives away an electron, which a primary acceptor captures. Because the antenna pigments absorb different wavelengths, the dish also collects a broader band of light than chlorophyll a could alone.

4/4The reaction centre passes an excited electron to the primary acceptor.

Fig. 11.7Many pigments collect light; one reaction-centre chlorophyll a gives up an electron.NCERT Fig. 11.4 · p. 138

A round protein disc holds three rings of small pigment circles around a central reaction centre labelled RC. In step one the antenna and centre are shown. In step two a wavy arrow, the photon, strikes a pigment on the outer ring, which glows. In step three curved arrows carry the energy inwards from ring to ring to the reaction centre. In step four an arrow leaves the reaction centre carrying an electron to a box labelled acceptor.

Each reaction centre is tuned to a slightly different red. PS I's reaction-centre chlorophyll a absorbs best at 700 nm, so it is called P700; the one in PS II absorbs best at 680 nm and is called P680.

Definition
Photosystem

A light-harvesting unit in the thylakoid membrane: an antenna of hundreds of pigment molecules on proteins around one reaction-centre chlorophyll a. PS I has P700 and PS II has P680.

Table 11.1The two photosystems
Photosystem IPhotosystem II
Reaction centreP700 (chlorophyll a)P680 (chlorophyll a)
Absorbs best at700 nm680 nm
Order of actionsecondfirst
Linked to water splittingnoyes
Found ingrana and stroma lamellaegrana only
Quick check
1 of 3
The reaction centre of PS I is called and that of PS II is called .
Show answer

Answer (1) P700, (2) P680

Each is named after the wavelength, in nanometres, that its chlorophyll a absorbs best.

11.6 The Electron Transport

Follow one electron through Fig. 11.8. Its trip has two climbs, each powered by light, and two descents. Climb 1: red light of 680 nm excites P680 in PS II, and the energised electron is captured by a primary acceptor. Descent 1: the acceptor hands it to an electron transport chain that includes cytochromes. Each carrier binds the electron a little more tightly than the one before (it lies lower on the redox-potential scale), so energy is released at every hand-over, and part of it is used to make ATP. The electron reaches PS I intact.

Climb 2: at PS I, light of 700 nm excites P700 and lifts an electron to a second acceptor, higher still. Descent 2: from there the electron runs downhill to NADPX+, which is reduced to NADPH+HX+. Plot every carrier on a redox-potential scale and the up–down–up–down path traces a Z lying on its side, hence the name Z scheme.

5/6Splitting water replaces the electrons PS II gave away.

Fig. 11.8Two light-driven lifts and two downhill runs give the Z its shape.NCERT Fig. 11.5 · p. 139

An upward arrow on the left shows electron energy. PS II with P680 sits low on the left, PS I with P700 in the middle and an NADPH box on the right. Step one: 680 nanometre light excites PS II and an electron, drawn as a circled e, rises to an acceptor. Step two: it runs downhill through the transport chain of carriers to PS I, and an ATP label branches off. Step three: 700 nanometre light lifts it from PS I to a second, higher acceptor. Step four: it runs down to the NADPH box. Step five: an arrow from below shows water splitting refilling PS II. Step six fades PS II and NADPH and draws a dashed cyclic arrow returning the electron from PS I's acceptor to the transport chain.

Definition
Z scheme

The path of electrons in the light reactions, from water through PS II, the electron transport chain and PS I to NADPX+. On a redox-potential scale the two uphill lifts and two downhill runs form a Z.

11.6.1 Splitting of Water

After P680 has given away an electron it is left electron-hungry, and it is a strong enough oxidising agent to take electrons from water, which almost nothing else in a cell can do. A water-splitting complex on PS II (it contains manganese) collects them four at a time from two water molecules:

Splitting of water
2 HX2O→OX2+4 HX++4 eX−
(11.4)

So every OX2 molecule a leaf gives off began as two water molecules at PS II. The chain of replacement runs backwards through the scheme: water refills PS II, and electrons from PS II, after the transport chain, refill PS I.

Where do the protons and oxygen appear? The water-splitting complex sits on the inner face of the thylakoid membrane, facing the lumen (the space inside the thylakoid). So protons and oxygen are released into the lumen. The oxygen diffuses out of the chloroplast; the protons stay and, as Section 11.6.3 shows, are put to work.

11.6.2 Cyclic and Non-cyclic Photo-phosphorylation

Cells store energy released from oxidisable substances in the chemical bonds of molecules such as ATP. Making ATP from ADP and inorganic phosphate (Pi) is called phosphorylation, and both mitochondria and chloroplasts do it. When the energy comes from light, the process is photophosphorylation.

The flow traced in the Z scheme is one-way. Electrons leave water, pass through PS II, the chain and PS I, and end up in NADPH; they never come back. ATP made during such one-way flow is the product of non-cyclic photophosphorylation, and it always comes with NADPH and released oxygen.

PS I has a second option. Its excited electron can be fed back into the transport chain instead of on to NADPX+, and so return to P700 to be excited again (step 6 of Fig. 11.8). Every lap through the chain still releases energy for ATP, but nothing is reduced and no water is split, so this cyclic photophosphorylation yields ATP alone. Two situations favour it. The stroma lamellae carry PS I but neither PS II nor the NADP reductase enzyme, so a loop is the only route open there; and light longer than 680 nm can excite P700 but not P680, so in such light PS I works alone.

Definition
Photophosphorylation

The synthesis of ATP from ADP and Pi using light energy. Non-cyclic: PS II and PS I in series, making ATP and NADPH. Cyclic: PS I alone, making ATP only.

Compare

Two routes for electrons

Non-cyclic

  • PS II and PS I in series
  • Electrons from water end on NADPX+
  • Makes ATP and NADPH
  • Releases OX2
  • Grana thylakoids

Cyclic

  • PS I only
  • Electrons return to PS I
  • Makes ATP only
  • No OX2 released
  • Stroma lamellae; light above 680 nm

11.6.3 Chemiosmotic Hypothesis

How does a flow of electrons actually make ATP? The answer, proposed by Peter Mitchell in 1961, is chemiosmosis. Energy from electron transport is first stored as a difference in proton concentration across a membrane, and protons flowing back down that gradient then drive ATP synthesis. Respiration uses the same idea (Chapter 12), but the protons collect in different places: in mitochondria they build up in the space between the two membranes, while in chloroplasts they build up inside the thylakoids, in the lumen.

Three processes in the light reactions build the gradient (Fig. 11.9):

  1. Water splitting. It happens on the lumen side of the membrane, so its protons are released straight into the lumen.
  2. A hydrogen carrier. The primary acceptor of PS II lies near the stroma side. It passes each electron not to a plain electron carrier but to a carrier of whole hydrogen atoms (plastoquinone). Taking the electron, the carrier also takes a proton from the stroma; when it hands the electron on near the lumen side, it releases that proton into the lumen.
  3. NADP reductase. This enzyme sits on the stroma side. Reducing NADPX+ to NADPH+HX+ uses electrons from PS I's acceptor together with protons taken from the stroma.

Add the three together and the lumen gains protons while the stroma loses them. The lumen becomes measurably more acidic than the stroma, and the membrane between them now holds a store of energy, like water held behind a dam.

4/4Protons flow back through CF0; CF1 makes ATP.

Fig. 11.9Protons pumped into the lumen can return only through ATP synthase, and their flow drives ATP synthesis.NCERT Fig. 11.7 · p. 141

A horizontal thylakoid membrane separates the stroma above from the lumen below. Embedded in it from left to right are PS II, a small hydrogen carrier, a cytochrome complex, PS I, the NADP reductase enzyme on the stroma side and ATP synthase, whose CF0 part spans the membrane and whose round CF1 head sits in the stroma. Protons are drawn as circles marked H+. Step one: water splitting at PS II releases protons into the lumen. Step two: dashed arrows show electrons moving along the membrane, and the carrier moves a proton from the stroma into the lumen. Step three: NADP reductase removes a proton from the stroma while making NADPH. Step four: protons crowd the lumen, marked low pH, and flow up through CF0 so that CF1 makes ATP.

The dam has one spillway. Protons can cross back only through the enzyme ATP synthase, and the energy they give up on the way makes ATP. The enzyme has two parts with two jobs. The channel, CF0, spans the membrane, and protons diffuse through it from lumen to stroma (facilitated diffusion). The catalytic head, CF1, sits on the stroma face, which is why the ATP appears in the stroma, right where the Calvin cycle needs it. Protons streaming through CF0 drive repeated changes in the shape of CF1, and each change helps join ADP and Pi into ATP.

In short, the dam needs a wall (a membrane that protons cannot cross freely), a pump (electron transport moving protons into the lumen), a head of water (the gradient) and a turbine (ATP synthase). The ATP it makes, with the NADPH from electron flow, is spent at once in the stroma on fixing COX2 and making sugars.

Definition
Chemiosmosis

ATP synthesis driven by a proton gradient: energy from electron transport pumps protons across a membrane, and their flow back through ATP synthase powers ATP formation.

ExampleIn the chloroplast, protons collect in the thylakoid lumen and flow back to the stroma through CF0.

Quick check
1 of 4
Electrons that leave P680 are replaced by electrons from
Show answer

Answer (C) the splitting of water

The water-splitting complex of PS II supplies them. P700 is the reaction centre that receives electrons from PS II, not the one that refills it.

11.7 Where are the ATP and NADPH Used?

Darken a leaf that has been photosynthesising and watch its COX2 uptake. It does not stop at once: it carries on for a little while and then dies away, and it resumes when the light returns. The reactions that fix COX2, the biosynthetic phase, evidently need no light themselves. What they need is the ATP and NADPH that the light reactions keep supplying, and they run until that stock is spent. Oxygen, the third product of the light reactions, plays no part here: it simply diffuses out of the chloroplast.

Which compound does COX2 enter first? Calvin's team answered this with radioactive 14C (see the box at the start of the chapter). After the briefest exposure of algal cells to labelled COX2, almost all the radioactivity was in one compound, 3-phosphoglyceric acid (PGA), an organic acid with three carbon atoms. His group went on to map every step of the route, which now bears his name.

Is PGA always first? Surveys of many species said no. In maize, sugarcane and their relatives the label turned up first in a four-carbon organic acid, oxaloacetic acid (OAA). So plants are sorted by the first stable product of COX2 fixation: C3 plants make the three-carbon PGA first (the C3 pathway), and C4 plants make the four-carbon OAA first (the C4 pathway). The two groups differ in other ways as well (Section 11.8).

11.7.1 The Primary Acceptor of COX2

A little arithmetic sets the puzzle. If one COX2 (one carbon) joins an acceptor and the first product, PGA, has three carbons, the obvious guess is an acceptor with two carbons. Researchers spent years hunting for one. The real acceptor came as a surprise: a five-carbon ketose sugar, ribulose-1,5-bisphosphate (RuBP). One COX2 plus one RuBP gives six carbons, which split at once into two molecules of PGA.

Carboxylation of RuBP
RuBP+COX2→RuBisCO2 PGA
(11.5)

11.7.2 The Calvin Cycle

RuBP is consumed in the first step, so the pathway could not continue unless something rebuilt it, and Calvin's group found that the later steps do exactly that. The pathway is therefore a loop, the Calvin cycle. Every photosynthetic plant runs it, C3, C4 or otherwise; C4 plants merely add a front end (Section 11.8). We split the loop into three stages (Fig. 11.10).

  1. Carboxylation, the key step. RuBisCO attaches COX2 to RuBP, and the unstable six-carbon product splits at once into two PGA (equation (11.5)), so COX2 is now part of a stable organic compound. The enzyme's full name, RuBP carboxylase-oxygenase, records that it can attach OX2 as well (Section 11.9).
  2. Reduction. PGA is phosphorylated with ATP and reduced with NADPH to a three-carbon sugar phosphate, triose phosphate. For every COX2 fixed, this stage uses 2 ATP and 2 NADPH. Some triose phosphate is drawn off to make glucose, sucrose and starch.
  3. Regeneration. The rest of the triose phosphate is rearranged to rebuild RuBP, so the cycle can keep accepting COX2. This needs 1 more ATP per COX2.

4/45 triose phosphate + 3 ATP rebuild 3 RuBP.

Fig. 11.10For every 3 COX2 fixed, the cycle uses 9 ATP and 6 NADPH and exports one triose phosphate.NCERT Fig. 11.8 · p. 144

A loop of boxes and arrows. Three carbon dioxide molecules enter from the top. Step one, carboxylation: 3 RuBP, each with 5 carbons, react with them to give 6 PGA of 3 carbons each. Step two, reduction: 6 ATP and 6 NADPH turn the PGA into 6 triose phosphates. Step three: one triose phosphate leaves the cycle to make sugars. Step four, regeneration: the other 5 triose phosphates, using 3 ATP, are rebuilt into the 3 RuBP the cycle started with.

Definition
Calvin cycle

The cyclic carbon reactions in the stroma: carboxylation of RuBP by RuBisCO, reduction of PGA to triose phosphate using ATP and NADPH, and regeneration of RuBP.

ExampleIt runs in all photosynthetic plants; in C4 plants only in the bundle sheath cells.

Now total the bill. Each turn fixes one carbon, so a six-carbon glucose takes six turns. Each turn costs 2 ATP in reduction and 1 ATP in regeneration, 3 ATP in all, plus 2 NADPH; equation (11.6) is the bill for a whole glucose. Notice the 3 : 2 ratio. One-way electron flow alone does not deliver ATP and NADPH in that proportion, and the extra ATP probably comes from cyclic photophosphorylation, which makes ATP without NADPH.

Calvin cycle: inputs and outputs for one glucose
6 COX2+18 ATP+12 NADPH→CX6HX12OX6+18 ADP+12 NADPX+
(11.6)
Example 11.2

The cost of one sucrose

A rice leaf (a C3 plant) makes one molecule of sucrose, CX12HX22OX11, entirely from COX2 it fixes. How many turns of the Calvin cycle does this take, and how many ATP and NADPH does the cycle use?

Try it yourself first. Then reveal the solution one step at a time.

Example 11.3

Counting carbons round the cycle

Show that three turns of the Calvin cycle keep the number of RuBP molecules the same while exporting one triose phosphate. Count carbons at each stage, and total the ATP and NADPH used.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 4
How many carbon atoms does the primary COX2 acceptor of the Calvin cycle have?
Show answer

Answer 5

RuBP is a five-carbon sugar: 5 + 1 = 6 carbons, which split into two three-carbon PGA. The tempting answer, 2, is the acceptor scientists first looked for.

11.8 The C4 Pathway

Maize, sugarcane, sorghum and many grasses of hot, dry tropical regions are C4 plants. They make OAA as their first product, yet their main route to sugar is still the Calvin cycle. So what sets them apart? They produce more biomass, cope with heat, keep gaining from very bright light, show almost no photorespiration, and have an unusual leaf anatomy. We begin with the anatomy.

Cut across a maize leaf and look at a vein (Fig. 11.11). Around each vascular bundle sits a ring of unusually large cells, the bundle sheath, sometimes several layers deep. Look closely and three things stand out: these cells are crowded with chloroplasts, their walls are thick enough to stop gases passing, and they fit together with no air spaces. The mesophyll cells radiate outward from the ring, and the whole pattern looks like a wreath, which is what the German word Kranz means; hence Kranz anatomy.

Compare a C3 dicot leaf, such as a bean leaf. Its mesophyll forms palisade and spongy layers with air spaces, and the cells around each vein are small and pale. Even a C3 grass such as wheat, whose mesophyll is not layered, lacks the wreath.

3/3Many chloroplasts, thick walls, no intercellular spaces.

Fig. 11.11In a C4 leaf, large chloroplast-rich bundle sheath cells form a wreath around each vein.NCERT p. 145

Two leaf cross-sections side by side, each between an upper and lower epidermis. Left, a C3 dicot leaf: a row of tall palisade cells, loose spongy cells with air spaces, and a vein ringed by small pale sheath cells. In step one only the C3 leaf is clear. In step two the C4 leaf appears on the right: its vein is ringed by large green bundle sheath cells packed with chloroplasts, with mesophyll cells radiating around them like a wreath. Step three outlines the wreath and lists its features: many chloroplasts, thick walls and no air spaces.

Definition
Kranz anatomy

The leaf anatomy of C4 plants: each vein is surrounded by a wreath of large bundle sheath cells with many chloroplasts, thick walls impervious to gases and no intercellular spaces.

ExampleMaize, sorghum and sugarcane leaves.

The biochemistry was worked out by M. D. Hatch and C. R. Slack in Australia in the mid-1960s, so the C4 route is called the Hatch and Slack pathway. It too is a cycle. Follow it in Fig. 11.12:

  1. Capture. In a mesophyll cell the enzyme PEP carboxylase (PEPcase) joins COX2 to a three-carbon acceptor, phosphoenolpyruvate (PEP), giving the four-carbon acid OAA. RuBisCO is absent from these cells, so PEPcase has the COX2 to itself.
  2. Shipping. OAA is quickly turned into a more stable four-carbon acid (malic acid in maize, aspartic acid in some other species), which travels through plasmodesmata into the bundle sheath.
  3. Release. In the sheath an enzyme strips COX2 off the four-carbon acid (decarboxylation), leaving a three-carbon remnant, pyruvate in maize.
  4. Return. Pyruvate goes back to the mesophyll, where it is rebuilt into PEP, closing the loop.

4/4Pyruvate returns to the mesophyll and becomes PEP.

Fig. 11.12The mesophyll fixes COX2 with PEPcase and pumps it, as a four-carbon acid, into the bundle sheath for the Calvin cycle.NCERT Fig. 11.9 · p. 146

Two cells side by side: a mesophyll cell on the left and a bundle sheath cell on the right. Step one: carbon dioxide from the air joins PEP, a 3-carbon molecule, through the enzyme PEPcase, giving OAA, a 4-carbon acid. Step two: OAA becomes malate, also 4-carbon, which crosses into the bundle sheath cell. Step three: malate releases carbon dioxide, which enters a circle labelled Calvin cycle with RuBisCO, and an arrow leads to sugars. Step four: the remaining 3-carbon pyruvate returns to the mesophyll cell and becomes PEP again.

The division of labour is now clear. The mesophyll, armed with PEPcase but no RuBisCO, only captures COX2 and ships it inward. The bundle sheath, rich in RuBisCO but without PEPcase, receives that COX2 and runs the Calvin cycle on it. So both kinds of plant make their sugar by the same Calvin cycle: a C3 leaf runs it throughout its mesophyll, a C4 leaf only in its bundle sheath.

Quick check
1 of 3
Put the steps of the Hatch and Slack pathway in order, starting in the mesophyll.
  1. Malate releases COX2 for the Calvin cycle
  2. Pyruvate returns and becomes PEP
  3. PEPcase fixes COX2 on PEP
  4. OAA is converted to malate
  5. Malate moves to the bundle sheath
Show answer
Answer
  1. PEPcase fixes COX2 on PEP
  2. OAA is converted to malate
  3. Malate moves to the bundle sheath
  4. Malate releases COX2 for the Calvin cycle
  5. Pyruvate returns and becomes PEP
Fixation by PEPcase comes first in the mesophyll; decarboxylation in the bundle sheath feeds the Calvin cycle, and the three-carbon remnant goes back to rebuild PEP.

11.9 Photorespiration

Why do C4 plants go to the trouble of pumping COX2? The answer lies in a weakness of the enzyme that runs the first step of the Calvin cycle (equation (11.5)). No enzyme on Earth is more abundant than RuBisCO, partly because it works slowly, so a leaf needs a great deal of it.

Its active site accepts either gas, COX2 or OX2 (Fig. 11.13); hence carboxylase-oxygenase. Offered equal amounts, it picks COX2 far more often, but the choice is a competition decided by how many molecules of each gas are around. Change the mixture and you change the outcome.

3/4RuBP + OX2 → PGA + phosphoglycolate: photorespiration.

Fig. 11.13COX2 and OX2 compete for RuBisCO's active site; high COX2 keeps it carboxylating.NCERT p. 147

A large enzyme shape labelled RuBisCO holds RuBP. Carbon dioxide molecules approach from the left and oxygen molecules from the right. In step one both gases approach: one site, two gases. In step two the carbon dioxide branch is highlighted: RuBP and carbon dioxide give 2 PGA, which go to the Calvin cycle. In step three the oxygen branch is highlighted: RuBP and oxygen give one PGA and one phosphoglycolate, with carbon lost and ATP used. In step four many more carbon dioxide molecules crowd in, as in a C4 bundle sheath cell, the oxygen route is crossed out and only carboxylation continues.

Air holds far more OX2 than COX2, so in a C3 leaf a share of RuBisCO's encounters are with OX2, and each one is a COX2 not fixed. Each time OX2 wins, RuBP is split into one PGA and one two-carbon phosphoglycolate instead of two PGA. This oxygen-consuming route, which runs only in light, is photorespiration.

Oxygenation of RuBP
RuBP+OX2→RuBisCOPGA+phosphoglycolate
(11.7)

For the plant it is pure loss. Carbon that had already been fixed is given off again as COX2, ATP is spent salvaging the phosphoglycolate, and no sugar, ATP or NADPH comes out of it. What purpose, if any, photorespiration serves is still not known.

This is where the C4 pump pays off. The mesophyll keeps delivering four-carbon acids to the bundle sheath, and their decarboxylation releases COX2 faster than it can leak out through the thick walls. COX2 around RuBisCO climbs far above its level in air, the competition is rigged in favour of COX2, and oxygenation all but disappears. With photorespiration negligible, C4 plants lose less of the carbon they fix, which is why they are so productive, and they keep this advantage in heat, when C3 plants photorespire most.

Definition
Photorespiration

The light-dependent pathway that begins when RuBisCO adds OX2 instead of COX2 to RuBP, giving PGA and phosphoglycolate. It makes no sugar, ATP or NADPH and releases fixed COX2; it is negligible in C4 plants.

Table 11.2C3 and C4 plants comparedNCERT Table 11.1 · p. 148
C3 plantsC4 plants
First stable product of COX2 fixationPGA (3C)OAA (4C)
Primary COX2 acceptorRuBP (5C)PEP (3C)
Enzyme of the first fixationRuBisCOPEPcase
Cells where COX2 is first fixedmesophyllmesophyll
Cells that fix COX2 at allone type: mesophylltwo types: mesophyll and bundle sheath
Cells running the Calvin cyclemesophyllbundle sheath
RuBisCO found inmesophyllbundle sheath
PEPcase for COX2 fixationnoyes, in mesophyll
Kranz anatomyabsentpresent
COX2 fixation in bright lightlowerhigher
Photorespiration in bright light or low COX2highnegligible
Photorespiration at high COX2negligiblenegligible
Usual temperature optimum20–25 °C30–40 °C
COX2 at which photosynthesis saturatesabove about 450 μL L−1about 360 μL L−1
Exampleswheat, rice, bean, mangomaize, sugarcane, sorghum, Amaranthus
Quick check
1 of 3
When RuBisCO acts on RuBP as an oxygenase, the products are
Show answer

Answer (B) one PGA and one phosphoglycolate

Adding OX2 splits RuBP (5C) into PGA (3C) and phosphoglycolate (2C). Two PGA form only when COX2 is added.

11.10 Factors Affecting Photosynthesis

Why does one field of wheat out-yield the next? Much of the answer is the rate of photosynthesis, and that rate depends on two sets of factors. External factors are the surroundings: sunlight, temperature, COX2 concentration and water. Internal factors belong to the plant: how many leaves it has and how large, old and well angled they are; how many mesophyll cells and chloroplasts they hold; how much chlorophyll they carry; and how much COX2 is inside them. These depend on the plant's genes and on how well it has grown.

All of these act at the same time, yet at any moment the rate is usually held back by one of them, the limiting factor: the one in shortest supply compared with what the leaf could use. A railway ticket queue is a fair picture. If only one counter is open, the queue moves at that clerk's pace, and printing more tickets will not speed it up. F. F. Blackman turned this idea into a law in 1905.

Law 11.1Blackman’s law of limiting factors (1905)

When a chemical process depends on more than one factor, its rate is set by the factor that is nearest its minimum value. That factor, the limiting factor, is the one whose change alters the rate.

Definition
Limiting factor

The factor in shortest supply relative to need, which alone controls the rate of a process at that moment.

ExampleOn a shaded forest floor, light limits photosynthesis.

Example 11.4

Finding the limiting factor

A student measures the rate of photosynthesis of a C3 leaf at 25 °C (in arbitrary units) at four light intensities and two COX2 levels, each for one hour.

Rate of photosynthesis (arbitrary units)
Light (units)at 0.04 % COX2at 0.06 % COX2
155
21010
41820
81827

(a) Which factor limits the rate at light intensities 1 and 2? (b) What limits the leaf at light 8 and 0.04 % COX2? (c) Predict the rate at light 16 and 0.04 % COX2.

Try it yourself first. Then reveal the solution one step at a time.

11.10.1 Light

Read the curve in Fig. 11.14 from left to right. At first (near W) the rate of COX2 fixation climbs in direct proportion to light intensity: double the light, double the rate, so light is limiting. Then the climb flattens (X, Y), not because light stops mattering but because something else, usually COX2, now limits. Leaves reach this plateau surprisingly early (NCERT puts light saturation at about 10 per cent of full sunlight), so in nature light limits mainly plants in shade or under a dense forest canopy. At the far right (Z), light so strong that it breaks down chlorophyll pulls the rate down.

Intensity is not the whole story. The quality of light (its wavelengths, Section 11.4) and the duration of daily exposure matter too.

2/4From X onwards extra light hardly helps; at Y the rate is flat.

Fig. 11.14Light limits on the rising line; another factor limits on the plateau.NCERT Fig. 11.10 · p. 149

The rate of photosynthesis rises along a straight line from zero as light increases, through point W, bends at point X, levels off along a plateau through point Y and dips slightly at point Z at the highest intensities. Step one shades the straight part: light limits. Step two shades the plateau: another factor limits. Step three adds a dashed curve for more carbon dioxide that follows the same straight line but levels off higher. Step four shades the dip at the far right: too much light.

InteractiveLimiting-factor lab

Two buttons choose a C3 plant (wheat) or a C4 plant (maize), and two more choose whether the plant is well watered or short of water. Sliders set the light from 0 to 100 per cent of full sunlight, the carbon dioxide from 100 to 1000 microlitres per litre and the leaf temperature from 0 to 50 degrees Celsius. A graph plots the rate of photosynthesis against light, with dashed lines for the ceiling that light, carbon dioxide and temperature each set alone, and a dot at the chosen light. Readouts give the rate and the limiting factor, and a message explains why changing the other factors would or would not help.

Fig. 11.15Change the light, COX2 and temperature for a C3 or a C4 plant and watch which factor sets the rate. The model is a simplified Blackman picture with typical values.

11.10.2 Carbon dioxide Concentration

Greenhouse growers of tomatoes and capsicum (bell pepper) pump extra COX2 into the air around their crops and harvest more fruit. Why does that work? Because COX2 is the factor that most often limits photosynthesis: air holds only about 0.04 per cent of it.Global average COX2 passed 420 µL per litre (0.042 per cent) in 2024 and is still rising. NCERT quotes the older range of 0.03–0.04 per cent. Up to about 0.05 per cent, more COX2 means faster fixation, though levels much above that harm plants if kept up for long.

C3 and C4 plants differ in how much extra COX2 they can use. In dim light neither responds, because light is limiting. In bright light both do, up to a point: a C4 plant is saturated by about 360 μL L−1, while a C3 plant keeps responding until beyond 450 μL L−1. Today's air therefore holds a C4 crop close to its maximum but still holds a C3 crop back, and tomatoes and capsicum are C3 plants.

11.10.3 Temperature

Enzymes run the carbon reactions, and enzyme activity rises with warmth up to an optimum and falls beyond it, so temperature strongly controls these reactions; the light-driven steps are far less sensitive. Optima differ between plants. C4 plants, with their COX2 pump, keep speeding up into the thirties (°C), while C3 plants peak at much cooler temperatures. Habitat matters too: a plant adapted to the tropics has a higher optimum than one adapted to a temperate climate.

11.10.4 Water

A wilting plant on a hot afternoon photosynthesises slowly, but not because it lacks water to split: the light reactions use only a tiny fraction of the water a plant takes up. The damage is indirect. To save water the plant shuts its stomata, which also shuts out COX2, and its drooping leaves present less surface to the light and slow their metabolism.

Quick check
1 of 3
A plant has plenty of light and water, but the rate of photosynthesis rises when more COX2 is supplied. By Blackman's law, the limiting factor was
Show answer

Answer (C) COX2

Only a change in the limiting factor changes the rate. Since adding COX2 raised it, COX2 was limiting.
Flash cards · 8

Numbers to remember

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Recap

Photosynthesis in Higher Plants: key points and summary

  1. Photosynthesis uses light energy to make sugar from COX2 and water and releases OX2; it feeds almost every food chain and refills the air's oxygen (Section 11.1).
  2. Starch tests on leaves show that chlorophyll, light and COX2 are all needed (Section 11.1).
  3. Priestley, Ingenhousz, Sachs, Engelmann and van Niel built the modern equation; the OX2 released comes from water (Section 11.2).
  4. Thylakoid membranes run the light reactions (ATP, NADPH, OX2); the stroma runs the carbon reactions that make sugar (Section 11.3).
  5. Chlorophyll a is the chief pigment; accessory pigments widen the usable spectrum and protect chlorophyll a (Section 11.4).
  6. Each photosystem's antenna funnels energy to a reaction-centre chlorophyll a: P700 in PS I, P680 in PS II (Section 11.5).
  7. In the Z scheme, electrons pass from water through PS II, a transport chain and PS I to NADPX+ (Section 11.6).
  8. Non-cyclic photophosphorylation makes ATP and NADPH; cyclic flow through PS I alone makes only ATP (Section 11.6.2).
  9. Protons pumped into the thylakoid lumen flow back through ATP synthase, whose CF1 makes ATP: chemiosmosis (Section 11.6.3).
  10. In the Calvin cycle RuBisCO fixes COX2 onto RuBP; each COX2 costs 3 ATP and 2 NADPH, and one glucose needs six turns (Section 11.7.2).
  11. C4 plants fix COX2 as OAA with PEPcase in the mesophyll and run the Calvin cycle in Kranz bundle sheath cells (Section 11.8).
  12. RuBisCO's oxygenase activity causes wasteful photorespiration in C3 plants; C4 plants suppress it by concentrating COX2 (Section 11.9).
  13. By Blackman's law the factor in shortest supply sets the rate; COX2 limits C3 plants today, and water acts mainly through the stomata (Section 11.10).
Practice · 18 questions

Practice questions with answers (NCERT “Exercises”)

  1. Short answerEasyNCERT Exercises Q1

    Two grasses grow side by side on a roadside verge: one has broad, dark leaves and the other narrow, pale ones. A friend says the broad-leaved one “looks like a C4 plant”. Can you tell C3 from C4 just by looking at the outside of a plant? Explain.

    Show solution

    AnswerNot reliably; the defining features are internal.

    No, not with confidence. Leaf colour, width, fast growth or a hot, dry habitat are at most hints: they change with conditions, and many C3 plants share them.

    What defines a C4 plant lies inside: Kranz anatomy in a leaf section, PEPcase in the mesophyll, and OAA as the first product of COX2 fixation. To decide, cut a thin leaf section and look for the wreath of bundle sheath cells, or test which compound picks up labelled carbon first.

  2. Short answerEasyNCERT Exercises Q2

    Your teacher hands you two unlabelled slides of leaf cross-sections. Which internal structure will you look at to sort them into C3 and C4, and what exactly do you expect to see in each?

    Show solution

    AnswerThe bundle sheath: Kranz anatomy marks the C4 leaf.

    Look at the cells around each vascular bundle. In the C4 leaf they form a wreath (Kranz anatomy): large bundle sheath cells, often in more than one layer, packed with chloroplasts, with thick walls and no intercellular spaces, and mesophyll cells radiating around them.

    In the C3 leaf the bundle sheath cells are small and pale with few chloroplasts, and the mesophyll is spread through the leaf (in dicots as palisade and spongy layers with air spaces).

  3. Long answerMediumNCERT Exercises Q3

    In a sugarcane leaf only the bundle sheath cells run the Calvin cycle, yet sugarcane is among the most productive crops known and out-yields wheat in hot weather. How can so few Calvin-cycle cells achieve so much?

    Show solution

    AnswerThe C4 pump keeps COX2 high around RuBisCO, so carbon is not lost to photorespiration.

    • PEPcase in every mesophyll cell captures COX2 efficiently, even when COX2 inside the leaf is low.
    • The four-carbon acids carry this carbon into the bundle sheath, where decarboxylation releases it; thick, gas-tight walls keep it there, so COX2 around RuBisCO is far above that in air.
    • RuBisCO therefore works almost only as a carboxylase: photorespiration is negligible, so no fixed carbon or ATP is wasted.
    • C4 plants also keep gaining from strong light and work best at 30–40 °C, the conditions in which sugarcane grows, whereas wheat (a C3 plant) loses much fixed carbon to photorespiration in heat.
  4. Short answerMediumNCERT Exercises Q4

    RuBisCO can add either COX2 or OX2 to RuBP.

    1. What decides which gas RuBisCO adds in a given cell?

      Show solution

      AnswerTheir relative concentrations at the active site.

      Both bind the same active site competitively, so the ratio of COX2 to OX2 around the enzyme decides. RuBisCO prefers COX2, so at nearly equal concentrations it mostly carboxylates; in normal air OX2 is far more plentiful, so some oxygenation occurs.

    2. Why does RuBisCO carry out mainly carboxylation in a C4 plant?

      Show solution

      AnswerThe bundle sheath has a high COX2 concentration.

      In C4 plants RuBisCO is found only in the bundle sheath, where four-carbon acids are decarboxylated. The released COX2 builds up behind thick, gas-tight walls, so COX2 wins the competition and oxygenation (photorespiration) is minimised.

  5. Short answerMediumNCERT Exercises Q5

    Imagine a mutant plant that makes plenty of chlorophyll b but no chlorophyll a.

    1. Could it photosynthesise? Explain.

      Show solution

      AnswerNo.

      No. The reaction centres of both photosystems, P680 and P700, are chlorophyll a molecules, and only a reaction centre can give away an excited electron to start electron transport. Chlorophyll b can absorb light but can only pass the energy on; with no chlorophyll a to receive it, no electrons flow, so no ATP, NADPH or OX2 is made.

    2. What, then, do chlorophyll b and the other accessory pigments do for a normal plant?

      Show solution

      AnswerWiden the usable light and protect chlorophyll a.

      They absorb wavelengths that chlorophyll a absorbs poorly (for example 450–500 nm) and pass the energy to chlorophyll a, so the leaf uses a wider range of light. Carotenoids also protect chlorophyll a from photo-oxidation in strong light.

  6. Short answerEasyNCERT Exercises Q6

    A tarpaulin left on a lawn for a week leaves a yellowish patch underneath. Why does the grass turn yellow or pale green, and what does this tell you about which pigments are more stable?

    Show solution

    AnswerChlorophyll breaks down in the dark; the more stable carotenoids remain.

    Chlorophyll is broken down all the time, and in flowering plants making new chlorophyll needs light. Under the tarpaulin chlorophyll is lost and not replaced, so the yellow carotenoids (carotenes and xanthophylls), which were masked by the green, show through. Carotenoids are therefore the more stable pigments.

  7. Short answerMediumNCERT Exercises Q7

    A money plant grows on a sunny balcony, and a cutting of the same plant grows in a dim corner of the living room. After a few months, which plant has the darker green leaves, and why?

    Show solution

    AnswerThe plant in the dim corner.

    The shaded plant's leaves are darker green. A leaf grown in weak light packs more chlorophyll into its chloroplasts (larger light-harvesting antennae, bigger grana) to capture as much of the scarce light as possible. Leaves in bright sun need less chlorophyll; they are paler and carry relatively more protective carotenoids.

  8. DiagramMediumNCERT Exercises Q8

    Use the light-response curve in Fig. 11.14 (points W, X, Y and Z).

    1. At which point is light alone the limiting factor?

      Show answer

      Answer (A) W

      On the straight rising part (W) the rate increases in proportion to light, so light alone limits. At X light and another factor both limit; at Y and Z extra light does not raise the rate.
    2. What is happening to the limiting factor near X?

      Show solution

      AnswerLight stops being the only limit; another factor starts to limit.

      X is the bend of the curve. Light is still partly limiting, but a second factor (usually COX2, or temperature) is beginning to limit too, so the rate no longer rises in proportion to light. Beyond X the leaf is approaching light saturation.

    3. What could be limiting at Y, and how would you test your idea?

      Show solution

      AnswerMost likely COX2 (or temperature); raise it and see if the plateau rises.

      On the plateau, light is in excess, so COX2 concentration (most often) or temperature limits. Repeat the curve at a higher COX2: if the plateau rises, as in step 3 of the figure, COX2 was limiting. If not, try a warmer temperature.

    4. Why does the curve fall near Z?

      Show solution

      AnswerVery strong light damages chlorophyll.

      At very high intensities excess light energy breaks down chlorophyll (photo-oxidation), so the photosynthetic machinery is damaged and the rate falls.

  9. Long answerMediumNCERT Exercises Q9

    Compare the following.

    1. The C3 and C4 pathways

      Show solution

      AnswerSee the comparison.

      • Primary COX2 acceptor: RuBP (5C) in C3; PEP (3C) in C4.
      • First stable product: PGA (3C) versus OAA (4C).
      • Enzyme of first fixation: RuBisCO versus PEPcase.
      • Where the Calvin cycle runs: all mesophyll cells versus bundle sheath cells only.
      • Photorespiration: significant versus negligible; C4 plants also tolerate higher temperatures and saturate at lower COX2.
    2. Cyclic and non-cyclic photophosphorylation

      Show solution

      AnswerSee the comparison.

      • Photosystems: PS I only versus PS II and PS I in series.
      • Electron path: back to PS I (a cycle) versus from water to NADPX+ (one way).
      • Products: ATP only versus ATP, NADPH and OX2.
      • Water splitting: none versus yes.
      • Where: stroma lamellae, or light above 680 nm, versus grana thylakoids.
    3. The anatomy of C3 and C4 leaves

      Show solution

      AnswerSee the comparison.

      • Bundle sheath: small, pale, few chloroplasts in C3; large, in a wreath, many chloroplasts in C4 (Kranz anatomy).
      • Sheath cell walls: thin versus thick and impervious to gases, with no intercellular spaces.
      • Mesophyll: spread through the leaf (palisade and spongy in dicots) versus radiating around the sheath.
      • Cells that fix COX2: one type versus two types.
  10. Quick answerEasy

    The reaction centre of photosystem II absorbs best at a wavelength of

    Show answer

    Answer (B) 680 nm

    PS II's reaction centre is P680. 700 nm belongs to P700 of PS I; 430 nm is the blue peak of chlorophyll a in general; 560 nm is green light, which chlorophyll absorbs poorly.
  11. Quick answerMedium

    Assertion (A): Photorespiration is negligible in C4 plants. Reason (R): Decarboxylation of four-carbon acids in the bundle sheath raises the COX2 concentration around RuBisCO.

    Show answer

    Answer (A) Both A and R are true, and R correctly explains A.

    Both are true, and the high COX2 around RuBisCO is exactly why it hardly ever oxygenates RuBP in C4 plants.
  12. Quick answerMedium

    How many ATP molecules does the Calvin cycle use to make five molecules of glucose?

    Show answer

    Answer 90

    5 glucose need 5 × 6 = 30 COX2, at 3 ATP each: 30 × 3 = 90 ATP (and 60 NADPH).
  13. Quick answerMedium

    Which features describe the bundle sheath cells of a C4 leaf? Choose all that apply.

    Select all that apply
    Show answer
    Answer
    • (A) They contain many chloroplasts
    • (B) Their walls are thick and impervious to gases
    • (D) They are rich in RuBisCO
    Bundle sheath cells are chloroplast-rich, thick-walled with no intercellular spaces, and hold the RuBisCO. PEPcase is in the mesophyll.
  14. Quick answerEasy

    Match each scientist with the finding.

    Tap an item on the left, then its match on the right.

    Show answer
    Answer
    • Priestley : plants restore air spoiled by a candle
    • Ingenhousz : only green parts in light give off oxygen
    • Engelmann : first action spectrum, with bacteria
    • van Niel : oxygen comes from the hydrogen donor, water
    • Calvin : PGA is the first product of COX2 fixation
    These five discoveries, in order, built the modern picture of photosynthesis.
  15. Quick answerMedium

    Put the carriers of non-cyclic electron flow in order, from the first electron donor to the final acceptor.

    1. electron transport chain
    2. P700 (PS I)
    3. NADPX+
    4. P680 (PS II)
    5. water
    Show answer
    Answer
    1. water
    2. P680 (PS II)
    3. electron transport chain
    4. P700 (PS I)
    5. NADPX+
    Electrons from water refill P680; after excitation they run through the transport chain to PS I, are lifted again and end on NADPX+.
  16. Quick answerEasy

    In the mesophyll cells of a C4 plant, COX2 is first fixed by the enzyme .

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    Answer PEP carboxylase

    PEP carboxylase (PEPcase) adds COX2 to PEP, giving OAA; C4 mesophyll cells have no RuBisCO.
  17. Quick answerMedium

    Assertion (A): In a leaf moved into darkness, the Calvin cycle stops after a short time. Reason (R): The Calvin cycle needs light to excite RuBisCO directly.

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    Answer (C) A is true, but R is false.

    A is true: the cycle runs for a while and stops once ATP and NADPH run out. R is false: light does not excite RuBisCO; the cycle depends on light only through the ATP and NADPH the light reactions make.
  18. Quick answerMedium

    Which statement about chemiosmosis in the chloroplast is correct?

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    Answer (C) Protons accumulate in the lumen and flow back through CF0

    Protons build up in the lumen and return to the stroma through the CF0 channel; CF1 projects into the stroma, and NADP reductase removes protons from the stroma.

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Quick check: MCQs on Photosynthesis in Higher Plants

  1. 11.1 What Do We Know?3 questions
  2. 11.2 Early Experiments3 questions
  3. 11.3 Where Does Photosynthesis Take Place?3 questions
  4. 11.4 How Many Types of Pigments are Involved in Photosynthesis?3 questions
  5. 11.5 What is Light Reaction?3 questions
  6. 11.6.3 Chemiosmotic Hypothesis4 questions
  7. 11.7.2 The Calvin Cycle4 questions
  8. 11.8 The $\mathrm{C_4}$ Pathway3 questions
  9. 11.9 Photorespiration3 questions
  10. 11.10.4 Water3 questions
Glossary · 15

Key terms (English–Hindi)

absorption spectrumअवशोषण स्पेक्ट्रमavashoshan spectrum
A graph of how strongly a pigment absorbs light of each wavelength.First seen in the chapter →
accessory pigments
Chlorophyll b, xanthophylls and carotenes: they absorb light that chlorophyll a misses, pass the energy to it and protect it from photo-oxidation.First seen in the chapter →
action spectrumक्रिया स्पेक्ट्रमkriya spectrum
A graph of the rate of photosynthesis under light of each wavelength.First seen in the chapter →
Calvin cycle
The cycle of carbon reactions in the stroma: carboxylation of RuBP, reduction to triose phosphate and regeneration of RuBP.First seen in the chapter →
chemiosmosisरसोपरासरणrasoparasaran
ATP synthesis driven by protons flowing back through ATP synthase down a gradient built across a membrane.First seen in the chapter →
Kranz anatomy
The leaf anatomy of C₄ plants: a wreath of large, chloroplast-rich, thick-walled bundle sheath cells around each vein.First seen in the chapter →
light reactions
The steps on the thylakoid membranes that light drives directly: absorbing light, splitting water, giving off oxygen and making ATP and NADPH.First seen in the chapter →
limiting factorसीमाकारी कारकseemakari karak
The factor in shortest supply relative to need, which alone sets the rate of a process at that moment.First seen in the chapter →
photophosphorylationप्रकाश-फॉस्फोरिलीकरणprakash-phosphorilikaran
Making ATP from ADP and inorganic phosphate using energy from light: cyclic (PS I only, ATP only) or non-cyclic (both photosystems, ATP and NADPH).First seen in the chapter →
photorespirationप्रकाश-श्वसनprakash-shvasan
RuBisCO adding O₂ instead of CO₂ to RuBP; it yields phosphoglycolate, makes no sugar or ATP and releases fixed CO₂.First seen in the chapter →
photosynthesisप्रकाश-संश्लेषणprakash-sanshleshan
The light-driven process in which green plants build sugars from carbon dioxide and water, releasing oxygen.First seen in the chapter →
photosystemप्रकाश-तंत्रprakash-tantra
A pigment–protein complex in the thylakoid membrane: an antenna of light-harvesting pigments around one reaction centre. Plants have PS I and PS II.First seen in the chapter →
reaction centreअभिक्रिया केंद्रabhikriya kendra
The single chlorophyll a molecule of a photosystem that gives away an excited electron: P700 in PS I, P680 in PS II.First seen in the chapter →
RuBisCO
Ribulose bisphosphate carboxylase-oxygenase, the enzyme that adds CO₂ (or O₂) to RuBP; the most abundant enzyme on Earth.First seen in the chapter →
Z scheme
The zigzag path of electrons from water through PS II, an electron transport chain and PS I to NADP⁺, drawn on a redox-potential scale.First seen in the chapter →