Principles of Inheritance and Variation: Class 12 Biology Chapter 4 Hinglish mein
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Is chapter mein aap kya seekhenge
- Samjho ki Mendel ka garden pea chunna, true-breeding lines aur quantitative method kaise unke results ko reliable banate the
- Punnett squares aur product rule se monohybrid aur dihybrid crosses ke genotypic aur phenotypic ratios predict karo, aur ek test cross design karo
- Law of dominance, segregation aur independent assortment batao aur unhe meiosis mein chromosomes ke behaviour se jodo
- Complete dominance, incomplete dominance aur co-dominance mein farq karo, gene products ke through dominance samjhao, aur ABO blood-group ke sawaal solve karo
- Linkage aur recombination samjhao aur recombination frequencies se ek simple gene map banao
- Polygenic inheritance aur pleiotropy ko examples ke saath samjhao
- XO, XY, ZW aur haplodiploid sex determination ko compare karo aur samjhao ki insaan ke bachche ka sex father ka sperm kyun decide karta hai
- Mutations ko classify karo, autosomal aur X-linked patterns ke liye pedigrees padho, aur main Mendelian aur chromosomal disorders ke baare mein batao
NCERT Biology Class 12, Chapter 4, pp. 53–78 par based original companion text. Yeh NCERT se juda nahi hai aur NCERT ne ise endorse nahi kiya hai.
Jo farmers hybrid rice ya hybrid maize ugaate hain, woh har season naya seed khareedte hain. Agar woh apni fasal ka anaaj bachakar bo dein, to agla khet ek mixed bag ban jaata hai. Kuch plants lambe aur kuch chhote, kuch jaldi aur kuch der se, aur zyaadatar kam yield dete hain. Iske ulat, traditional variety se bachaya seed saal-dar-saal bilkul apne parents jaisa hi ugta hai. Ek khet ka seed true breed kyun karta hai jabki doosre ka bikhar jaata hai? Is chapter ke end tak tum ise samjha paoge.
Aise sawaalon ke peeche ki science genetics (आनुवंशिकी) hai. Yeh do jude hue sawaal poochti hai. Characters parents se offspring tak kaise pahunchte hain? Is aage dene ko inheritance (वंशागति) kehte hain. Aur offspring kabhi apne parents ki, ya ek doosre ki, exact copy kyun nahi hote? Yeh differences variation (विविधता) hain.
Selective breeding genetics se kahin zyaada purani hai. Traditional crop varieties, aur India ki Gir aur Tharparkar cattle ya Murrah buffaloes, hazaaron saalon mein un logon ne banayi jo chunte the ki kin plants aur animals se breed karna hai, bina yeh jaane ki yeh chunna kaam kyun karta hai. Agli generation ko predict kar sakne wale pehle rules 1860s mein ek monastery ke garden se nikle.
4.1 Mendel's Laws of Inheritance
Gregor Mendel, Brno (ab Czech Republic mein) ke ek monk, ne 1856 se 1863 tak saat saal garden pea plants ko cross karne aur unke offspring ginne mein lagaye. Teen aadatein unke kaam ko alag banati thi. Woh poore plant ki jagah ek baar mein ek clear-cut character follow karte the. Unhone hazaaron plants ugaaye aur score kiye, taaki chance ke effects barabar ho jaayein. Aur woh counts se mathematically reasoning karte the, har idea ko agli generation predict karke aur phir use ugaakar test karte the. Isse pehle biology mein kisi sawaal ko settle karne ke liye numbers aur probability ka use shaayad hi kabhi hua tha.
Pea ne khud kai tarah se unki madad ki:
- Iske flowers normally band petals ke andar khud ko pollinate karte hain, isliye alag rakhi gayi line generations tak pure rehti hai.
- Jab bhi experimenter koi khaas cross chahe, inhi flowers ko khol kar haath se pollinate kiya ja sakta hai.
- Ek generation ek hi season mein ug jaati hai, aur har plant ginne ke liye bahut saare seeds deta hai.
- Iske kai characters do bilkul alag forms mein aate hain, beech ka kuch nahi, isliye har plant ko bina behas ke score kiya ja sakta hai.
Kuch bhi cross karne se pehle Mendel ne pakka kiya ki har starting line true-breeding ho: generation-dar-generation self-pollination ke baad woh line, jis character ko woh study kar rahe the, uske liye bilkul parents jaise offspring hi deti thi. Aisi chaudah lines, saat pairs mein mila kar, unka material thi. Ek pair ke partners ek character ko chhodkar baaki sab mein ek jaise the. Saat characters the seed shape (round ya wrinkled), seed colour (yellow ya green), flower colour (violet ya white), flower position (stem ke saath-saath ya uske tip par guchchhe mein), pod shape (inflated ya constricted), pod colour (green ya yellow) aur stem length (tall ya dwarf).
Do lines ko cross karne ke liye Mendel ko chune hue seed parent ko khud ko fertilise karne se rokna tha aur phir use sirf ek doosre plant ka pollen dena tha. Fig. 4.1 yeh procedure dikhata hai. Flower bud se anthers pollen girane se pehle hi hata diye jaate hain, is step ko emasculation kehte hain, aur flower ko ek bag se dhak diya jaata hai taaki koi bhatka hua pollen us tak na pahunche. Jab stigma ready hota hai, to chune hue pollen parent ka pollen us par chhidka jaata hai, bag wapas lag jaata hai, aur jo seeds bante hain woh cross ki pehli generation hain.
4/5Chune hue pollen parent ka pollen stigma par chhidka jaata hai.
Ek schematic pea flower jo khola gaya hai taaki beech mein pistil dikhe, jiske upar gol stigma hai aur uske chaaron taraf chaar yellow anthers. Step 1, bud: stigma aur anthers labelled hain. Step 2, emasculate: anthers gayab hain, sirf dashed outlines dikhte hain jin par anthers removed likha hai. Step 3, bag: ek dashed paper bag flower ko gher leta hai. Step 4, dust: bag hat gaya hai, aur pollen label wala ek arrow right mein ek chhote flower ke anthers se, jis par pollen parent likha hai, stigma tak jaata hai, jahan ab yellow pollen grains baithe hain. Step 5, seeds: bag wapas lag gaya hai aur ovary se ek arrow ek green pod tak jaata hai jismein paanch seeds hain aur us par pod with F1 seeds likha hai.
Answer dekho
Answer (C) Taaki flower khud ko pollinate na kar sake
Answer dekho
Answer Galat
Answer dekho
Answer (B) Ek woody stem jo kai saal jeeta hai
4.2 Ek Gene ki Inheritance
Mendel ke character pairs mein se ek lo, pod colour. Ek true-breeding line mein green pods hain, doosri mein yellow. Inhe cross karo, aur seeds ugkar first filial generation, yaani (Latin mein son ya daughter ke liye) banate hain. Har plant mein green pods hote hain. Yellow halka hokar yellowish green nahi bana; woh nazar se gayab ho gaya hai.
Ab plants ko khud ko pollinate karne do. Second filial generation, , mein yellow pods wapas aa jaate hain, bilkul utne hi yellow jitne original parent mein the. Mendel ne 428 green-pod wale aur 152 yellow-pod wale plants gine, yaani har yellow ke liye lagbhag teen green. Unke baaki chhe characters ne bhi aisa hi behave kiya (Table 4.1): mein sirf ek form, mein dono forms lagbhag 3 : 1 ratio mein, aur kabhi koi blend nahi.
| Character | plants | Ratio |
|---|---|---|
| Seed ka shape: round / wrinkled | 5474 / 1850 | 2.96 : 1 |
| Seed ka colour: yellow / green | 6022 / 2001 | 3.01 : 1 |
| Flower ka colour: violet / white | 705 / 224 | 3.15 : 1 |
| Flower ki position: axial / terminal | 651 / 207 | 3.14 : 1 |
| Pod ka shape: inflated / constricted | 882 / 299 | 2.95 : 1 |
| Pod ka colour: green / yellow | 428 / 152 | 2.82 : 1 |
| Stem: tall / dwarf | 787 / 277 | 2.84 : 1 |
Mendel ki explanation apne time ke hisaab se kaafi bold thi. Unka kehna tha ki har plant har character ke liye do hereditary particles rakhta hai, jinhe unhone factors kaha; ek gamete inmein se sirf ek leta hai, aur yeh particles kabhi mix nahi hote, na badalte hain. Aaj hum unke factors ko genes kehte hain. Gene DNA (Chapter 5) ka ek hissa hai jismein kisi character ke peeche ke instructions hote hain, aur yeh ek se zyaada versions mein ho sakta hai. Ek gene ke versions uske alleles (युग्मविकल्पी) hain: pod colour ka ek allele green ke liye hai aur ek yellow ke liye.
Gene ke alternative forms mein se ek; pair ke do alleles homologous pair ke do chromosomes par same position par hote hain aur ek character ke contrasting forms ko control karte hain.
ExampleG (green pods) aur g (yellow pods) pea ke pod-colour gene ke alleles hain.
Geneticists har gene ko ek letter dete hain. Capital letter us allele ke liye hai jo mein dikhta hai, aur usi letter ka small form uske partner ke liye. Isliye G (green) aur g (yellow) turant ek hi gene ke alleles ke roop mein pehchaan mein aa jaate hain. Har plant mein gene ki do copies hoti hain, isliye teen combinations bante hain: GG, Gg aur gg. Do ek jaise alleles wala plant, GG ya gg, homozygous hai; do alag alleles wala plant, Gg, heterozygous hai.
Yeh letters plant ka genotype batate hain, yaani us character ke liye uska genetic make-up. Jo hum dekhte hain, green ya yellow pod, woh uska phenotype hai. GG aur Gg plants ka phenotype same hai lekin genotype alag, kyunki Gg mein G allele g ko chhupa deta hai. Isliye G dominant (प्रभावी) hai aur g recessive (अप्रभावी). plants ek character ke liye heterozygous hain, isliye woh monohybrids hain, aur GG × gg ek monohybrid cross hai.
Yellow wapas kyun aata hai? Alleles ko alag-alag tokens samjho. Meiosis pair ke do alleles ko alag kar deta hai, isliye har gamete mein har gene ka bilkul ek token hota hai. Green parent sirf G de sakta tha aur yellow parent sirf g, isliye har plant mein ek-ek hota hai aur woh green dikhta hai. Lekin uske andar g token sahi-salaamat hai. Jab gametes banata hai, to aadhe ko G aur aadhe ko g milta hai, bilkul chance se, pollen aur eggs dono mein, aur jab g pollen grain g egg se milta hai to phir se yellow-pod wala plant ban jaata hai.
Gametes ke har possible milan ka hisaab rakhne ke liye geneticists Cambridge ke Reginald C. Punnett ka banaya ek chequerboard use karte hain, Punnett square. Egg types ko ek side neeche ki taraf likho aur pollen types ko upar across. Jahan ek row aur ek column milte hain, us box mein us khaas egg aur pollen grain ka offspring hota hai. Kyunki har milan barabar likely hai, isliye har box bhi. Fig. 4.2 cross ko parents se tak follow karta hai.
5/5Teen boxes green pods dete hain, ek yellow deta hai; genotypes 1 : 2 : 1 hain.
Step 1: parents, ek green pod jis par GG likha hai aur ek yellow pod jis par gg, aur beech mein cross ka nishaan. Step 2: arrows ek-ek gamete circle, G aur g, tak jaate hain aur phir ek F1 green pod tak jis par Gg, all green likha hai. Step 3: self label wala ek arrow ek khaali two by two grid tak jaata hai, jiske upar pollen gametes G aur g hain aur side mein egg gametes G aur g. Step 4: chaaron boxes GG green, Gg green, Gg green aur gg yellow se bhar jaate hain, green aur yellow tints ke saath. Step 5: neeche do lines F2 phenotypes, 3 green to 1 yellow, aur genotypes, 1 GG to 2 Gg to 1 gg, dikhati hain.
Boxes gino: ek GG, do Gg aur ek gg. Isliye ka genotypic ratio 1 : 2 : 1 hai. Kyunki GG aur Gg dono green pods dete hain, phenotypic ratio 3 green : 1 yellow hai. Yahi answer algebra se bhi mil sakta hai: gametes mein G aur g dono ki probability 1/2 hai, aur is sum ko square karne par har zygote apni probability ke saath list ho jaata hai, bilkul binomial expansion ki tarah.
Do coins jinhe tum ek baar ya 10, 100 ya 1000 ke batches mein uchhalte ho. Ek bar chart dikhata hai ki har result, HH, HT, TH aur TT, kitni baar aaya hai, saath mein har ek ki theoretical value ek-chauthai. Ek readout un tosses ka share track karta hai jinmein kam se kam ek head hai, yaani kam se kam ek G allele wale aur isliye green pods wale offspring, aur use theoretical teen-chauthai se compare karta hai.
- 10 baar uchhalo. Kya 'kam se kam ek head' ka share bilkul 0.75 hai? Kyun nahi?
- Ab 1000 baar aur uchhalo. Share 0.75 ke kitna kareeb aata hai?
- Kaunsa result yellow-pod wale (gg) plant ko darshaata hai, aur uska share kis value ki taraf jaana chahiye?
Mendel ne kuch lines ko aage ki generations tak chalaya. Yellow pods wale plants ko self karne par unse kabhi yellow-pod wale offspring ke alawa kuch nahi mila, isliye woh homozygous, gg, hi hone chahiye the. Green-pod wale plants kam predictable the (Example).
Kaunse green plants true breed karte hain?
Ek grower ek (Gg × Gg) se 300 green-pod wale plants rakhta hai aur har ek ko khud ko pollinate karne deta hai. (a) Inmein se lagbhag kitne true breed karenge? (b) Agar har plant se barabar number mein seeds collect kiye jaayein, to saare offspring ko milakar green aur yellow pods ka kya ratio expected hai?
Pehle khud try karo. Phir solution ek-ek step karke kholo.
Green pod se pata chalta hai ki plant mein kam se kam ek G hai, lekin yeh nahi ki woh GG hai ya Gg. Trick yeh hai ki use ek homozygous recessive plant se cross karo. Aisa test cross (परीक्षार्थ संकरण) isliye kaam karta hai kyunki recessive partner sirf recessive alleles de sakta hai, jo kuch nahi chhupate: test kiya gaya plant jo bhi allele aage deta hai, wahi seedhe har offspring ka phenotype decide karta hai.
Fig. 4.4 flower position ke liye ek test cross karke dikhata hai, jahan axial flowers (A: stem ke saath-saath flowers) terminal flowers (a: tip par guchchhe mein flowers) par dominant hain.
3/3Aa plant A aur a barabar deta hai: aadhe offspring terminal hain.
Upar, ek stem jiski length ke saath flowers hain, us par axial, A question mark likha hai, aur use ek aise stem se cross kiya gaya hai jiske flowers tip par guchchhe mein hain, jis par terminal, aa likha hai. Step 1 sirf yeh sawaal dikhata hai. Step 2, left panel, agar yeh AA hai: anjaan plant ke gametes A aur A tester ke gamete a se milte hain, do Aa boxes bante hain, jin par all axial, no terminal ones likha hai. Step 3, right panel judta hai, agar yeh Aa hai: gametes A aur a, a se milte hain, ek Aa box aur ek aa box bante hain, jin par 1 axial to 1 terminal, half are terminal likha hai.
Agar har offspring axial hai, to test kiya gaya plant lagbhag pakka AA tha; agar lagbhag aadhe terminal hain, to woh Aa tha. Is asymmetry par dhyaan do: ek bhi terminal offspring saabit kar deta hai ki parent mein a hai, lekin lagaataar axial offspring sirf AA ko zyaada se zyaada likely bana sakte hain (Example).
Test cross ko padhna
Do axial-flowered plants, X aur Y, dono ko ek terminal-flowered plant se cross kiya jaata hai. X se 46 axial aur 41 terminal offspring milte hain; Y se 64 axial aur ek bhi terminal nahi. Har plant ka genotype nikaalo, aur yeh chance bhi ki Y phir bhi Aa ho sakta hai.
Pehle khud try karo. Phir solution ek-ek step karke kholo.
4.2.1 Law of Dominance
Ek character wale crosses se Mendel ne do general rules nikaale. Aaj inhe law of dominance aur law of segregation kehte hain.
Har character alag-alag hereditary units (genes) ke ek pair par depend karta hai. Agar pair ke do members alag hain, to unmein se sirf ek, jise dominant kehte hain, apna effect dikhata hai; uska partner, jise recessive kehte hain, chhupa rehta hai.
Isiliye monohybrid apne parents mein se sirf ek jaisa dikhta hai; segregation ke saath milkar yahi ka 3 : 1 bhi banata hai.
4.2.2 Law of Segregation
Gametes bante samay pair ke do alleles ek doosre se alag ho jaate hain, taaki har gamete ko unmein se sirf ek mile. Hybrid mein saath rehte hue bhi alleles na blend hote hain, na ek doosre ko badalte hain.
Dekho ki yeh law gametes ke baare mein kya predict karta hai. GG aur gg plants ek-ek tarah ke gametes banate hain, jabki Gg plant G aur g gametes 1 : 1 ratio mein banata hai, bilkul wahi jo test cross dikhata hai. Is law ka sabse mazboot saboot yellow pod hai, jo ek generation chhupe rehne ke baad bhi apne grandparent jitna hi yellow hai. Kyunki har gamete mein ek single, bina mila hua allele hota hai, is law ko law of purity of gametes bhi kehte hain.
Answer dekho
Answer (1) two, (2) 1:1
Answer dekho
Answer (B) 400
Answer dekho
Answer (C) Recessive form F2 mein bina badle wapas aata hai
4.2.2.1 Incomplete Dominance
Mendel ke saaton characters ne complete dominance dikhaya, lekin doosre organisms ke kai characters aisa nahi karte. Four o'clock plant, Mirabilis jalapa (kai Indian gardens mein gulbas, naam un flowers par pada jo dopahar ke baad khulte hain), mein true-breeding red-flowered line ko true-breeding white-flowered line se cross karne par mein pink flowers aate hain. Hybrid apne parents ke beech mein hai. Yeh incomplete dominance (अपूर्ण प्रभाविता) hai: koi bhi allele doosre ko poori tarah nahi chhupata.
Pink ko self karo to mein red, pink aur white plants aate hain (Table 4.2). Ise pea cross se compare karo. Punnett square bilkul same hai, 1 RR : 2 Rr : 1 rr. Ab har genotype ka apna alag look hai, isliye phenotypes 3 : 1 ki jagah 1 : 2 : 1 aate hain. Red aur white bhi bilkul waise hi wapas aate hain jaise grandparents mein the, isliye alleles khud kabhi blend nahi hue; hybrid mein sirf unke effects milte hain.
| R pollen | r pollen | |
|---|---|---|
| R egg | RR red | Rr pink |
| r egg | Rr pink | rr white |
Allele ko dominant kya banata hai?
Ek allele doosre ko kyun chhupaye? Jawaab is baat mein hai ki genes kya banate hain. Ek aise flower ko socho jiska violet pigment ek single enzyme banata hai, jo do alleles wale ek gene se code hota hai. V mein kaam karne wale instructions hain, jabki v ek kharaab copy hai jo bekaar enzyme deti hai ya bilkul nahi (Fig. 4.5). VV plant bahut saara pigment banata hai. Vv plant kam enzyme banata hai, phir bhi har petal ko poora rangne ke liye kaafi, isliye woh bilkul VV jaisa dikhta hai: V dominant hai. Sirf vv plant, jiske paas koi working copy nahi, white flowers deta hai.
Isse ek general pattern samajh aata hai: recessive alleles aksar gene ke non-working versions nikalte hain, aur usually ek working copy kaafi hoti hai. Lekin har badla hua allele toota hua nahi hota. Kuch ab bhi aisa enzyme banate hain jo normally ya lagbhag normally kaam karta hai; aisa allele original ke barabar hai aur kuch aisa nahi badalta jo hum dekh sakein, aur aise pairs common hain. Aur jab phenotype product ki amount par depend karta hai, jaise four o'clock plant mein (Section 4.2.2.1), to ek working copy sirf aadha pigment deti hai aur heterozygote beech ka hota hai.
2/4Vv: aadha enzyme, lekin phir bhi kaafi pigment: violet. V dominant hai.
Left: do chromosome bars, har ek par ek allele box; working allele ek solid blue box hai jisse ek arrow hexagonal enzyme tak jaata hai, faulty allele ek dashed box hai jis par cross hai aur koi enzyme nahi. Beech mein: enzymes. Right: ek tank jo pigment level dikhata hai, ek dashed line ke saath jo poore colour ke liye kaafi amount mark karti hai, aur ek paanch petals wala flower. Step 1, VV: do enzymes, bhara hua tank, violet flower. Step 2, Vv: ek enzyme, tank aadha bhara lekin line se upar, flower ab bhi violet. Step 3, vv: koi enzyme nahi, khaali tank, white flower. Step 4, aise plant mein Rr jahan colour amount ke hisaab se chalta hai: line hat gayi hai, tank aadha bhara aur flower halka pink.
4.2.2.2 Co-dominance
Blood transfusion se pehle hospital check karta hai ki patient chaar groups, A, B, AB ya O, mein se kis group ka hai. Groups un chhoti sugar chains mein alag hote hain jo red blood cells ki surface ko sajaati hain (Fig. 4.6). Group A cells par sugar A hoti hai, group B cells par sugar B, AB cells par dono aur O cells par koi nahi.
Ek gene, I, sugar decide karta hai. Human population mein iske teen alleles hote hain: sugar A banata hai, sugar B banata hai, aur kuch nahi banata. Pehle ek insaan ko dekho. Koi allele doosre ko nahi chhupata: dono sugars aati hain, har ek poori. Yeh co-dominance (सहप्रभाविता) hai: heterozygote dono alleles ke phenotypes saath-saath dikhata hai, incomplete dominance ke beech wale hybrid ya complete dominance ke ek-tarfa hybrid se alag.
Allele alag behave karta hai. Kyunki yeh koi sugar nahi jodta, ek insaan ko insaan se alag nahi pehchaana ja sakta, isliye aur dono par dominant hain. Teen alleles chhe tarah se pair ban sakte hain, jisse chhe genotypes aur chaar blood groups bante hain (Table 4.3).
3/4 aur saath hon to dono sugars aati hain: co-dominance.
Ek bada oval red cell jiske kinaare par chhote stalks hain. Har stalk ya to ek solid blue triangle, A sugar, ya ek orange circle, B sugar, par khatam hota hai, jaisa legend dikhata hai. Step 1, group A: har stalk par triangle hai; genotype I A I A ya I A i padha jaata hai. Step 2, group B: har stalk par circle hai; genotype I B I B ya I B i. Step 3, group AB: triangles aur circles baari-baari se hain; genotype I A I B. Step 4, group O: koi stalk nahi; genotype i i.
| Group | Genotypes | Cells par sugars |
|---|---|---|
| A | ya | Sirf A |
| B | ya | Sirf B |
| AB | A aur B | |
| O | koi nahi |
Dhyaan do ki I gene ke teen alleles hain, jabki hum mein se har ek mein sirf do hote hain. Population mein do se zyaada alleles wale gene ke baare mein kaha jaata hai ki uske multiple alleles hain; inhe sirf bahut saare individuals ka survey karke hi pata lagaya ja sakta hai, ek ko study karke kabhi nahi. Rabbits mein coat colour ek aur example hai: ek gene ke chaar alleles full-coloured, chinchilla (silvery grey), Himalayan (white, dark kaan, naak aur panjon ke saath) aur albino coats dete hain.
Ek family mein blood groups
Group AB ka ek aadmi aur group O ki ek aurat ke bachche hain. (a) Unke bachchon ke kaunse blood groups ho sakte hain, aur kis probability se? (b) Ek laboratory is couple ke ek bachche ko group O report karti hai. Tumhe kya conclude karna chahiye?
Pehle khud try karo. Phir solution ek-ek step karke kholo.
Answer dekho
Answer (C) Aadha
Answer dekho
Answer (D) O
Answer dekho
- (A) Heterozygote dono parental phenotypes dikhata hai
- (C) Group AB red cells par A aur B dono sugars hoti hain
Answer dekho
Answer Galat
4.3 Do Genes ki Inheritance
Iske baad Mendel ne ek saath do characters follow kiye. Unke experiment ke hamare version mein flower position aur pod colour hain. Ek true-breeding parent mein axial flowers aur green pods hain (AAGG); doosre mein terminal flowers aur yellow pods (aagg). Har parent sirf ek tarah ka gamete banata hai, AG ya ag, isliye har plant AaGg hai, axial flowers aur green pods ke saath. Ab tak kuch bhi surprising nahi: har character waise hi behave karta hai jaise akele karta. Do genes ke liye heterozygous hone se ek dihybrid hai, aur yeh cross ek dihybrid cross hai.
Ab ko khud ko pollinate karne do. mein ek baar mein ek character dekho to kuch naya nahi dikhta. Teen-chauthai plants axial hain aur ek-chauthai terminal, aur, alag se, teen-chauthai mein green pods hain aur ek-chauthai mein yellow. Har character ab bhi 3 : 1 mein batta hai, bilkul monohybrid cross ki tarah. Naya sawaal yeh hai ki dono characters aapas mein kaise judte hain.
4.3.1 Law of Independent Assortment
mein chaar phenotypes hain: axial green, axial yellow, terminal green aur terminal yellow, 9 : 3 : 3 : 1 ratio mein. Inmein se do, axial yellow aur terminal green, new combinations hain jo kisi bhi original parent mein nahi the. Yeh ratio bas do 3 : 1 ratios ka guna hai, jo tab expect hota hai jab har character doosre se bina matlab rakhe inherit hota hai:
Alag-alag genes ke alleles gametes mein independently jaate hain: ek gamete ko ek gene ka kaunsa allele mila, isse yeh bilkul pata nahi chalta ki use doosre gene ka kaunsa allele mila, isliye har combination barabar likely hai.
(Section 4.3.3 mein hum dekhenge ki yeh alag-alag chromosomes par wale genes ke liye sahi hai, lekin ek hi chromosome par paas-paas wale genes ke liye nahi.)
AaGg plant mein gamete formation ko do independent coin tosses ki tarah socho: ek decide karta hai A ya a, doosra G ya g. Do coins se chaar barabar likely outcomes milte hain, isliye plant AG, Ag, aG aur ag gametes banata hai, har ek ek-chauthai, eggs aur pollen dono mein. Inhe Punnett square ki dono sides par rakhne se 16 barabar likely boxes ka 4 × 4 grid banta hai (Fig. 4.7).
4/4Nau axial green, teen axial yellow, teen terminal green, ek terminal yellow.
Pollen gametes AG, Ag, aG aur ag upar chalte hain aur wahi chaar egg gametes left side mein neeche, har ek ek circle mein. Step 1 sirf gametes aur ek khaali grid dikhata hai, saath mein one quarter each ka note. Step 2 saare 16 boxes ko genotypes se bharta hai, jaise top left mein AAGG aur bottom right mein aagg, har ek ke saath ek chhota code: ax gr, ax ye, te gr ya te ye. Step 3 boxes ko phenotype ke hisaab se tint karta hai: axial green, axial yellow, terminal green aur terminal yellow, har ek ka apna tint hai. Step 4 counts ke saath ek legend jodta hai: 9 axial green, 3 axial yellow, 3 terminal green, 1 terminal yellow.
16 boxes mein sirf nau alag genotypes hain, jo chaar phenotypes mein aate hain. Table 4.4 check karne se pehle khud inhe sort karke dekho. Genotypic ratio 9 : 3 : 3 : 1 nahi hai. Yeh 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1 hai, jo (1 : 2 : 1) × (1 : 2 : 1) hai.
| Genotype | Boxes (16 mein se) | Phenotype |
|---|---|---|
| AAGG | 1 | axial, green |
| AAGg | 2 | axial, green |
| AaGG | 2 | axial, green |
| AaGg | 4 | axial, green |
| AAgg | 1 | axial, yellow |
| Aagg | 2 | axial, yellow |
| aaGG | 1 | terminal, green |
| aaGg | 2 | terminal, green |
| aagg | 1 | terminal, yellow |
Bade crosses ke liye shortcuts
Bina grid banaye nikaalo (a) AaGg × AaGg ke offspring ka kitna fraction terminal flowers aur green pods wala hai, (b) kitna fraction AaGg hai, aur (c) genotype AaGgRRTt wala plant kitni tarah ke gametes banata hai, agar chaaron genes independently assort karte hain.
Pehle khud try karo. Phir solution ek-ek step karke kholo.
Answer dekho
Answer (B) 2
Answer dekho
Answer 0.25
Answer dekho
Answer (C) 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1
4.3.2 Chromosomal Theory of Inheritance
Mendel ne apne results 1865 mein present kiye aur woh 1866 mein print hue, phir bhi tees saal se zyaada tak shaayad hi kisi ne unpar aage kaam kiya. Historians iske kai kaaran batate hain:
- Koi physical basis nahi. Koi bhi, Mendel bhi, cell mein kisi factor ki taraf ishaara nahi kar sakta tha, na bata sakta tha ki woh kis cheez ka bana hai.
- Ajeeb method. Us zamaane ke biologists describe aur compare karte the; bahut kam log ratios aur probability se nikaale gaye conclusions maanne ko taiyaar the.
- Blending obvious lagti thi. Nature mein zyaadatar variation, height, weight ya colour mein, continuous hota hai, jo is baat ka saboot lagta tha ki parental characters mix hote hain, na ki discrete factors aage jaate hain.
- Ek anjaan journal. Unka paper ek chhoti local society ki proceedings mein chhapa aur shaayad hi kisi ne padha.
Is beech cell biologists, behtar lenses aur naye dyes ke saath, nuclei ko divide hote dekh rahe the. Unhone dhaage jaisi bodies dekhi jo stain ko bahut zyaada leti thi, isiliye naam pada chromosomes, yaani 'coloured bodies'; har ek division se pehle double hota tha, aur 1902 tak meiosis mein unke move karne ka tareeka samajh aa gaya tha. 1900 mein teen botanists ne alag-alag kaam karte hue, Hugo de Vries, Carl Correns aur Erich von Tschermak, apne crosses mein Mendel ke ratios paaye aur phir unka bhula hua paper dhoondh nikaala. Kaam ki yeh do lines milne hi waali thi.
Pea garden se gene maps tak
- 1856–1863
Mendel peas cross karte hain
Brno ke monastery garden mein saat saal ke crosses aur counts.
- 1866
Mendel ka paper print hua
1865 mein ek local society ke saamne padha gaya aur phir zyaadatar ignore kar diya gaya.
- 1900
Rediscovery
De Vries, Correns aur von Tschermak independently ratios confirm karte hain.
- 1902
Chromosomes par genes
Sutton aur Boveri Mendel ke factors ko meiosis mein chromosomes ke behaviour se jodte hain.
- 1910
Morgan ki white-eyed fly
Fruit-fly ke ek eye-colour gene ko X chromosome tak trace kiya jaata hai.
- 1913
Pehla genetic map
Sturtevant recombination frequency se fly ke X chromosome par genes ka order lagata hai.
Yeh 1902 mein mile, jab United States mein Walter Sutton aur Germany mein Theodor Boveri ne bataya ki meiosis mein chromosomes bilkul waise hi behave karte hain jaise Mendel ke factors ko karna chahiye (neeche ka comparison). Unka proposal, jise Sutton ne chromosomal theory of inheritance ke roop mein rakha, kehna simple hai: Mendel ke factors chromosomes ke hisse hain, aur segregation aur independent assortment wahi hain jo chromosomes meiosis mein karte hain. Body cells mein chromosomes homologous pairs mein hote hain, har pair ka ek member har parent se. Gene ke do alleles pair ke do members par same position par baithe hote hain, jise gene ka locus kehte hain.
Sutton aur Boveri ne jo parallel notice kiya
Genes (Mendel ke factors)
- Body cells mein pairs mein hote hain
- Gametes bante samay pair ke dono alag ho jaate hain, ek-ek har gamete mein
- Alag-alag pairs ek doosre se independently alag hote hain
Meiosis mein chromosomes
- Body cells mein homologous pairs ke roop mein hote hain
- Anaphase I par homologues alag hote hain, isliye har gamete ko har pair ka ek milta hai
- Har pair metaphase I par doosre pairs ki parwaah kiye bina apni position leta hai
Fig. 4.9 dikhata hai ki isse independent assortment kaise samajh aata hai. Maan lo gene A chromosomes ke ek pair par hai aur gene G doosre pair par. Metaphase I par har pair cell ke beech mein line up karta hai, ek homologue har pole ki taraf. Kaunsa homologue kis pole ki taraf hoga, yeh har pair ke liye alag se tay hota hai, jaise do coins independently uchhale gaye hon. Ek alignment A aur G ko ek pole par aur a aur g ko doosre par bhejta hai; doosra, utna hi likely, alignment A ko g ke saath aur a ko G ke saath bhejta hai. Bahut saare meioses mein chaaron tarah ke gametes barabar number mein bante hain.
4/4Bahut saare meioses mein chaar tarah ke gametes barabar number mein.
Left: AaGg label wala ek cell jismein chromosomes ka ek lamba pair hai, ek blue jis par A aur ek orange jis par a, aur ek chhota pair, blue G aur orange g, har ek do sister chromatids ke roop mein bana hai. Step 1 sirf yeh cell dikhata hai. Step 2: ek oval cell jismein dashed metaphase plate hai; plate ke upar A aur G hain, neeche a aur g; arrows do gametes, AG aur ag, tak jaate hain. Step 3 ek doosra, utna hi likely arrangement jodta hai, jis par or likha hai: plate ke upar A aur g, neeche a aur G, jisse gametes Ag aur aG bante hain. Step 4 conclusion jodta hai: chaar tarah ke gametes, har ek ek-chauthai.
Is theory ko New York ki Columbia University mein Thomas Hunt Morgan aur unke students ne fruit fly Drosophila melanogaster ki madad se test kiya. Kai features ne is fly ko ideal banaya:
- Lagbhag har do hafte mein nayi generation, isliye ek saal mein kai generations.
- Ek single pair se saikdon offspring, reliable ratios ke liye kaafi.
- Eye colour, body colour aur wings ke kai inherited variants, jo hand lens ya low-power microscope se dikh jaate hain.
- Rakhna sasta: flies bottles mein simple artificial food par rehti hain.
- Males aur females ko pehchaanna aasaan hai, aur cells mein sirf chaar pairs chromosomes hote hain.
Morgan ke group ne dikhaya ki ek khaas gene ek khaas chromosome par hota hai, aur unke kaam ko 1933 ka Nobel Prize in Physiology or Medicine mila. Yeh fly aaj bhi biology ke sabse useful model organisms mein se ek hai.
4.3.3 Linkage and Recombination
Independent assortment ki ek built-in limit hai. Cell mein chromosomes se kahin zyaada genes hote hain (fruit fly mein hazaaron genes hain lekin chromosomes ke sirf chaar pairs), isliye kai genes ko ek chromosome share karna padta hai, aur ek chromosome share karne wale genes ko saath-saath chalna chahiye. Morgan ke group ne bilkul yahi paaya. X chromosome par do genes wale fly crosses lo, jaise eye colour aur body colour ke liye. Characters ke grandparental combinations 9 : 3 : 3 : 1 ki ijaazat se kahin zyaada baar wapas aaye, jabki new combinations rare the.
Morgan ne ek chromosome par genes ke physical judaav ko linkage (सहलग्नता) naam diya aur alleles ke naye combinations banne ko recombination (पुनर्योजन). Linked genes bhi recombine kar sakte hain, crossing over ke through: prophase I ke dauraan homologous pair ke do non-sister chromatids milte-julte points par tootte hain aur phir judte hain, aur segments exchange karte hain.
Ek saaf example fly ke chromosome 2 par do genes ka hai: body colour (grey, , black, , par dominant) aur wing shape (normal, , vestigial, , par dominant). Ek true-breeding grey, normal-winged fly ko black, vestigial-winged fly se cross karo, to har female ke ek chromosome 2 par aur hote hain aur uske homologue par aur . In females ko black, vestigial males se test-cross karo. (Females isliye use hoti hain kyunki male fruit flies mein crossing over nahi hota.) Independent assortment se chaaron tarah ke offspring barabar number mein aate. Iski jagah, ek typical batch Table 4.5 jaisa dikhta hai.
| Offspring | Number | Type |
|---|---|---|
| grey, normal wings | 333 | parental |
| black, vestigial wings | 331 | parental |
| grey, vestigial wings | 69 | recombinant |
| black, normal wings | 67 | recombinant |
| kul | 800 | sab |
Do parental classes 800 mein se 664 flies hain aur do recombinant classes 136. Recombination frequency offspring ka woh fraction hai jo recombinant hai: , yaani 17 %. Fig. 4.10 dikhata hai ki recombinants kahan se aate hain: sirf un gametes mein naya combination hota hai jinmein dono genes ke beech kahin crossover hua.
4/4Is cross mein 17 % gametes recombinant hain: genes 17 map units door hain.
Chaar horizontal chromatids, upar mother se do blue aur neeche father se do orange, har ek par do gene positions marked hain: blue par b plus aur vg plus, orange par b aur vg. Step 1 sirf paired chromosomes dikhata hai. Step 2: genes ke beech koi crossover nahi, to neeche sirf do tarah ke gametes dikhte hain, blue mein b plus vg plus aur orange mein b vg, dono par parental likha hai. Step 3: crossover label wala ek X andar wale blue aur orange chromatids ko dono genes ke beech jodta hai, aur do naye gametes dikhte hain, aadhe blue aur aadhe orange: b plus vg aur b vg plus, jin par recombinant likha hai. Step 4 totals jodta hai: 83 per cent parental, 17 per cent recombinant, isliye b aur vg 17 map units door hain.
Kuch linked pairs doosron se zyaada recombine kyun karte hain? Morgan ki laboratory ke ek student, Alfred Sturtevant, ne socha ki crossovers chromosome par kam-zyaada random points par hote hain. Door-door wale do genes ke beech crossover girne ke kai mauke hote hain; do padosi genes ke beech bahut kam. Isliye paas-paas ke genes tightly linked hote hain aur kabhi-kabhi hi recombine karte hain, jabki door wale genes loosely linked hote hain aur aksar recombine karte hain. 1913 mein Sturtevant ne ise ek method bana diya: recombination frequency ko distance maankar unhone kai X-chromosome genes ko ek line par order mein rakha, yeh pehla genetic map tha. Aaj 1 % recombination ek map unit, yaani ek centimorgan (cM), define karta hai.
Frequency 50 % se upar nahi ja sakti: itne door ke genes ki crossovers lagbhag hamesha unhe alag kar dete hain, woh aise assort karte hain jaise unlinked hon. Recombination se bane maps ne baad mein poore genomes ki sequencing ko guide kiya, human genome ko bhi (Chapter 5).
Ek hi chromosome par genes ka saath-saath inherit hone ka tendency, kyunki woh physically jude hote hain; woh jitne paas hon, crossing over unhe utni kam baar alag karta hai.
ExampleFruit-fly chromosome 2 par body colour aur wing shape genes sirf lagbhag 17 % gametes mein recombine karte hain.
Teen genes ko order mein rakhna
Teen genes, P, Q aur R, ek plant ke ek chromosome par hain. Test crosses se yeh recombination frequencies milti hain: P aur Q, 8 %; Q aur R, 15 %; P aur R, 23 %. Unka order aur map distances nikaalo.
Pehle khud try karo. Phir solution ek-ek step karke kholo.
Answer dekho
Answer (A) 0.12
Answer dekho
Answer (D) Parental classes recombinant classes se kahin zyaada hain
Answer dekho
Answer Galat
Answer dekho
Answer (A) Alfred Sturtevant
4.4 Polygenic Inheritance
Apni class ko height ke hisaab se line mein khada karo, to tumhe Mendel ke tall aur dwarf peas jaise do saaf groups nahi milenge, balki ek smooth range milegi jismein zyaadatar log beech ke aas-paas honge. Aisa continuous variation tab aata hai jab kai genes, har ek ka chhota effect, ek character par kaam karte hain. Environment bhi apna asar jodta hai: achha khaana khaane wala bachcha usi bachche se lamba hota hai jo kam poshan par palta. Is tarah ke characters ko polygenic kehte hain, aur polygenic inheritance (बहुजीनी वंशागति) dikhata hai ki Mendel ke discrete factors bhi smooth variation kaise bana sakte hain, wahi observation jisne kabhi biologists ko unpar shak karwaya tha.
Sabse simple model mein har contributing allele phenotype mein ek fixed amount jodta hai: effects additive hote hain. Ek classic case wheat grains ka colour hai, jise Swedish geneticist Herman Nilsson-Ehle ne lagbhag 1909 mein study kiya. Maan lo do genes, A aur B, laali ko control karte hain, har capital allele red pigment ki ek dose jodta hai aur har small allele kuch nahi. AABB grains dark red hain, aabb grains white, aur AaBb grains, do doses ke saath, medium red. AaBb plants ko self karo to capital alleles ki sankhya, 0 se 4, ke hisaab se paanch shades mein batta hai, 1 : 4 : 6 : 4 : 1 ratio mein (Fig. 4.12).
3/4Teen genes: saat classes, 1 : 6 : 15 : 20 : 15 : 6 : 1.
Ek bar chart jiske horizontal axis par dark-grain alleles ki sankhya, 0 se 6, hai aur side mein F2 ka share. Step 1, ek gene: 0, 1 aur 2 par teen bars, 1 to 2 to 1 ratio mein. Step 2, do genes: 0 se 4 par paanch bars, 1 to 4 to 6 to 4 to 1 ratio mein. Step 3, teen genes: 0 se 6 par saat bars, 1 to 6 to 15 to 20 to 15 to 6 to 1 ratio mein, jo pehle se hi bell-shaped hain. Step 4 saat bars rakhta hai aur unke upar ek smooth dotted bell curve bichhata hai, jis par three genes plus environment, a smooth range likha hai.
Teen aise genes ke saath saat classes hoti hain, 0 se 6 doses tak, 1 : 6 : 15 : 20 : 15 : 6 : 1 ratio mein, aur bars pehle se ek bell banane lagte hain. Human skin colour ko bhi lambe samay se isi tarah model kiya gaya hai, kai genes ke roop mein jinke 'darker' alleles jud jaate hain, aur phir sunlight result ko adjust karti hai. Kisi bhi polygenic character mein environmental effects jodo to alag-alag classes dhundhli hokar wahi smooth curve ban jaati hain jo hum asal mein dekhte hain.
Doses ginna
Teen unlinked genes, A, B aur C, har capital allele par pigment ki ek dose jodte hain. Do parents, dono AaBbCc, ke bachche hain. Bachchon ka kitna fraction expected hai jo (a) AABBCC insaan jitna dark ho, aur (b) jismein parents jitni hi doses hon?
Pehle khud try karo. Phir solution ek-ek step karke kholo.
Answer dekho
Answer (C) Additive effects wale kai genes, aur environment, ise control karte hain
Answer dekho
Answer 0.375
4.5 Pleiotropy
Untreated phenylketonuria (PKU) wale baby mein kai problems aati hain jo aapas mein judi nahi lagti. Brain theek se develop nahi hota, urine mein ek unusual acid hota hai, aur skin aur baal aksar family ke baaki logon se zyaada halke hote hain. Yeh sab ek hi faulty gene se aate hain, enzyme phenylalanine hydroxylase ka gene, jo normally amino acid phenylalanine ko tyrosine mein badalta hai (Fig. 4.13). Jab ek gene is tarah kai alag characters par asar daalta hai, to us gene ko pleiotropic kehte hain aur is effect ko pleiotropy (बहुप्रभाविता).
Ek gene itna kuch kaise kar sakta hai? Usually uska product cell ki chemistry ke ek chauraahe par kaam karta hai. PKU mein ruke hue step ke consequences dono directions mein hote hain. Phenylalanine jama hota jaata hai aur develop hote brain ko nuksaan pahunchata hai, jisse intellectual disability hoti hai; uska by-product phenylpyruvic acid urine mein aa jaata hai; aur pigment melanin banane ke liye kam tyrosine bachta hai.
Left mein faulty PAH gene label wala ek box neeche point karta hai, no working enzyme note ke saath, phenylalanine tak, jisse cross wala ek dashed blocked arrow tyrosine tak jaata hai. Right mein teen boxes effects dikhate hain: bahut zyaada phenylalanine badhte brain ko nuksaan pahunchata hai; urine mein phenylpyruvic acid aata hai; melanin ke liye kam tyrosine se skin aur baal halke hote hain. Ek caption line par one gene, several effects likha hai.
Sickle-cell allele (Section 4.8.2) bhi pleiotropic hai. Ek amino-acid change se anaemia, chhoti blood vessels ka block hona, dard ke episodes, spleen jaise organs ko nuksaan aur, carriers mein, malaria se kuch protection hota hai. Marfan syndrome mein ek connective-tissue protein ki kharaabi skeleton (lambe haath-pair aur ungliyan), aankhon ke lenses aur heart se nikalne wali main artery par asar daalti hai.
Answer dekho
Answer (C) Ek gene jo brain development aur skin pigmentation dono par asar daalta hai
Answer dekho
Answer (B) Kam tyrosine banta hai, aur melanin banane ke liye tyrosine chahiye
4.6 Sex Determination
Kuch offspring males aur kuch females kyun bante hain? Kahani 1891 mein Hermann Henking se shuru hoti hai, jo ek insect, firebug, mein sperm bante dekh rahe the. Ek gehra stain lene wali nuclear body ne unka dhyaan kheencha: woh sirf aadhe sperm mein pahunchti thi. Yeh na jaante hue ki woh kya hai, unhone use bas 'X body' kaha. Baad mein doosron ne dikhaya ki yeh ek chromosome hai, aur naam chal pada: X chromosome. Sex decide karne wale chromosomes sex chromosomes hain; baaki saare autosomes hain.
Grasshoppers aur cockroaches mein female ke cells mein do X chromosomes hote hain aur male mein sirf ek, bina partner ke: yeh sex determination ka XO type hai. Isliye male grasshopper mein female se ek chromosome kam hota hai, aur uske sperm do tarah ke hote hain, X ke saath aur bina X ke, jabki har egg mein ek X hota hai. Kaunsa sperm egg ko fertilise karta hai, yahi sex decide karta hai: X wala sperm XX beti deta hai, bina X wala sperm XO beta.
Humans, doosre mammals aur fruit fly XY type use karte hain. Females XX hoti hain; males mein ek X aur ek chhota partner, Y chromosome, hota hai, isliye dono sexes mein chromosomes ki sankhya same hoti hai. Kyunki do tarah ke sperm male banata hai, isliye XO aur XY dono systems ko male heterogamety kehte hain (hetero, alag; gamety, gametes).
Birds mein yeh ulta hai. Hen mein do alag sex chromosomes hote hain, jinhe X aur Y se confusion se bachne ke liye Z aur W naam diya gaya, jabki cock mein do Z chromosomes hote hain; chromosome number phir se dono sexes mein same hai. Yahan female do tarah ke egg banati hai, Z wale aur W wale, barabar number mein, aur chick ka sex is par depend karta hai ki kis tarah ka egg fertilise hua. Yeh female heterogamety hai; zyaadatar butterflies aur moths mein bhi yahi hota hai. Fig. 4.14 teeno systems ko saath-saath rakhta hai.
2/3Humans: 44 + XX aur 44 + XY; aadhe sperm mein X, aadhe mein Y.
Teen rows jin par parents, gametes aur offspring likha hai, female left mein aur male right mein. Sex chromosomes letter tiles ke roop mein bane hain, Y aur W, X aur Z se chhote, aur autosomes ek number ya AA ke roop mein likhe hain. Step 1, grasshoppers mein XO type: female AA plus XX, male AA plus X; saare eggs mein X; sperm mein X ya kuch nahi; offspring AA XX female aur AA X male, 1 to 1; note: male makes two kinds of sperm. Step 2, humans aur fruit flies mein XY type: female 44 plus XX, male 44 plus XY; eggs 22 plus X; sperm 22 plus X ya 22 plus Y; offspring 44 XX girl aur 44 XY boy. Step 3, birds mein ZW type: female AA plus ZW, male AA plus ZZ; eggs mein Z ya W; sperm mein Z; offspring ZZ male aur ZW female; note: female makes two kinds of egg.
4.6.1 Sex Determination in Humans
Har human egg ek baat mein same hai: usmein 22 autosomes aur ek X hota hai. Sperm same nahi hote. Aadmi ke cells mein autosomes ke 22 pairs aur ek X aur ek Y hote hain, aur meiosis aadhe sperm mein X aur baaki aadhe mein Y daalta hai (Table 4.6). X wale sperm se fertilise hua egg XX zygote banta hai aur ladki ke roop mein develop hota hai. Y wale sperm se fertilise hua egg XY banta hai aur ladke ke roop mein develop hota hai, kyunki Y par ek gene, SRY, develop hote gonads ko testes banane ki taraf mod deta hai.
Isse do conclusions nikalte hain. Bachche ka sex father ka sperm tay karta hai, mother nahi. Aur kyunki dono tarah ke sperm barabar number mein bante hain aur egg tak pahunchne ke barabar chances rakhte hain, har pregnancy mein ladki hone ka 1/2 chance hota hai, pehle ke bachche chahe kisi bhi sex ke hon.
| X sperm | Y sperm | |
|---|---|---|
| X egg | XX ladki | XY ladka |
4.6.2 Sex Determination in Honey Bee
Honey-bee colony mein ek queen, das-hazaaron female workers aur, season mein, kuch sau male drones hote hain. Egg female banega ya male, yeh is par depend karta hai ki woh fertilise hua bhi ya nahi. Queen apni mating flights se sperm store karti hai aur har egg dete samay use release karti hai, ya nahi karti. Fertilised egg ko do chromosome sets (2n = 32) milte hain aur woh female banta hai: worker ya, agar larva ko poore samay royal jelly khilayi jaaye, to queen. Unfertilised egg phir bhi develop hota hai, parthenogenesis se, aur haploid drone (n = 16) banta hai (Fig. 4.15). Yahan sex chromosome sets ki sankhya se tay hota hai, isliye is system ko haplodiploid kehte hain.
3/3Fertilised eggs se females (32) bante hain; unfertilised eggs se drones (16).
Step 1: queen, female, 2n equals 32 label wala ek box, jisse meiosis label wala arrow 16 chromosomes wale egg tak jaata hai. Step 2 drone, male, n equals 16 label wala ek box jodta hai, jisse mitosis label wala arrow 16 wale sperm tak jaata hai. Step 3: not fertilised label wala ek arrow egg se ek box tak jaata hai jis par drone, n equals 16, no father likha hai; egg aur sperm dono se fertilised label wale arrows ek box tak jaate hain jis par queen or worker, 2n equals 32, female likha hai.
Aisi species mein family trees ajeeb dikhte hain. Ek drone ki ancestry banao: uski mother hai lekin father nahi, jabki uski mother ke dono the, isliye uska grandfather zaroor hai. Woh mitosis se sperm banata hai, kyunki uske paas shuru se hi chromosomes ka sirf ek set hai. Uske sperm sirf un eggs ko fertilise kar sakte hain jo betiyaan banti hain, isliye uske kabhi bete nahi ho sakte; lekin un betiyon ke through uske pote ho sakte hain.
Answer dekho
Answer (B) Egg
Answer dekho
Answer (B) Male
Answer dekho
Answer Sahi
Answer dekho
Answer 0.5
4.7 Mutation
Recombination maujooda alleles ko naye combinations mein phenta hai. Mutation (उत्परिवर्तन) variation ka doosra bada source hai: DNA sequence mein hi badlaav, jo genotype ko aur uske through phenotype ko badal sakta hai.
Mutations bahut bade se bahut chhote tak hote hain. Bade wale end par chromosome ke poore segments kho jaate hain (deletion) ya jud jaate hain (insertion ya duplication). Kyunki chromosome asal mein ek continuous, kaskar packed DNA molecule hai (Chapter 5), aisa badlaav segment ke har gene ko hata deta hai ya repeat kar deta hai. Yeh chromosomal aberrations kai cancer cells ki pehchaan hain; jaise chronic myeloid leukaemia mein chromosomes 9 aur 22 ke hisse aapas mein jagah badal lete hain.
Sabse chhote scale par ek single base pair badal sakta hai: yeh point mutation hai. Sabse jaana-maana example sickle-cell anaemia hai, jismein ek base substitution β-globin ka ek amino acid badal deta hai (Fig. 4.16). Gene ke andar ek base insert ya delete karna usually kahin zyaada nuksaan karta hai. Cell gene ko teen-teen bases ke lagaataar groups (codons) mein padhta hai, isliye badlaav ke baad ka har codon galat padha jaata hai, jab tak ki bilkul teen bases na jude ya na ghatein. Inhe frame-shift mutations kehte hain.
2/5GAG → GTG: glutamic acid valine ban jaata hai, yahi sickle-cell change hai.
DNA codon boxes ki ek row, har ek se ek arrow us amino acid tak jise woh code karta hai. Step 1, starting gene: CCT, GAG, GAG, AAG se Pro, Glu, Glu, Lys milte hain, beta-globin ke codons 5 se 8. Step 2, ek base badla, A se T: CCT, GTG, GAG, AAG se Pro, Val, Glu, Lys; sirf doosra codon aur amino acid highlighted hain. Step 3, ek base juda, C: CCT, GCA, GGA, GAA aur ek bacha hua G se Pro, Ala, Gly, Glu aur aage milte hain; insertion ke baad ka har codon highlighted hai. Step 4, ek base khoya, G: CCT, AGG, AGA aur bacha hua AG se Pro, Arg, Arg; phir se badlaav ke baad sab kuch badal gaya. Step 5 chromosome segments A se F dikhata hai: normal order, C ke bina ek deletion, aur C do baar wala ek duplication.
Mutations chance se hote hain, jaise DNA replicate hote samay copying errors se, aur environment ke kuch agents unki rate badha dete hain. In mutagens mein physical agents jaise UV radiation (ek kaaran ki baar-baar sunburn se skin cancer ka risk badhta hai), X-rays aur gamma rays, aur chemical agents shaamil hain, jinmein tobacco smoke ke kai substances bhi hain. Mutation ke molecular mechanisms is chapter se aage ki baat hain.
Answer dekho
Answer (A) point mutation
Answer dekho
Answer (D) Insertion ke baad ka har codon naye frame mein padha jaata hai
Answer dekho
- (A) UV radiation
- (B) X-rays
- (C) Tobacco smoke ke kuch chemicals
4.8 Genetic Disorders
Section 4.7 ke kai mutations jo health ke liye matter karte hain, inherited hote hain, families mein waise hi neeche jaate hain jaise Mendel ke alleles. Yeh section un disorders ko dekhta hai jo yeh paida karte hain, aur yeh bhi ki geneticists unhe kaise trace karte hain.
4.8.1 Pedigree Analysis
Peas study karne wala geneticist kisi bhi do plants ko cross karke agle season saikdon offspring gin sakta hai. Insaanon ko study karne wala geneticist dono mein se kuch nahi kar sakta: families chhoti hoti hain, generations lambi hoti hain, aur koi experiment ke liye shaadiyan arrange nahi karta. Iski jagah human genetics pehle se maujood families ke records par chalti hai. Kai generations ke chart ki tarah banaya gaya, jismein har woh insaan mark ho jo koi khaas trait dikhata hai, aisa record pedigree hai. Usse yeh nikaalna ki trait kaise inherit hota hai, pedigree analysis (वंशावली विश्लेषण) hai. Log bahut pehle se jaante the ki kuch conditions families mein chalti hain, aur systematic pedigree studies Mendel ke kaam ki rediscovery ke kuch hi baad shuru hui. Fig. 4.17 standard symbols dikhata hai.
Do columns mein pedigree symbols ki key: male ke liye square; female ke liye circle; jis insaan ka sex pata nahi uske liye diamond; affected individuals ke liye bhara square aur bhara circle; carrier ke liye beech mein dot wala circle; mating ke liye horizontal line se jude square aur circle; relatives ke beech mating ke liye double line se jude square aur circle; aur ek mated pair jisse ek line neeche ek horizontal bar tak jaati hai, jisse do bachche latakte hain, sabse bada left mein.
Pedigree ko upar se padho. Har row ek generation hai, Roman numerals se numbered. Ek row mein do symbols ko jodne wali line mating hai, aur unke bachche uske neeche ek horizontal line se latakte hain, sabse bada left mein. Carriers, yaani recessive allele ki ek copy wale log jo khud affected nahi hain, pata chalne ke baad aksar dot se mark kiye jaate hain.
4.8.2 Mendelian Disorders
Inherited disorders do badi tarah ke hote hain. Mendelian disorder ek gene mein badlaav se hota hai, isliye yeh generation-dar-generation Mendel ke rules follow karta hai aur pedigrees se track kiya ja sakta hai. Examples mein thalassaemia, sickle-cell anaemia, phenylketonuria, cystic fibrosis, haemophilia aur colour blindness shaamil hain. Chromosomal disorder missing, extra ya rearranged chromosomes se hota hai (Section 4.8.3).
Do sawaal Mendelian disorder ko classify karte hain: faulty allele dominant hai ya recessive, aur woh autosome par hai ya X chromosome par? Achhi tarah bana pedigree usually dono ka jawaab de deta hai. Fig. 4.18 teen common patterns mein se har ek ke liye ek family dikhata hai, us clue ke saath jo faisla karta hai:
- Autosomal recessive: do unaffected parents ka affected bachcha ho sakta hai, kyunki dono carriers hain; betiyaan aur bete barabar affected hote hain. Examples: sickle-cell anaemia, thalassaemia, phenylketonuria, cystic fibrosis.
- Autosomal dominant: har affected insaan ka kam se kam ek parent affected hota hai, isliye trait har generation mein dikhta hai; do affected parents ka unaffected bachcha ho sakta hai; yeh father se bete tak ja sakta hai. Examples: myotonic dystrophy, Huntington disease.
- X-linked recessive: females se kahin zyaada males affected hote hain; affected beton ki mothers usually unaffected carriers hoti hain; yeh kabhi father se bete tak nahi jaata, kyunki father bete ko Y deta hai, X nahi. Examples: haemophilia, red–green colour blindness.
1/3Do unaffected parents ki ek affected beti: recessive, aur X-linked nahi.
Left mein neeche ki taraf generations I, II aur III marked hain; bhare symbols affected hain, aur dot carrier ko mark karta hai. Step 1, autosomal recessive: do unaffected parents ke chaar bachche hain, jinmein ek beti affected hai; ek unaffected beti ek unaffected aadmi se shaadi karti hai aur uske do unaffected bachche hain; clue: unaffected parents, affected beti, isliye recessive aur X par nahi. Step 2, autosomal dominant: ek affected father aur unaffected mother ka ek affected beta, ek unaffected beti aur ek affected beti hai; affected beti ek affected aadmi se shaadi karti hai aur unki ek unaffected beti aur ek affected beta hai; clue: do affected parents ka unaffected bachcha, isliye dominant, aur father se bete tak, isliye autosomal. Step 3, X-linked recessive: ek unaffected father aur carrier mother ka ek affected beta, ek unaffected beta aur ek carrier beti hai; carrier beti aur unaffected pati ka ek affected beta, ek unaffected beti aur ek unaffected beta hai; clue: sirf bete affected, carrier mothers ke through, kabhi father se bete tak nahi.
Colour blindness. Red–green colour blindness aadmiyon mein itni zyaada common kyun hai, kai populations mein lagbhag 8 % aadmiyon mein lekin aurton mein 1 % se bhi kaafi kam? Aankh ke cone cells ke red-sensing aur green-sensing pigments ke genes X chromosome par hote hain, aur red aur green ko pehchaanna mushkil banane wale faulty alleles recessive hain. Aadmi, jiske paas ek single X hai, tab colour blind hota hai jab us X par faulty allele ho. Aurat ko apne dono X chromosomes par faulty alleles chahiye, jo kahin kam likely hai. Ek ke saath woh unaffected carrier hai, aur uske har bete ke colour blind hone ka 1/2 chance hai (Example).
Do families mein colour vision
(a) Ek aurat jiske father colour blind the, uski vision normal hai. Woh aur uska pati, jiski vision bhi normal hai, family plan karte hain. Unke bete ke colour blind hone ka chance kya hai, aur beti ke hone ka? (b) Ek colour-blind aadmi ek aisi aurat se shaadi karta hai jo carrier nahi hai. Unke bachchon ke baare mein tum kya keh sakte ho?
Pehle khud try karo. Phir solution ek-ek step karke kholo.
| sperm | Y sperm | |
|---|---|---|
| egg | normal beti | normal beta |
| egg | carrier beti | colour-blind beta |
Haemophilia. Haemophilia ki sabse famous carrier Britain ki Queen Victoria thi: unka ek beta affected tha, aur unki do betiyaan carriers thi jinki apni betiyaan yeh allele Spain aur Russia ke royal families tak le gayi. Yeh disorder X-linked recessive hai. Normal clotting proteins ke ek cascade par depend karti hai, jismein har ek agle ko on karta hai. Haemophilia mein inmein se ek protein missing ya faulty hota hai, isliye chhote cut se, ya joint ke andar, bleeding rokna mushkil hota hai. Affected ladkiyan bahut rare hain, kyunki ladki ko carrier mother ke saath affected father bhi chahiye, aur modern treatment se pehle kam hi affected aadmi father banne tak jee paate the.
Sickle-cell anaemia. Microscope ke neeche is disease wale insaan ke blood mein kai red cells naram, gol discs ki jagah sakht crescents mein mude dikhte hain. Kaaran haemoglobin mein hai. Jab oxygen kam hoti hai, to us insaan ke haemoglobin molecules judkar lambi rods ban jaate hain jo cell ko kheenchkar uska shape bigaad dete hain. Sickled cells chhoti blood vessels ko jam kar dete hain, jisse dard aur organ damage hota hai, aur jaldi nasht ho jaate hain, jisse anaemia hota hai.
Faulty haemoglobin normal wale se apni β chain ke 146 amino acids mein se sirf ek mein alag hai: position 6 par glutamic acid (Glu) ki jagah valine (Val). Yeh aage ek single base se aata hai: β-globin gene ka chhatha codon DNA mein GAG ki jagah GTG padhta hai, ya mRNA mein GAG ki jagah GUG (Fig. 4.16).
Yeh disorder autosomal recessive hai, do alleles ke saath, aur . Sirf logon ko disease hoti hai. Carriers () usually healthy hote hain lekin average mein apne aadhe bachchon ko dete hain, isliye do carriers ke couple ke har bachche ke affected hone ka 1/4 chance hota hai. Yeh disease central aur western India ke kai tribal communities mein common hai, jahan 2023 mein shuru hua ek national mission iski screening karne aur 2047 tak ise public-health problem ke roop mein khatam karne ka lakshya rakhta hai.
Phenylketonuria. PKU ko hum pleiotropy ke example ke roop mein mil chuke hain (Section 4.5). Yeh ek inborn error of metabolism hai jo autosomal recessive ki tarah inherit hota hai. Sirf woh bachche affected hote hain jinmein enzyme gene ki do faulty copies hon, isliye carrier parents ke har baar affected bachche ka 1/4 chance hota hai. Kidneys phenylalanine ke by-products ko theek se reabsorb nahi karti, isiliye woh urine mein dikhte hain. Janm ke kuch hi baad blood test, aur phir phenylalanine kam wali diet, brain damage ka zyaadatar hissa rok deti hai.
Thalassaemia. Adult haemoglobin do tarah ki globin chains, α aur β, se barabar number mein banta hai. Thalassaemia mein ek mutation ya deletion ek tarah ki chain ka production dheema kar deta hai, isliye cell kaafi normal haemoglobin nahi bana paata aur insaan anaemic hota hai. Sickle-cell anaemia ki tarah yeh bhi autosomal recessive hai: affected bachche usually do healthy carriers ke ghar paida hote hain. Iske do main forms us chain ke naam par hain jiski kami hoti hai:
- α-thalassaemia: α-globin ka production gir jaata hai. Chromosome 16 par do padosi genes, HBA1 aur HBA2, dono α-globin code karte hain, aur har parent se ek chromosome 16 milne se insaan mein aise chaar genes hote hain. Chaar mein se jitne zyaada delete ya damage hon, cells utna kam α-globin bana paate hain.
- β-thalassaemia: β-globin ka production gir jaata hai. Yahan sirf ek gene shaamil hai, chromosome 11 par HBB, aur disorder insaan ki do copies mein se ek ya dono mein mutations se hota hai.
Bahut kam, ya galat tarah ka?
Thalassaemia
- Globin chains bahut kam banti hain
- Ek quantitative problem
- α ya β chain affected ho sakti hai
Sickle-cell anaemia
- β chains kaafi hain, lekin badli hui tarah ki
- Ek qualitative problem
- Ek amino acid badla: Glu → Val
Answer dekho
Answer (B) 1/2
Answer dekho
Answer (A) 0
Answer dekho
Answer (D) Ek affected beti jiske father unaffected hain
Left mein koi item tap karo, phir right mein uska match.
Answer dekho
- Sickle-cell anaemia : β-globin mein Glu ki jagah Val
- Thalassaemia : Bahut kam globin chains banti hain
- Haemophilia : Ek clotting protein missing hai
- Phenylketonuria : Phenylalanine tyrosine mein nahi badalta
4.8.3 Chromosomal Disorders
Chromosomes ki ginti bhi galat ho sakti hai. Meiosis ke dauraan pair ke do members, ya do sister chromatids, kabhi-kabhi alag nahi ho paate, is galti ko nondisjunction kehte hain. Tab ek gamete mein us chromosome ki ek extra copy hoti hai aur uske partner gamete mein ek bhi nahi (Fig. 4.19). Normal gamete se fertilise hone par inse aise zygotes bante hain jinmein us chromosome ki teen copies (trisomy, 2n + 1) ya ek copy (monosomy, 2n − 1) hoti hai. Is tarah individual chromosomes ka judna ya khona aneuploidy (असुगुणिता) hai. Human cells mein normally 46 chromosomes hote hain, autosomes ke 22 pairs aur sex chromosomes ka ek pair; zyaadatar aneuploid embryos survive nahi karte, aur jo karte hain unhe chromosomal disorder hota hai.
3/3Normal gamete ke saath inse trisomy (2n + 1) ya monosomy (2n − 1) banti hai.
Left mein ek cell jismein ek chromosome pair hai, ek blue aur ek orange, jis par one chromosome pair, 2n, aur meiosis likha hai. Arrows do gamete circles tak jaate hain. Step 1, normal: har gamete ko ek chromosome milta hai aur us par n likha hai; each gamete gets exactly one copy. Step 2, error: upar wale gamete ko dono chromosomes milte hain, n plus 1 label ke saath, aur neeche wale ko koi nahi, n minus 1 label ke saath; the pair fails to separate. Step 3, zygotes: har gamete ek normal gamete, plus n, se judta hai, jo ek green chromosome jodta hai. Upar wale zygote mein teen copies hain, trisomy, 2n plus 1; neeche wale mein ek, monosomy, 2n minus 1.
Ek cell chromosomes ka poora extra set bhi paa sakta hai, jaise jab telophase ke baad cytokinesis fail ho jaaye aur double hue chromosomes ek hi cell mein saath reh jaayein. Yeh polyploidy hai. Animals mein rare aur usually lethal, lekin plants mein common: bread wheat hexaploid (chhe sets) hai aur zyaadatar khaane wale kele triploid (teen sets) hain.
Chromosomal disorders ka diagnosis karyotype se hota hai, jo cell ke chromosomes ki ek picture hai jismein woh size aur shape ke hisaab se pairs mein lagaaye hote hain. Teen common examples Table 4.8 mein compare kiye gaye hain:
Down's syndrome (trisomy 21, 47 chromosomes) teeno mein sabse zyaada jaana-maana hai, aur iska risk mother ki umar ke saath badhta hai. John Langdon Down ne ise 1866 mein describe kiya, iska kaaran pata chalne se bahut pehle. Is syndrome wale logon mein typically physical, psychomotor aur mental development der se hota hai aur kad chhota hota hai. Doosre common features hain chauda palm jis par aksar ek single crease hoti hai, chhota gol sir, furrowed tongue aur thoda khula munh, aur kaafi baar janm se maujood heart defect.
Baaki do sex chromosomes se jude hain, aur dono milkar dikhate hain ki maleness Y decide karta hai, X chromosomes ki sankhya nahi. Klinefelter's syndrome wale insaan mein do X chromosomes aur ek Y hota hai (47, XXY). Y use male banata hai, lekin extra X kuch female features la sakta hai jaise breast development (gynaecomastia), aur woh sterile hota hai. Turner's syndrome wale insaan mein ek single X hota hai aur Y nahi (45, X0). Woh female ke roop mein develop hoti hai, usually chhote kad ki, lekin uske ovaries rudimentary rehte hain, isliye woh sterile hoti hai aur baaki secondary sexual characters develop nahi hote.
| Disorder | Karyotype | Khaas features |
|---|---|---|
| Down's syndrome | 47, +21 (trisomy 21) | chhota kad, chhota gol sir, furrowed tongue, der se development, heart defects |
| Klinefelter's syndrome | 47, XXY | male; kuch breast development; sterile |
| Turner's syndrome | 45, X0 | female; chhota kad; rudimentary ovaries; sterile |
Left mein koi item tap karo, phir right mein uska match.
Answer dekho
- Down's syndrome : 47, +21
- Klinefelter's syndrome : 47, XXY
- Turner's syndrome : 45, X0
Answer dekho
Answer (C) 47
Answer dekho
Answer (D) cytokinesis fail hota hai, isliye poore chromosome sets double ho jaate hain
Summary aur key points
- Genetics inheritance (parents se offspring tak jaane wale characters) aur variation (offspring kaise alag hote hain) ko study karti hai.
- Mendel ki success true-breeding pea lines, ek baar mein ek character, bade samples aur mathematical reasoning se aayi (Section 4.1).
- Monohybrid cross se uniform aur aisa milta hai jismein 3 : 1 phenotypes aur 1 : 2 : 1 genotypes hain; recessive ke saath test cross anjaan genotype ko saamne laata hai (Section 4.2).
- Law of dominance aur law of segregation: alleles pairs mein aate hain, ek doosre ko chhupa sakta hai, aur woh bina badle gametes mein alag ho jaate hain (Section 4.2.2).
- Incomplete dominance se beech ka hybrid aur 1 : 2 : 1 phenotypic ratio milta hai; co-dominance dono alleles dikhata hai, jaise AB blood mein (Section 4.2.2.1, Section 4.2.2.2).
- Dominance is baat ko dikhata hai ki allele ka product kya karta hai aur hum kaunsa phenotype examine karte hain; ABO multiple alleles bhi dikhata hai (Allele ko dominant kya banata hai?).
- Dihybrid cross mein 9 : 3 : 3 : 1 deta hai kyunki do allele pairs independently assort karte hain (Section 4.3.1).
- Sutton aur Boveri ki chromosomal theory: genes chromosomes par hote hain, jinka meiosis mein behaviour Mendel ke laws ko samjhata hai (Section 4.3.2).
- Ek chromosome par genes linked hote hain; crossing over unhe recombine karta hai, aur recombination frequency unki distance map karti hai (Section 4.3.3).
- Polygenic characters kai additive genes aur environment ki wajah se continuously vary karte hain; pleiotropic gene ke kai effects hote hain (Section 4.4, Section 4.5).
- Sex XO, XY ya ZW chromosomes se tay hota hai ya, honey bees mein, haplodiploidy se; humans mein sperm decide karta hai (Section 4.6).
- Mutations single-base changes aur frame-shifts se lekar chromosomal deletions aur duplications tak hote hain; mutagens unki rate badhate hain (Section 4.7).
- Pedigrees Mendelian disorders (haemophilia, colour blindness, sickle-cell, PKU, thalassaemia) ko saamne laate hain; aneuploidy se Down's, Klinefelter's aur Turner's syndromes hote hain (Section 4.8.2, Section 4.8.3).
Practice questions answers ke saath (NCERT “Exercises”)
Mendel ne garden pea ke saath kaam kiya. Pea ke chaar features list karo jinse unke experiments possible hue, aur samjhao ki isi kaam ke liye mango ka ped ek kharaab choice kyun hota.
Solution dikhao
- Self-pollinating flowers lines ko true-breeding rakhte hain, phir bhi unhe haath se cross-pollinate kiya ja sakta hai.
- Ek generation ek hi season leti hai.
- Har plant ginne ke liye bahut saare seeds deta hai.
- Kai characters do bilkul alag forms mein aate hain.
Mango ka ped phal dene mein kai saal leta hai, har phal mein kam seeds deta hai, zyaadatar insects se pollinate hota hai aur itna heterozygous hai ki uske seedlings alag-alag hote hain; true-breeding lines aur jaldi, bade counts lagbhag impossible hote.
Har pair ke do terms mein farq samjhao, is chapter se ek example dete hue.
Dominant allele aur recessive allele
Solution dikhao
Dominant allele apna effect tab bhi dikhata hai jab sirf ek copy ho (Gg mein G green pods deta hai); recessive allele sirf tab dikhta hai jab do copies hon (yellow pods ke liye gg chahiye).
Homozygous aur heterozygous individual
Solution dikhao
Homozygote mein gene ke do ek jaise alleles hote hain (GG ya gg) aur woh ek tarah ka gamete banata hai; heterozygote mein do alag alleles hote hain (Gg) aur woh do tarah ke gametes barabar number mein banata hai.
Monohybrid cross aur dihybrid cross
Solution dikhao
Monohybrid cross ek character follow karta hai (GG × gg; F2 3 : 1); dihybrid cross ek saath do characters follow karta hai (AAGG × aagg; F2 9 : 3 : 3 : 1).
Maan lo har gene independently assort karta hai.
Paanch loci par heterozygous ek diploid plant kitni tarah ke gametes bana sakta hai?
Solution dikhao
Paanch heterozygous loci: tarah ke gametes.
Genotype AaBBCcdd wala plant kitni tarah ke gametes bana sakta hai?
Solution dikhao
Sirf Aa aur Cc choice dete hain, isliye : ABCd, ABcd, aBCd aur aBcd.
Peas mein inflated pods (N) constricted pods (n) par dominant hain. True-breeding inflated-pod wale aur constricted-pod wale plants ke cross se samjhao ki law of dominance F1 aur F2 results ko kaise explain karta hai.
Solution dikhao
Parents NN (inflated) × nn (constricted) sirf N aur sirf n gametes banate hain, isliye har F1 plant Nn hai.
Law of dominance ke hisaab se Nn mein N n ko chhupa deta hai, isliye poora F1 inflated hai: sirf ek parental form dikhta hai.
Nn ko self karne se NN, Nn, Nn aur nn (1 : 2 : 1) milte hain. Kyunki N dominant hai, NN aur Nn dono inflated hain, isliye F2 mein 3 inflated : 1 constricted dikhta hai. Recessive form bina badle sirf nn plants mein wapas aata hai.
Test cross define karo. Ek dog breed mein black coat (B) brown coat (b) par dominant hai. Ek breeder jaanna chahta hai ki ek black dog mein brown allele hai ya nahi. Ek test cross design karo aur batao ki kaunse results har possible genotype ko dikhayenge.
Solution dikhao
Test cross mein dominant phenotype lekin anjaan genotype wale individual ko homozygous recessive individual se cross kiya jaata hai, taaki offspring anjaan genotype ko saamne la dein.
Black dog ko brown (bb) dog se cross karo. Agar black dog BB hai, to har pup ko usse B milta hai aur woh black (Bb) hota hai. Agar woh Bb hai, to lagbhag aadhe pups ko usse b milta hai aur woh brown (bb) hote hain. Ek bhi brown pup saabit karta hai ki dog Bb hai; bina kisi brown pup wala bada litter BB ko bahut likely bana deta hai.
Peas mein round seeds (R) wrinkled seeds (r) par dominant hain. Har cross ke liye Punnett square use karo.
Seed parent rr × pollen parent Rr: offspring kaunsa phenotypic ratio dikhate hain?
Solution dikhao
Eggs: sirf r. Pollen: R aur r. Offspring Rr (round) aur rr (wrinkled) barabar number mein: 1 : 1.
Seed parent RR × pollen parent Rr: offspring kaunsa phenotypic ratio dikhate hain?
Solution dikhao
Eggs: sirf R. Offspring RR aur Rr (1 : 1 genotypes), sab round.
Ek axial-flowered, green-pod wala plant (AaGg) ek terminal-flowered, green-pod wale plant (aaGg) se cross kiya jaata hai. Offspring ka kitna fraction expected hai jo
axial ho aur yellow pods wala ho?
Solution dikhao
Aa × aa se axial 1/2 milta hai; Gg × Gg se yellow 1/4; isliye .
terminal ho aur green pods wala ho?
Solution dikhao
Terminal 1/2 aur green 3/4: .
Do flies, dono do linked genes A aur B ke liye heterozygous, cross ki jaati hain. Maan lo genes itne paas hain ki unke beech koi crossing over nahi hota.
Dono flies ke ek chromosome par AB aur doosre par ab hai. Offspring ka phenotypic ratio batao.
Solution dikhao
Sirf AB aur ab gametes (har ek 1/2). Offspring: 1/4 AB/AB, 1/2 AB/ab, 1/4 ab/ab, isliye 3 dono ke liye dominant : 1 dono ke liye recessive. Do mixed phenotypes nahi aate.
Dono flies ke ek chromosome par Ab aur doosre par aB hai. Phenotypic ratio batao.
Solution dikhao
Sirf Ab aur aB gametes. Offspring: 1/4 Ab/Ab (sirf A dominant), 1/2 Ab/aB (dono ke liye dominant), 1/4 aB/aB (sirf B dominant): 1 : 2 : 1 ratio, bina kisi double recessive ke.
Thoda sa crossing over (a) ke result ko kaise badalta?
Solution dikhao
Kuch Ab aur aB recombinant gametes bante, isliye do mixed phenotypes (sirf A, sirf B) thode number mein dikhte, aur ratio thoda 9 : 3 : 3 : 1 ki taraf khisakta, jahan woh sirf free recombination (50 %) par pahunchta hai.
T. H. Morgan aur unke group ne genetics mein jo teen cheezein jodi, unka summary do.
Solution dikhao
- Experiment se saabit kiya ki khaas genes khaas chromosomes par hote hain (fly ke X chromosome par ek eye-colour gene), jisse chromosomal theory confirm hui.
- Linkage aur recombination discover kiye, aur recombinants ko crossing over se samjhaya.
- Apne student Sturtevant ke through recombination frequencies se pehla genetic map banaya; aur Drosophila ko genetics ka standard organism bana diya.
Pedigree kya hai, aur human geneticists pedigree analysis par kyun nirbhar rehte hain? Do practical uses batao.
Solution dikhao
Pedigree kai generations tak ek family ka chart hai jo dikhata hai ki kisme koi khaas trait hai. Insaanon mein controlled crosses aur badi families arrange nahi ki ja sakti, isliye maujooda family records hi main saboot hain.
Uses: yeh tay karna ki disorder dominant hai ya recessive aur autosomal hai ya X-linked; aur yeh risk estimate karna ki couple ka bachcha affected ya carrier hoga, jise genetic counsellors families ko salaah dene ke liye use karte hain.
Ek couple ki teen betiyaan hain aur woh chauthe bachche ki ummeed kar rahe hain. Ek rishtedaar kehta hai ki mother 'sirf ladkiyan hi paida kar sakti hai'. Humans mein sex determination ke mechanism se samjhao ki baby ka sex kaun decide karta hai aur bete ka chance kya hai.
Solution dikhao
Aurtein 44 + XX hoti hain aur har egg mein 22 + X hota hai. Aadmi 44 + XY hote hain, aur meiosis barabar number mein 22 + X ya 22 + Y wale sperm deta hai. X sperm se XX (ladki) banti hai; Y sperm se XY (ladka). Isliye father ka sperm decide karta hai, aur har pregnancy mein independently bete ka 1/2 chance hota hai, pehle ke bachche chahe jo bhi hon. Rishtedaar ki baat ka koi biological basis nahi hai.
Blood group A ki ek aurat, jiski mother group O thi, ke group B ke ek aadmi ke saath bachche hain, jiske father group O the.
Aurat aur aadmi ke genotypes likho.
Solution dikhao
Dono ko group O parent se mila, isliye aurat hai aur aadmi .
Unke bachchon ke kaunse blood groups ho sakte hain, aur kin probabilities se?
Solution dikhao
Gametes ya (aurat) aur ya (aadmi): bachche (AB), (A), (B) aur (O), har ek 1/4 probability se.
Ek true-breeding red-flowered plant ko usi species ke true-breeding white-flowered plant se cross kiya jaata hai.
Agar alleles incomplete dominance dikhate hain to F1 aur F2 describe karo, aur ek real example ka naam do.
Solution dikhao
F1 beech ka (pink) hai. F2 1 red : 2 pink : 1 white hai, jo genotypes RR : Rr : rr se match karta hai. Example: four o'clock plant (Mirabilis jalapa) mein flower colour.
Agar alleles iski jagah co-dominant hote to F1 describe karo, aur ABO blood groups ke alawa ek real example ka naam do.
Solution dikhao
F1 dono colours ek saath poore dikhata, jaise red aur white patches ya dhaariyan, koi blend nahi. F2 phir se 1 : 2 : 1 hota. Example: cattle mein roan coat, jahan red × white cross se aise calves aate hain jinmein red aur white baal mile hote hain.
Point mutation kya hai? β-globin gene ke chhathe codon ke badlaav se samjhao ki ek single base change disease kaise paida kar sakta hai.
Solution dikhao
Point mutation DNA ka sirf ek base pair badalta hai.
Sickle-cell anaemia mein β-globin gene ka chhatha codon GAG se GTG (mRNA mein GUG) ban jaata hai, isliye glutamic acid ki jagah valine aa jaata hai. Badla hua haemoglobin kam oxygen par fibres banata hai, red cells sickle-shaped ho jaate hain, chhoti vessels ko block karte hain aur jaldi toot jaate hain: insaan ko anaemia aur dard hota hai.
Yeh idea ki genes chromosomes par hote hain, aur meiosis mein chromosomes ka behaviour Mendel ke laws ko samjhata hai, kisne diya?
Answer dekho
Answer (B) Walter Sutton aur Theodor Boveri
Sutton aur Boveri ne chromosomal theory of inheritance propose ki; Morgan ne baad mein use test kiya.Autosomes par recessive alleles se hone wale do disorders chuno. Har ek ke liye affected gene product ka naam do aur ek symptom batao.
Solution dikhao
- Sickle-cell anaemia: glutamic acid ki jagah valine wala β-globin; sickled red cells anaemia aur dard bhare blockages karte hain.
- Thalassaemia: bahut kam α- ya β-globin; haemoglobin ki kami se anaemia hota hai.
- Phenylketonuria: phenylalanine hydroxylase missing hai; phenylalanine jama hota hai aur intellectual disability karta hai (inmein se koi bhi do, ya cystic fibrosis, sahi maane jaayenge).
Blood group O ke do parents ka group A ka bachcha ho sakta hai.
Answer dekho
Answer Galat
Dono parents hain aur sirf aage dete hain, isliye saare bachche , group O, hain.Teen additive genes ek character control karte hain. AaBbCc × AaBbCc ke offspring mein kitne fraction mein bilkul do capital alleles hain? Decimal mein do.
Answer dekho
Answer 0.234375
.Har organism ko uske sex determination system se match karo (2n ya n haplodiploidy ke liye hai).
Left mein koi item tap karo, phir right mein uska match.
Answer dekho
Answer- grasshopper : XO
- human : XY
- hen : ZW
- honey bee : 2n ya n
Grasshopper males XO hain; humans XY; birds ZW (females heterogametic); honey bee drones haploid hain.Controlled cross ke steps ko order mein lagao.
- Flower ko phir se dhako aur seeds banne do
- Chune hue pollen parent ka pollen stigma par chhidko
- Seed parent ke bud se anthers hatao
- Flower ko bag se dhako
Answer dekho
Answer- Seed parent ke bud se anthers hatao
- Flower ko bag se dhako
- Chune hue pollen parent ka pollen stigma par chhidko
- Flower ko phir se dhako aur seeds banne do
Emasculate, bag, pollinate, re-bag: bag pakka karta hai ki stigma tak sirf chuna hua pollen pahunche.Ek test cross do genes ke beech 50 % recombination dikhata hai. Tum kya conclude kar sakte ho?
Answer dekho
Answer (C) Woh independently assort karte hain: alag chromosomes par ya ek par bahut door
50 % maximum hai aur unlinked genes yahi dete hain; tightly linked genes kam recombination dikhate hain.
Apna NCERT exercise question dhoondo
Hamare practice questions ncert.ai ke liye likhe gaye hain aur NCERT exercises ko follow karte hain. Apni textbook ke question se match karne wala question dhoondo; uska answer uske saath hai.
| Tumhari NCERT textbook mein | Yahan practice question |
|---|---|
| NCERT Exercises Q1 | Practice Q1 |
| NCERT Exercises Q2 | Practice Q2 |
| NCERT Exercises Q3 | Practice Q3 |
| NCERT Exercises Q4 | Practice Q4 |
| NCERT Exercises Q5 | Practice Q5 |
| NCERT Exercises Q6 | Practice Q6 |
| NCERT Exercises Q7 | Practice Q7 |
| NCERT Exercises Q8 | Practice Q8 |
| NCERT Exercises Q9 | Practice Q9 |
| NCERT Exercises Q10 | Practice Q10 |
| NCERT Exercises Q11 | Practice Q11 |
| NCERT Exercises Q12 | Practice Q12 |
| NCERT Exercises Q13 | Practice Q13 |
| NCERT Exercises Q14 | Practice Q14 |
| NCERT Exercises Q15 | Practice Q15 |
| NCERT Exercises Q16 | Practice Q16 |
Quick check: MCQs
- 4.1 Mendel's Laws of Inheritance3 questions
- 4.2.2 Law of Segregation3 questions
- 4.2.2.2 Co-dominance4 questions
- 4.3.1 Law of Independent Assortment3 questions
- 4.3.3 Linkage and Recombination4 questions
- 4.4 Polygenic Inheritance2 questions
- 4.5 Pleiotropy2 questions
- 4.6.2 Sex Determination in Honey Bee4 questions
- 4.7 Mutation3 questions
- 4.8.2 Mendelian Disorders4 questions
- 4.8.3 Chromosomal Disorders3 questions
Key terms (English + Hindi)
- alleleयुग्मविकल्पीyugmavikalpi
- Gene ke alternative forms mein se ek, jaise G (green pods) aur g (yellow pods).Chapter mein pehli baar yahan aaya →
- aneuploidyअसुगुणिताasugunita
- Ek ya kuch chromosomes ka judna ya khona, jaise trisomy 21 mein.Chapter mein pehli baar yahan aaya →
- co-dominanceसहप्रभाविताsahaprabhavita
- Aisi inheritance jismein heterozygote mein dono alleles poori tarah express hote hain, jaise group AB mein.Chapter mein pehli baar yahan aaya →
- dominantप्रभावीprabhavi
- Aisa allele jo sirf ek copy hone par bhi apna effect dikhata hai.Chapter mein pehli baar yahan aaya →
- genotypeजीनप्ररूपjeenpraroop
- Kisi character ke liye individual ka genetic make-up, alleles ke roop mein likha, jaise Gg.Chapter mein pehli baar yahan aaya →
- heterozygousविषमयुग्मजीvishamayugmaji
- Gene ke do alag alleles hona, jaise Gg mein.Chapter mein pehli baar yahan aaya →
- homozygousसमयुग्मजीsamayugmaji
- Gene ke do ek jaise alleles hona, jaise GG ya gg mein.Chapter mein pehli baar yahan aaya →
- incomplete dominanceअपूर्ण प्रभाविताapoorn prabhavita
- Aisi inheritance jismein heterozygote do homozygotes ke beech ka hota hai.Chapter mein pehli baar yahan aaya →
- inheritanceवंशागतिvanshagati
- Parents se offspring tak characters ka aage jaana; heredity ka basis.Chapter mein pehli baar yahan aaya →
- linkageसहलग्नताsahalagnata
- Ek chromosome par genes ka saath-saath inherit hone ka tendency.Chapter mein pehli baar yahan aaya →
- mutationउत्परिवर्तनutparivartan
- DNA sequence mein badlaav, ek single base se lekar poore chromosome segment tak.Chapter mein pehli baar yahan aaya →
- pedigree analysisवंशावली विश्लेषणvanshavali vishleshan
- Kai generations ke family chart mein kisi trait ko trace karna.Chapter mein pehli baar yahan aaya →
- phenotypeलक्षणप्ररूपlakshanpraroop
- Character ka dikhne wala form, jaise green pods.Chapter mein pehli baar yahan aaya →
- pleiotropyबहुप्रभाविताbahuprabhavita
- Ek single gene ka kai alag characters par effect.Chapter mein pehli baar yahan aaya →
- polygenic inheritanceबहुजीनी वंशागतिbahujeeni vanshagati
- Additive effects wale kai genes se control hone wale character ki inheritance, jisse continuous variation milta hai.Chapter mein pehli baar yahan aaya →
- recessiveअप्रभावीaprabhavi
- Aisa allele jiska effect sirf do copies hone par dikhta hai.Chapter mein pehli baar yahan aaya →
- sex chromosomeलिंग गुणसूत्रling gunsootra
- Sex decide karne mein shaamil chromosome, jaise X, Y, Z ya W.Chapter mein pehli baar yahan aaya →
- test crossपरीक्षार्थ संकरणparikshaarth sankaran
- Dominant-phenotype individual ka homozygous recessive individual se cross, uska genotype jaanne ke liye.Chapter mein pehli baar yahan aaya →
- variationविविधताvividhata
- Offspring apne parents se aur ek doosre se kitna alag hote hain, uski degree.Chapter mein pehli baar yahan aaya →