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ScienceCh 9 Light – Reflection and Refraction

Light – Reflection and Refraction: Class 10 Science · Chapter 9

Science · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 100 min
  • 34 practice questions
  • 28 MCQs

What you will learn in Light – Reflection and Refraction

  • State the laws of reflection and describe the image formed by a plane mirror
  • Identify concave and convex mirrors and their pole, centre of curvature, principal axis, principal focus and focal length, and use R = 2f
  • Draw ray diagrams to find the position, size and nature of the image formed by spherical mirrors and lenses for any object position
  • Apply the New Cartesian sign convention with the mirror formula, the lens formula and magnification to solve numerical problems
  • Explain refraction through a glass slab using the laws of refraction and Snell's law
  • Relate refractive index to the speed of light and compare the optical densities of media
  • Calculate the power of a lens in dioptres and add the powers of lenses in contact

Original companion text aligned to NCERT Science Class 10, Chapter 9, pp. 134–160. Not affiliated with or endorsed by NCERT.

During a power cut on a moonless night, your room seems to vanish. The bed and the cupboard are still there, yet you cannot see them. Light a candle and they come back. We see a thing only when light travels from it into our eyes. The Sun, a bulb or a candle flame makes its own light; a book, a wall or a face sends back part of the light that falls on it. Light can also pass through clear glass and water, which is why a window lets you see the street.

Watch a torch beam in a dusty room, or a shaft of sunlight through a gap in a curtain: it runs straight. A small bulb casts a shadow with sharp edges, because light does not curve round an object into the space behind it. We draw this straight path as a line with an arrow and call it a ray. In this chapter, rays are all we need to explain mirrors, lenses and the bending of light. The same ideas lead on to the human eye and the rainbow in the next chapter.

9.1 Reflection of Light

Smooth, shiny surfaces such as a mirror, a polished steel plate or still water send back most of the light that reaches them. You met the two rules of reflection in earlier classes. They apply to every surface, flat or curved, provided we measure angles from the normal: the line drawn at right angles to the surface at the point where the ray strikes it.

LawLaws of reflection

(i) The reflected ray makes the same angle with the normal as the incident ray does: ∠r=∠i. (ii) The incident ray, the normal where it strikes and the reflected ray all lie in one flat plane.

3/3Traced backwards, the reflected rays meet behind the mirror. The image is virtual, upright, the same size, and as far behind as the object is in front.

Fig. 9.1Two rays from the tip of an object are enough to find its image in a plane mirror.

An upright arrow stands in front of a vertical plane mirror. Step 1: a ray from the arrow's tip strikes the mirror and the normal is drawn there as a dashed line, with the angle of incidence i marked. Step 2: the reflected ray travels on to an eye, making angle r with the normal, equal to i. Step 3: the reflected ray is traced back behind the mirror as a dashed line; a second ray that hits the mirror straight on comes back on itself, and its dashed extension meets the first one at the image of the tip. The image arrow stands behind the mirror, the same height as the object, and the distances d in front and behind are equal.

So a plane mirror gives an image that is virtual (no light actually reaches the spot behind the glass), erect and the same size as the object. It sits exactly as deep behind the glass as the object stands in front, and it is laterally inverted: your right hand appears as the image's left hand. This is why the word AMBULANCE is painted back to front on the bonnet of an ambulance. A driver ahead reads it the right way round in the rear-view mirror.

What happens when the mirror is curved? Try the activity below before reading on.

The two sides of the katori are curved mirrors. The most useful curved mirrors have a reflecting surface that is part of a sphere, so they are called spherical mirrors.

Quick check
1 of 2
A ray strikes a plane mirror, making an angle of 30∘ with the mirror surface. What is the angle of reflection?
°
Show answer

Answer 60 °

Angles are measured from the normal, not from the surface. The normal is at 90∘ to the mirror, so i=90∘−30∘=60∘, and r=i=60∘. Answering 30∘ means measuring from the mirror.

9.2 Spherical Mirrors

Picture a hollow glass ball, silvered and cut into pieces. Each piece is a spherical mirror. If the reflecting face is the inner, caved-in one, which faces the centre of the sphere, the piece is a concave mirror (अवतल दर्पण). If the reflecting face bulges outwards, it is a convex mirror (उत्तल दर्पण). The inside of a steel spoon is roughly concave and its back is roughly convex. In diagrams we draw a spherical mirror as a curved line and hatch its back, the side that does not reflect.

3/4Rays parallel to the axis reflect through the principal focus F, halfway between P and C.

Fig. 9.2A concave and a convex mirror cut from the same sphere share the same centre of curvature C.NCERT Fig. 9.2 · p. 136

A dashed circle stands for a hollow sphere with centre C. Step 1: two pieces of it are highlighted, one on the right and one on the left, and the radius R is drawn. Step 2: only the right piece remains, reflecting on its inner side; this is a concave mirror, with its pole P where the principal axis meets it, and the distance from C to P marked R. Step 3: rays parallel to the axis strike the concave mirror and all reflect through one point F, halfway between P and C. Step 4: only the left piece remains, reflecting on its outer side; this is a convex mirror. Parallel rays reflect and spread out, and dashed lines traced backwards meet at F behind the mirror, with C also behind it.

A few names let us describe these mirrors exactly (Fig. 9.2).

Definition
Pole (P)

The midpoint of a spherical mirror's shiny face. Unlike C and F, it is a point on the mirror itself.

Definition
Centre of curvature (C)

The centre of the whole sphere that the mirror was cut from. A concave mirror has C on its shiny side and a convex mirror has it behind; either way, C is off the mirror. The distance PC is the radius of curvature R.

Definition
Principal axis

The straight line joining the pole P to the centre of curvature C. It meets the mirror at right angles at P, so it is the normal there.

Sunlight arrives as rays parallel to one another. When rays parallel to the principal axis strike a concave mirror, they all reflect through a single point on the axis. When they strike a convex mirror they spread out, but traced backwards they seem to come from a single point behind the mirror (the last two steps of Fig. 9.2).

Definition
Principal focus (F)

The point on the principal axis where rays parallel to the axis meet after reflection from a concave mirror, or from which they appear to spread after reflection from a convex mirror.

Definition
Focal length (f)

The distance from the pole to the principal focus of a mirror (or from the optical centre to the principal focus of a lens).

The width of the reflecting surface is its aperture. We deal only with mirrors whose aperture is small compared with their radius of curvature. For these, the focus lies exactly halfway between the pole and the centre of curvature, so the radius of curvature is twice the focal length:

Radius of curvature and focal length
R=2f
Quick check
1 of 3
A concave mirror is cut from a sphere of radius 30 cm. What is its focal length?
cm
Show answer

Answer 15 cm

For a small-aperture mirror R=2f, so f=30/2=15 cm. Doubling instead of halving gives the wrong answer of 60 cm.

9.2.1 Image Formation by Spherical Mirrors

A plane mirror always gives the same kind of image. A concave mirror does not: its image may form in front of the mirror or behind it, and may be larger or smaller, upright or upside down, depending on where the object is. Two words describe every image.

Table 9.3Images formed by a concave mirrorNCERT Table 9.1 · p. 138
ObjectNature of imageSizeWhere the image forms
At infinity (very far)Real, invertedA point, highly diminishedAt F
Beyond CReal, invertedDiminishedBetween F and C
At CReal, invertedSame sizeAt C
Between C and FReal, invertedEnlargedBeyond C
At FReal, inverted (rays leave parallel)Very largeAt infinity
Between F and PVirtual, erectEnlargedBehind the mirror

9.2.2 Representation of Images Formed by Spherical Mirrors Using Ray Diagrams

Every point of an object sends rays in all directions, and the mirror forms an image of each point. To find where the image of the tip of an object lies, we do not need all those rays. We follow two rays whose paths after reflection we can predict and see where they cross. Four rays are especially easy to follow (Fig. 9.3).

  1. A ray parallel to the principal axis reflects through F (concave mirror), or reflects so that it seems to come from F (convex mirror).
  2. A ray through F (concave mirror), or one heading towards F (convex mirror), reflects parallel to the principal axis. This is the first rule run backwards.
  3. A ray through C (concave mirror), or one heading towards C (convex mirror), meets the mirror along the normal and returns along the same line.
  4. A ray that strikes the pole reflects at an equal angle on the other side of the principal axis, because the axis is the normal at P.

1/4A ray parallel to the axis passes through F after reflection (concave), or seems to come from F (convex).

Fig. 9.3Each special ray is just the law of reflection applied at a convenient point.NCERT Figs. 9.3–9.6 · p. 138

Two panels, a concave mirror above and a convex mirror below, each with P, F and C marked on the principal axis. Step 1: a ray parallel to the axis reflects through F for the concave mirror; for the convex mirror it reflects upwards and its dashed backward extension passes through F behind the mirror. Step 2: a ray through F of the concave mirror reflects parallel to the axis; for the convex mirror a ray aimed at F behind it reflects parallel. Step 3: a ray through C (or aimed at C) hits the mirror head-on and returns along the same line, with arrows both ways. Step 4: a ray striking the pole reflects below the axis, the two marked angles at P being equal.

None of these is a new law: each one is the law of reflection applied at a convenient point. Use any two of them to locate an image; a third ray is a useful check.

(a) Image formation by a concave mirror

Fig. 9.4 uses the parallel ray and the ray through (or from) F for each object position in Table 9.3. Step through it and notice the pattern. As the object moves in towards F, the real image runs away from the mirror and grows. Once the object is inside F, the reflected rays no longer meet in front, and the image jumps behind the mirror.

4/6Image beyond C: real, inverted, enlarged.

Fig. 9.4One concave mirror, six object positions: compare each step with a row of Table 9.3.NCERT Fig. 9.7 · p. 140

A concave mirror on the right with P, F and C marked on the principal axis; each step shows one object position with two rays, blue (parallel to the axis, then through F) and orange (through F, then parallel). Step 1, object at infinity: parallel rays meet at F, giving a point-sized image there. Step 2, object beyond C: a small inverted image forms between F and C. Step 3, object at C: an inverted image of the same size forms at C. Step 4, object between C and F: a large inverted image forms beyond C. Step 5, object at F: the two reflected rays are parallel to each other, so the image is at infinity. Step 6, object between F and P: the reflected rays spread out; their dashed extensions meet behind the mirror at a large, upright, virtual image.

InteractiveMirror explorer

An interactive ray diagram. Two buttons choose a concave or a convex mirror. You can drag the object arrow along the principal axis, or use a slider to set its distance from the pole, from 1 centimetre up to four focal lengths; for the concave mirror, five buttons jump the object beyond C, to C, between C and F, to F, or inside F. A second slider sets the focal length. Three rays are drawn: one parallel to the axis, one to the pole and one along a radius through C, with dashed extensions when the image is virtual. Cards show the signed values of u, v, f, m and the image height, and a status line says whether the image is real or virtual, inverted or erect, enlarged or diminished.

Fig. 9.5Choose a concave or convex mirror, then drag the object (or use the buttons and sliders). The status line names the object's position and describes the image.

In the explorer, tap each position button for the concave mirror and check the status line against Table 9.3. Then slide the object slowly through F and watch the image disappear to infinity on one side and reappear behind the mirror.

Uses of concave mirrors. Each use matches a row of Table 9.3:

  • Solar cookers and solar furnaces: a large concave reflector brings sunlight to its focus, where the concentrated energy cooks food or even melts metal (the first row).
  • Dentists' mirrors: a small concave mirror held close to a tooth shows a magnified view of it.
  • Shaving and make-up mirrors: your face is closer than F, so you see an enlarged, upright image (the last row).
  • Torches, searchlights and vehicle headlights: the bulb sits at F, so the reflected light leaves as a strong parallel beam (the at-F row).

(b) Image formation by a convex mirror

A convex mirror spreads light out, so the reflected rays never meet in front of it. Wherever the object is, the rays only seem to come from a point behind the mirror, between P and F. So the image is always virtual, upright and smaller than the object. Only two cases need a diagram: an object very far away and an object at an ordinary distance (Fig. 9.6).

2/2The image is behind the mirror between P and F: virtual, erect and diminished.

Fig. 9.6A convex mirror always gives a virtual, erect, diminished image behind it, between P and F.NCERT Fig. 9.8 · p. 141

A convex mirror bulges towards the left, with P on its surface and F and C behind it on the right. Step 1: rays parallel to the axis reflect and spread upwards; their dashed backward extensions meet at F behind the mirror, a point-sized virtual image. Step 2: an upright object stands in front of the mirror. A blue ray parallel to the axis reflects as if from F, and an orange ray aimed at F reflects parallel to the axis; their dashed extensions meet behind the mirror between P and F, where a small upright dashed image arrow is drawn.

Table 9.4Images formed by a convex mirrorNCERT Table 9.2 · p. 141
ObjectNature of imageSizeWhere the image forms
At infinityVirtual, erectA point, highly diminishedAt F, behind the mirror
Anywhere between infinity and PVirtual, erectDiminishedBetween P and F, behind the mirror

2/2The bulging surface reflects light from a much wider region: all three vehicles are in view.

Fig. 9.7A convex mirror shows a wider field of view than a plane mirror of the same size.

Seen from above, a mirror sits at the top, you are below it, and three vehicles are lined up behind you at the bottom. Step 1: with a plane mirror, the region you can see in it is a narrow shaded wedge that includes only the middle vehicle. Step 2: the mirror is replaced by a convex mirror of the same width; because its surface bulges, the shaded wedge is much wider and includes all three vehicles.

Uses of convex mirrors. Look at the wing mirror of a bus or a scooter: it bulges. A driver needs two things from it. First, an upright image at every distance, so that traffic behind never appears upside down. Second, a wide view of the road behind: the bulge gathers light from a much wider angle than a flat mirror of the same size. The same mirrors guard sharp bends on ghat roads and the corners of shops. The catch is that vehicles look smaller, so they seem farther away than they really are.

Quick check
1 of 3
A ray heading towards the focus of a convex mirror strikes it. After reflection, the ray…
Show answer

Answer (C) travels parallel to the principal axis

Rule 2: a ray aimed at F of a convex mirror reflects parallel to the axis. A ray returns along its own path only if it is aimed at C.
Practice · 4 questions

Practice 9.1 (NCERT in-text questions, p. 142): questions with answers

  1. Short answerEasyNCERT in-text Questions p. 142, Q1

    Sunlight falls on a concave mirror parallel to its principal axis. Where do the reflected rays go? Use your answer to explain, in one sentence, what the principal focus of a concave mirror is.

    Show solution

    AnswerThey all pass through one point on the principal axis; that point is the principal focus.

    After reflection, all rays that were parallel to the principal axis pass through a single point on the axis, in front of the mirror. This point is the principal focus F of the concave mirror; its distance from the pole is the focal length.

  2. NumericalEasyNCERT in-text Questions p. 142, Q2

    A shaving mirror is ground to a radius of curvature of 24 cm. Find the size of its focal length.

    cm
    Show solution

    For a mirror of small aperture, R=2f. So f=R/2, which is 24/2=12 cm.

  3. Short answerEasyNCERT in-text Questions p. 142, Q3

    A jeweller wants an upright, magnified view of a tiny engraving inside a ring. Which kind of mirror should she use, and where should the ring be?

    Show solution

    AnswerA concave mirror, with the ring between its pole and its focus.

    Only a concave mirror can give an erect, enlarged image, and only when the object is between P and F (Table 9.3, last row). The image is then virtual, so she views it by looking into the mirror.

  4. Short answerMediumNCERT in-text Questions p. 142, Q4

    Bus drivers use convex mirrors, not plane mirrors, as side mirrors. Give two reasons.

    Show solution

    AnswerA convex mirror always gives an upright image, and it shows a much wider area behind the bus.

    • A convex mirror always forms an erect (upright) image, whatever the distance of the vehicle behind, so the driver is never confused by an inverted view.
    • Because it bulges outwards it has a much wider field of view than a plane mirror of the same size, so the driver sees more lanes and more traffic (Fig. 9.7).

9.2.3 Sign Convention for Reflection by Spherical Mirrors

To use a formula for mirrors we must say which way each distance points. We use the New Cartesian sign convention. It treats the principal axis as the x-axis of a graph, with the origin at the pole (Fig. 9.8):

  1. Place the object to the left of the mirror, so that light travels from left to right towards the mirror.
  2. Measure every distance along the principal axis from the pole.
  3. Distances measured to the right of the pole (along +x) are positive; distances to the left (along −x) are negative.
  4. Heights measured upwards from the principal axis (+y) are positive.
  5. Heights measured downwards from the principal axis (−y) are negative.

3/3The object's height is positive. A real image below the axis has a negative height.

Fig. 9.8Distances to the left of the pole and heights below the axis are negative.NCERT Fig. 9.9 · p. 143

A concave mirror stands at the origin of x and y axes, with its pole P at the origin and the principal axis along the x-axis; plus x is to the right, plus y upwards, and an arrow at the top left shows light arriving from the left. Step 2: an upright object stands to the left, beyond F; an arrow from P to the object points left and is labelled u less than 0, and another from P to F is labelled f less than 0. Step 3: a real, inverted image forms below the axis between the object and F; the object height is labelled h greater than 0 and the image height h prime less than 0.

Two shortcuts follow. The object distance u is always negative, because the object is always on the left. A concave mirror's focus is in front of it, so its f (and R) is negative; a convex mirror's focus is behind it, so its f is positive.

9.2.4 Mirror Formula and Magnification

Three lengths, all measured from the pole, describe a mirror set-up: the object distance u, the image distance v, and f for the focus. The mirror formula links them:

Mirror formula
1v+1u=1f
(9.1)
where
u
object distance from the pole
v
image distance from the pole
f
focal length

One formula covers every case, concave or convex, object near or far, as long as each quantity goes in with its sign. Never guess a sign: decide it from the convention, put it in, and let the algebra tell you the sign of the answer.

Magnification. The magnification (आवर्धन) m says how many times taller the image is than the object. With h the object height and h′ the image height:

Magnification
m=h′h
(9.2)

It can also be found from the two distances:

m=h′h=−vu
(9.3)

The object stands on the axis pointing up, so h is positive. Then the sign of m tells you the nature of the image. A negative m means the image hangs below the axis: it is inverted, and real. A positive m means it is upright, and virtual. The size of m tells you the rest: ∣m∣>1 enlarged, ∣m∣=1 same size, ∣m∣<1 diminished.

Example 9.1NCERT Example 9.1 · p. 144

A mirror at a hairpin bend

A convex mirror with a radius of curvature of 4.0 m is fixed at a sharp bend on a ghat road. A car 1.6 m high is 6.0 m from the mirror. Find the position, nature and height of the car's image.

Try it yourself first. Then reveal the solution one step at a time.

Example 9.2NCERT Example 9.2 · p. 144

Catching an image on a screen

A concave mirror has a focal length of 20 cm. A candle flame 2.5 cm tall stands 30 cm from it. Where must a screen be placed to get a sharp image? Describe the image and find its height.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
A concave mirror has a focal length of 15 cm, and an object stands 45 cm from it. Find the image distance v, with its sign.
cm
Show answer

Answer -22.5 cm

f=−15, u=−45, so 1/v=−1/15+1/45=−2/45 and v=−22.5 cm: real, 22.5 cm in front. Writing f=+15 gives a wrong, positive answer.
Practice · 2 questions

Practice 9.2 (NCERT in-text questions, p. 145): questions with answers

  1. NumericalEasyNCERT in-text Questions p. 145, Q1

    A convex mirror is cut from a sphere of radius 50 cm. What is its focal length, with its sign?

    cm
    Show solution

    f=R/2=50/2=25 cm. The focus of a convex mirror is behind it, so f=+25 cm.

  2. NumericalMediumNCERT in-text Questions p. 145, Q2

    A bulb 15 cm from a concave mirror throws a real image on a wall, four times as tall as the bulb. How far is the wall from the mirror, and what is the focal length?

    1. Image distance v, with its sign (cm):

      cm
      Show answer

      Answer -60 cm

      −v/u=−4 with u=−15 cm gives v=4u=−60 cm: the wall is 60 cm from the mirror.
    2. Focal length f, with its sign (cm):

      cm
      Show answer

      Answer -12 cm

      1/f=1/v+1/u, which is −1/60−4/60, so f=−12 cm.
    Show solution

    Real image, so m=−4, and u=−15 cm.

    m=−vu⇒v=−mu=4×(−15)

    So v=−60 cm: the image is 60 cm in front of the mirror. Then 1/f=1/v+1/u=−1/60−4/60=−5/60, so f=−12 cm. Check: the object at 15 cm is between F (12 cm) and C (24 cm), as an enlarged real image requires.

9.3 Refraction of Light

Look down into a clear swimming pool and the bottom seems nearer than it is; people who jump in expecting shallow water get a shock. A straw in a glass of nimbu-paani looks broken at the surface. A glass paperweight seems to lift the words beneath it, and a fish in a round bowl looks bigger when you view it from the side.

In each case light crosses from one transparent material into another, from water or glass into air, before it reaches your eye. Light from the part of the straw under water leaves the surface in a new direction. Your brain assumes light travels in straight lines, so it places that part of the straw in the wrong spot. The effect is stronger for some pairs of materials than for others: a straw in cooking oil looks bent by a different amount. This change of direction is called refraction (अपवर्तन).

Definition
Refraction

The change in the direction of light when it passes at a slant from one transparent medium into another.

3/3The eye traces the ray straight back, so the coin appears higher than it is.

Fig. 9.9Refraction at the water surface lets light from the hidden coin reach your eye.NCERT Activity 9.8 · p. 146

A mug is shown in cross-section with a coin on its bottom and an eye above and to the left. Step 1: the mug is empty; the eye's line of sight just grazes the rim and hits the far wall, so the coin is hidden. Step 2: the mug is filled with water; a ray from the coin travels up to the surface, bends away from the dashed normal, passes over the rim and reaches the eye. Step 3: the ray entering the eye is traced backwards as a dashed line into the water; it ends above the real coin, where a dashed outline shows the coin appears to be, raised towards the surface.

9.3.1 Refraction through a Rectangular Glass Slab

A rectangular glass slab is the simplest place to trace a refracted ray, because its two long faces are flat and parallel. The classic method uses pins.

3/4The emergent ray runs parallel to the incident ray, shifted sideways.

Fig. 9.10The emergent ray is parallel to the incident ray but shifted sideways.NCERT Fig. 9.10 · p. 147

A wide rectangular glass slab lies between air above and air below. Step 1: a ray travels down to the top face at O, where a dashed normal is drawn; inside the glass it bends towards the normal, with angle of incidence i and angle of refraction r marked. Step 2: at the bottom face a second normal is drawn; the ray leaves into air and bends away from the normal, at angle of emergence e. Step 3: the incident ray is continued straight through as a dotted line; the emergent ray is parallel to it, and a double arrow between the two marks the sideways shift. Step 4: a green ray strikes the slab straight on, along the normal, and passes through without bending.

The bending at the two faces is equal and opposite. Because the faces are parallel, the second face exactly undoes what the first one did to the direction. So the ray leaves in its original direction, displaced a little to one side. The thicker the slab and the more slanted the ray, the bigger this lateral (sideways) shift. A ray that meets the slab along the normal goes straight through without bending.

Why does light bend at all? Its speed changes as it crosses from one medium into another: light travels more slowly in glass than in air. Picture a row of soldiers marching at a slant from a road onto sand. The end of the row that reaches the sand first slows down first, so the whole row swings round to a new direction. Experiments show that refraction obeys two laws.

LawLaws of refraction

(i) The ray going in, the ray coming out and the normal at the boundary point lie in one plane. (ii) For one colour of light crossing between one pair of media, sin⁡i divided by sin⁡r keeps the same value whatever the angle of incidence (for 0∘<i<90∘). This is Snell's law.

Snell's law
sin⁡isin⁡r=constant
(9.4)

This constant has a name, the refractive index, and it is the subject of the next section.

Quick check
1 of 3
A ray passes at a slant from air into glass. At the boundary it…
Show answer

Answer (B) bends towards the normal

Light slows down in glass, so it bends towards the normal. It bends away when it passes from glass into air. It goes straight only if it meets the boundary along the normal.

9.3.2 The Refractive Index

Some pairs of media bend light a lot and others only a little. The refractive index (अपवर्तनांक) puts a number on this, and the number is tied to the speed of light. Nothing beats light in empty space, about 3×108 m/s. Air slows it by only about 0.03 %, but water and glass slow it by a quarter to a third.

Let light cross from medium 1, where its speed is v1, into medium 2, where its speed is v2. Dividing the first speed by the second gives n21, the refractive index of medium 2 relative to medium 1:

n21=v1v2
(9.5)
where
v1
how fast light moves in medium 1
v2
how fast light moves in medium 2

Swap the media and the ratio turns upside down:

n12=v2v1=1n21
(9.6)

When the first medium is vacuum (air is close enough that we treat it the same way), the ratio is the absolute refractive index of the medium, usually just called its refractive index nm. With c the speed of light in vacuum and v its speed in the medium:

nm=cv
(9.7)
where
c
speed of light in vacuum, about 3×108 m/s
v
speed of light in the medium
Definition
Refractive index (n)

The number of times by which light is faster in vacuum (or air) than in a medium. It has no unit; the larger it is, the more slowly light travels in the medium.

For water n=1.33: in the time light covers 1.33 m in air, it covers only 1 m in water. Crown glass has n=1.52. You need not memorise such values, but you should be able to use them. Fig. 9.11 sends the same ray into three materials: the larger the refractive index, the more sharply the ray turns towards the normal.

2/3In crown glass it is 34.7∘: more bending.

Fig. 9.11Same angle of incidence, three media: a larger refractive index means more bending.

A ray in air strikes a flat boundary at 60 degrees to the dashed normal; a dotted line shows where it would go without bending. Step 1: below the boundary is water, refractive index 1.33, and the ray bends to 40.6 degrees from the normal. Step 2: the lower medium is glass, refractive index 1.52, and the ray bends to 34.7 degrees. Step 3: the lower medium is diamond, refractive index 2.42, and the ray bends sharply to 21.0 degrees.

Table 9.6Refractive index and speed of light in some materialsNCERT Table 9.3 · p. 149
MaterialRefractive index nSpeed of light (× 10⁸ m/s)
Air1.00033.00
Ice1.312.29
Water1.332.26
Ethyl alcohol1.362.21
Kerosene1.442.08
Glycerine1.472.04
Turpentine oil1.472.04
Benzene1.502.00
Crown glass1.521.97
Rock salt1.541.95
Carbon disulphide1.631.84
Dense flint glass1.651.82
Diamond2.421.24
Example

Using refractive indices

(a) Diamond has a refractive index of 2.42. Find the speed of light in diamond. (b) Crown glass has n=1.52 and water n=1.33. Find the refractive index of glass with respect to water, and say what it means.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 3
A plastic has a refractive index of 1.25. What is the speed of light in it, in m/s? (Take c=3.0×108 m/s.)
m/s
Show answer

Answer 240000000 m/s

v=c/n, so v=3.0×108÷1.25, which is 2.4×108 m/s. Multiplying by n would give a speed faster than light in vacuum, which is impossible.
Practice · 5 questions

Practice 9.3 (NCERT in-text questions, p. 150): questions with answers

  1. Short answerEasyNCERT in-text Questions p. 150, Q1

    Light from a fish crosses the water surface at a slant on its way to your eye. As it leaves the water, which way does it turn relative to the normal, and why?

    Show solution

    AnswerAway from the normal, because light speeds up when it goes from water into air.

    Air is optically rarer than water (smaller refractive index), so light speeds up as it enters air. Leaving a denser medium for a rarer one, a ray turns away from the normal.

  2. NumericalEasyNCERT in-text Questions p. 150, Q2

    Light passes from air into a glass of refractive index 1.60. Find the speed of light in this glass. (Speed of light in vacuum =3×108 m/s.)

    m/s
    Show solution
    v=cn=3×1081.60≈1.88×108 m/s
  3. Short answerEasyNCERT in-text Questions p. 150, Q3

    Using Table 9.6, name the liquid with the highest optical density and the solid with the lowest optical density.

    Show solution

    AnswerCarbon disulphide (1.63) among the liquids; ice (1.31) among the solids.

    The larger the refractive index, the optically denser the medium. Among the liquids, carbon disulphide has the largest value (1.63). Among the solids, ice has the smallest (1.31).

  4. Quick answerEasyNCERT in-text Questions p. 150, Q4

    In which of these does light travel fastest?

    Show answer

    Answer (C) Ice

    Ice has the smallest refractive index of the three (1.31, against 1.36 and 1.50), so light is fastest in ice.
  5. Short answerEasyNCERT in-text Questions p. 150, Q5

    A data book lists rock salt with n=1.54. Explain in one sentence what this number tells you about light in rock salt.

    Show solution

    AnswerLight travels 1.54 times faster in vacuum (or air) than in rock salt.

    n=c/v=1.54, so the speed of light in vacuum is 1.54 times its speed in rock salt. In rock salt light travels at about 1.95×108 m/s.

9.3.3 Refraction by Spherical Lenses

A watch repairer fits a small magnifier into one eye; reading glasses make print look bigger; a phone camera hides a stack of tiny lenses. A lens (लेंस) is a clear piece of glass or plastic shaped so that at least one of its faces is curved like part of a sphere; the other face may be flat.

A lens that is thicker in the middle than at the edges is a convex lens. It brings parallel rays together, so it is also called a converging lens. A lens that is thinner in the middle is a concave lens; it spreads parallel rays apart and is called a diverging lens. In this chapter, 'convex lens' means a lens with both faces bulging outwards, and 'concave lens' one with both faces curving inwards.

2/4Parallel rays converge to the principal focus F2 on the far side.

Fig. 9.12A lens has two centres of curvature, an optical centre and two principal foci.NCERT Fig. 9.12 · p. 150

Step 1: two large dashed circles overlap; their common part is a convex lens, and the circles' centres C1 and C2 lie on the principal axis on either side, with the optical centre O at the middle of the lens. Step 2: rays parallel to the axis pass through the convex lens and converge to the focus F2 on the far side. Step 3: the lens is replaced by a concave lens; parallel rays spread out after it, and dashed lines traced backwards meet at F1 on the side the light came from. Step 4: a slanting ray passes through O without bending, and the focal length f is marked equal on both sides of the lens.

Each curved face is part of a sphere, so a lens has two centres of curvature, C1 and C2. The line through them is the principal axis. The central point of the lens on this axis is its optical centre O. The diameter of the lens is its aperture. We study only thin lenses with small apertures, whose two centres of curvature are equally far from O.

Definition
Optical centre (O)

The central point of a lens on its principal axis. A ray passing through it goes straight on without changing direction.

Rays parallel to the principal axis, after passing through a convex lens, meet at a point on the axis on the far side: the principal focus. After a concave lens, they spread out as if they came from a point on the axis on the side they entered. Light can enter a lens from either side, so every lens has two principal foci, F1 and F2, one on each side and equally far from O. That distance is the focal length f of the lens.

Quick check
1 of 3
Which lens is thicker at the middle than at the edges?
Show answer

Answer (B) A convex lens

A convex (converging) lens bulges in the middle. A concave lens is thinnest in the middle.

9.3.4 Image Formation by Lenses

Like a concave mirror, a convex lens forms different kinds of image depending on where the object is. We can find them with a bench experiment much like Activity 9.3.

Table 9.8Images formed by a convex lensNCERT Table 9.4 · p. 152
ObjectNature of imageSizeWhere the image forms
At infinityReal, invertedA point, highly diminishedAt F2
Beyond 2F1Real, invertedDiminishedBetween F2 and 2F2
At 2F1Real, invertedSame sizeAt 2F2
Between F1 and 2F1Real, invertedEnlargedBeyond 2F2
At F1Real, inverted (rays leave parallel)Very largeAt infinity
Between F1 and OVirtual, erectEnlargedOn the same side as the object
Table 9.9Images formed by a concave lensNCERT Table 9.5 · p. 153
ObjectNature of imageSizeWhere the image forms
At infinityVirtual, erectA point, highly diminishedAt F1
Anywhere between infinity and OVirtual, erectDiminishedBetween F1 and O

9.3.5 Image Formation in Lenses Using Ray Diagrams

Ray diagrams for lenses work just like those for mirrors, except that the rays pass through instead of bouncing back. For a thin lens we draw all the bending at the central line of the lens. Any two of these three rays locate an image (Fig. 9.13):

  1. A ray parallel to the principal axis passes through F2 after a convex lens, or spreads out as if it came from F1 after a concave lens.
  2. A ray through F1 of a convex lens, or one heading towards F2 of a concave lens, comes out parallel to the principal axis.
  3. A ray through the optical centre O goes straight on without bending.

1/3Convex: through F2. Concave: as if from F1.

Fig. 9.13Any two of these rays locate the image formed by a lens.NCERT Figs. 9.13–9.15 · p. 153

Two panels, a convex lens above and a concave lens below, each with foci F1 and F2 marked on the principal axis. Step 1: a ray parallel to the axis passes through the convex lens and then through F2; through the concave lens it bends away from the axis, and its dashed backward extension passes through F1. Step 2: a ray through F1 of the convex lens comes out parallel to the axis; a ray aimed at F2 of the concave lens comes out parallel, its original direction shown dashed. Step 3: in both lenses a slanting ray through the optical centre O continues in a straight line.

Fig. 9.14 applies the parallel ray and the ray through O to every row of Table 9.8 and Table 9.9. Then use the lens explorer: drag the object across 2F1 and F1 and watch the image change side and character.

4/8Image beyond 2F2: real, inverted, enlarged.

Fig. 9.14Convex lens images for six object positions, then the concave lens.NCERT Figs. 9.16–9.17 · p. 155

A lens stands in the middle of the principal axis with 2F1 and F1 marked on the left and F2 and 2F2 on the right. Each step uses a blue ray parallel to the axis and an orange ray through the optical centre. Steps 1 to 6 use a convex lens. Step 1, object at infinity: parallel rays meet at F2. Step 2, object beyond 2F1: a small inverted image between F2 and 2F2. Step 3, object at 2F1: a same-size inverted image at 2F2. Step 4, object between F1 and 2F1: a large inverted image beyond 2F2. Step 5, object at F1: the rays leave parallel, so the image is at infinity. Step 6, object between F1 and O: the rays spread out and their dashed extensions meet on the object's side, giving a large, upright, virtual image. Steps 7 and 8 use a concave lens: parallel rays seem to come from F1, and an object at any distance gives a small, upright, virtual image between F1 and O.

InteractiveLens explorer

An interactive ray diagram for lenses. Two buttons choose a convex or a concave lens. You can drag the object arrow along the principal axis, or use a slider to set its distance from the optical centre, from 1 centimetre up to four focal lengths; for the convex lens, five buttons jump the object beyond 2F1, to 2F1, between F1 and 2F1, to F1, or inside F1. A second slider sets the focal length. Three rays are drawn: one parallel to the axis, one through the optical centre and one through (or towards) a focus, with dashed extensions when the image is virtual. Cards show the signed values of u, v, f, m and the image height, and a status line describes the image.

Fig. 9.15Choose a convex or concave lens and drag the object along the axis. Read the signed u, v, f and m, and check them against the lens formula.
Quick check
1 of 3
An object is placed between F1 and 2F1 of a convex lens. The image is…
Show answer

Answer (B) beyond 2F2, real, inverted and enlarged

This is the fourth row of Table 9.8: the image is real, inverted, enlarged and beyond 2F2. A diminished image needs the object beyond 2F1.

9.3.6 Sign Convention for Spherical Lenses

Lenses use the same New Cartesian convention as mirrors, with one change: every distance is measured from the optical centre O instead of the pole. Light still comes from the left, so u is negative. The focus that matters for a convex lens, F2, is on the right, so its focal length is positive; a concave lens has a negative focal length. Heights above the axis are positive and heights below it negative, as before.

Table 9.10Signs at a glance for mirrors and lenses
Concave mirrorConvex mirrorConvex lensConcave lens
Focal length f−++−
v for a real image−(no real image)+(no real image)
v for a virtual image++−−
m− real, + virtual+− real, + virtual+

9.3.7 Lens Formula and Magnification

The lens formula links u, v and f for a lens. Notice the minus sign, which is different from the mirror formula:

Lens formula
1v−1u=1f
(9.8)
where
u
object distance from O
v
image distance from O
f
focal length

As with mirrors, one formula serves both kinds of lens and every object position, provided the signs come from the convention. Magnification is defined exactly as for mirrors:

m=h′h
(9.9)

But its link with the distances has no minus sign:

m=h′h=vu
(9.10)

Why the difference? A real image from a lens forms on the right (v positive) while the object is on the left (u negative), so v/u is already negative for a real, inverted image. For a mirror, a real image forms on the same side as the object, so an extra minus sign is needed to make m negative. The meaning is the same for both: negative m means real and inverted, positive m means virtual and erect.

Example 9.3NCERT Example 9.3 · p. 156

Where is the object?

A concave lens of focal length 20 cm forms an image 12 cm from the lens. How far from the lens is the object? Find the magnification.

Try it yourself first. Then reveal the solution one step at a time.

Example 9.4NCERT Example 9.4 · p. 156

A real image from a convex lens

An object 3.0 cm tall stands upright on the principal axis, 18 cm from a convex lens of focal length 12 cm. Find the position, size and nature of the image, and the magnification.

Try it yourself first. Then reveal the solution one step at a time.

Quick check
1 of 2
An object is 30 cm from a convex lens of focal length 10 cm. Find v with its sign.
cm
Show answer

Answer 15 cm

1/v=1/f+1/u=1/10−1/30=2/30, so v=+15 cm: a real image on the far side. Using the mirror formula by mistake gives a wrong answer.

9.3.8 Power of a Lens

Hold a thick and a thin magnifying glass in sunlight. The thick one brings the light to a point much nearer to itself, because it turns the rays more sharply. Concave lenses behave alike: the shorter the focal length, the harder they spread light. The power (क्षमता) of a lens measures this bending ability. It is the reciprocal of the focal length:

Power of a lens
P=1f
(9.11)
where
f
focal length in metres

With f in metres, power is in dioptres (D), and 1 D=1 m−1: a lens that focuses parallel light one metre away has a power of one dioptre. A convex lens has positive power and a concave lens negative power, following the sign of f (Fig. 9.16).

Definition
Power of a lens (P)

The reciprocal of the focal length in metres, measured in dioptres (D). It is positive for a convex lens and negative for a concave lens.

2/2P=1/0.20 m=+5.0 D: sharper bending, a closer focus.

Fig. 9.16A shorter focal length means a more powerful lens.

Parallel rays enter a convex lens from the left. Step 1: a thin lens bends them gently and they meet at F far away, 50 centimetres from the lens; its power is plus 2.0 dioptres. Step 2: a fatter lens bends the same rays sharply so that they meet at F only 20 centimetres away and then spread out again; its power is plus 5.0 dioptres.

Opticians write prescriptions in dioptres. A prescription of +1.25 D means a convex lens with f=1/1.25=+0.80 m. One of −4.0 D means a concave lens with f=−0.25 m, that is, 25 cm.

Quick check
1 of 3
What is the power of a convex lens of focal length 25 cm?
D
Show answer

Answer 4 D

Convert to metres first: f=+0.25 m, so P=1/0.25=+4 D. Using 25 instead of 0.25 gives 0.04, the classic mistake.
Practice · 3 questions

Practice 9.4 (NCERT in-text questions, p. 158): questions with answers

  1. Short answerEasyNCERT in-text Questions p. 158, Q1

    An optician says a lens has a power of exactly 1 D. What is its focal length? Use this to define one dioptre.

    Show solution

    Answer1 m. A lens that focuses parallel light one metre away has a power of one dioptre.

    f=1/P=1/1=1 m. So a lens with a focal length of exactly 1 m has a power of one dioptre: 1 D=1 m−1.

  2. NumericalMediumNCERT in-text Questions p. 158, Q2

    On a lens bench, a screen 40 cm behind a convex lens shows a sharp image exactly as tall as the object, but upside down. How far in front of the lens is the object, and what is the power of the lens?

    1. Distance of the pin from the lens, in cm:

      cm
      Show answer

      Answer 40 cm

      Same size and real: object at 2F1, image at 2F2, so both are 40 cm from the lens.
    2. Power of the lens, in dioptres:

      D
      Show solution

      With u=−40 cm and v=+40 cm: 1/f=1/40+1/40=1/20, so f=+20 cm=+0.20 m and P=1/0.20=+5 D.

  3. NumericalEasyNCERT in-text Questions p. 158, Q3

    A concave lens has a focal length of 80 cm. What is its power?

    D
    Show solution

    For a concave lens f is negative: f=−0.80 m. P=1/f=−1.25 D.

Recap

Light – Reflection and Refraction: key points and summary

  1. Light travels in straight lines in a uniform medium, so we draw its path as rays.
  2. Every reflecting surface obeys the laws of reflection: ∠i=∠r, and the incident ray, the normal and the reflected ray lie in one plane (Law).
  3. A plane mirror gives a virtual, erect, same-size, laterally inverted image; image and object are equally far from the mirror (Section 9.1).
  4. Spherical mirrors are concave or convex; for small apertures, F is midway between P and C, so R=2f (Section 9.2).
  5. A concave mirror gives real, inverted images for objects beyond F and a virtual, erect, enlarged image inside F; a convex mirror always gives a virtual, erect, diminished image (Table 9.3, Table 9.4).
  6. Images are located by drawing two special rays: through F, C or P for mirrors, and through F or O for lenses (Section 9.2.2, Section 9.3.5).
  7. In the New Cartesian sign convention, distances are measured from the pole or optical centre, positive to the right and upwards; u is always negative (Section 9.2.3).
  8. Mirror formula 1/v+1/u=1/f; magnification m=h′/h=−v/u ((9.1), (9.3)).
  9. Light bends towards the normal entering an optically denser medium and away from it entering a rarer one; a glass slab shifts a ray sideways without changing its direction (Section 9.3.1).
  10. Snell's law: sin⁡i/sin⁡r is constant for a given pair of media and colour of light ((9.4)).
  11. Refractive index n=c/v; light travels at about 3×108 m/s in vacuum and more slowly in every medium (Section 9.3.2).
  12. A convex lens converges light and a concave lens diverges it; a concave lens always gives a virtual, erect, diminished image (Section 9.3.4).
  13. Lens formula 1/v−1/u=1/f; magnification m=h′/h=v/u ((9.8), (9.10)).
  14. Power P=1/f with f in metres, measured in dioptres; convex lenses have positive power, and the powers of lenses in contact add (Section 9.3.8).
Practice · 20 questions

Practice questions with answers (NCERT “Exercises”)

  1. Quick answerEasyNCERT Exercises Q1

    Which of these could not be shaped into a working lens?

    Show answer

    Answer (C) Polished teak wood

    Wood is opaque, so light cannot pass through it however well it is polished. Water, acrylic and clear ice are transparent and can all act as lenses.
  2. Quick answerEasyNCERT Exercises Q2

    A make-up mirror shows an upright face that is larger than the real one. Where is the face?

    Show answer

    Answer (B) Between the pole and F

    A concave mirror gives an erect, enlarged (virtual) image only when the object is between P and F. Between F and C the image is enlarged but inverted.
  3. Quick answerMediumNCERT Exercises Q3

    A stamp is to be photographed at exactly its own size, as a real image, using a convex lens of focal length 8 cm. How far from the lens must the stamp be?

    cm
    Show answer

    Answer 16 cm

    At 2F1: u=−2f=−16 cm. Then v=+16 cm and m=−1.
  4. Quick answerMediumNCERT Exercises Q4

    Using the New Cartesian convention, a mirror and a thin lens are both labelled f=+20 cm. What kinds are they?

    Show answer

    Answer (C) both convex

    A positive focal length means the focus is to the right: behind a convex mirror, and on the far side of a convex lens. A concave mirror and a concave lens both have negative f.
  5. Quick answerMediumNCERT Exercises Q5

    However far away you stand, your image in a certain mirror is always upright. Which mirrors could it be? Select all that apply.

    Select all that apply
    Show answer
    Answer
    • (A) Plane
    • (C) Convex
    Plane and convex mirrors always give virtual, erect images. A concave mirror gives an inverted image once you stand beyond its focus.
  6. Quick answerEasyNCERT Exercises Q6

    Which lens would you choose to read the tiny print on a medicine strip?

    Show answer

    Answer (A) A convex lens of focal length 4 cm

    A convex lens with the print inside its focus gives an enlarged, erect, virtual image. A short focal length gives a larger magnification at a comfortable distance. Concave lenses only make things look smaller.
  7. DiagramMediumNCERT Exercises Q7

    Arjun holds a concave mirror of focal length 12 cm near a postage stamp so that the stamp looks upright in it. How far from the mirror can the stamp be? Is the image real or virtual, bigger or smaller than the stamp? Draw the ray diagram.

    Show solution

    AnswerLess than 12 cm away (between P and F); the image is virtual, erect and larger than the stamp.

    A concave mirror gives an erect image only when the object is between the pole and the focus, so the object must be less than 12 cm from the mirror.

    The image is virtual and erect, formed behind the mirror, and larger than the object.

    Ray diagram: draw a ray from the top of the object parallel to the axis, reflecting through F; and a ray along the line from F through the top of the object, reflecting parallel to the axis. The reflected rays spread out, so extend them backwards (dashed) behind the mirror: they meet at the top of an enlarged upright image. Compare with the last step of Fig. 9.4.

  8. Short answerEasyNCERT Exercises Q8

    Which mirror does each of these use, and why?

    1. A dentist's mouth mirror

      Show answer

      Answer (A) Concave

      Held close, with the tooth inside F, a concave mirror gives an enlarged, upright view.
    2. A large mirror in the corner of a shop, for spotting shoplifters

      Show answer

      Answer (B) Convex

      A convex mirror gives an upright image and a wide field of view, so the whole shop is visible.
    3. The reflector of a solar cooker

      Show answer

      Answer (A) Concave

      A concave reflector brings parallel sunlight to its focus, concentrating the energy on the cooking pot.
  9. ActivityMediumNCERT Exercises Q9

    A convex lens is projecting a sharp image of a candle onto a screen. Riya sticks black tape over the top half of the lens. Her friend says half of the flame will vanish from the screen. Is he right? How could they test it, and what would they see?

    Show solution

    AnswerNo: the whole flame still appears, but dimmer.

    Check: focus a candle's image on a screen with the uncovered lens, then stick black paper over the top half of the lens without moving anything, and look at the screen again.

    Expect: the whole candle is still there, in the same place and of the same size, but fainter. Every part of the lens receives light from every point of the candle and sends it to the matching image point. The uncovered half still does this for all points, so the image stays complete; only half as much light arrives, so it is dimmer.

  10. NumericalMediumNCERT Exercises Q10

    A cardboard arrow 4.0 cm tall stands 30 cm from a convex lens whose focal length is 12 cm. Where will a screen catch its image? How tall is the image, and what kind is it? Sketch the ray diagram.

    1. Image distance v (cm, with sign):

      cm
      Show solution
      1v=1f+1u=112−130=120

      v=+20 cm: on the far side of the lens.

    2. Image height h′ (cm, with sign):

      cm
      Show solution

      m=v/u=−2/3, so h′=mh=−2.7 cm. The image is real, inverted and diminished, as expected for an object beyond 2F1 (24 cm). The ray diagram is the second step of Fig. 9.14.

  11. NumericalMediumNCERT Exercises Q11

    Looking through a concave lens (f=30 cm), you see a small upright image of a pencil 20 cm from the lens. Where is the pencil really? Sketch the ray diagram.

    cm
    Show solution
    1u=1v−1f=−120+130=−160

    u=−60 cm: the object is 60 cm in front of the lens, and m=v/u=+1/3. Ray diagram: as in the last step of Fig. 9.14, a ray parallel to the axis bends away as if from F1, and a ray through O goes straight; traced back, they meet at the small upright image 20 cm from the lens.

  12. NumericalMediumNCERT Exercises Q12

    A convex mirror has a focal length of 30 cm. A toy stands 20 cm from it. Where is the toy's image, and what kind of image is it?

    cm
    Show solution
    1v=1f−1u=130+120=112

    v=+12 cm: the image is 12 cm behind the mirror. m=−v/u=−12/(−20)=+0.6, so it is virtual, erect and diminished.

  13. Short answerEasyNCERT Exercises Q13

    For one particular mirror, the magnification is +1 wherever the object is placed. Which mirror is it, and what do the sign and the size of this number tell you?

    Show solution

    AnswerA plane mirror: '+' means a virtual, erect image; '1' means it is the same size as the object.

    The plus sign means the image is erect, and therefore virtual. The value 1 means h′=h: the image is exactly the same size as the object. Only a plane mirror does this for every object position.

  14. NumericalMediumNCERT Exercises Q14

    A convex mirror has a radius of curvature of 40 cm. A toy car 6.0 cm tall stands 40 cm from it. Where is the image? Describe it and find its height.

    1. Image distance v (cm, with sign):

      cm
      Show solution
      1v=120+140=340

      v=+13.3 cm: behind the mirror.

    2. Image height h′ (cm):

      cm
      Show solution

      m=−v/u=+1/3 and h′=mh=+2.0 cm. The image is virtual, erect and diminished.

  15. NumericalMediumNCERT Exercises Q15

    In a school lab, a candle 5.0 cm tall stands 36 cm from a concave mirror with a focal length of 24 cm. How far from the mirror must the screen go for a sharp image? How tall is the image, and is it upright?

    1. Image distance v (cm, with sign):

      cm
      Show solution
      1v=−124+136=−172

      v=−72 cm: place the screen 72 cm in front of the mirror.

    2. Image height h′ (cm, with sign):

      cm
      Show solution

      m=−2 and h′=−10 cm: the image is real, inverted and twice the size of the object.

  16. NumericalEasyNCERT Exercises Q16

    A spectacle lens is marked −5.0 D. What is its focal length, and does it converge or diverge light?

    m
    Show solution

    f=1/P=1/(−5.0), so f=−0.20 m, that is −20 cm. The focal length is negative, so the lens is concave (diverging).

  17. NumericalEasyNCERT Exercises Q17

    Dadi's reading glasses are marked +2.5 D. How far from each lens would it focus sunlight, and what kind of lens is it?

    m
    Show solution

    f=1/P=1/2.5, so f=+0.40 m, that is 40 cm. Positive, so the lens is converging (convex).

  18. Quick answerMedium

    Assertion (A): A ray of light passing from glass into air along the normal does not bend. Reason (R): Light travels at the same speed in glass and in air.

    Show answer

    Answer (C) A is true, but R is false

    A is true: a ray along the normal does not change direction. R is false: light is about 1.5 times faster in air than in glass. The ray still changes speed; it just does not change direction when it meets the boundary straight on.
  19. NumericalHard

    Case study. On an optical bench, Meera records object and image distances for a convex lens (all in cm): (1) u=−60, v=+20; (2) u=−45, v=+22.5; (3) u=−30, v=+30; (4) u=−24, v=+32; (5) u=−20, v=+60.

    1. Using reading 3, find the focal length of the lens, in cm.

      cm
      Show answer

      Answer 15 cm

      u=−v means the object is at 2F1, so 2f=30 cm and f=15 cm.
    2. Which reading was recorded wrongly?

      Show answer

      Answer (C) Reading 4

      Reading 4 gives 1/32+1/24=7/96, so f≈13.7 cm, not 15. With u=−24 cm the image should be at v=+40 cm. The other readings all give f=15 cm.
    3. Find the power of the lens, in dioptres.

      D
      Show answer

      Answer 6.67 D

      P=1/0.15≈+6.7 D.
    4. In which reading is the image largest, and what is the magnification there?

      Show solution

      AnswerReading 5, with m=−3.

      m=v/u: reading 5 gives 60/(−20)=−3, the largest size. The object is closest to F1 there, between F1 and 2F1, so the image is real, inverted and three times as tall.

  20. Quick answerEasy

    Match each device with the mirror or lens it uses.

    Tap an item on the left, then its match on the right.

    Show answer
    Answer
    • Torch reflector : Concave mirror
    • Wing mirror of a scooter : Convex mirror
    • Magnifying glass : Convex lens
    • Door peephole that shows a wide, small view : Concave lens
    A torch needs a parallel beam (bulb at F of a concave mirror); a wing mirror needs a wide erect view (convex mirror); a magnifier needs an enlarged virtual image (convex lens); a peephole uses a diverging (concave) lens to show a wide, diminished, upright view.

Find your NCERT exercise question

Our practice questions are written for ncert.ai and follow the NCERT exercises. Find the one that matches the question in your textbook; its answer is with it.

In your NCERT textbookPractice question here
NCERT in-text Questions p. 142, Q1Practice 9.1 (NCERT in-text questions, p. 142) · Q1
NCERT in-text Questions p. 142, Q2Practice 9.1 (NCERT in-text questions, p. 142) · Q2
NCERT in-text Questions p. 142, Q3Practice 9.1 (NCERT in-text questions, p. 142) · Q3
NCERT in-text Questions p. 142, Q4Practice 9.1 (NCERT in-text questions, p. 142) · Q4
NCERT in-text Questions p. 145, Q1Practice 9.2 (NCERT in-text questions, p. 145) · Q1
NCERT in-text Questions p. 145, Q2Practice 9.2 (NCERT in-text questions, p. 145) · Q2
NCERT in-text Questions p. 150, Q1Practice 9.3 (NCERT in-text questions, p. 150) · Q1
NCERT in-text Questions p. 150, Q2Practice 9.3 (NCERT in-text questions, p. 150) · Q2
NCERT in-text Questions p. 150, Q3Practice 9.3 (NCERT in-text questions, p. 150) · Q3
NCERT in-text Questions p. 150, Q4Practice 9.3 (NCERT in-text questions, p. 150) · Q4
NCERT in-text Questions p. 150, Q5Practice 9.3 (NCERT in-text questions, p. 150) · Q5
NCERT in-text Questions p. 158, Q1Practice 9.4 (NCERT in-text questions, p. 158) · Q1
NCERT in-text Questions p. 158, Q2Practice 9.4 (NCERT in-text questions, p. 158) · Q2
NCERT in-text Questions p. 158, Q3Practice 9.4 (NCERT in-text questions, p. 158) · Q3
NCERT Exercises Q1Exercises · Q1
NCERT Exercises Q2Exercises · Q2
NCERT Exercises Q3Exercises · Q3
NCERT Exercises Q4Exercises · Q4
NCERT Exercises Q5Exercises · Q5
NCERT Exercises Q6Exercises · Q6
NCERT Exercises Q7Exercises · Q7
NCERT Exercises Q8Exercises · Q8
NCERT Exercises Q9Exercises · Q9
NCERT Exercises Q10Exercises · Q10
NCERT Exercises Q11Exercises · Q11
NCERT Exercises Q12Exercises · Q12
NCERT Exercises Q13Exercises · Q13
NCERT Exercises Q14Exercises · Q14
NCERT Exercises Q15Exercises · Q15
NCERT Exercises Q16Exercises · Q16
NCERT Exercises Q17Exercises · Q17

Quick check: MCQs on Light – Reflection and Refraction

  1. 9.1 Reflection of Light2 questions
  2. 9.2 Spherical Mirrors3 questions
  3. (b) Image formation by a convex mirror3 questions
  4. 9.2.4 Mirror Formula and Magnification3 questions
  5. 9.3.1 Refraction through a Rectangular Glass Slab3 questions
  6. 9.3.2 The Refractive Index3 questions
  7. 9.3.3 Refraction by Spherical Lenses3 questions
  8. 9.3.5 Image Formation in Lenses Using Ray Diagrams3 questions
  9. 9.3.7 Lens Formula and Magnification2 questions
  10. 9.3.8 Power of a Lens3 questions
Glossary · 15

Key terms (English–Hindi)

centre of curvatureवक्रता केंद्रvakrata kendra
The centre of the sphere of which a mirror (or a lens surface) is a part, marked C.
concave mirrorअवतल दर्पणavatal darpan
A spherical mirror whose reflecting surface curves inwards, facing the centre of the sphere.First seen in the chapter →
convex mirrorउत्तल दर्पणuttal darpan
A spherical mirror whose reflecting surface bulges outwards.First seen in the chapter →
focal lengthफोकस दूरीfocus doori
The distance from the pole of a mirror, or the optical centre of a lens, to its principal focus.
lensलेंसlens
A transparent piece of material bounded by two surfaces, at least one of them spherical. Convex lenses converge light; concave lenses diverge it.First seen in the chapter →
magnificationआवर्धनaavardhan
The ratio of image height to object height, m = h′/h; its sign shows whether the image is inverted (−) or erect (+).First seen in the chapter →
optical centreप्रकाशिक केंद्रprakaashik kendra
The central point of a lens on its principal axis; a ray through it is not deviated.First seen in the chapter →
poleध्रुवdhruv
The middle point of a spherical mirror's shiny face, labelled P.
power of a lensलेंस की क्षमताlens ki kshamata
The reciprocal of focal length in metres, P = 1/f, measured in dioptres (D).First seen in the chapter →
principal axisमुख्य अक्षmukhya aksh
The straight line joining P and C of a mirror, or C₁ and C₂ of a lens. It is normal to the mirror at P.
principal focusमुख्य फोकसmukhya focus
The point where rays parallel to the principal axis meet, or seem to come from, after reflection or refraction.
real imageवास्तविक प्रतिबिंबvaastavik pratibimb
An image formed where rays actually meet; it can be caught on a screen.First seen in the chapter →
refractionअपवर्तनapavartan
The change in direction of light when it passes at a slant from one transparent medium into another.First seen in the chapter →
refractive indexअपवर्तनांकapavartanaank
How many times faster light travels in vacuum than in a given medium: n = c/v.First seen in the chapter →
virtual imageआभासी प्रतिबिंबaabhaasi pratibimb
An image formed where rays only appear to meet; it cannot be caught on a screen.First seen in the chapter →