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ExplorationCh 10 Sound Waves: Characteristics and Applications

Sound Waves: Characteristics and Applications: Class 9 Science · Chapter 10

Exploration · Companion notes, simulations and practice · Official NCERT chapter PDF ↗

Published · Updated

  • 95 min
  • 28 practice questions
  • 28 MCQs

What you will learn in Sound Waves: Characteristics and Applications

  • Show with simple activities that sound is produced by vibrating objects and needs a medium to travel
  • Describe a sound wave as a longitudinal, mechanical wave of compressions and rarefactions, and tell it apart from a transverse wave
  • Draw and read density–distance graphs, and define wavelength, frequency, time period and amplitude
  • Use T = 1/ν and v = λν to solve numerical problems, and compare the speed of sound in different media
  • Relate pitch, loudness and timbre to frequency, amplitude and overtones, and state the audible range
  • Explain echo and reverberation, and calculate distances from echo times with 2d = vt
  • Describe uses of ultrasound and infrasound, including echolocation and sonar

Original companion text aligned to NCERT Science Class 9, Chapter 10, pp. 184–207. Not affiliated with or endorsed by NCERT.

A pressure cooker whistles in the kitchen, an auto-rickshaw honks outside, a temple bell rings down the lane and a friend calls your name from the next room. You know what each of these is without looking, because each one reaches you as sound.

In Chapter 7 you saw that energy never appears from nothing or disappears; it only changes form. Sound is one of those forms. This chapter asks three questions. What kind of motion makes a sound? How does that sound get from its source to your ear? And what can we measure about it? The answers explain echoes in a hall, the shrill note of a referee's whistle and how a ship finds a wreck far below the waves.

10.1 Production of Sound

Twang a steel ruler pressed on the edge of a desk, tap a steel glass with a spoon, or blow across the mouth of an empty bottle. Each time something shakes rapidly back and forth, and you hear a sound. You have made sounds like these in your arts classes. In Grade 7 you also met sonority: the ringing sound that metals such as brass and steel give when they are struck, as a temple bell or a pair of manjira does.

Definition
Vibration

A rapid, repeated to-and-fro motion of an object about its resting position.

ExampleA plucked guitar string, or the wings of a buzzing mosquito.

4/4In a flute the air column inside the pipe vibrates.

Fig. 10.1Different parts vibrate in different instruments, but every sound starts with a vibration.NCERT Fig. 10.1 · p. 184

Three sound makers sit side by side: a string stretched over a wooden box, a drum with a skin on top, and a flute-like pipe. In the first step all three are still and silent. In the second step the string is shown bending up and down with dashed outlines and sound arcs. In the third step the drum skin bulges up and down with sound arcs. In the fourth step a dashed wave inside the pipe shows the air column vibrating, with sound arcs at the open end.

So sound is produced by a vibrating object, and the object that vibrates is called the source of the sound. Sources come in a few families: stretched strings (sitar, ektara), stretched skins or membranes (tabla, dholak), columns of air (bansuri, shehnai, conch) and solid bodies (bell, manjira). Most instruments use more than one. In a sitar, the strings shake the hollow gourd, and the air inside the gourd vibrates too.

Rest your fingertips lightly on the front of your throat and hum: you feel a buzz. It comes from the vocal cords, two folds of muscle stretched across your voice box (the larynx). Breath pushed up from the lungs sets them vibrating as they open and close. Your tongue, teeth, lips and the hollows of your mouth and nose then mould that buzz into words or a song. Insects have other tricks: a cicada clicks drum-like plates on its body, and a cricket scrapes a ridged edge of one wing over the other.

10.1.1 Tuning fork

Music teachers and physics labs keep the same handy sound source: the tuning fork. Picture a capital U of steel or aluminium standing on a short handle, the stem. Tap one of its two arms, the prongs (or tines), on a rubber pad and the fork rings with one steady, clean note. Each fork always gives the same note, and its value is stamped on it.

3/3A prong touching water throws up ripples: proof that it vibrates.

Fig. 10.2A struck fork looks still, but its prongs are vibrating: the water shows it.NCERT Fig. 10.4 · p. 186

On the left a tuning fork stands upright on its stem, with labels for a prong and the stem, next to a rubber pad. In the second step, after the fork is struck on the pad, dashed outlines show both prongs moving in and out, with sound arcs on both sides. In the third step the fork is turned over and the tip of a prong touches the water in a bowl, and rings of ripples spread out from that point.

Practice · 2 questions

Pause and ponder (Q1–2): questions with answers

  1. ActivityEasyPause and Ponder Q1

    Make a sound in five different ways using only things from your school bag (a ruler, a pencil box, a water bottle and so on). For each one, name the part that vibrates.

    Show solution

    AnswerAny five sound makers, each with its vibrating part named.

    Sample answers: a ruler pressed on the desk edge and twanged (the free end of the ruler vibrates); blowing across the mouth of a half-full bottle (the air column above the water); tapping a steel pencil box (the walls of the box); running a fingernail along a comb (the teeth of the comb); a rubber band stretched over the box (the band). Your list may differ: what matters is naming what vibrates.

  2. Quick answerEasyPause and Ponder Q2

    Match each instrument with the part that vibrates to make its sound.

    Tap an item on the left, then its match on the right.

    Show answer
    Answer
    • Sitar : stretched strings
    • Dholak : stretched skin
    • Bansuri : air column inside the pipe
    • Manjira : two small metal discs
    A sitar is plucked (strings), a dholak is struck on its skins, a bansuri is blown (the air inside vibrates), and manjira are small cymbals struck together.
Quick check
1 of 3
A girl plucks a sitar string and then lays her palm on it. The sound stops because…
Show answer

Answer (D) the string stops vibrating

No vibration, no sound. Her palm stops the string moving; the tension is the same as before.

10.2 Propagation of Sound

A sound has to cross the gap between its source and you. Air is the obvious route. But can sound also pass through a wooden bench, or through a bucket of water? Two quick tests settle it.

Wood, water, air: sound got through all three. The stuff a sound passes through on its way to you is its medium, which can be any state of matter: solid, liquid or gas.

Definition
Medium

The material (solid, liquid or gas) through which a sound, or any wave, travels from one place to another.

ExampleAir carries a friend's voice to you; water carries a dolphin's clicks.

That raises a puzzle. What if there were no stuff at all between the source and you? A region empty of all matter is a vacuum. Can sound cross one?

10.2.1 Sound needs a medium to propagate

Put a battery buzzer under an airtight glass dome, a bell jar, standing on a plate that is connected to a vacuum pump. Switch on the buzzer: you hear it clearly. Now start pumping out the air Fig. 10.3.

3/4Almost no air: almost no sound, though the hammer still strikes.

Fig. 10.3Remove the air and the sound fades, even though the buzzer keeps working.NCERT Fig. 10.7 · p. 187

A glass dome stands on a plate with a buzzer inside it. A pipe runs from the plate to a vacuum pump. Blue dots inside the dome stand for air, and a bar on the right shows how loud the buzzer sounds outside. In the first step the dome is full of dots, sound arcs leave it and the bar is full. In the second step half the dots are gone, only one faint arc remains and the bar is under half. In the third step there are no dots, no arcs and the bar is almost empty, although the buzzer hammer is still there. In the fourth step an arrow shows air let back in, the dots and arcs return and the bar is full again.

The loudness bar in Fig. 10.3 tells the story. The fewer air particles left in the jar, the fainter the ring, yet through the glass you can see the hammer striking the whole time. With hardly any air left, the buzzer is close to silent; open the valve and the ringing comes back. The buzzer kept vibrating throughout. Only the medium changed, so sound needs a medium, and a vacuum does not carry it.

Space between the planets is almost a perfect vacuum. A spanner clanging against a satellite sends no sound through empty space to an astronaut floating nearby. An astronaut touching the satellite, though, could feel the vibration through the metal and the suit. Spacewalkers talk by radio sets inside their helmets: radio waves, like light, need no medium. The same goes for the opening puzzle: the Moon has almost no air, so a clap there sends no sound to a partner five metres away.

Quick check
1 of 3
Through which of these can sound travel?
Select all that apply
Show answer
Answer
  • (A) A steel railway line
  • (B) The water of a pond
  • (C) The air in a classroom
Sound travels through solids, liquids and gases. The space between the Earth and the Moon is almost a vacuum, so sound cannot cross it.

10.3 Sound Waves

We know that sound needs a medium. But what actually happens to the air between a drum and your ear? Sound leaves a source in many directions at once (that is why the tuning fork could be heard from every side). The exact pattern depends on the shape of the source. Following all of that is messy, so we simplify, as scientists often do: imagine the sound trapped in a long, narrow pipe, where it can travel only one way.

Now swap the slinky for air in a long tube. One end of the tube is closed by a piston that can slide in and out; the other end is open. The piston is our model of a source: think of it as a loudspeaker cone seen from the side. Follow the steps in Fig. 10.4.

4/4A steady in-and-out motion sends out C, R, C, R… The marked particle only jiggles.

Fig. 10.4C is a compression, R is a rarefaction. The pattern travels along the tube; the marked particle stays near home.NCERT Fig. 10.9 · p. 189

A horizontal tube is filled with rows of blue dots for air particles, with a piston at the left end and one particle column marked in orange. In the first step the dots are evenly spaced. In the second step the piston has moved right and the dots next to it are crowded, labelled C. In the third step the piston has moved back to the left; the dots next to it are spread out, labelled R, and the crowded patch C has moved further along the tube. In the fourth step the whole tube shows alternating crowded C and spread R regions, while the orange marked particle is still close to the dashed mark showing its rest position.

Think of the air in the tube as a long queue of people, each standing one step from the next. At rest every gap is the same, and the air has its normal, average density. Now the piston lurches forward. The first layer of air is shoved into the second before the second has had time to move, so for a moment these particles are packed closer than usual. A packed region like this is a compression (C). The second layer then shoves the third, and the third shoves the fourth. The packed region is passed down the tube like a jolt passing down a queue, while each person only stumbles forward a little and steps back.

When the piston draws back, it leaves a little extra room behind it. The nearest layer of air drifts back into that room, and then the next layer follows. So a region with wider gaps than usual, a rarefaction (R), also runs down the tube.

Keep the piston moving in and out and it launches packed and stretched regions one after the other: C, R, C, R. This travelling pattern of high and low density is a sound wave. Notice what does not travel: the air itself. Only the pattern moves, and the direction in which it moves is the direction of propagation of the wave.

Out in the open, nothing hems the particles in. Each compression pushes outwards on every side and grows into an expanding shell around the source, like a balloon being blown up. A small source therefore sends out spherical shells of compression and rarefaction. When these shells reach your ear, you hear the sound.

Look again at Fig. 10.4. Each particle moves to and fro along the tube, the same line along which the wave travels.

Definition
Longitudinal wave

A wave whose particles swing to and fro along the same line as the wave is moving.

ExampleSound in air; a pulse of bunched coils on a slinky.

Because sound needs particles to pass the disturbance along, it cannot exist without matter. Waves of this kind are called mechanical waves.

Definition
Mechanical wave

A wave that needs a material medium to travel through, because the particles of the medium carry the disturbance.

ExampleSound, ripples on a pond, waves on a rope.

Mechanical waves come in two kinds. Tie one end of a rope to a pole and flick the other end up and down. Humps run along the rope, while each bit of rope moves up and down, at right angles to the direction the humps travel. A wave in which the particles vibrate perpendicular to the direction of travel is a transverse wave Fig. 10.5. Sound, as we have seen, is a longitudinal wave.

2/2On a rope, particles vibrate across the direction the wave travels.

Fig. 10.5In a longitudinal wave the particles move along the direction of travel; in a transverse wave, across it.NCERT Fig. 10.12, 10.13 · p. 190

The top row shows a slinky drawn as vertical coils that are bunched in some places and spread in others. A double-headed arrow along the slinky says particles vibrate, and an arrow underneath says the wave travels to the right, in the same direction. The bottom row, which appears in the second step, shows a wavy rope with a bead on it; a vertical double-headed arrow says the particles vibrate up and down, while the arrow below shows the wave travelling to the right, at right angles to the vibration.

Quick check
1 of 3
As a sound wave passes through the air in a room, the particles of air…
Show answer

Answer (C) vibrate back and forth along the direction the wave travels

Sound is a longitudinal wave: each particle vibrates about its own mean position along the line of travel. The particles are not carried to the listener.

10.4 Energy of Sound Waves

3/3A hard strike carries more energy: the grains jump high.

Fig. 10.6The louder the sound reaching the film, the higher the grains jump.NCERT Fig. 10.14 · p. 192

On the left a round steel plate is being struck by a ladle. On the right is a bowl covered with stretched film with a row of grains resting on it. In the first step there are no sound arcs and the grains lie on the film. In the second step one sound arc travels from the plate and the grains lift slightly. In the third step three arcs travel from the plate and the grains jump high above the film.

A vibrating source does work on the layer of air next to it. Each particle passes the push on by colliding with its neighbours, so energy is handed along from particle to particle, although no particle makes the journey itself. In a sound wave it is energy that travels, not the medium. Air particles are never truly still: they dart about at random because of their thermal energy. A passing sound wave adds a small, orderly to-and-fro motion on top of this random motion, and the extra motion fades once the wave has gone by.

Quick check
1 of 2
A temple bell rings 40 m away from you. What actually travels from the bell to your ear?
Show answer

Answer (D) Energy, handed on by air particles

The air near the bell stays near the bell; it only vibrates. What reaches you is the energy handed from particle to particle as the wave passes.

10.5 Graphical Representation of a Sound Wave

Freeze a sound wave at one instant and measure the density of the air at points along its path. In the compressions the density is above average; in the rarefactions it is below. Plot density up the page against distance from the source across the page, and you get a smooth, wavy curve. A dashed horizontal line marks the average density, the density of undisturbed air Fig. 10.7.

3/3The peaks are crests, the dips are troughs; the dashed line is the average density.

Fig. 10.7Each compression is a crest of the graph; each rarefaction is a trough.NCERT Fig. 10.16 · p. 193

At the top, four rows of dots are crowded together in three places, labelled C, and spread out in between, labelled R. In the second step a graph appears below with density on the vertical axis and distance on the horizontal axis. A wavy curve rises above a dashed average line under each C and dips below it under each R, and dotted guide lines join each C to a peak of the curve. In the third step the labels crest, trough and average are added to a peak, a dip and the dashed line.

The peaks of the curve, where the density is greatest, are called crests; they lie at the centres of the compressions. The dips, where the density is least, are called troughs; they lie at the centres of the rarefactions. Between a crest and a trough the density passes through its average value.

A second kind of graph is just as useful. Stand at one fixed point and record the density there as time passes. As compressions and rarefactions sweep by, the density at that point rises and falls, so a graph of density against time has the same wavy shape. Only the label on the horizontal axis changes.

Practice · 1 question

Pause and ponder (Q6): questions with answers

  1. DiagramMediumPause and Ponder Q6

    In a row of air particles, the particles are crowded at 2 cm, 6 cm and 10 cm from a source, and spread out at 0, 4, 8 and 12 cm.

    1. Which positions are compressions and which are rarefactions?

      Show solution

      AnswerCompressions at 2, 6 and 10 cm; rarefactions at 0, 4, 8 and 12 cm.

      Crowded particles mean higher-than-average density, so 2, 6 and 10 cm are compressions (C). Spread-out particles mean lower density, so 0, 4, 8 and 12 cm are rarefactions (R).

    2. Sketch the density–distance graph from 0 to 12 cm. Where are the crests and troughs, and what is the wavelength?

      Show solution

      AnswerCrests at 2, 6, 10 cm; troughs at 0, 4, 8, 12 cm; wavelength 4 cm.

      Draw a dashed average-density line. The curve starts at a trough (0 cm), rises through the average line at 1 cm to a crest at 2 cm, falls through the average at 3 cm to a trough at 4 cm, and repeats. Crests: 2, 6 and 10 cm. Troughs: 0, 4, 8 and 12 cm. Neighbouring crests are 4 cm apart, so the wavelength is 4 cm. Compare your sketch with Fig. 10.7.

Quick check
1 of 3
On a density–distance graph of a sound wave, a crest shows…
Show answer

Answer (A) the centre of a compression

A crest is a point of maximum density, which is the middle of a compression. Troughs are the middles of rarefactions.

10.6 Characteristics of a Sound Wave

To compare one sound with another, we need quantities we can measure. A sound wave is described by its wavelength, its frequency (and the closely linked time period), its amplitude and its speed.

10.6.1 Wavelength, frequency and time period

The distance from one crest to the next crest, or from one trough to the next trough, is the wavelength of the wave Fig. 10.8. It is written λ (the Greek letter lambda). Since it is a length, its SI unit is the metre (m).

Definition
Wavelength (λ)

The distance between two neighbouring crests (or two neighbouring troughs) of a wave. SI unit: metre (m).

1/2Crests far apart: a long wavelength.

Fig. 10.8The wavelength is the crest-to-crest distance.NCERT Fig. 10.18 · p. 194

A graph of density against distance with a dashed average line. In the first step an orange curve has only two and a bit waves across the graph, and a double-headed arrow marked lambda spans from one crest to the next. In the second step a blue curve with more than five waves across the same width appears instead, and the lambda arrow between two neighbouring crests is much shorter.

Now imagine a tiny density meter fixed at one spot in the air, like a tide gauge on a pier. As the wave goes by, its reading climbs to a high (a compression is passing), sinks to a low (a rarefaction) and climbs again. Each full cycle of the reading, high to low and back to high, is one oscillation. Count the cycles the meter shows in one second and you have the frequency of the wave, written ν (the Greek letter nu). Its unit, "per second" (s−1), is called the hertz (Hz).

Definition
Frequency (ν)

The number of complete density oscillations at a point in one second. SI unit: hertz (Hz), where 1 Hz=1 s−1.

How long one cycle of the meter reading lasts is the time period T, measured in seconds. If the meter completes 100 cycles every second, each cycle must last one-hundredth of a second. So frequency and time period are reciprocals of each other: the higher the frequency, the shorter the time period.

Definition
Time period (T)

How long one full oscillation (maximum density, minimum, and back to maximum) takes at a fixed point. SI unit: second (s).

Time period and frequency
Tν=1orT=1ν
(10.1)
where
T
time period, in s
ν
frequency, in Hz

Most everyday sounds, such as voices, traffic or a pressure cooker, are a mixture of many frequencies at once. A struck tuning fork or a steady whistle comes very close to a single frequency, which is why they are handy for experiments.

Example 10.1NCERT Example 10.1 · p. 195

The hum of a temple bell

A sensor fixed near a large temple bell counts 750 complete density oscillations in 2.5 s as the bell hums. Find (a) the frequency and (b) the time period of the hum.

Try it yourself first. Then reveal the solution one step at a time.

Practice · 3 questions

Pause and ponder (Q7–9): questions with answers

  1. Short answerEasyPause and Ponder Q7

    A guitar has a thick string and a thin string. Tuned to the same tension and plucked, the thin string vibrates faster. Compare the frequency and the time period of the sounds from the two strings.

    Show solution

    AnswerThe thin string gives a higher frequency and a shorter time period.

    Vibrating faster means completing more oscillations each second, so the thin string has the higher frequency. Since T=1/ν, a higher frequency goes with a shorter time period. (You can hear this as a higher, shriller note.)

  2. NumericalEasyPause and Ponder Q8

    The cone of a loudspeaker vibrates at 50 Hz. How many vibrations does it complete in one minute?

    vibrations
    Show answer

    Answer 3000 vibrations

    In one second it makes 50 vibrations, and one minute is 60 s, so 50×60=3000 vibrations.
  3. NumericalMediumPause and Ponder Q9

    On a density–distance graph, the first crest is at 0.5 cm from the source and the third crest is at 4.5 cm. What is the wavelength, and what is half the wavelength?

    Show solution

    Answerλ=2 cm; half of it is 1 cm.

    From the first crest to the third crest is two wavelengths: 2λ=4.5−0.5=4.0 cm. So λ=2.0 cm and λ/2=1.0 cm. Half a wavelength is the distance from a crest to the next trough.

10.6.2 Amplitude and intensity of the sound waves

Two sounds can have the same wavelength and frequency and yet differ in how hard they squeeze the air. The greatest amount by which the density moves away from its average value is the amplitude of the wave. On the graph, it is the height of a crest above the dashed average line, or the depth of a trough below it Fig. 10.9.

Definition
Amplitude

The largest change in the density of the medium in a compression (or a rarefaction), measured from the average density.

2/2A large swing in density, same wavelength: a loud sound.

Fig. 10.9Same wavelength, different amplitude: the bigger the swing in density, the louder the sound.NCERT Fig. 10.20 · p. 195

A graph of density against distance with a dashed average line. In the first step a blue curve swings only a little above and below the line, and a short double-headed arrow from the line to a crest is labelled amplitude, with the word softer. In the second step an orange curve with the same crest spacing swings much higher and lower, its amplitude arrow is three times as long, and the word louder appears.

The bigger the amplitude, the more energy the wave carries. Your grain drum showed this: a hard strike on the plate sent the grains flying much higher than a gentle tap, because far more energy reached the film.

How strongly a sound arrives at a place is measured by its intensity. This is the sound energy that passes each second through one square metre of area held face-on to the direction the sound is travelling.

Definition
Intensity of sound

The sound energy passing each second through a unit area held perpendicular to the direction in which the sound travels.

As sound moves away from a small source, the same energy is spread over larger and larger spherical shells. At twice the distance it is shared over four times the area, and at three times the distance over nine times the area Fig. 10.10. So the intensity falls quickly as you move away, which is why a shout fades as you walk off. It is also why a big temple bell can be heard across the village while a tinkling anklet is lost within a few metres. The bell starts with far more energy to spread.

3/3At three times the distance it covers 9 times the area: much weaker.

Fig. 10.10The same energy spreads over more area the farther it goes, so each square metre gets less.NCERT Fig. 10.21 · p. 196

A small source on the left sends sound into a cone drawn with dashed lines. In the first step a small square patch sits in the cone at distance r, labelled area times 1. In the second step a patch twice as wide, divided into four squares, appears at distance 2r, labelled area times 4. In the third step a patch three times as wide, divided into nine squares, appears at distance 3r, labelled area times 9. The same energy has to cover all of each patch.

Quick check
1 of 2
Two sounds have the same frequency, but sound X has three times the amplitude of sound Y. Which statement is right?
Show answer

Answer (C) X carries more energy and sounds louder

A bigger amplitude means a bigger swing in density, which carries more energy and is heard as louder. Pitch, speed and wavelength depend on frequency and the medium, which are the same for both.

10.6.3 Speed of Sound

The speed of sound tells us how fast the pattern of compressions and rarefactions moves through the medium. Pick one feature of the wave, say a crest, and ask how far it moves in one second.

DerivationSpeed from wavelength and frequency

In one time period T, each particle completes one oscillation, and in that same time the pattern moves forward by exactly one wavelength λ. So

v=distancetime=λT

From (10.1), 1/T=ν. Putting this in gives

Speed = wavelength × frequency
v=λ ν
(10.2)
where
v
speed of sound, in m/s
λ
wavelength, in m
ν
frequency, in Hz

Sound moves at different speeds in different media. It is quickest in solids, a little slower in liquids, and slowest of all in gases. It travels roughly four to five times faster in water than in air, and fifteen to twenty times faster in many solids Table 10.4.

Table 10.4Approximate speed of sound in some mediaNCERT Table 10.1 · p. 197
StateMediumSpeed (m/s)
GasDry air at 0 °C331
GasDry air at 25 °C346
LiquidPure water1500
LiquidSeawater1530
SolidSteel5000
SolidAluminium6400

Air on a hot, sticky afternoon carries sound a little faster than air on a cold, dry morning: both warmth and moisture raise the speed. In dry air, sound travels at about 331 m/s at 0 °C and about 346 m/s at 25 °C, roughly 0.6 m/s more for every degree.

The low notes and high notes of a song reach you together, so in air every frequency must travel at the same speed. What changes with frequency is the wavelength: λ=v/ν, so doubling the frequency halves the wavelength. Try it in Fig. 10.11: raise the frequency and watch the wavelength shrink while the speed stays at 340 m/s all along. Some porous foams and specially engineered materials break this rule, but air, water and ordinary solids do not.

InteractiveSound wave lab

A tube of air particles with one particle marked in orange, and below it a graph of density against distance with a dashed average line and a bracket marking one wavelength. A frequency slider runs from 100 to 600 hertz, and three buttons set a small, medium or large amplitude. Play animates the wave slowly, Step moves it on by an eighth of a period, and Hear it plays a one-second tone at low volume. A panel shows the frequency, the time period, the wavelength worked out as 340 divided by the frequency, and the speed.

Fig. 10.11Change the frequency and amplitude, press Play, and watch the particles, the density graph and λ=v/ν change together.
Example 10.2NCERT Example 10.2 · p. 197

A dhol and a whistle

A dhol produces a deep beat of frequency 85 Hz, and a referee's whistle a shrill note of 3400 Hz. If sound moves through the air at 340 m/s, how long is each wave?

Try it yourself first. Then reveal the solution one step at a time.

Example 10.3NCERT Example 10.3 · p. 197

How far away was the firework?

On Diwali night you see a rocket burst high in the sky and hear the bang 2.5 s later. The air is at about 25 °C, so take the speed of sound as 346 m/s. How far away was the burst? (Light reaches you almost instantly.)

Try it yourself first. Then reveal the solution one step at a time.

Example 10.4NCERT Example 10.4 · p. 197

Reading a wave in water

The graph below shows the density along a sound wave travelling through water at 1500 m/s. Find (a) its wavelength, (b) its frequency and (c) its time period.

Fig. 10.12A sound wave in water: crests at 0, 1.5, 3.0 and 4.5 m.NCERT Fig. 10.22 · p. 197

A graph of density against distance in metres, with ticks at 0, 1.5, 3.0 and 4.5. A wavy curve starts at a crest at 0 and has crests again at 1.5, 3.0 and 4.5, so three complete waves fit between 0 and 4.5 metres.

Try it yourself first. Then reveal the solution one step at a time.

Practice · 2 questions

Pause and ponder (Q10–11): questions with answers

  1. NumericalEasyPause and Ponder Q10

    Use Table 10.4 to compare speeds.

    1. How many times faster is sound in seawater than in air at 25 °C?

      times
      Show answer

      Answer 4.42 times

      1530÷346≈4.4, so sound is about 4.4 times faster in seawater.
    2. How many times faster is sound in aluminium than in seawater?

      times
      Show answer

      Answer 4.18 times

      6400÷1530≈4.2.
  2. NumericalMediumPause and Ponder Q11

    A worker taps one end of a straight steel water pipe 680 m long. A friend at the other end has one ear on the pipe and hears the tap twice: once through the steel and once through the air. Take the speed of sound as 5000 m/s in steel and 340 m/s in air. Two sounds must arrive at least 0.1 s apart to be heard separately.

    1. What is the time gap between the two sounds?

      s
      Show answer

      Answer 1.864 s

      Air: 680/340=2.0 s. Steel: 680/5000=0.136 s. Gap: 2.0−0.136=1.864 s.
    2. Can the friend hear the two taps separately? Why?

      Show solution

      AnswerYes, because 1.86 s is much more than 0.1 s.

      Yes. The gap of about 1.86 s is far more than the 0.1 s needed, so the friend hears a tap through the steel first and a second tap through the air nearly two seconds later.

Quick check
1 of 3
A tuning fork of frequency 170 Hz is struck in air, where sound travels at 340 m/s. What is the wavelength of its sound?
m
Show answer

Answer 2 m

λ=v/ν=340/170=2 m.

10.6.4 Human perception of sound

A sound meter and your ear do different jobs. The meter reports numbers (frequency, amplitude, speed) that come out the same whoever reads them. Your ear and brain report experiences: shrill or deep, loud or soft, flute or voice. Pitch and loudness are names for these experiences, and they are tied to the physical numbers only loosely, not by a neat formula Table 10.5.

Table 10.5What we measure and what we hear
Measured propertyWhat we perceiveExample
FrequencyPitch (how high or low)Whistle (high) versus drum (low)
AmplitudeLoudnessShout versus whisper
Mix of overtonesTimbre (quality)Flute versus harmonium on one note

Pitch is our sense of how high or low a sound is. A mosquito's whine and a pressure-cooker whistle sit high; a bull's bellow and a big dhol sit low. Raising the frequency raises the pitch, but the ear does not measure frequency like a ruler. To your ear, going from 100 Hz to 200 Hz sounds like the same step up as going from 1000 Hz to 2000 Hz.

You know a friend's voice on the phone partly from its frequency. The shape of their throat, mouth and nose matters too, acting like the body of an instrument. In the early teens a boy's voice "breaks": his vocal cords grow longer and heavier, vibrate fewer times each second, and his voice drops lower.

Our ears are deaf to most of the frequencies that exist. A healthy young ear responds only from about 20 Hz to about 20 000 Hz (20 kHz), the audible range; children usually hear higher tones than their grandparents can. Below 20 Hz lies infrasonic sound (infrasound), and above 20 kHz lies ultrasonic sound (ultrasound) Fig. 10.13. Other animals tune in where we cannot. A dog hears the squeak of a "silent" whistle, bats, cats and dolphins hear ultrasound, and elephants rumble to one another in infrasound across kilometres of forest.

2/2Elephants hear some infrasound; dogs, bats and dolphins hear ultrasound.

Fig. 10.13Humans hear from about 20 Hz to 20 kHz. Animal ranges shown are approximate.NCERT p. 199

A horizontal band shows frequency increasing to the right, with marks at 20 hertz, 1 kilohertz and 20 kilohertz. The part below 20 hertz is labelled infrasonic, the part from 20 hertz to 20 kilohertz is labelled humans hear, and the part above 20 kilohertz is labelled ultrasonic. In the second step four bars appear for the approximate hearing ranges of animals: the elephant bar starts below 20 hertz, while the dog, bat and dolphin bars run well beyond 20 kilohertz.

Loudness is our sense of how strong a sound is, and it follows amplitude. A shout makes big swings in density and sounds loud, a whisper makes small ones and sounds soft. Walk away from a loudspeaker and it seems quieter, because less intensity reaches you. Intensity and loudness are related but not the same thing. Two people standing at one spot receive the same intensity, yet the one with weaker hearing finds the sound less loud.

A sound with just one frequency, such as a tuning fork or a phone's test beep, is a tone. Real music is richer. A note sung by a singer or played on a harmonium mixes a lowest frequency, the fundamental, with higher ones called overtones. Its graph therefore has a bumpier shape that still repeats Fig. 10.14. The sitar takes this further: beneath its main strings run extra strings (taraf) that are never plucked but hum along in sympathy and thicken the mix.

Fig. 10.14A tone has one frequency; a note adds overtones to its fundamental, but the pattern still repeats.NCERT Fig. 10.25 · p. 200

Two graphs of density against time. The top one, labelled tone, is a smooth regular wave. The bottom one, labelled note, has a bumpy shape made of a main wave plus smaller ripples, and a bracket shows that the whole bumpy pattern repeats every time period T.

Hear one note played equally loudly on a violin, a shehnai and a harmonium, and you can still name each instrument with your eyes shut. That difference in character is called timbre (say "tam-ber"). It depends on which overtones are present and how strong each one is, and that in turn depends on the instrument's shape, material and build. Two notes whose fundamental frequencies are in the ratio 2 : 1, such as 220 Hz and 440 Hz, are an octave apart, just like Sa and the upper Sa in Activity 10.7.

Quick check
1 of 3
Match each physical property with what we perceive.

Tap an item on the left, then its match on the right.

Show answer
Answer
  • Frequency : pitch
  • Amplitude : loudness
  • Mix of overtones : timbre
Higher frequency gives higher pitch; larger amplitude gives greater loudness; the overtone mix gives each instrument its timbre.

10.7 Reflection of Sound

Sound that meets a wall, a hillside or the surface of a lake does not simply vanish: much of it bounces back. This is the reflection of sound, and it follows the rules you learnt for light in Grade 8. Measured from the normal (the line at right angles to the surface), the reflected sound leaves at the same angle as the incoming sound arrived. Also, the incoming direction, the reflected direction and the normal lie in one plane.

2/2It is heard best when the second tube makes an equal angle: r=i.

Fig. 10.15Sound reflects from a hard surface at the same angle to the normal as it arrives.NCERT p. 200

A hard board lies flat at the bottom with a dashed normal line rising from its centre. A tube on the left, with a ticking clock at its upper end, points down at the board at an angle to the normal, and an orange arc marks that angle. In the second step a second tube appears on the right, making the same angle with the normal on the other side, with an ear position at its end and a matching orange arc, showing the reflected sound leaving at an equal angle.

You can try this with two long cardboard tubes and a hard board: send the tick of a clock down one tube and listen at the end of the other. The tick is loudest when the two tubes make equal angles with the normal.

10.7.1 Echo

Call out across a deep valley in the hills, or towards a big dam wall, and your own voice answers you a moment later. That answering sound is an echo.

Definition
Echo

A sound heard again after it reflects from a distant surface, arriving late enough to be heard separately from the original sound.

The catch is timing. Your brain blends two sounds into one if the second follows within about a tenth of a second (0.1 s): clap twice very quickly and you hear one blurred clap. So an echo is heard only if the reflection comes back at least 0.1 s after the original. In a classroom the walls are close, the reflections return far sooner than that, and they simply merge with your voice. This rule tells us how far away a reflecting surface must be.

DerivationThe shortest distance for an echo

The sound goes out to the surface and comes back, so it covers twice the distance d to the surface in the time t before the echo is heard Fig. 10.16:

Distance from an echo
2d=v td=v t2
(10.3)
where
d
distance to the reflecting surface
v
speed of sound
t
time between the sound and its echo

For a separate echo, t must be at least 0.1 s. In air at 22 °C, v=344 m/s, so

d=344×0.12 m=17.2 m

The reflecting surface must be at least about 17 m away for you to hear a clear echo.

3/3The echo returns after travelling 2d in total, so 2d=vt.

Fig. 10.16The echo travels to the cliff and back: twice the distance d.NCERT p. 201

A person stands on flat ground on the left, and a tall cliff rises on the right. A double-headed arrow along the ground marks the distance d between them. In the first step sound arcs leave the person towards the cliff. In the second step the arcs have reached the face of the cliff. In the third step dashed blue arcs travel back from the cliff towards the person, labelled echo, and the label 2d equals v t appears.

The surface matters too. Bare rock, concrete and glass send most of the sound straight back, so their echoes are crisp. A hillside covered in trees breaks the sound up and scatters it in many directions. A room full of cushions, carpets and drapes swallows much of it, so any echo is faint or smeared.

Example 10.5NCERT Example 10.5 · p. 201

Shouting at a hillside

Standing in front of a rocky hillside, you shout "Hello!" and hear the echo 1.2 s later. Take the speed of sound as 345 m/s. How far away is the hillside?

Try it yourself first. Then reveal the solution one step at a time.

Practice · 1 question

Pause and ponder (Q12): questions with answers

  1. NumericalMediumPause and Ponder Q12

    For a school echo demonstration, the echo of a clap must come back no sooner than 0.15 s after the clap so that everyone hears it clearly. Sound travels at 346 m/s. At least how far from the wall should the clapper stand?

    m
    Show answer

    Answer 25.95 m

    In 0.15 s sound travels 346×0.15=51.9 m, which is the round trip. The wall must be at least half of this: d=25.95 m, about 26 m.

10.7.2 Reverberation

Clap once in an empty school hall and listen: the sound does not stop dead but hangs in the air for a moment. It is bouncing from wall to ceiling to floor and back, again and again, losing a little energy at each bounce. These reflections reach you only a few hundredths of a second apart (less than about 0.05 s), so they blur into a fading tail instead of separate echoes. This lingering is called reverberation.

Definition
Reverberation

The persistence of a sound for a while after its source has stopped, caused by many reflections that arrive very close together.

Designers of concert halls and auditoriums aim for just the right amount. A little reverberation makes music sound full and warm; too much turns a speech into mush. So they shape curved reflectors behind the stage to throw sound towards the back rows, and they tame stray reflections with padded seats, carpets, heavy curtains and sound-absorbing panels.

Quick check
1 of 3
You clap near a large building and hear the echo 0.6 s later. The speed of sound is 340 m/s. How far away is the building, in metres?
m
Show answer

Answer 102 m

d=vt/2=340×0.6/2=102 m. Forgetting to halve gives 204 m, the round trip.

10.8 Ultrasonic and Infrasonic Waves, and their Applications

Sounds we cannot hear are still sound waves, and they have become powerful tools in science, medicine and industry.

Compare

Putting unheard sound to work

Infrasonic (below 20 Hz)

  • Sensor networks track the deep rumble of distant earthquakes and volcanic eruptions.
  • Huge storms, and even meteors entering the air, give out infrasound that can be tracked from hundreds of kilometres away.

Ultrasonic (above 20 kHz)

  • Ultrasonography: pictures of organs, or of a baby in the womb, without any cut.
  • Shattering kidney stones with focused pulses so the bits can be flushed out naturally.
  • Factory baths that shake dirt off jewellery and machine parts; joining plastic parts by ultrasonic welding.
  • Checking rails, pipes and welds for hidden cracks.
  • Measuring distances from reflected pulses, as in sonar and car parking sensors.

10.8.1 Echolocation

Back to the bat on a moonless night. Most bats hunt by sound: as one flies, it calls out in short bursts of ultrasound, about ten a second, far too high for us to hear. Every moth, twig and wall throws back a faint echo. The delay tells the bat how far away the object is, and the difference between its two ears tells it which side. As it closes in on a moth, it calls faster and faster, up to about two hundred calls a second. Finding things by their echoes like this is called echolocation. Dolphins and toothed whales hunt the same way under water, and oilbirds and some swiftlets use echoing clicks to fly through pitch-dark caves.

Ships use the same idea under water in sonar (sound navigation and ranging). A transmitter under the hull sends a pulse of ultrasound into the water, and a receiver picks up the echo Fig. 10.17. Sound in seawater travels at a known speed, so the time until the echo gives the distance, using (10.3). Repeated pulses reveal the direction and speed of a submarine, a shoal of fish or a wreck.

3/3The echo returns; the depth is d=vt/2.

Fig. 10.17Depth = speed of sound in water × (echo time ÷ 2).NCERT Fig. 10.28 · p. 203

A ship floats on the sea surface at the top, and a wreck lies on the seabed at the bottom. A double-headed arrow on the left marks the depth. In the first step sound arcs leave the bottom of the ship, labelled pulse sent. In the second step the arcs are near the wreck. In the third step dashed blue arcs travel back up from the wreck to the ship, labelled echo returns.

Example 10.6NCERT Example 10.6 · p. 203

A fish-finder at sea

A fishing boat off the Kerala coast uses an echo-sounder. A pulse returns from a shoal of fish 0.24 s after it is sent. The speed of sound in seawater is 1520 m/s. How deep is the shoal?

Try it yourself first. Then reveal the solution one step at a time.

Practice · 1 question

Pause and ponder (Q13): questions with answers

  1. NumericalEasyPause and Ponder Q13

    A research ship maps the ocean floor with sonar. At one spot the echo returns 2.6 s after the pulse is sent. Sound moves through seawater at 1500 m/s. How deep is the ocean there?

    m
    Show answer

    Answer 1950 m

    Half the echo time is 1.3 s, so d=1500×1.3 =1950 m.
Quick check
1 of 3
Which of these are uses of ultrasound?
Select all that apply
Show answer
Answer
  • (A) Seeing a baby in the womb
  • (B) Breaking up kidney stones
  • (D) Finding a crack inside a steel beam
Imaging, breaking kidney stones and finding hidden cracks use ultrasound. A distant eruption is picked up by its infrasound.
Recap

Sound Waves: Characteristics and Applications: key points and summary

  1. Every sound starts with a vibration: of a string, a skin, an air column or a solid body (Section 10.1).
  2. Sound needs a medium (solid, liquid or gas) and cannot travel through a vacuum (Section 10.2.1).
  3. A sound wave is a travelling train of compressions and rarefactions; the particles only vibrate about their mean positions (Section 10.3).
  4. Sound is a longitudinal, mechanical wave; waves on a rope are transverse (Section 10.3).
  5. Sound carries energy, not matter, from the source to the listener (Section 10.4).
  6. On a density–distance graph, crests are compressions and troughs are rarefactions (Section 10.5).
  7. Wavelength λ is the crest-to-crest distance; frequency ν is oscillations per second; Tν=1 (Section 10.6.1).
  8. Amplitude is the largest change in density; intensity is energy per second through unit area and falls with distance (Section 10.6.2).
  9. Speed v=λν; sound is fastest in solids and slowest in gases, and faster in warmer air (Section 10.6.3).
  10. We hear frequency as pitch and amplitude as loudness; humans hear about 20 Hz to 20 kHz (Section 10.6.4).
  11. An echo needs a delay of at least 0.1 s, so a surface at least about 17 m away; 2d=vt (Section 10.7.1).
  12. Reverberation is sound lingering through many quick reflections (Section 10.7.2).
  13. Infrasound (below 20 Hz) and ultrasound (above 20 kHz) are used in medicine, industry, sonar and echolocation (Section 10.8).
Practice · 18 questions

Practice questions with answers (NCERT “Revise, reflect, refine”)

  1. Quick answerEasyNCERT Exercises Q1

    A friend says, "Sound is a mechanical wave." Which piece of evidence backs her up best?

    Show answer

    Answer (C) Sound cannot cross empty space

    A mechanical wave needs a material medium. The bell-jar test shows that sound cannot cross a vacuum. Reflection and carrying energy are true of light too, so they do not prove it.
  2. Quick answerEasyNCERT Exercises Q2

    A singer in a room moves from a low note to a higher note. Which property of her sound decreases?

    Show answer

    Answer (B) Its wavelength

    A higher note has a higher frequency, so more compressions arrive each second. The speed in air is fixed, so λ=v/ν gets smaller. (The time period also gets smaller.)
  3. Quick answerEasyNCERT Exercises Q3

    A sensor in a stadium records 45 rarefactions of a deep rumble in 3 seconds. What is the frequency of the rumble?

    Show answer

    Answer (C) 15 Hz

    ν=45/3=15 Hz. Multiplying gives 135 and dividing the other way gives 0.067, both wrong. At 15 Hz this sound is infrasonic.
  4. Short answerMediumNCERT Exercises Q4

    Will you hear a separate echo, or not? Give a reason each time.

    1. In a big empty godown, sound reflected from the far wall reaches you 0.25 s after you clap.

      Show solution

      AnswerYes, a separate echo.

      0.25 s is more than 0.1 s, so the brain hears the reflection as a separate sound: an echo.

    2. In a tiled bathroom, reflected sound reaches you 0.03 s after you speak.

      Show solution

      AnswerNo echo; reflections like this cause reverberation.

      0.03 s is less than 0.1 s (and less than 0.05 s), so the reflections merge with your voice. Many such quick reflections make the sound linger: reverberation, which is why singing in a bathroom sounds fuller.

  5. Short answerEasyNCERT Exercises Q5

    Wave P has crests 6 cm apart, and its density rises 2 units above the average at each crest. Wave Q has crests 4 cm apart, and its density rises 5 units above the average. Both graphs use the same scales.

    1. Which wave has the greater wavelength?

      Show answer

      Answer (A) P

      P: 6 cm against Q: 4 cm.
    2. Which wave has the smaller amplitude?

      Show answer

      Answer (A) P

      P rises only 2 units above the average; Q rises 5.
  6. Quick answerMediumNCERT Exercises Q6

    Three sounds X, Y and Z travel through the same air. Their wavelengths are X: 0.5 m, Y: 1.7 m and Z: 0.85 m. Put them in order from highest to lowest frequency.

    1. Y (1.7 m)
    2. X (0.5 m)
    3. Z (0.85 m)
    Show answer
    Answer
    1. X (0.5 m)
    2. Z (0.85 m)
    3. Y (1.7 m)
    With v fixed, ν=v/λ. At 340 m/s: X is 680 Hz, Z is 400 Hz and Y is 200 Hz.
  7. DiagramMediumNCERT Exercises Q7

    Draw the density–distance graph of a sound wave with a density amplitude of 2 units and a wavelength of 5 cm, from 0 to 10 cm.

    Show solution

    AnswerA wave crossing the average line at 0, 2.5, 5, 7.5 and 10 cm, with crests 2 units up at 1.25 and 6.25 cm and troughs 2 units down at 3.75 and 8.75 cm.

    Draw axes: distance (cm) across, density up. Draw a dashed horizontal line for the average density. Starting on the average line at 0, rise to a crest 2 units above the line at 1.25 cm, come back to the line at 2.5 cm, fall to a trough 2 units below it at 3.75 cm and return to the line at 5 cm. Repeat for 5 to 10 cm. Check: crest to crest is 6.25−1.25=5 cm, the wavelength.

  8. Short answerMediumNCERT Exercises Q8

    A video game shows two scenes. In the first, lightning strikes a hill 3 km from the player, and the thunder is heard at the same instant as the flash. In the second, two satellites collide in space, and an astronaut floating 1 km away hears a loud crash. What is wrong with each scene? (Speed of sound in air: 340 m/s.)

    Show solution

    AnswerThunder should arrive about 9 s after the flash; in space no crash can be heard because there is no medium.

    Scene 1: light reaches the player almost instantly, but sound takes t=3000/340≈8.8 s. The thunder should be heard about 9 s after the flash, not with it.

    Scene 2: space is nearly a vacuum, so sound cannot travel from the collision to the astronaut. She would see the crash in silence.

  9. NumericalEasyNCERT Exercises Q9

    A harmonium reed sends out a sound whose wavelength in the room is 0.85 m. Sound travels at 340 m/s. How long does one oscillation of this sound last?

    s
    Show answer

    Answer 0.0025 s

    First ν=v/λ, which is 340/0.85=400 Hz. Then T=1/400 =0.0025 s (2.5 ms).
  10. NumericalEasyNCERT Exercises Q10

    A floating ocean instrument has broken loose and sunk to the seabed. The research ship above it sends a sonar pulse straight down and picks up the echo from the instrument 3.2 s later. Ultrasound travels at 1520 m/s in seawater. How deep is the instrument?

    m
    Show answer

    Answer 2432 m

    The pulse takes 1.6 s each way, so d=1520×1.6 =2432 m, about 2.4 km.
  11. NumericalMediumNCERT Exercises Q11

    A smart walking stick for people who cannot see well sends out ultrasound of about 40 kHz and beeps when an obstacle is 1.5 m ahead. Take the speed of sound in air as 345 m/s.

    1. How long does the pulse take to reach the obstacle and come back, in seconds?

      s
      Show answer

      Answer 0.0087 s

      The round trip is 3.0 m, so t=3.0/345 ≈0.0087 s.
    2. What is the wavelength of this ultrasound, in millimetres?

      mm
      Show answer

      Answer 8.6 mm

      λ=v/ν =345/40 000 =0.0086 m, about 8.6 mm.
  12. NumericalHardNCERT Exercises Q12

    A factory siren is 1.0 km away. Sound in dry air travels at 331 m/s at 0 °C and 346 m/s at 25 °C. How much longer does the siren take to reach you on a 0 °C winter morning than on a 25 °C afternoon? Assume nothing else changes.

    s
    Show answer

    Answer 0.131 s

    At 0 °C: 1000/331≈3.021 s. At 25 °C: 1000/346≈2.890 s. The difference is about 0.13 s.
  13. NumericalMediumNCERT Exercises Q13

    A density–distance graph of a sound in air shows exactly 4 complete waves in a length of 34 cm. The speed of sound is 340 m/s.

    1. Find the wavelength in centimetres.

      cm
      Show answer

      Answer 8.5 cm

      λ=34/4=8.5 cm.
    2. Find the frequency in hertz.

      Hz
      Show answer

      Answer 4000 Hz

      With λ=0.085 m, ν=340/0.085 =4000 Hz.
  14. NumericalMediumNCERT Exercises Q14

    Two sounds A and B travel through air at 345 m/s. On their graphs, A has crests every 2.3 cm and B has crests every 6.9 cm. Find the frequency of each.

    1. Frequency of A, in hertz.

      Hz
      Show answer

      Answer 15000 Hz

      νA=345/0.023 =15 000 Hz.
    2. Frequency of B, in hertz.

      Hz
      Show answer

      Answer 5000 Hz

      νB=345/0.069 =5000 Hz. B has three times the wavelength, so one-third the frequency.
  15. NumericalHardNCERT Exercises Q15

    Two identical beepers are the same distance from a concrete harbour wall: one in the air above the water and one under the water. Both beep at the same moment. The echo takes 4.4 times as long to return to the beeper in air as to the one under water. What is the ratio of the speed of sound in air to that in water?

    Show solution

    AnswerAir : water =1:4.4 (that is, 5 : 22).

    Both sounds travel the same distance 2d, so v=2d/t and the speed is inversely proportional to the time.

    vairvwater=twatertair=14.4

    So the speeds are in the ratio air : water =1:4.4. With 340 m/s in air, this gives about 1500 m/s in water, as expected.

  16. Quick answerEasy

    Sound waves with frequencies above 20 kHz are called waves, and those below 20 Hz are called waves.

    Show answer

    Answer (1) ultrasonic, (2) infrasonic

    Above the audible range: ultrasonic. Below it: infrasonic.
  17. Quick answerMedium

    Put the steps of a sonar depth measurement in order.

    1. Pulse hits the seabed
    2. Send a pulse down
    3. Measure the time
    4. Echo reaches the ship
    5. Use d = vt/2
    Show answer
    Answer
    1. Send a pulse down
    2. Pulse hits the seabed
    3. Echo reaches the ship
    4. Measure the time
    5. Use d = vt/2
    The pulse goes down, reflects, returns and is timed; only then can the depth be found from d=vt/2.
  18. Quick answerEasy

    Match each task with the use of sound that does it.

    Tap an item on the left, then its match on the right.

    Show answer
    Answer
    • A bat catching a moth : echolocation
    • A doctor checking a baby in the womb : ultrasonography
    • A navy ship finding a submarine : sonar
    • A station sensing a far-off volcano : infrasound detection
    Bats echolocate; doctors use ultrasound imaging; ships use sonar; distant eruptions are picked up by their infrasound.

Find your NCERT exercise question

Our practice questions are written for ncert.ai and follow the NCERT exercises. Find the one that matches the question in your textbook; its answer is with it.

In your NCERT textbookPractice question here
Pause and Ponder Q1Pause and ponder (Q1–2) · Q1
Pause and Ponder Q2Pause and ponder (Q1–2) · Q2
Pause and Ponder Q6Pause and ponder (Q6) · Q6
Pause and Ponder Q7Pause and ponder (Q7–9) · Q7
Pause and Ponder Q8Pause and ponder (Q7–9) · Q8
Pause and Ponder Q9Pause and ponder (Q7–9) · Q9
Pause and Ponder Q10Pause and ponder (Q10–11) · Q10
Pause and Ponder Q11Pause and ponder (Q10–11) · Q11
Pause and Ponder Q12Pause and ponder (Q12) · Q12
Pause and Ponder Q13Pause and ponder (Q13) · Q13
NCERT Exercises Q1Revise, reflect, refine · Q1
NCERT Exercises Q2Revise, reflect, refine · Q2
NCERT Exercises Q3Revise, reflect, refine · Q3
NCERT Exercises Q4Revise, reflect, refine · Q4
NCERT Exercises Q5Revise, reflect, refine · Q5
NCERT Exercises Q6Revise, reflect, refine · Q6
NCERT Exercises Q7Revise, reflect, refine · Q7
NCERT Exercises Q8Revise, reflect, refine · Q8
NCERT Exercises Q9Revise, reflect, refine · Q9
NCERT Exercises Q10Revise, reflect, refine · Q10
NCERT Exercises Q11Revise, reflect, refine · Q11
NCERT Exercises Q12Revise, reflect, refine · Q12
NCERT Exercises Q13Revise, reflect, refine · Q13
NCERT Exercises Q14Revise, reflect, refine · Q14
NCERT Exercises Q15Revise, reflect, refine · Q15

Quick check: MCQs on Sound Waves: Characteristics and Applications

  1. 10.1.1 Tuning fork3 questions
  2. 10.2.1 Sound needs a medium to propagate3 questions
  3. 10.3 Sound Waves3 questions
  4. 10.4 Energy of Sound Waves2 questions
  5. 10.5 Graphical Representation of a Sound Wave3 questions
  6. 10.6.2 Amplitude and intensity of the sound waves2 questions
  7. 10.6.3 Speed of Sound3 questions
  8. 10.6.4 Human perception of sound3 questions
  9. 10.7.2 Reverberation3 questions
  10. 10.8.1 Echolocation3 questions
Glossary · 15

Key terms (English–Hindi)

amplitudeआयामaayaam
The largest change in density of the medium from its average value as a sound wave passes.First seen in the chapter →
compressionसंपीडनsampeedan
A region of a sound wave where the particles are crowded together, so the density is higher than average.First seen in the chapter →
echoप्रतिध्वनिpratidhvani
A reflected sound heard separately, at least 0.1 s after the original.First seen in the chapter →
frequencyआवृत्तिaavritti
The number of complete oscillations per second, written ν; SI unit hertz (Hz).First seen in the chapter →
intensityतीव्रताteevrata
Sound energy passing each second through unit area held perpendicular to the direction of travel.First seen in the chapter →
longitudinal waveअनुदैर्ध्य तरंगanudairghya tarang
A wave in which the particles vibrate parallel to the direction in which the wave travels, as in sound.
mechanical waveयांत्रिक तरंगyantrik tarang
A wave that needs a material medium to travel; sound is one.First seen in the chapter →
mediumमाध्यमmadhyam
The material (solid, liquid or gas) through which sound travels.First seen in the chapter →
pitchतारत्वtaaratva
How high or low a sound seems to a listener; it rises with frequency.First seen in the chapter →
rarefactionविरलनviralan
A region of a sound wave where the particles are spread out, so the density is lower than average.First seen in the chapter →
reverberationअनुरणनanuranan
The lingering of a sound caused by many reflections arriving close together.First seen in the chapter →
time periodआवर्तकालaavartkaal
The time for one complete oscillation, T=1/ν; SI unit second.First seen in the chapter →
ultrasonic waveपराश्रव्य तरंगparashravya tarang
Sound of frequency above 20 kHz, too high for humans to hear. Sound below 20 Hz is infrasonic.First seen in the chapter →
vibrationकंपनkampan
A rapid, repeated to-and-fro motion of an object about its resting position.
wavelengthतरंगदैर्ध्यtarangdairghya
The distance between two neighbouring crests (or troughs) of a wave, written λ; SI unit metre.First seen in the chapter →